DO NOT BREAK THE SEALS WITHOUT BEING INSTRUCTED TO DO SO BY THE INVIGILATOR Ïi;k bu funsZ'kksa dks /;ku ls i<+ sA vkidks 5 feuV fo'ks"k :i ls bl dke ds fy, fn;s x;s gSaA Please read the instructions carefully. You are allotted 5 minutes specifically for this purpose. A. lkekU ; : 1. ;g iqfLrdk vkidk iz'u&i= gSA bldh eqgj rc rd u rksM+s tc rd fujh{kd ds } kjk bldk funZs'k u fn;k tk;sA 2. iz'u&i= dk dks M (CODE) bl i`"B ds Åijh ck;s a dkSus ij Nik gS A 3. dPps dk;Z ds fy, [kkyh i`"B vkSj [kkyh LFkku bl iqfLrdk es a gh gSaA dPps dk;Z ds fy, dks bZ vfrfjDr dkxt ugha fn;k tk;sxkA 4. dks js dkxt] fDyi ck sMZ ] ykW x rkfydk ] LykbM :y] dS Ydqys Vj] dS ejk] ls yQks u] is tj vkS j fdlh izdkj ds bys DVªkWfud midj.k ijh{kk d{k esa vuqefr ugha gS aA 5. bl iqfLrdk ds fiNys i`"B ij fn, x, LFkku es a viuk uke vkS j QkWeZ uEcj fyf[k,A 6. mÙkj i=] ,d ;a =&Js.khdj.k ;ks X; i= (ORS) gS tks fd vyx ls fn;s tk;saxsA 7. vks-vkj-,l- (ORS) ;k bl iqfLrdk esa gsj&Qsj@foÏfr u djsaA 8. bl iqfLrdk dh eqgj rks M+us ds i'pkr d`i;k tk¡p ys a fd bles a 38 i`"B gSa vkS j izR;sd fo"k; ds lHkh 22 iz'u vkSj muds mÙkj fodYi Bhd ls i<+ s tk ldrs gSaA lHkh [kaMks a dh 'kq:vkr es a fn;s gq , funsZ'kksa dks /;ku ls i<+ sA B. vks-vkj-,l- (ORS) dk Hkjko : 9. ijh{kkFkhZ dks gy fd;s x;s iz'u dk mÙkj ORS mÙkj iqfLrdk esa lgh LFkku ij dkys ckWy ikbUV dye ls mfpr xksys dks xgjk djds nsuk gS A 10. ORS ds (i`"B la [;k 1) ij ekaxh xbZ leLr tkudkjh /;ku iwoZd vo'; Hkjsa vkS j vius gLrk{kj djs aA C. iz'ui= dk izk:i : bl iz'u&i= ds rhu Hkkx (xf.kr] HkkSfrd foKku vkSj jlk;u foKku) gSaA gj Hkkx ds nks [kaM gSaA INSTRUCTIONS / lwpuk,¡ 01CT313083 KOTA - 1/38 Your Target is to secure Good Rank in JEE 2014 A. General : 1. The booklet is your Question Paper. Do not break the seal of this booklet before being instructed to do so by the invigilator. 2. The question paper CODE is printed on the left hand top corner of this sheet. 3. Blank spaces and blank pages are provided in the question paper for your rough work. No additional sheets will be provided for rough work. 4. Blank papers, clipboards, log tables, slide rules, calculators, cameras, cellular phones, pagers and electronic gadgets are NOT allowed inside the examination hall. 5. Write your name and Form number in the space provided on the back cover of this booklet. 6. The answer sheet, a machine-readable Optical Response Sheet (ORS), is provided separately. 7. DO NOT TAMPER WITH/MUTILATE THE ORS OR THE BOOKLET. 8. On breaking the seal of the booklet check that it contains 38 pages and all the 22 questions in each subject and corresponding answer choices are legible. Read carefully the instructions printed at the beginning of each section. B. Filling the ORS : 9. A candidate has to write his / her answers in the ORS sheet by darkening the appropriate bubble with the help of Black ball point pen as the correct answer(s) of the question attempted. 10. Write all information and sign in the box provied on part of the ORS (Page No. 1). C. Question Paper Formate : The question paper consists of 3 parts (Mathematics, Physics and Chemistry). Each part consists of two sections. Ïi;k 'ks"k funsZ'kksa ds fy;s bl iqfLrdk ds vfUre i`"B dks i <+ sA Please read the last page of this booklet for read the instructions PAPER – 2 PATTERN : JEE (Advanced) LEADER & ENTHUSIAST COURSE PAPER CODE TM Path to success KOTA (RAJASTHAN) 0 1 C T 3 1 3 0 8 3 Date : 23 - 04 - 2014 TARGET : JEE 2014 SCORE-II : TEST # 03 le; : 3 ?k.Vs egÙke vad : 243 Time : 3 Hours Maximum Marks : 243
38
Embed
lwpuk,¡ - ALLEN Kota€¦ · xxxC xx (B) 21xx xC++++45 (C) 43---+ 1 2xxxC x (D) None of these (Where 'C' is constant of integration) 3 5 42 35 x xxxx dx,x0 xx x1 ++ >--- ò Kkr dhft,
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Transcript
DO N
OT B
REA
K TH
E SE
ALS
WIT
HOUT
BEI
NG
INST
RUCT
ED T
O DO
SO
BY T
HE I
NVI
GILA
TOR
Ïi;k bu fun sZ'kks a dks /;ku ls i<+ sA vkidks 5 feuV fo'ks"k :i ls bl dke ds fy, fn;s x;s gS aAPlease read the instructions carefully. You are allotted 5 minutes specifically for this purpose.
A. lkekU; :
1. ;g iqfLrdk vkidk iz'u&i= gSA bldh eqgj rc rd u
rksM+ s tc rd fujh{kd ds }kjk bldk fun Z s'k u fn;k
01CT313083 KOTA - 1/38Your Target is to secure Good Rank in JEE 2014
A. General :
1. The booklet is your Question Paper. Do not break
the seal of this booklet before being instructed to
do so by the invigilator.
2. The question paper CODE is printed on the left hand
top corner of this sheet.
3. Blank spaces and blank pages are provided in the
question paper for your rough work. No additional
sheets will be provided for rough work.4. Blank papers, clipboards, log tables, slide rules,
calculators, cameras, cellular phones, pagers andelectronic gadgets are NOT allowed inside theexamination hall.
5. Write your name and Form number in the space
provided on the back cover of this booklet.
6. The answer sheet, a machine-readable Optical
Response Sheet (ORS), is provided separately.
7. DO NOT TAMPER WITH/MUTILATE THE ORS OR THE
BOOKLET.8. On breaking the seal of the booklet check that it
contains 38 pages and all the 22 questions in eachsubject and corresponding answer choices arelegible. Read carefully the instructions printed at thebeginning of each section.
B. Filling the ORS :9. A candidate has to write his / her answers in the ORS
sheet by darkening the appropriate bubble with thehelp of Black ball point pen as the correct answer(s)of the question attempted.
10. Write all information and sign in the box provied on
part of the ORS (Page No. 1).
C. Question Paper Formate :The question paper consists of 3 parts(Mathematics, Physics and Chemistry). Each partconsists of two sections.
Ïi;k 'ks"k funs Z'kks a ds fy;s bl iqfLrdk ds vfUre i`"B dks i<+ sAPlease read the last page of this booklet for read the instructions
· Stefan–Boltzmann constant s = 5.67 × 10–8 Wm–2–K–4
· Wien's displacement law constant b = 2.89 × 10–3 m–K· Permeability of vacuum µ0 = 4p × 10–7 NA–2
· Permittivity of vacuum Î0 = 20
1
cm· Planck constant h = 6.63 × 10–34 J–s
TARGET : JEE 2014 23-04-2014
LEADER & ENTHUSIAST COURSE(DATE : 23-04-2014)
MATHEMATICSTM
Path to success KOTA (RAJASTHAN)
01CT313083 KOTA - 3/38
PAPER – 2
PART-1 : MATHEMATICS
Hkkx-1 : xf.krSECTION–I : (i) Only One option correct Type
[k.M-I : (i) dsoy ,d lgh fodYi izdkjThis section contains 9 multiple choice questions. Each question has four choices (A), (B), (C) and(D) out of which ONLY ONE is correct.
bl [k.M esa 9 cgqfodYi iz'u gSA izR;sd iz'u esa pkj fodYi (A), (B), (C) vkSj (D) gSa ftuesa ls dsoy ,d
lgh gSA1. Given two points A º (–2, 0) and B º (0, 4). The coordinates of point M on the line x = y so that
perimeter of DAMB is least is :(A) (1, 1) (B) (0, 0) (C) (2, 2) (D) (3, 3)
nks fcUnq A º (–2, 0) rFkk B º (0, 4) fn, x, gSA js[kk x = y ij fcUnq M ds funsZ'kkad bl izdkj gS fd f=Hkqt AMB
O;Dr dj ldrs gks] rks f(x) dk vf/kdre laHko eku gksxk :
(A) 1 (B) 12
(C) 14
(D) 18
7. A straight line cuts the x-axis at point A(1, 0) and y-axis at point B, such that ÐOAB = a (a >4p
),
2pæ öa ¹ç ÷
è ø C is the middle point of AB. if B' is is mirror image of B with respect to the line OC and C' is the
mirror image of C with respect to the line BB', then find the ratio of areas of triangles ABB' and BB'C' :
(A) 1 (B) 12
(C) 2 (D) depends upon a
,d ljy js[kk x-v{k dks fcUnq A(1, 0) rFkk y-v{k dks fcUnq B ij bl izdkj dkVrh gS fd ÐOAB = a (a >4p
),
2pæ öa ¹ç ÷
è ø gS rFkk C, AB dk e/; fcUnq gSA ;fn js[kk OC ds lkis{k fcUnq B dk izfrfcEc B' rFkk js[kk BB' ds lkis{k fcUnq
C dk izfrfcEc C' gks] rks f=Hkqtksa ABB' rFkk BB'C' ds {ks=Qy dk vuqikr gksxk -
(A) 1 (B) 12
(C) 2 (D) a ij vkfJr
MATHEMATICSTARGET : JEE 2014(DATE : 23-04-2014)
TM
Path to success KOTA (RAJASTHAN)
01CT313083KOTA - 6/38
PAPER – 2
Space for Rough Work / dPps dk;Z ds fy, LFkku
8.24
20
x (sin 2x cos 2x)dx
(1 sin 2x)cos x
p
-
+ò equals to :
(A) 2
ln216 4p p
- (B) 2
ln216 4p p
+ (C) 2
ln 28 4p p
+ (D) None of these
24
20
x (sin 2x cos 2x)dx
(1 sin 2x)cos x
p
-
+ò dk eku gksxk :
(A) 2
ln216 4p p
- (B) 2
ln216 4p p
+ (C) 2
ln 28 4p p
+ (D) buesa ls dksbZ ugha
9. If A, B, Cur ur ur
are three non-zero vectors, no two of them are parallel if A B+ur ur
is collinear to Cur
, B C+ur ur
is
collinear to Aur
then A B C+ +ur ur ur
is equal to :
(A) Aur
(B) Bur
(C) Cur
(D) None of these
;fn A, B, Cur ur ur
rhu v'kwU; lfn'k] ftlesa dksbZ Hkh nks lekUrj ugha gS ;fn A B+ur ur
, Cur
ds lejS[kh;] B C+ur ur
, Aur
ds
lejS[kh; gks] rks A B C+ +ur ur ur
cjkcj gksxk :
(A) Aur
(B) Bur
(C) Cur
(D) buesa ls dksbZ ugha
LEADER & ENTHUSIAST COURSE(DATE : 23-04-2014)
MATHEMATICSTM
Path to success KOTA (RAJASTHAN)
01CT313083 KOTA - 7/38
PAPER – 2
Space for Rough Work / dPps dk;Z ds fy, LFkku
(ii) One or more options correct Type
(ii) ,d ;k vf/kd lgh fodYi izdkjThis section contains 4 multiple choice questions. Each question has four choices (A), (B), (C) and(D) out of which ONE or MORE are correct.
bl [k.M esa 4 cgqfodYi iz'u gSaA izR;sd iz'u esa pkj fodYi (A), (B), (C) vkSj (D) gSa] ftuesa ls ,d ;k
vf/kd lgh gSA
10. If tan6q + 27 tan2q = 3(1 + 11 tan4 q) is satisfied if q is equals to :
(A) ( )1 1 1 7cos sin(cos (cos x) 2 tan (tan x)) x
2- - - p
- = -
(B) ( )1 1 1 9cos sin(cos (cos x) 2 tan (tanx)) x
2- - - p
- = -
(C) ( )1 1 1tan cot(2sin (sin x) tan (tanx)) x2
- - - p+ = +
(D) ( )1 1 1 5tan cot(2sin (sinx) tan (tanx)) x
2- - - p
+ = -
ekuk 5x , 3
2pæ öÎ pç ÷
è ø gks] rks :
(A) ( )1 1 1 7cos sin(cos (cos x) 2 tan (tan x)) x
2- - - p
- = -
(B) ( )1 1 1 9cos sin(cos (cos x) 2 tan (tanx)) x
2- - - p
- = -
(C) ( )1 1 1tan cot(2sin (sin x) tan (tan x)) x2
- - - p+ = +
(D) ( )1 1 1 5tan cot(2sin (sinx) tan (tanx)) x
2- - - p
+ = -
13. The points P, Q and R are taken on the ellipse 2 2
2 2
x y1
a b+ = with eccentric angles q, q + a, q +2a then
area of triangle PQR is :(A) Independent of q (B) Independent of a
(C) Maximum when 23p
a = (D) Maximum when 2p
q=
nh?kZoÙk 2 2
2 2
x y1
a b+ = ij fcUnq P, Q rFkk R ftuds mRØsUæu dks.k q, q + a, q +2a gks] rks f=Hkqt PQR dk {ks=Qy gksxk :
(A) q ls LorU= (B) a ls LorU=
(C) vf/kdre tc 23p
a = (D) vf/kdre tc 2p
q =
Space for Rough Work / dPps dk;Z ds fy, LFkku
LEADER & ENTHUSIAST COURSE(DATE : 23-04-2014)
MATHEMATICSTM
Path to success KOTA (RAJASTHAN)
01CT313083 KOTA - 9/38
PAPER – 2
(iii) Paragraph Type (iii) vuqPNsn izdkj
This section contains 2 paragraphs each describing theory, experiment, data etc. Six questions relateto two paragraphs with three questions on each paragraph. Each question of a paragraph has onlyone correct answer among the four choices (A), (B), (C) and (D).bl [k.M esa fl¼kUrksa] iz;ksxksa vkSj vk¡dM+ksa vkfn dks n'kkZus okys 2 vuqPNsn gSA nksuksa vuqPNsn ls lacaf/kr N% iz'ugSa] ftuesa ls gj vuqPNsn ij rhu iz'u gSaA vuqPNsn esa gj iz'u ds pkj fodYi (A), (B), (C) vkSj (D) gSa ftuesals dsoy ,d lgh gSA
Paragraph for Question 14 to 16iz'u 14 ls 16 ds fy;s vuqPNsn
A matrix is a rectangular array of number. The numbers may be real or complex. A matrix with m rowsand n columns is called m × n matrix. If ij m nA (a ) ´= be a matrix. the transpose of A, denoted by A' or byAT. A square matrix is said to be symmetric if A' = A and skew symmetric if A' = –A. If A is any n-rowed squared matrix then a matrix B if exist, such that AB = BA = In is called inverse of A and denotedby B = A–1.,d vkO;wg la[;kvksa dh ,d vk;rkdkj lkj.kh ds :i esa izcU/k gSA la[;k;sa okLrfod ;k dkYifud gks ldrh gSA miafDr;ksa rFkk n LrEHkksa okys vkO;wg dks m × n vkO;wg dgrs gSA vkO;wg ij m nA (a ) ´= ds ifjorZ dks A' ;k AT }kjk n'kkZ;k
tkrk gSA ,d oxZ vkO;wg dks lefer dgk tkrk gS] ;fn A' = A rFkk fo"ke lefer dgk tkrk gS] ;fn A' = –A gSA ;fnA dksbZ n-iafDr oxZ vkO;wg gks rFkk oxZ vkO;wg B bl izdkj fo|eku gks fd AB = BA = In gks] rks bls A dk izfryksedgrs gS rFkk B = A–1 }kjk iznf'kZr gksrk gSA
14. Let M and N be two 3 × 3 non-singular symmetric matrix such that MN = NM. If PT dentotes thetranspose of a matrix P then M2N2 (MTN)–1 (MN–1)T is equal to:(A) M2 (B) –N2 (C) –M2 (D) MNekuk M rFkk N nks 3 × 3 ds O;qRØe.kh; lefer vkO;wg bl izdkj gS fd MN = NM gSA ;fn PT, vkO;wg P ds ifjorZdks n'kkZrk gS] rks M2N2 (MTN)–1 (MN–1)T cjkcj gksxk :(A) M2 (B) –N2 (C) –M2 (D) MN
15. Let p be an odd prime number and Tp be the following set of 2 × 2 matrices:
Pa b
T A ; a, b, c {0, 1, .....p 1}c a
ì üé ùï ï= = Î -í ýê úï ïë ûî þ
The number of A in Tp such that A is either symmetric or skew symmetric or both and det(A) isdivisible by p:(A) (p–1)2 (B) 2(p–1)2 (C) (p–1)2 + 1 (D) 2p –1ekuk p ,d fo"ke vHkkT; la[;k rFkk Tp fuEu 2 × 2 vkO;wgksa dk leqPp; gS
16. Let A and B be two non singular matrices such that (AB)k = AkBk for three consecutive positiveintegral values of k then calculate BA2B–1:(A) A2 (B) B (C) A (D) B2
ekuk A rFkk B nks O;qRØe.kh; vkO;wg gS rFkk k ds rhu Øekxr /kukRed iw.kk±d eku bl izdkj gS fd (AB)k = AkBk
gS] rks BA2B–1 gksxk :(A) A2 (B) B (C) A (D) B2
MATHEMATICSTARGET : JEE 2014(DATE : 23-04-2014)
TM
Path to success KOTA (RAJASTHAN)
01CT313083KOTA - 10/38
PAPER – 2
Paragraph for Question 17 to 19
iz'u 17 ls 19 ds fy;s vuqPNsnLet x and y be two numbers chosen at random from the set {1, 2, 3 .... n} with replacement. Let Qn (p)denotes the probability that xp–1 – yp–1 is divisible by p where p is a prime number.
ekuk x rFkk y iquLFkkZiu ds lkFk leqPp; {1, 2, 3 .... n} esa ls ;knPN;k p;fur nks la[;k;sa gSaA ekuk Qn (p), xp–1 – yp–1
dh p ls foHkkftr gksus dh izkf;drk dks n'kkZrk gS] tgk¡ p ,d vHkkT; la[;k gSA17. Q25 (3) equals :
SECTION –II / [k.M – II & SECTION –III / [k.M – III
Matrix-Match Type / eSfVªDl&esy izdkj Integer Value Correct Type / iw.kk±d eku lgh izdkj
No question will be asked in section II and III / [k.M II ,oa III esa dksb Z iz'u ugha gSA
Space for Rough Work / dPps dk;Z ds fy, LFkku
LEADER & ENTHUSIAST COURSE(DATE : 23-04-2014)
MATHEMATICSTM
Path to success KOTA (RAJASTHAN)
01CT313083 KOTA - 11/38
PAPER – 2
SECTION-IV : (Integer Value Correct Type)
[k.M-IV : (iw.kk±d eku lgh izdkj)This section contains 3 questions. The answer to each question is a single digit Integer, ranging from0 to 9 (both inclusive)
Hkkx-2 : HkkSfrdhSECTION–I : (i) Only One option correct Type
[k.M-I : (i) dsoy ,d lgh fodYi izdkjThis section contains 9 multiple choice questions. Each question has four choices (A), (B), (C) and(D) out of which ONLY ONE is correct.
bl [k.M esa 9 cgqfodYi iz'u gSA izR;sd iz'u esa pkj fodYi (A), (B), (C) vkSj (D) gSa ftuesa ls dsoy ,d
lgh gSA
1. A triangular wedge of mass M which is free to move, lies at rest on smooth horizontal plane. A man ofmass m initially at rest starts running over wedge with constant speed u relative to wedge. If we doanalysis from ground while man is running without jumping with constant speed over wedge.(A) the power due to normal contact force on man is zero.(B) the friction force acting on man is mg sinq(C) power due to friction on man is zero.(D) power due to normal contact force on wedge is positive.
m
u
M
q
xfr ds fy, Lora= ,d M æO;eku dk f=Hkqtkdkj ost fpdus {kSfrt ry ij fojkekoLFkk esa j[kk gqvk gSA ,d m æO;eku
dk O;fDr] tks izkjEHk esa fojkekoLFkk esa gS] ost ds lkis{k fu;r pky u ls ost ij nkSM+uk izkjEHk djrk gSA ;fn ge /kjkry
2. A uniform thin rod AB is equipped at both ends with the hooks shown and is supported by a frictionlesshorizontal table. Initially the rod is hooked at A to a fixed pin C about which it rotates with a constantangular velocity w1. Suddenly end B of the rod hits pin D and gets hooked to pin D, causing end A tobe released. Determine the magnitude of the angular velocity w2 of the rod in its subsequent rotationabout D. (Assume length and mass of the hook is negligible. Pin C & D are lying on a same horizontalline),d le:i iryh NM + AB ds nksuksa fljkas ij gqd yxs gq;s gS rFkk ;g ?k"kZ.kjfgr {kSfrt Vscy ij j[kh gq;h gS] fp= ns[ksaAizkjEHk esa bl NM + ds fljs A dks ,d fLFkj fiu C ls gqd }kjk tksM+ fn;k tkrk gS] ftlds lkis{k ;g fu;r dks.kh; osx w1
ls ?kw.kZu djrh gSA vpkud NM+ dk fljk B fiu D ls Vdjkrk gS rFkk gqd }kjk fiu D ls tqM + tkrk gS] ftlds dkj.k fljkA NwV tkrk gSA fljs D ds lkis{k NM + dh rnksijkUr ?kw.kZu xfr esa NM + ds dks.kh; osx w2 dk ifjek.k gksxk (gqd dk æO;ekurFkk yEckbZ ux.; ekusa ,oa fiu C rFkk D ,d gh {kSfrt js[kk esa gS) :-
AC
B
B'D
A'w2
w1
(A) 3w1 (B) w1/2 (C) w1 (D) none of these
3. A light ray travelling in air is incident vertically on one face of a right angled prism with a refractive
index m = 3 as shown in the figure and the ray follows the path shown in the figure. If q = 60° and the
base of the prism is horizontal and silvered, what is the angel f made by emergent ray with the normalto the right face of the prism?
ok;q esa xfr'khy ,d izdk'k fdj.k m = 3 viorZukad okys ,d ledks.k fizTe ds ,d Qyd ij Å/okZ/kj :i ls
fxjrh gS rFkk ;g fdj.k fp=kuqlkj iFk dk vuqlj.k djrh gSA ;fn q = 60° gks rFkk fizTe dk vk/kkj {kSfrt o jtfrr gksrks fizTe ds nka;s Qyd ij cus vfHkyEc ls fuxZr fdj.k }kjk cuk;k x;k dks.k f gksxk%&
q
f Emergent rayIncident
ray
(A) 0° (B) 30° (C) sin-11
3
æ öç ÷è ø
(D) none of these
LEADER & ENTHUSIAST COURSE(DATE : 23-04-2014)
PHYSICSTM
Path to success KOTA (RAJASTHAN)
01CT313083 KOTA - 15/38
PAPER – 2
Space for Rough Work / dPps dk;Z ds fy, LFkku
4. A vessel with a hole in its bottom is fastened on a cart. The mass of the vessel and the cart is M and thearea of the vessel base is A. What force F should the cart be pulled with so that maximum amount ofwater remains in the vessel? The dimensions of the vessel are shown in the figure. Assume there is nofriction between cart and ground and vessel is fixed with cart. (r is density of water)
,d ik= ds isnsa esa fNnz cuk gqvk gS rFkk ;g ik= ,d xkM+h ij j[kk gqvk gSA bl ik= rFkk xkM+h dk æO;eku M rFkk ik=
ds vk/kkj dk {ks=Qy A gSA bl xkM+h dks fdl cy F ls [khapk tk;s rkfd ik= esa ty dh vf/kdre ek=k cuh jgs\ bl
5. The radius and surface tension of a spherical soap bubble be r and T respectively. Find the chargeuniformly distributed over the outer surface of the bubble, is required to double its radius. (Given thatatmospheric pressure is P
0 and inside temperature of the bubble during expansion remains constant.)
,d xksykdkj lkcqu ds cqycqys dh f=T;k rFkk i`"B ruko Øe'k% r o T gSA bl cqycqys dh f=T;k dks nqxquh djus ds fy;s
cqycqys dh ckgjh lrg ij fdruk vkos'k ,dleku :i ls forjhr gksuk pkfg,\ (ekuk ok;qe.Myh; nkc P0 gS rFkk izlkj
6. A wire carrying a current I is bent into the shape of an exponential spiral, r = eq, from q = 0 toq = 2p as shown in figure. To complete a loop, the ends of the spiral are connected by a straight wirealong the x-axis. Find the magnitude of B at the origin.
,d rkj esa I /kkjk izokfgr gks jgh gS rFkk bls q = 0 ls q = 2p rd ,d pj?kkrkadh lfiZykdkj iFk r = eq esa fp=kuqlkj eksM+k
7. Mark the INCORRECT statement :-(A) The saturation behavior of nuclear forces, implies that the nuclear forces act over a very small
range.(B) At very short distances much smaller than the range the nuclear forces become repulsive that is why
nuclear volume being proportional to square of the total number of nucleons.(C) At very short distances much smaller than the range the nuclear forces become repulsive therefore
nuclear density is constant.(D) The saturation behavior of nuclear forces, implies that a particular nucleon interacts only with its
8. In the below figure a dielectric is released inside the capacitor at t = 0 from the end of the capacitor. Thenwhich of the following current (i) Vs time(t) graph is correct in one complete oscillation. If clockwisecurrent is taken as positive and anticlockwise as negative. (a > c). Neglect electrical and mechanicalresistance.
iznf'kZr fp= esa ,d ijkoS|qr dks t = 0 ij la/kkfj= ds fljs ls la/kkfj= ds vUnj fojkekoLFkk ls NksM+k tkrk gSA ,d iw.kZ
½.kkRed ekuk x;k gS] (a > c) gS ,oa fo|qr rFkk ;kaf=d izfrjks/k dks ux.; ekuasA
V
a ´ b c b
k
a c
(A)
i
t (B)
i
t
(C)
i
t (D)
i
t \
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9. Three capacitor of capacitance C each are connected in series as shown in the figure. Initially switch Sis open. Now capacitors are charged by a battery of emf V by connecting between terminal A and B.After long time battery is disconnected and inductor of inductance L is connected between A and B attime t = 0 so that an oscillatory circuit is formed. Now at an instant t0 switch S is closed, then find theamplitude of charge oscillations of the remaining capacitors.
çR;sd C /kkfjrk okys rhu la/kkfj=ksa dks fp=kuqlkj Js.khØe esa tksM+k x;k gSA izkjEHk esa fLop S [kqyk gqvk gSA vc fljkas A
cSVjh dks gVkdj le; t = 0 ij L izsjdRo okyh ,d izsjd dq.Myh dks A o B ds e/; tksM+ nsrs gS rkfd ,d nksyuh
ifjiFk cu tk;sA vc {k.k t0 ij fLop S dks can dj fn;k tkrk gSA 'ks"k la/kkfj=ksa ds vkos'k nksyuksa dk vk;ke gksxk%&
AC C
S
B
CL
(A)
20
3cos t
LC1CV 1
6 3
æ öæ öç ÷ç ÷ç ÷ç ÷è ø-ç ÷ç ÷ç ÷è ø
(B)
20
3cos t
LCCV 11
3 5 3
æ öæ öç ÷ç ÷ç ÷ç ÷è ø-ç ÷ç ÷ç ÷è ø
(C)
20
3cos t
LC1CV 1
4 3
æ öæ öç ÷ç ÷ç ÷ç ÷è ø-ç ÷ç ÷ç ÷è ø
(D) CV3
Space for Rough Work / dPps dk;Z ds fy, LFkku
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(ii) One or more options correct Type
(ii) ,d ;k vf/kd lgh fodYi izdkjThis section contains 4 multiple choice questions. Each question has four choices (A), (B), (C) and(D) out of which ONE or MORE are correct.
bl [k.M esa 4 cgqfodYi iz'u gSaA izR;sd iz'u esa pkj fodYi (A), (B), (C) vkSj (D) gSa] ftuesa ls ,d ;k
vf/kd lgh gSA
10. Three particles, each of mass m are placed at the points (x1,y1,z1), (x2,y2,z2) and (x3,y3,z3) on theinner surface of a paraboloid of revolution obtained by rotating the parabola, x2 = 4ay about they-axis. Neglect the mass of the paraboloid. (y-axis is along the vertical)(A) The moment of inertia of the system about the axis of the paraboloid is I = 4ma (y1 + y2 +y3).(B) If potential energy at O is taken to be zero, the potential energy of the system is
mg (y1 + y2 + y3).
(C) If the particle at (x1,y1,z1) slides down the smooth surface, its speed at O is 1gy2(D) If the paraboloid spins about OY with an angular speed w, the kinetic energy of the system
(C) ;fn (x1,y1,z1) ij fLFkr d.k fpduh lrg ij uhps dh vksj xfr djrk gS rks O ij bldh pky 1gy2 gksxhA
(D) ;fn ijoy;t OY ds ifjr% dks.kh; pky w ls pØ.k djs rks fudk; dh xfrt ÅtkZ ma (y1 + y2 +y3)w2
gksxhA
Space for Rough Work / dPps dk;Z ds fy, LFkku
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11. If a graph of Binding energy (B/A) per nucleon versus mass number (A) looks like as shown in figure.Then using the curve choose CORRECT option(s).(A) Fusion of two nuclei with mass numbers 30 and 45 will have Q value 99 MeV(B) Fission of nuclei with mass number 80 into two nuclei of equal mass number will have Q value
256 MeV(C) Fission of nuclei with mass number 150 into two nuclei of equal mass number will release energy(D) Fission of nuclei with mass number 80 into two nuclei of equal mass number will release energy
(C) æO;eku la[;k 150 okys ukfHkd ds leku æO;eku la[;k okys nks ukfHkdkas esa fo[k.Mu ds QyLo:i ÅtkZ mRlftZr
gksrh gSA
(D) æO;eku la[;k 80 okys ukfHkd ds leku æO;eku la[;k okys nks ukfHkdkas esa fo[k.Mu ds QyLo:i ÅtkZ mRlftZr
gksrh gSASpace for Rough Work / dPps dk;Z ds fy, LFkku
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12. n moles of a monoatomic gas undergoes a cyclic process ABCDA as shown. ProcessesAB ® Isobaric, BC ® adiabatic, CD ® isochoric, DA ® Isothermal. The maximum temperature andminimum temperature in the cycle are 4T0 and T0 respectively. Then(A) TB> TC> TD
(B) heat is released by the gas in the process CD.(C) heat is supplied to the gas in the process AB(D) total heat supplied to the gas is zero
V
P
A B
C
D
n eksy ,d ijekf.od xSl fp=kuqlkj pØh; çØe ABCDA ls xqtjrh gSA izØe AB ® lenkch;, BC ® :¼ks"e,
CD ® levk;rfud, DA ® lerkih; gSA bl pØ esa vf/kdre rFkk U;wure rkieku Øe'k% 4T0 rFkk T0 gSA rc %&(A) TB> TC> TD
(B) izØe CD esa xSl }kjk Å"ek mRlftZr dh tkrh gSA
(C) izØe AB esa xSl dks Å"ek nh tkrh gSA
(D) xSl dks nh x;h dqy Å"ek 'kwU; gSA
Space for Rough Work / dPps dk;Z ds fy, LFkku
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13. The current velocity of a river is directly proportional to the perpendicular distance from its bank and isits maximum ‘v
0’ in the middle. Near the banks the velocity is zero. A boat is moving in the river such
that its velocity u relative to the river flow is constant and perpendicular.(A) The horizontal drift through which the boat crossing the river will be carried away by the current
0v c2u
(B) The horizontal drift through which the boat crossing the river will be carried away by the current
0v c4u
(C) Time taken by the boat to cross the river will be cu
(D) Time taken by the boat to cross the river will be c
(A) /kkjk ds dkj.k uko }kjk unh esa r; fd;k x;k {kSfrt viokg 0v c2u
gSA
(B) /kkjk ds dkj.k uko }kjk unh esa r; fd;k x;k {kSfrt viokg 0v c4u
gSA
(C) uko dks unh ikj djus esa cu
le; yxsxkA
(D) uko dks unh ikj djus esa c
2u le; yxsxkA
Space for Rough Work / dPps dk;Z ds fy, LFkku
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(iii) Paragraph Type (iii) vuqPNsn izdkj
This section contains 2 paragraphs each describing theory, experiment, data etc. Six questions relateto two paragraphs with three questions on each paragraph. Each question of a paragraph has onlyone correct answer among the four choices (A), (B), (C) and (D).bl [k.M esa fl¼kUrksa] iz;ksxksa vkSj vk¡dM+ksa vkfn dks n'kkZus okys 2 vuqPNsn gSA nksuksa vuqPNsn ls lacaf/kr N% iz'ugSa] ftuesa ls gj vuqPNsn ij rhu iz'u gSaA vuqPNsn esa gj iz'u ds pkj fodYi (A), (B), (C) vkSj (D) gSa ftuesals dsoy ,d lgh gSA
Paragraph for Question 14 to 16iz'u 14 ls 16 ds fy;s vuqPNsn
A free uniform disc of mass m = 1 kg and radius R = 1 m is rotating on smooth horizontal floor withangular velocity wo = 10 rad/s. A particle of mass 2 kg is released from height 5 m above disc. Particlehits disc at distance R/2 from centre of disc. Collision of particle with disc is inelastic and particle sticksto disc after collision due to friction. Disc does not bounce from ground during collision of particle withdisc.
æO;eku m = 1 kg rFkk f=T;k R = 1 m okyh ,d Lora= le:i pdrh fpduh {kSfrt lrg ij dks.kh; osx
wo = 10 rad/s ls ?kw.kZu dj jgh gSA bl pdrh ls 5 m Å¡pkbZ ls 2 kg æO;eku ds d.k dks NksM+k tkrk gSA d.k pdrh ds
dsUnz ls R/2 nwjh ij pdrh ls Vdjkrk gSA d.k dh pdrh ls VDdj vizR;kLFk gksrh gS rFkk ?k"kZ.k ds dkj.k VDdj ds ckn
d.k pdrh ls fpid tkrk gSA d.k dh pdrh ls VDdj ds nkSjku pdrh /kjkry ij ls mNyrh ugha gSA
R/2
h
m(side view)(Top view)
w0
14. The angular velocity of disc immediately after collision is
iz'u 17 ls 19 ds fy;s vuqPNsnIn the figure shown a uniform conducting rod of mass m and length l is suspended in vertical plane bytwo conducting springs of spring constant K. Upper end of springs are connected to each other bycapacitor of capacitance C. A uniform horizontal magnetic field (B0) perpendicular to plane of springsexists in space. Initially rod is in equilibrium but if rod is pulled down and released, it performs SHM.(Assume resistance of springs and rod are negligible also neglect the self inductance of both the spring)
iznf'kZr fp= esa æO;eku m rFkk yEckbZ l okyh ,d le:i pkyd NM+ dks Å/okZ/kj ry esa fLizax fu;rkad K okyh nks
pkyd fLizaxksa dh lgk;rk ls yVdk;k x;k gSA fLizaxkas ds Åijh fljs dks ,d&nwljs ls C /kkfjrk okys ,d la/kkfj= }kjk
vkil esa tksM+ fn;k tkrk gSA ;gk¡ fLizaxkas ds ry ds yEcor~ ,d le:i {kSfrt pqEcdh; {ks= (B0) fo|eku gSA izkjEHk esa
(A) Electrical energy stored in capacitor is maximum when rod is at its lower extreme position
(B) Electrical energy stored in capacitor is maximum when rod is at its mean position
(C) Current in rod is maximum at mean position of rod
(D) If magnetic field is switched off then mean position of rod will change.
lgh fodYi pqfu;s%&
(A) tc NM+ bldh fuEure fLFkfr ij gksrh gS rks la/kkfj= esa laxzfgr fo|qr ÅtkZ vf/kdre gksrh gSA
(B) tc NM+ bldh ek/; fLFkfr ij gksrh gS rks la/kkfj= esa laxzfgr fo|qr ÅtkZ vf/kdre gksrh gSA
(C) NM+ dh ek/; fLFkfr ij NM+ esa /kkjk vf/kdre gksrh gSA
(D) ;fn pqEcdh; {ks= can dj fn;k tk;s rks NM+ dh ek/; fLFkfr ifjofrZr gks tk;sxhA
19. Find the ratio of current (i) to acceleration of rod at any instant (other then equilibrium) :
lkE;koLFkk ds vfrfjDr vU; fdlh {k.k ij NM+ esa /kkjk (i) rFkk mlds Roj.k dk vuqikr gksxk%&
(A) BlC (B) BCl
(C) B2l
2C (D) None of these
SECTION –II / [k.M – II & SECTION –III / [k.M – III
Matrix-Match Type / eSfVªDl&esy izdkj Integer Value Correct Type / iw.kk±d eku lgh izdkj
No question will be asked in section II and III / [k.M II ,oa III esa dksb Z iz'u ugha gSA
Space for Rough Work / dPps dk;Z ds fy, LFkku
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PAPER – 2
SECTION-IV : (Integer Value Correct Type)
[k.M-IV : (iw.kk±d eku lgh izdkj)This section contains 3 questions. The answer to each question is a single digit Integer, ranging from0 to 9 (both inclusive)
fuxZr fLFkjoS|qr ¶yDl dk eku (V-m) esa gksxkA2. The limbs of a glass U-tube are lowered into vessels A and B as shown in the figure. Some air is
pumped out through a valve at C, placed at the top of tube and then the valve is closed. The liquid in theleft hand limb then rises to a height h1 and in the right hand one to height h2. The density of the liquid in
limb B is 1k
(in gm/cc) if water is present in limb A. Given h1 = 10 cm and h2 = 20 cm. Calculate the
value of K.
dk¡p dh ,d U-uyh dh Hkqtkvksa dks fp=kuqlkj ik=ksa A rFkk B esa Mqcks;k tkrk gSA bl uyh ds 'kh"kZ Hkkx C ij yxs ,dokYo dh lgk;rk ls dqN ok;q ckgj fudky nh tkrh gS rFkk blds ckn okYo dks can dj nsrs gSaA vc ck¡;h Hkqtk esa Hkjk gqvkæo h1 Å¡pkbZ rd rFkk nk¡;h Hkqtk esa Hkjk æo h2 Å¡pkbZ rd p<+rk gSA ;fn Hkqtk A esa ty Hkjk gqvk gks rks Hkqtk B esa æo dk
3. Image distance v vs object distance u curve for two biconvex lens with same radii of curvatures is
shown in the figure. If refractive index of lens 1 is 52
, find refractive index of lens 2.
leku oØrk f=T;kvksa okys nks f}&mÙky ysUlksa ds fy, izfrfcEc nwjh v rFkk fcEc nwjh u ds e/; vkjs[k fp= esa n'kkZ;s
x;s gSaA ;fn ysUl 1 dk viorZukad 52
] gks rks ysUl 2 dk viorZukad Kkr dhft,A
30 cm
20 cm
(1)
(2)
|v|
|u| 45°
Space for Rough Work / dPps dk;Z ds fy, LFkku
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PAPER – 2
PART-3 : CHEMISTRY Hkkx-3 : jlk;u
SECTION–I : (i) Only One option correct Type [k.M-I : (i) dsoy ,d lgh fodYi izdkj
This section contains 9 multiple choice questions. Each question has four choices (A), (B), (C) and(D) out of which ONLY ONE is correct.bl [k.M esa 9 cgqfodYi iz'u gSA izR;sd iz'u esa pkj fodYi (A), (B), (C) vkSj (D) gSa ftuesa ls dsoy ,d
lgh gSA1. In the electrolysis of CuCl
2 soluton using Cu electrodes, the weight of Cu increased by 2gram at cathode.
At the anode -(A) 0.2 mole of Cu2+ will go into solution (B) Cl
2 is produced
(C) No loss in weight (D) 2 gram of copper goes into solution as Cu2+
CuCl2 foy;u ds oS|qr vi?kVu esa Cu bysDVªksMks dk mi;ksx fd;k x;kA dSFkksM ij Cu dk Hkkj 2 xzke c< tkrk gS
(C) Hkkj esa gkfu ugha gksxh (D) Cu2+ ds :i esa 2 xzke dkWij foy;u esa ?kqy tk;sxk2. Which of the following is the correct order of C = C bond lengths among these compounds ?
I. CH3O – CH = CH – NO
2II. CH
2 = CH – NO
2
III. CH2 = CH – Cl IV. CH
2 = CH
2
(A) I > II > III > IV (B) IV > III > II > I (C) I > III > II > IV (D) II > III > I > IV
fuEu ;kSfxdksa esa ls C = C cU/k yEckbZ;ksa dk lgh Øe dkSulk gS ?I. CH
3O – CH = CH – NO
2II. CH
2 = CH – NO
2
III. CH2 = CH – Cl IV. CH
2 = CH
2
(A) I > II > III > IV (B) IV > III > II > I (C) I > III > II > IV (D) II > III > I > IV3. Which pairs of the salts should have identical solubilities in methanol ?
yo.kksa ds dkSuls ;qXe dh esFksukWy esa ?kqyu'khyrk leku gksuh pkfg, ?
(A) I & IV (B) I & III (C) II & III (D) II & IV
Space for Rough Work / dPps dk;Z ds fy, LFkku
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Space for Rough Work / dPps dk;Z ds fy, LFkku
4. Salt -A ¾¾¾ ®¾ testLayer If Reddish brown layers comes first then(A) Br– absent (B) I– absent (C) Cl– Present (D) I– present
8. The product formed in the following reaction is
fuEu vfHkfØ;k esa cuus okys mRikn gS
CH – CH – CH2 2 2 CH = CH2 ¾¾¾ ®¾NBS
(A) CH – CH – CH2 2 CH = CH2
Br
(B) CH – CH – CH2 2 CH = CH2
|Br
(C) CH – CH – CH2 2 CH = CH2
|Br
(D) CH – CH – CH2 2 2 CH – CH Br2|Br
9. Two liquids A and B are mixed at temperature T in a certain ratio to form an ideal solution. It is foundthat the partial vapour pressure of A i.e. P
A is equal to P
B, the vapour pressure of B for the liquid mixture.
What is the total vapour pressure of the liquid mixture in terms of oAP and o
BP (the vapour pressure of
the pure liquids A and B at the temprature) ?nks æoksa A rFkk B dks ,d fuf'pr vuqikr esa T rki ij fefJr dj ,d vkn'kZ foy;u cuk;k x;kA ;g ik;k x;kfd æo feJ.k ds fy, A dk vkaf'kd ok"inkc] tks P
A gS] B ds vkaf'kd nkc P
B ds cjkcj gSA o
AP rFkk oBP ds inksa
es a æo feJ.k dk dqy ok"inkc D;k gksxk (rki ij 'kq¼ æoksa A rFkk B dk ok"inkc gS) ?
(A) o oA B
o oA B
P PP P+ (B)
oA
o oA B
PP P+ (C)
o oA B
o oA B
2P PP P+ (D)
oB
o oA B
2PP P+
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Space for Rough Work / dPps dk;Z ds fy, LFkku
(ii) One or more options correct Type (ii) ,d ;k vf/kd lgh fodYi izdkj
This section contains 4 multiple choice questions. Each question has four choices (A), (B), (C) and(D) out of which ONE or MORE are correct.
bl [k.M esa 4 cgqfodYi iz'u gSaA izR;sd iz'u esa pkj fodYi (A), (B), (C) vkSj (D) gSa] ftuesa ls ,d ;k
vf/kd lgh gSA
10. CH CH CH –Cl22 2AlCl3
(catalytic amount) P + HCl(mf C H )10 12
P can not be (P ugha gks ldrk) :
(A) (B) (C) (D)
11. Which of the following will not change if the choice of the zero potential energy is changed in Bohrmodel -
(A) Total energy (B) Potential energy (C) Kinetic energy (D) None of these
;fn cksgj ekWMy esa 'kwU; fLFkfrt ÅtkZ esa ifjorZu gksrk gS rks fuEu esa ls dkSulk ifjofrZr ugha gksxk -
This section contains 2 paragraphs each describing theory, experiment, data etc. Six questions relateto two paragraphs with three questions on each paragraph. Each question of a paragraph has onlyone correct answer among the four choices (A), (B), (C) and (D).bl [k.M esa fl¼kUrksa] iz;ksxksa vkSj vk¡dM+ksa vkfn dks n'kkZus okys 2 vuqPNsn gSA nksuksa vuqPNsn ls lacaf/kr N% iz'ugSa] ftuesa ls gj vuqPNsn ij rhu iz'u gSaA vuqPNsn esa gj iz'u ds pkj fodYi (A), (B), (C) vkSj (D) gSa ftuesals dsoy ,d lgh gSA
Paragraph for Question 14 to 16iz'u 14 ls 16 ds fy;s vuqPNsn
A crystalline solid consist of a large number of small units, called crystals, each of which possesses adefinite geometric shape bounded by plane faces. The crystals of a given substance produced under adefinite set of conditions are always of the same shape.From external appearance we come across a varietyof crystal forms in many shapes. But on the basis of length of axes and the axial angles, it has been possibleto classify the various crystal forms into only seven fundamental systems. These are:Cubic, Orthorhombic, Tetragonal, Monoclinic,Triclinic,Hexagonal, Rhombohedral.The crystals belonging to any one system may differ in shape, in size, etc., but their axial ratios as alsothe axial angles will always be the same. The intercepts on the three axes are denoted by a, b and c andthe axial angles by a, b and g.,d fØLVyh; Bksl] NksVh&NksVh bdkbZ;ksa] ftUgs fØLVy dgrs gS] dh cgqr cM+h la[;k ls cus gksrs gS] ; s lHkh ,d fuf'prT;kfefr; vkd`fr esa lery Qyd }kjk cU/kh gksrh gSA fn;s x;s inkFkZ ds fØLVy] fLFkfr;ksa ds ,d fuf'pr leqPp; esafufeZr gskrs gS] tks lnSo leku vkdfr ds gksrs gSA cká ifjorZuksa ls ge dbZ vkdfr;ksa esa fofHkUu fØLVyh; :iksa dks cukldrs gSA ijUrq v{kksa dh yEckbZ rFkk v{kh; dks.kksa ds vk/kkj ij dsoy lkr ewyHkwr ra=ksa esa fofHkUu fØLVyh; :iksa dkoxhZdj.k lEHko gSA;sa gS, ?kuh;, fo"keyEck{k, prq"dks.kh;, ,durk{k, f=urk{k, "kV~dks.kh;] f=leurk{k (Rhombohedral)fdlh ,d ra= ls lEcfU/kr fØLVy dks vkdfr] vkdkj vkfn esa foHksfnr fd;k tk ldrk gSA ijUrq buds v{kh; vuqikrds lkFk v{kh; dks.k Hkh lnSo leku gksxsaA rhuksa v{kksa ij izfrPNsnks dks a, b rFkk c }kjk rFkk v{kh; dks.kks dks a, b rFkk g}kjk vafdr fd;k tkrk gSA
14. A tetragonal system is -,d prq"dks.kh; ra= esa gksrk gS –(A) a ¹ b ¹ c (B) a = b = g = 90º (C) a = b = c (D) a = b = 90º ¹ g
15. In a multi layered close-packed structure(A) there are twice as many tetrahedral holes as there are close-packed atoms(B) there are as many tetrahedral holes as there are closed packed atoms(C) there are twice as many octahedral holes as there are close-packed atoms(D) there are as many tetrahedral holes as there are octahedral holes,d cgqijrh; ca/k ladqyu lajpuk esa(A) ftrus cUn ladqfyr ijek.kq gksrs gS mlds nqxus prq"dks.kh; gkWy gksrs gS(B) ftrus cUn ladqyhr ijek.kq gksrs gS mrus gh prq"dks.kh; gkWy gksrs gS(C) ftrus cUn ladqfyr ijek.kq gksrs gS mlds nqxus v"VQydh; gkWy gksrs gS(D) ftrus v"VQydh; gkWy gksrs gS mrus gh prq"dks.kh; gkWy gksrs gS
16. For an Ionic solid of the general formula AB and coordination number 6, the value of the radius ratiowill be(A) less than 0.225 (B) in between 0.225 and 0.414(C) between 0.414 and 0.732 (D) greater than 0.732lkekU; lw= AB ds ,d vk;fud Bksl ftldk leUo; la[;k 6 gS] ds fy,] f=fT;; vuqikr ds eku gksxsa(A) 0.225 ls de (B) 0.225 rFkk 0.414 ds e/;(C) 0.414 rFkk 0.732 ds e/; (D) 0.732 ls vf/kd
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PAPER – 2
Paragraph for Question 17 to 19iz'u 17 ls 19 ds fy;s vuqPNsn
17. Which of the following statement is correct about S?(A) It will not give yellow/orange or red colour with 2, 4-DNP.(B) It will give red colour with Cerric Ammonia Nitrate(C) It will not give Fehling test.(D) It will give Bielstien testS ds lUnHkZ esa fuEu esa ls dkSulk dFku lgh gS ?(A) ;g 2, 4-DNP ds lkFk ihyk@ukjaxh ;k yky jax ugha nsrk gS(B) ;g lsfjd veksfu;e ukbVªsV ds lkFk yky jax nsrk gS(C) ;g Qsgfyax ifj{k.k ugha nsxk(D) ;g fCyLVhu ifj{k.k nsxk
18. Which of the following statement is correct about V?(A) It will not give mustard oil reaction.(B) It will not give carbylamine test or isocyanide test(C) It is less basic than aniline(D) It will give base soluble product with Hinsburg reagentfuEu esa ls dkSulk dFku V ds lUnHkZ esa lgh gS ?(A) ;g eLVMZ vkW;y vfHkfØ;k ugh nsxk(B) ;g dkchZy ,ehu ifj{k.k ;k vkblkslk;ukbM ifj{k.k ugha nsxk(C) ;g ,fufyu dh rqyuk esa U;wu {kkjh; gksrk gS(D) ;g ghal cxZ vfHkdeZd ds lkFk {kkj esa ?kqyu'khy mRikn nsxk
19. Which of the following reaction will be useful for conversion of R into S.(A) Clemmenson's reduction (B) Oppenauer oxidation(C) Meerwin Pondorff Verely reduction (D) Tischenko reactionR ls S esa :ikUrj.k ds fy, fuEu esa ls dkSulh vfHkfØ;k mi;ksxh gksxh(A) DyhesUlu vip;u (B) vksihukWj vkWDlhdj.k(C) ehjfou iwUMªksQ osjyh vip;u (D) fV'kadks vfHkfØ;k
SECTION –II / [k.M – II & SECTION –III / [k.M – IIIMatrix-Match Type / eSfVªDl&esy izdkj Integer Value Correct Type / iw.kk±d eku lgh izdkj
No question will be asked in section II and III / [k.M II ,oa III esa dksb Z iz'u ugha gSA
1. On passing electricity through nitrobenzene solution, it is converted into azobenzene. Calculate themass of azobenzene (in gm) if same quantity of electricity produces oxygen just sufficient to burn 96 gmof fullerene (C60).
Fill your answer as sum of digits (excluding decimal places) till you get the single digit answer.
ukbVªkscsUthu foy;u esa ls oS|qr /kkjk izokfgr djus ij] ;g ,stkscsUthu esa :ikUrfjr gks tkrk gSA ;fn oS|qr /kkjk dh leku
12. [kaM–II & III esa ,d Hkh iz'u ugha gSA13. [kaM-IV es a 3 iz'u gSaA izR;sd iz'u dk mÙkj 0 ls 9 rd
(nksuksa 'kkfey) ds chp dk ,dy vadh; iw.kk±d gSA
D. vadu ;kstuk :14. [kaM-I (i & ii) ds gj iz'u esa dsoy lgh mÙkjksa (mÙkj) okys
lHkh cqycqyksa (cqycqys) dks dkyk djus ij 3 vad vkSj dksbZHkh cqycqyk dkyk ugha djus ij 'kwU; (0) vad iznku fd;ktk;sxkA vU; lHkh fLFkfr;ksa esa ½.kkRed ,d (–1) vad iznkufd;k tk;sxkA
15. [kaM-I (iii) ds gj iz'u esa dsoy lgh mÙkjksa (mÙkj) okys lHkhcqycqyksa (cqycqys) dks dkyk djus ij 4 vad vkSj dksbZ Hkhcqycqyk dkyk ugha djus ij 'kwU; (0) vad iznku fd;k tk;sxkAvU; lHkh fLFkfr;ksa esa ½.kkRed ,d (–1) vad iznku fd;ktk;sxkA
16. [k aM-IV es a gj iz'u es a dsoy lgh mÙkj okys cqycqys(BUBBLE) dks dkyk djus ij 6 vad vkSj dksbZ Hkh cqycqykdkyk ugha djus ij 'kwU; (0) vad iznku fd;k tk;sxk bl [ akMds iz'uksa esa xyr mÙkj nsus ij dksbZ ½.kkRed vad ugha fn;stk;saxsaA
11. SECTION – I(i) Contains 9 multiple choice questions. Each
question has four choices (A), (B), (C) and (D)out of which ONLY ONE is correct.
(ii) Contains 4 multiple choice questions. Eachquestion has four choices (A), (B), (C) and (D)out of which ONE or MORE are correct.
(iii) Contains 2 paragraphs each describing theory,experiment, date etc. Six questions relate totwo paragraphs with three questions on eachparagraph. Each question of a paragraph hasONLY ONE correct answer among the fourchoices (A), (B), (C) and (D)
12. There is no questions in SECTION-II & III13. Section-IV contains 3 questions The answer to each
question is a single digit integer, ranging from0 to 9 (both inclusive)
D. Marking scheme :14. For each question in Section-I (i & ii), you will be
awarded 3 marks if you darken all the bubble(s)corresponding to only the correct answer(s) andzero mark if no bubbles are darkened. In all othercases minus one (–1) mark will be awarded
15. For each question in Section-I (iii), you will beawarded 4 marks if you darken all the bubble(s)corresponding to only the correct answer(s) andzero mark if no bubbles are darkened. In all othercases minus one (–1) mark will be awarded
16. For each question in Section-IV, you will be awarded6 marks if you darken the bubble corresponding tothe correct answer and zero mark if no bubbles aredarkened No negative marks will be awarded forincorrect answers in this section.