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Lecture 22 Frequency Response Hung-yi Lee
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Lecture 22 Frequency Response Hung-yi Lee Filter Outline (Chapter 11) Amplitude Ratio Phase Shift Highpass Filter Frequency Response Bode Plot Draw frequency.

Dec 16, 2015

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  • Slide 1
  • Slide 2
  • Lecture 22 Frequency Response Hung-yi Lee
  • Slide 3
  • Filter Outline (Chapter 11) Amplitude Ratio Phase Shift Highpass Filter Frequency Response Bode Plot Draw frequency response Ch 11.4 Ch 11.1 Ch 11.2 Lowpass Filter Notch Filter Bandpss Filter
  • Slide 4
  • Review Network Function Output depends on input and complex frequency s.
  • Slide 5
  • Frequency Response Only focus on the change of frequency In this lecture, we only focus on s=j. H(j) is the frequency response. That is, only consider H(j)
  • Slide 6
  • Frequency Response H(j) is a complex number, so frequency response is usually represented by two curves Magnitude Ratio Phase Shift
  • Slide 7
  • Example 11.1 Network Function: Frequency Response:
  • Slide 8
  • Example 11.1 Based on Superposition:
  • Slide 9
  • Example 11.1 InputOutput
  • Slide 10
  • Example 11.2 Assume C=1/aR Find Network Function a=1/RC
  • Slide 11
  • Example 11.2 Set s=j The amplitude ratio is constant.
  • Slide 12
  • Example 11.2 Magnitude Ratio Phase Shift Distance of j to a Distance of j to -a
  • Slide 13
  • Example 11.2 Phase shift network: Waveform distortion
  • Slide 14
  • Another Example for Phase Shift Network
  • Slide 15
  • Slide 16
  • Computing Frequency Response by Poles and Zeros
  • Slide 17
  • Frequency Response K: gain factor p 1, p 2, : poles z 1, z 2, : zeros
  • Slide 18
  • Frequency Response - Magnitude Ratio Distance of j to z 1 Distance of j to p 1 Distance of j to p 2 Distance of j to z 2
  • Slide 19
  • Frequency Response - Magnitude Ratio Gain factor is K Magnitude ratio at =| Gain factor| all distance to zeros all distance to poles X
  • Slide 20
  • Frequency Response - Phase Shift
  • Slide 21
  • Example 11.3
  • Slide 22
  • Slide 23
  • Slide 24
  • Homework 11.2, 11.4
  • Slide 25
  • Application: Hearing Reference: http://hyperphysics.phy-astr.gsu.edu/hbase/sound/hearcon.html
  • Slide 26
  • Range of Hearing Range of Audio: 300Hz 3.4KHz Frequency Range of hearing: 20Hz - 20KHz dB
  • Slide 27
  • Equal Loudness Contour Red Curve: Equal loudness Blue Line: Same Energy 60 phon means as loud as the 60dB 1kHz sound. phon (unit): dB
  • Slide 28
  • Hearing v.s. Age Application: 68 ( )
  • Slide 29
  • Phase and Sound Pass a Phase shift network
  • Slide 30
  • Structure of Ear
  • Slide 31
  • Cochlea ( ) to brain Each neuron only passes a specific frequency. Pass high frequency Pass low frequency Pass 20kHz Pass 20Hz
  • Slide 32
  • Cochlea ( ) to brain Neuron for =300 Neuron for =100 Neuron for =20 =300, Amplitude=10 =20, Amplitude=10
  • Slide 33
  • Machine Hearing Each triangle is the amplitude ratio of a filter How? Ear of machine A set of filters (filter bank) Energy of the signal of the output of the filter Send to computer How to write a program for speech recognition? a. Observe data, and write down some rules b. Simulate human brain, and let the computer learn by itself. Feature
  • Slide 34
  • Speech Signal ? ? Acoustic Model Language Model Text Machine Learning Deep Neural Network (Brain) Features Speech Recognition Signal Processing (Filter Bank)
  • Slide 35
  • Thank you!
  • Slide 36
  • Answer 11.2: 11.4:
  • Slide 37
  • Acknowledgement (b02) (b02) (b02)