Page 1 of 13 Short Laboratory Report 2015 MP2.2 Vapour Compression Refrigeration Cycle Chloé Marie Taylor 1322748 Lab Group: Mech 18 Date of Experiment: 10 th November 2015 Date of Lab Report: 24 th December 2015
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ShortLaboratoryReport2015
MP2.2VapourCompressionRefrigerationCycle
ChloéMarieTaylor
1322748
LabGroup:Mech18
DateofExperiment:10thNovember2015DateofLabReport:24thDecember2015
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Contents
1–Summary------------------------------------------------------------------------------------------------------------22–Introduction--------------------------------------------------------------------------------------------------------33–AimsofExperiment----------------------------------------------------------------------------------------------34–TheoryofVapourCompressionRefrigerationCycles--------------------------------------------------.45–Set-upandProcedure-------------------------------------------------------------------------------------------66–ObservationsandResults---------------------------------------------------------------------------------------67–DiscussionandAnalysisofResults---------------------------------------------------------------------------88–SourcesandDiscussionofError------------------------------------------------------------------------------119–Conclusion----------------------------------------------------------------------------------------------------------1210–References---------------------------------------------------------------------------------------------------------1211–Appendix------------------------------------------------------------------------------------------------------------13
1–Summary
Anairconditioningunitwasusedfortheexperiment.Thepurposeoftheexperimentwastostudytheperformanceofavapourcompressionrefrigerationcyclebycalculatingtheunit’scoefficientof performance (COPR). Air was heated, humidified, cooled and dehumidified and then reheatedduringtheprocess.Temperaturereadingsfortheairandtherefrigerantandworkingparametersoftheunitwererecordedduringtheexperiment.Thestateoftheairateachpointwasplottedonapsychometricchart,whichshowedthattheunitdidnotreducethehumidityoftheairasmuchasexpected.Thiswassuggestedtobeduetotherefrigerantnotremovingasmuchheatfromtheairasexpected.Therefrigerantcyclewasplottedonap-hdiagram,wheretheidealandactualcycleswereshownalongwith irreversibleprocesses. Itwas shown that theactual cyclemovedmore into thesuper-heatedregionmeaningmoreheatwasrejectedintotheenvironmentthantheidealcycle.
The cooling loads from the air and into the refrigerant were calculated, giving values of2.55kWand2.78kWrespectively.Thedifferencebetweenthesevalueswassaidtobeduetotheunitbeingbadlyinsulatedhencetherefrigerantabsorbedheatfromtheenvironmentaswellastheair.COPRvaluesfortherefrigerationcyclewerecalculatedbasedontheairandtherefrigerantcoolingloads,yieldingvaluesof1.19and1.3respectively.TheCOPRbasedontherefrigerantwassaidtobemoreaccurateasitdidnothavetheinaccuraciesofthewetbulbtemperaturereadingsthattheairbasedCOPRhad.Sourcesoferror,howtominimisethemandimprovementsfortheexperimentandtheairconditioningunitarediscussed.
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2-IntroductionIntroduction Heat pumps are very important in today’s society, being the basis for refrigerators andfreezersaswellassomeheatingmethods.Heatpumpsaremachineswhichmoveheatfromalowertemperature reservoir (called the source) to a higher temperature reservoir (called the heat sink)drivenbyaworkinput.Dependingontheaim,theycanbeheatersbyrejectingheatintotheheatsink,orrefrigeratorsbyabsorbingheatfromthesource.Theirperformanceismeasuredbytheratioofcoolingobtainedtoworkrequired,calledthecoefficientofperformance(COP)showninequation1below.
!"#$ = '() ,+,. 1
Where:'(=coolingload(heatremovedfromsource)(W))=Workinput(W)
COPvalueswillgenerallybeabove1asmoreheatwillberemovedfromthesourcethanworkisputinduetothenatureofthecycle(discussedin3–TheoryofVapourCompressionRefrigerationCycles).
ThisexperimentaimstofindtheCOPofavapourcompressionrefrigerationcycleasitisusedtocoolanddehumidifyair.Irreversibilitiesoftheprocessandotherpointsofinterestwillbediscussed.
3-AimsofExperiment
Anairconditioningunitoperatingavapourcompressionrefrigerationcyclewillbeusedtoheatair to a warm and humid state, then dehumidify and cool air. Temperatures of the air and therefrigerantworkingfluidwillberecordedfromtheairconditioningunit.Otherworkingparametersincludingdifferentialpressures,massflowratesandvoltage/currentvalueswillberecorded.Thesesetofresultswillallow:
• Thepathoftheairconditioningprocesstobeplottedonapsychometricchart• Thestateoftheairateachpointtobefoundandcommentstobemadeonthefinalquality
oftheair• Thecoolingloadfromtheairduringtheairconditioningcycletobecalculated• Theidealandrealcyclefortherefrigerantonap-hdiagramtobeplotted• Thecoolingloadfortherefrigerantduringthecycletobecalculated• Thecoefficientofperformanceoftherefrigerator(COP)tobecalculated
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4-TheoryofVapourCompressionRefrigerationCyclesCarnotCycle Thisexperimentusesavapourcompressionrefrigerationcyclewhichcoolsairdown.Thoughthe air is heated and cooled in the air conditioning unit it is the refrigeration cycle (using R12refrigerantastheworkingfluid)whichisthemainfocusoftheexperiment.Therefrigerationcycleremoves heat from the air and rejects it to the environment, acting as a reverse heat engine –commonlycalledaheatpump.HeatpumpsarebasedaroundreverseCarnotcycles,whichareexactlythesameasCarnotcyclebuttheprocessdirectionsandhenceworkandheatinputsandoutputsarereversed.Figure1and2belowarethepressure-volume(p-v)andtemperature-entropy(T-s)diagramsforareverseCarnotcycle.
Figure1:PressureVolumediagramshowingFigure2:Temperature-Entropygraphwith
Carnotcycle.sssssssssssssssssssssssddfffffffffffhsslkcsdasaturationcurveshowingCarnotcycle.
Theprocessesrelatingtothepointsinfigure1and2aredetailedbelow:1-2:Isentropiccompression–workisdoneontheworkingfluidataconstantentropy,resultinginanincreaseintemperature
2-3:Isothermalheatrejection–heatisrejectedintothehightemperaturereservoir3-4:Isentropicexpansion–workisdonebytheworkingfluidataconstantentropy,resultinginadecreaseintemperature
4-1:Isothermalheatabsorption–heatisabsorbed('()fromalowtemperaturereservoir
Notethatfigure2showsthesaturationcurveforthecycle.Enclosedinthesaturationcurvethe refrigerant is a mixed state of vapour and liquid. To the left of the saturated liquid line therefrigerant is a sub-cooled liquid, to the right of the saturated vapour line the refrigerant issuperheatedvapour.Theimportanceofthisisdiscussedbelow. TobasearefrigerationcyclearoundthereverseCarnotcycle,aworkingfluidmustbefoundthatiscapableofisothermalheatrejectionandabsorptionatthetemperaturesofthehighandlowtemperaturereservoirs(THandTL).Thiscanbeobtainedbyusingfluidsthatcondenseandevaporatearoundthesetemperaturesasphasechangesareprocessesinwhichheatisinputoroutputwithnotemperature change. This can be understood more by looking at the Carnot cycle encased in asaturationcurve(figure2).Bychoosingarefrigerantwhichhassaturationtemperatures(THandTL)attherequiredpressures,thephasechangesoftherefrigerantcanbeusedtofacilitatetheisothermalprocesses2-3and4-1.Therefrigerantwillhavealowboilingpointallowingittochangephase(andabsorbheat)fromanalreadycooltemperature.
P
V
11
3
4
2
T
s
1
3
4
2TH
TL
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Practicalvapourcompressionrefrigerationcycle InpracticethereverseCarnotcycleisadjustedtothevapourcompressionrefrigerationcycleshownbelowinfigure3.Theworkingfluidisarefrigerantthatsuitsthehighandlowtemperaturereservoirstemperatures.
Figure3:TemperatureEnthalpydiagramshowing
vapourcompressionrefrigerationcycle.
Theprocessesinfigure3areasfollows:1-2:Isentropiccompression–therefrigerantiscompressedtoasuper-heatedvapour2-3:Heatrejection–thesuperheatedvapouriscooledtothesaturationtemperature(TH)thenrejectsheatatconstanttemperatureuntilitreachesthesaturatedliquidpoint3-4:Expansion – the refrigerant is cooledquicklybyuseofa throttlevalve toTL, forminga liquidvapourmixture4-1: Heat absorption – the refrigerant absorbs heat ('() from low temperature reservoir until itreachesthesaturatedvapourpoint
Thedifferences in figure3aremainlydueto thepracticalitiesof runninga reverseCarnotcycle.Stage1-2isthemostnotablydifferentasitisshiftedcompletelyoutofthesaturationcurve.Compressorsdonothavehighefficiencyandrequiremoremaintenancewhentheyoperatewithamixedstatemedium,hencethecompressionstageisshiftedintothesuperheatedvapourregion.Thismeansthatprocess2-3cannolongerbeisothermalasthesuper-heatedvapourmustfirstbecooledtoitssaturationtemperature(TH)beforeitcanundergothephasetransitiontothesaturatedliquid.
Process3-4isanirreversibleexpansionprocessusingathrottlingvalve.Throttlingvalvesareusedratherthanisentropicexpansionengines(whichexpandsaturatedliquids)asthereisonlyasmallamountofworkoutputtobegained–thecostsforanenginewouldnotbejustifiable.Thethrottlevalve reduces the pressure of the saturated liquid abruptly, causing flash evaporation (partialevaporationofliquidduetosuddendropinpressure)oftheliquidandreducingitstemperature.Itisideallyaconstantenthalpyprocess.
Figure3showsanidealrefrigerationcycle.Inrealitythecompressionprocess(1-2)islikelytonotbeisentropichenceanincreaseinentropywillbeseen.Thiswillalsomeanthatthesuper-heatedvapourwillalsoreachahighertemperaturemeaningtheheatrejectionprocesswillhavetoreducethetemperaturemorebeforereachingthesaturationtemperature(TH).Therewillbeothergenerallyfrictionallossesduringtheprocesswhichwillcancausepressuredropswithintheprocesses.
T
s
1
TH
TL
4
2
3
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5-Set-upandProcedureEquipment
Theapparatususedisanairconditioningunit.Theunitisdividedintostationswherevariousreadingscanbetaken.AtstationAairistakeninfromtheroomandenterstheunit.StationBisformixingre-circulatingairthathasalreadypassedthroughtheunitinwiththefreshairfromtheroom.Airwillnotbere-circulatedduringtheexperimentsoanyreadingsfromstationAandBshouldbeidentical.BetweenstationBandCelectricpre-heatersandsteaminjectionoccurstobringtheairtothe conditions of a warm humid climate. Between station C and D the air passes though anevaporator where it is cooled and excess moisture is condensed out. The evaporator usesdichlorodifluoromethane(R12)refrigerant–thecycleoftherefrigerantisofkeyimportancetotheexperimentandwillbediscussedinmoredetailinSection7–DiscussionandAnalysisofResults.Between stationD and E there is re-heating of the air to increase its temperature and reduce itshumidity.Eachstationhastwothermocoupledthermometers–awetandadrybulb.Bytakingthesetworeadingswecandeterminethestateoftheair(itsrelativehumidity).Otherreadingsabouttheunit such asmass flow rates, current in compressors, relative pressures and temperatures in therefrigerantcyclewillberecorded.
Set-upandProcedure Hotandhumidairmustbeproducedfortheairconditioningcycle.Thisairwillthenbecooledanddehumidifiedandthenreheatedtoarequiredtemperatureof20°C.
Theunitisturnedonandairflowissettoaminimumof0.07kgs-1(anylowerandthereliabilityof thewetbulb thermocoupleswillbepoor).Theboilersandrefrigeratorunitsare turnedonandallowedtostabiliseforabout5minutes.Oncesteamisbeingproducedbytheboilers,twoofthethreeboilersareturnedoffandthere-heaterbetweenstationDandEisturnedon,adjustingitsothattheairbeforethecoolingisheatedto25°Candarelativehumidityof90%(awarmhumidclimate).Theunit is then left again to stabilise for 10minutes, after which the re-heater is adjusted to give atemperatureofabout20°Candrelativehumidityof50-60%afterthecoolingasitexitstheunit.Afterallowingtheunittostabilisefor10minutesoncemore,thermocouplereadingsandotherparametersateachstationcanbetaken.Theresultscanbeseeninthesectionbelow.
6-ObservationsandResults
Thetemperaturereadingsfromthethermocouples(wetanddrybulbs)wererecordedandshownintable1.Thecorrectedvaluesforthewetbulbtemperaturearealsoshown–thecorrectionvaluewasfoundusingfigure6whichshowstherelationshipbetween‘Screen’and‘Sling’wetbulbtemperatureswhen the dry bulb temperature is known. Figure 6 and a brief explanation of howcorrectionvaluesareobtainedisshownintheAppendix.
Station DryBulbTemperature(°C)
WetBulbTemperature(observed)(°C)
WetBulbTemperature(corrected)(°C)
A–Intake 20.0 16.0 16.4B–AfterMixing 21.0 17.0 17.4C–AfterPre-heatingandSteamInjection
27.5 27.5 27.5
D–AfterCoolingandDehumidification
18.3 18.3 18.3
E–AfterRe-heating 24.0 22.0 22.2Table1:Dry,Wetbulbandcorrectedwetbulbtemperaturereadingsfromeachstation.
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NotethatwhenthereadingsforstationCandDweretakenthewetbulbtemperatureswerehigherthanthedrybulbtemperatures.Thewetbulbismeanttobelessthanorequaltothedrybulbso the wet bulbs were given the same temperature as the dry bulb. No correction values wereobtainedforthesetemperatures.Thisisfurtherdiscussedinthesection8-SourcesofError.
TheairatAandBisexpectedtobeidenticalasthereisnochangeintheairbetweenthesetwopoints.HoweveratstationBthereisanincreaseintemperatureof1°Cforboththewetandthedry bulb. This could be due to the air conditioning unit acting as an insulation to the outsideenvironmentsoairfurtherintheunit(stationB)willbewarmerwhereasstationAisnotwellenclosed.Itcouldalsobeduetoatooshortstabilisationperiod.
Thetemperaturereadingsfromtherefrigerantcycleareshownintable2.Thesewillbeused
inSection7–DiscussionandAnalysisofResultstoplotamorerealisticcycleonap-hdiagram.
R12Temperature: Temperature(°C)BeforeExpansionvalve 33AfterExpansionvalve 0AfterEvaporator 21.5AfterCompressor 92Table2:TemperatureofR12refrigerantatvariousstages
throughcycle.
Thevoltagesupply,andcurrentsthroughtherelevantequipmentarerecorded,shownintable3.
ReadingVoltage(V) 233Pre-heatercurrent(A) 2Boilercurrent(A) 8Compressorandcoolingfancurrent(A) 9.2Re-heatercurrent(A) 2Circulatingfancurrent(A) 0.8Table3:Voltageandcurrentreadingsfromtheunit.
Using the value of voltage and compressor and cooling fan current we can calculate theamountofpowerthecompressorandcoolingfanrequire.Thisiscalculatedusingequation2belowandweobtainapowerof2.144kW.
#/0+1 = 23 = 9.2×233 = 2143.6),+,. 2Thisvalueofpoweristheworkinputtotherefrigerantcycle.Itwillbeusedlatertofinda
valuefortheCOPRoftherefrigerantcycle.
Othervariablesoftheunitwhichwererecordedareshownintable4.TheywillbeusedinlatercalculationsfindingtheCOPandmassflowratesoftheairandrefrigerant.
Reading UnitsOrificeDifferential(intake) mmH20 0.7OrificeDifferential(outlet) mmH20 0.7EvaporatorPressure(gauge) kPa 200CondenserPressure(gauge) kPa 750Refrigerantmassflowrate kgs-1 0.024
Table4:Orificedifferentialintakeandoutlet,evaporatorandcondenserpressureandrefrigerantmass
flowrateasrecordedfromtheunit.
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7-DiscussionandanalysisofResults
AirCalculationsPsychometricchart
Thetemperaturereadings(dryandwetcorrected)fromtable1areplottedonapsychometriccharttoenablethestateoftheairateachstationtobefound.Thisisshowninfigure4below[1].Eachpointhasbeenlabelledandfromthegraphwecanfindthespecificenthalpy,%saturationandspecificvolumeoftheairateachstation.Thedataobtainedfromthegraphisshownintable5below.
Figure4:Psychometric chart forairat101.325kPawithpointsofairateach station
plottedon.[1]
StationA StationB StationC StationD StationESpecificEnthalpy
(kJ/kg)45 49 87 50 66
%Saturation 72 70 100 100 88SpecificVolume
(m3/kg)0.843 0.848 0.884 0.842 0.863
Table5:Specificenthalpy,%saturationandspecificvolumeforairateachstationreadfrom
figure4.
WecanseethatthestatesofAandBareverysimilar–thisisexpectedandwasdiscussedearlierinsection5-Set-upandProcedure.StationCwasaimedtohavea%saturationof90andatemperatureofaround25°C,table5andtable1showthatactualvalueswere100%saturationand27.5°C.StationEwasaimedtobeat50-60%saturationandaround20°C,table5and1showthatactualvalueswere88%and22.2°C.Theactual%saturationatEisconsiderablyhigherthanexpected,showing there-heatingprocessbetweenDandEdidnot reducetherelativehumidityasmuchasexpected.Thefinaltemperatureoftheairleavingtheconditioningunit(stationE)was2.2°Cabovetheaimedvalue,suggestingthattherefrigerationprocessmaynothavereducedthetemperatureasmuchaswasrequired.Hadtherefrigerationcyclecooledtheairmore,moreheatcouldhavebeen
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addedbackduringthere-heatingprocesswhichmayhavedecreasedthe%saturationmore,givingacloservalueofboth%saturationandtemperaturetotheaim.
Otherdifferencesbetweentheaimedandactualvaluesarecommentedoninthesection8-SourcesofError. CoolingLoad Thecoolingloadontheairistheamountofheatremovedfromitasitpassesthroughtheheatexchangerwherethecooledrefrigerantflows.Itcanbecalculatedusingequation3below.
'( = :(ℎ= − ℎ?),+,. 3Where::=massflowrate(kgs-1)(air)ℎ==specificenthalpyofairbeforecooling(stationC)(kJ/kg)ℎ?=specificenthalpyofairaftercooling(stationD)(kJ/kg)
Thevaluesofℎ=andℎ?fromtable5are87kJ/kgand50kJ/kgrespectively.Themassflowrateofaircanbecalculatedusingequation4shownbelow.
: = 0.0757 ∆EFG,+,. 4
Where:∆E=intakeorificedifferentialpressure(mmH20)FG=specificvolumeatintake(stationA)(m3/kg)
Thevaluefor∆Ewasrecordedtobe0.7mmH20(table4)andthevalueofFGwasfoundtobe0.843m3/kg(graph1andtable5).Thesetwovaluescanbesubstitutedintoequation4andgiveavalue of 0.0690kgs-1 for the airmass flow rate. Substituting themass flow rate and both specificenthalpiesforstationDandC(table5)intoequation3acoolingloadontheairof2.55kWisobtained.RefrigerantCalculationsRefrigerationCycleonpressure-enthalpyDiagram Thereadingsthatweretakenduringtheexperimentcanbeusedtoplotap-hdiagramfortherefrigerantcycle.Apressureenthalpy(p-h)diagramshowninfigure5[2]canthenbeusedtofindtheenthalpyoftherefrigerantateachstageandhencethecoolingloadcanbecalculated.ThiscanthenbeusedtocalculatetheCOPRoftherefrigerationcycle.
A pressure enthalpy diagram for dichlorodifluoromethane (R12)was used, by plotting thepointsthechangesinphaseoftherefrigerantcanclearlybeseen.Notethatonthisgraphtherearemultiple axes. In order to plot the points the absolute pressures at which the condenser andevaporatorarerunningonmustbecalculated.Thegaugerunningpressuresoftheevaporatorandcondenserwererecordedtobe200kPaand750kParespectively(table4).Toconvertthevaluestoabsolutepressuretheatmosphericpressure(takenas100kPa)isaddedtoeachvalue.Fromthistheevaporatorpressureisfoundtobe300kPaandthecondenserpressureisfoundtobe850kPa. Eachpointisplottedonthediagram(figure5),notethatthesamenomenclatureforthepointsis used as in the theory section (4) above. Point one represents the refrigerant as a superheatedvapourasitexitstheevaporator.Itisplottedat0.3bar(evaporatorpressure)andonthesaturatedvapour curve. Process 1-2 is a constant entropy compression of the refrigerant to the condenserpressure(0.85bar),sopoint2isplottedat0.85bar(condenserpressure)andatentropyaspoint1(0.7kJ/kg/K).Process2-3isacondensingprocesswheretherefrigerantiscooledandphasechangesintoaliquid.Point3canbeplottedat0.85bar(condenserpressure)andonthesaturatedliquidcurve.Process 3-4 is a constant enthalpy expansion process where the refrigerant is bought to theevaporator pressure (0.3 bar) so point 4 is plotted at the same enthalpy as point 3 and on theevaporatorpressureline.
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Point 1 has been plotted assuming that the evaporator only heats the refrigerant to thesaturatedvapourpoint.Theactualpoint1(1a)canbeplottedonthegraphusingthetemperatureoftherefrigerantasitexitstheevaporatorwhichfromtable2isfoundtobe21.5°C.Notethatthisismuchhigherthantheidealtemperaturevalueof0°C.It isseenthatpoint1a is inthesuperheatedregioninthep-hdiagram,meaningtheevaporatorhasheatedtherefrigerantmorethanisexpected.Theimportanceofthiswillbediscussedwhencalculatingthecoolingloadontherefrigerant(laterinsection).
Point2hasbeenplottedassumingtheprocess1-2isisentropic(constantentropy).Inrealityitwillnothavebeenanisentropicprocess,therewillhavebeenasmallamountofheattransferintotherefrigerantresultinginahigherfinaltemperature.Amorerealisticpoint2canbeplottedbyusingthetemperatureoftherefrigerantattheendofthecompressionprocess.Fromtable2thevalueisfoundtobe92°Candcanbeplotted(aspoint2a)onthecondenserpressureline(0.85bar)usingaconstanttemperature line. It isseenthattheactualpoint(2a) isfurthertotherightthanthe idealisentropicpoint(2),astheidealpointisatatemperatureof40°C.Thismeansthatmorecoolingisneeded to cool the superheated refrigerant to a saturated vapour, and also represents anirreversibilityinthecycle.
Point1aand2ahavebeenconnectedanddrawnonfigure5,toallowcomparisonbetweentheactualandidealcycle.
Figure5:Pressure-enthalpydiagramshowingtherefrigerantcycle.Notethatpoint1
and 1a and the isentropic (2) and actual (2a)points of the compression are shown.
Dashedlinesrepresentirreversibleprocesses.[2]
Irreversibilitiesinthevapourcompressionrefrigerationcyclehavebeenshownonfigure5bydashedlines.Process1ato2aisirreversibleasitdoesisnotanisentropicprocess(duetotherebeingsmallamountsofheattransfer)henceitcannotbereversed.Process3to4isirreversibleduetothenatureoftheairconditioningunit,thiswasdiscussedinSection4–TheoryofVapourCompressionRefrigerationCycles.
Speci�c Enthalpy (kJ\kg)
Ab
solu
te P
ress
ure
(M
Pa
)
Constant Speci�c
Entropy (kJ\kg\K)
4
3 2 2
11 a
a
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CoolingLoad Thecoolingloadontheaircanbecalculatedusingequation3fromabove,notethatℎ=andℎ?correspondtothespecificenthalpiesoftherefrigerantatpoints1and4onfigure5–186kJ/kgand70 kJ\kg respectively. These values and the mass flow rate of the refrigerant from table 4 of0.024kgs-1canbesubstitutedintoequation3,givingacoolingloadof2.78kW.Notethatthisislargerthanthecoolingloadcalculatedfortheair(2.55kW),showingthattherefrigerantgainedmoreenergythantheairintheunitlost.Thisdifferenceisfurtherdiscussedinthesection8-SourcesofError.CoefficientofPerformance TheCOPRcanbecalculatedfortherefrigerationunitusingequation1shownbelow.
!"#$ = '() ,+,. 1
Where:'(=coolingload(W))=Workinput(powerofthecompressor)(W) The work input into this cycle is the compressor, its power was calculated in section 6 -ObservationsandResultsandwas found tobe2.144kW.Thisand thevalue for cooling load fromabove(2.78kW)canbesubstitutedintoequation1yieldingaCOPRof1.30.ThisCOPRvaluemeansthatforevery1kWofworkinput,1.3kWofheatwillberemovedfromtheair. TheCOPR canalsobe calculatedusing the cooling loadbasedon theair’s calculations. Thecompressorpowerandthecoolingloadbasedontheair(2.55kW)canbesubstitutedintoequation4togiveaCOPRof1.19.ThisissmallerthantheCOPRbasedaroundtherefrigerant,andisduetothecoolingloadoftheairbeinglowerthanthecoolingloadfortherefrigerant.ThisCOPRvaluemeansthatforevery1kWofworkinput,1.19kWofheatwillberemovedfromtheair.Thesignificanceofthisisdiscussedinsection8–SourcesandDiscussionofError.
8-SourcesandDiscussionofError As this experiment was mainly descriptive, it is difficult to quantify any errors. No fits orexpectedtrendscanbecomparedtotheresults,insteadthesystematicandexperimentalerrorsandimprovementsfortheexperimentandtheairconditioningunitarediscussed. Theairconditioningunitwasusedinalargeroomwithotherlargepiecesofequipmentrunningnearby.Intermittentconstructionworkwasgoingonintheroomadjacent,meaningthatthequalityoftheairmayhavefluctuatedduringtheexperiment.Itisalsopossiblethattheairhadahigherdustandparticulatecontentthannormal.Theexperimentwasconductedwithina2hoursession,thistimeconstraintlimitedthetimethatcouldbeusedforstabilisationoftheunit.Iftheexperimentweretobedoneagain,anisolated,airconditionedandfilteredroomshouldbeusedandlongertimesshouldbeallowedforthestabilisationoftheunit. Allreadingsweretakenfromneedlescaleswhichwerefluctuating,increasingtheerrorintheresults.Theunitwasnotcalibratedbeforeusageandhencetheresultsobtainedmayhavesystematicerror. A digital scalemay have increased the precision of the results obtained though thiswouldrequireadjustmentontheunit. Insection6theresultsobtainedshowedthatfortwooftherecordedtemperaturesthewetbulbwashigherthanthedrybulbtemperature-thismayhavehappenedduetotheunitnothavingenoughtimetofullystabilise. Insection7itwasshownthattheaimedtemperatureandsaturationsatstationsCandEweredifferenttothevaluesaimedfor.Thiswassuggestedtobeduetotherefrigerationcyclenotremovingasmuchheatfromtheairasexpected.Thisissupportedbythefactthatthecoolingloadontheairwasfoundtobelessthanthecoolingloadgainedbytherefrigerant(2.55kWto2.78kW,section7),showingtherefrigerantwasremovingmoreheatthanwaslostfromtheair.Theextraheatgainedbytherefrigerantcouldbeduetoitalsoabsorbingheatfromthesurroundingenvironmentastheunit
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maynotbewellinsulatedonthesectionwheretheheatexchangeoccurs.Theextraheatabsorptionisalsosupportedbytheactualcycleplottedonthep-hdiagramwheretheevaporatorincreasesthetemperatureoftherefrigerantaswellaschangesitsphase(pushingitintothesuperheatedregion). TwoCOPRvalueswerecalculated,oneusingthecoolingloadtotherefrigerant(1.3)andonefromthecoolingloadfromtheair(1.19).TheCOPRbasedontheairismoreconservativeasitusesthe cooling load that was directlymeasured from the air and is the desired outcome of the air-conditioningprocess.HowevertherefrigerantbasedCOPRismoreaccurateasitdoesnothavetheinaccuraciesinmeasurementofthewetbulbreadingsastheairCOPRdoes. TheCOPRvaluesobtainedfortheunitcouldbeimprovedinanumberofways.Fromequation1itisclearthattheCOPvaluecanbeincreasedbymakingthecoolingloadlarger,ortheworkinputsmaller.Thecoolingloadcouldbemadelargerbyinsulatingtheheatexchangesectiontoensurethatallheatabsorbedbytherefrigerantisfromtheair.Itcouldalsobeincreasedbyusingacontra-currentflowoftherefrigerantandairwhentheexchangetakesplaceasthismaintainsahighertemperaturegradient increasing the amount of heat exchange.Work input could be reduced by using amoreefficientcompressor.
9–Conclusion Theresultsobtainedallowedustoplotthestateoftheaironapsychometricchart.Itwasshownthatthe%saturationsoftheairweredifferenttothevaluesthatwereaimedfor,thiswasattributedtotherefrigerantremovinglessheatfromtheairthanexpectedhenceremovinglesshumidity.Thetemperaturesoftheairwererelativelyclosetotheaimedvalues,thoughthefinaltemperatureoftheairwas2.2°Cabovetheaimedvalue,againsuggestingthattherefrigerationcycledidnotreducetheair’stemperatureenough. Therefrigerantcyclewasplottedonap-hdiagram,showingtheidealandactualcyclealongwithirreversibilities.Theactualcyclemovedintothesuper-heatedvapourregionofthegraphmuchmorethantheactualcycle,meaningthatmoreheatwasrejectedtotheenvironmentthanexpected.The cooling loads on the air and to the refrigerant were calculated, giving 2.55kW and 2.78kWrespectively.Thishigherrefrigerantcoolingloadwassaidtobeduetotheairconditioningunitnotbeing well insulated so heat was removed from the surrounding environment as well as the air. COPRvalueswerecalculatedbasedonthecoolingloadsfortheairandtherefrigerant,yieldingvaluesof1.3and1.19respectively.TheCOPRbasedon theair’scooling loadwassaid tobemoreconservativeasitusedasmallercoolingloadandthedesiredoutcomeoftherefrigeration,howeverit is more inaccurate as it includes the measurements of the wet bulb temperatures which areinherently inaccurate. Improvements for theairconditioningunitwerediscussed includingusingamoreefficientcompressorandacounter-currentflowintheheatexchanger.
10–References[1]-HeikalMorganR.,MillerA.J.(2011).AIRCONDITIONING.Available:http://www.thermopedia.com/content/550.Lastaccessed24thDec2015.Edited.[2]-UniversityofBirmingham(2015).LaboratoryExperimentMP2.2.Appendix5–EnthalpydiagramforR12.p10.Edited. [3]-UniversityofBirmingham(2015).LaboratoryExperimentMP2.2.Appendix6:Relationshipbetween“Screen”and“Sling”wetbulbtemperatures.p11.Edited.
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11–AppendixRelationshipbetween“Screen”and“Sling”wetbulbtemperatures
Figure6:Relationshipbetween‘Screen’and‘Sling’wetbulbtemperatures.[3]
ForthereadingsfromstationAvaluesof20°Cand16°Cwereobtainedforthedryandthe
wetbulbrespectively.Toobtainthecorrectionvalueforthewetbulbtemperaturealinewasdrawnupfrom16°Conthexaxisuntilthedrybulbtemperatureof20°Cwasreached.Alinewasthendrawnhorizontallyandweobtainacorrectionvalueof0.4°C.ThesameprocesswasusedforeachsetofthermocoupledreadingsandthecorrectedvaluesareshowninTable1.