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TRNGI HCXYDNG
BIBI GINGGING MNMN HCHC
.Email: [email protected]
Tel: 0906. 655. 553
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CHNG 5. GIN THP
5.1. I CNG VGIN THP
5.2. TNH TON GIN THP
5.3. NT GIN THP
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5.1. I CNG V GIN THP
1. Phn loi gin thp
2. Hnh d n in th
.
4. Cc kch thc chnh ca gin
5. Hging khng gian
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5.1. I CNG V GIN THP
GinGin thpthp ll
gg??
gin thp
thp ?
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5.1. I CNG V GIN THP
Cc khi ni m v in th :
nh ngha.
Cc thanh in:Thanh cnh trn,
Thanh bn xin
Thanhxinu
Thanh cnh di
gin
Thanh ng
Lin kt ti nt gin: cc thanh gin c thlin kt trc tip vi nhau; hoc
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thng thng chng lin k t vi nhau thng qua cc bn thp (hay bn m).5
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5.1. I CNG V GIN THP
l lin kt hn (l phbin nht), hoc lin kt bulng, hoc lin kt inh tn.
10
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5.1. I CNG V GIN THP
1. Phn loi gin
1.1 Theo cng dng:Gin mi nh cng nghip, gin mi nh dn dng (v ko).
Gin cu, gin cu trc, gin thp khoan,
1.2 Theo cu to ca cc thanh ginGin nh: khi ni lc trong cc thanh cnh N < 200 tn; ti trng tcdng nhv vt khu nh.
Cc thanh gin c to thnh tmt thp gc L hay mt thp trn;Gin thn :
Sdng khi ni lc trong cc thanh cnh l kh ln N < 5000 kN; ti trng
Cc thanh gin c to thnh t2 thp gc, c dng hnh chT, chthp
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5.1. I CNG V GIN THP
Gin nng:
Ni lc trong thanh cnh rt ln N 5000 kN; c sdng lm gincu, gin cu chy,...
Cc thanh gin c dng thp tcc thp hnh hoc thp bn, c dng
chI, hnh hp, . a) b) c)
1.3 Theo skt cu:
Gin ki u d m n gin:
,ln lch gia 2 gi ta.
, , .
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5.1. I CNG V GIN THP
Gin kiu dm lin t c:
: c ng u n n n so v g nn gin, chiu cao gin nhhn, tit
.
N: chto v dng lp phc tp
ln lch gia cc gi ta.
Gin kiu dm c mt tha:
:Ni lc phn btrong cc thanh gin hp l hn so vi ginkhng c mt tha, c thcn bng biu mmen gia gi v nhp
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dm.9
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5.1. I CNG V GIN THP
e)
: Sdng lm khung chu
trnh c khu nhp ln
: Sdng lm kt cu chu lc cho cc cng trnh
vt u r t n, vt n p m ; n n tr nlm, nh ththao, k
Gin kiu thp tr:
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, ,sng,
10
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5.1. I CNG V GIN THP
2. Hnh dng gin
Cc yu cu chnh khi la chn gii php kt cu gin:
.
b) Yu cu thot nc mi:dc mi i ln hay b, hay mi dc hay mi thoi l.
c) Yu cu vlin kt gia gin mi v ct: lin kt khp hay cng, nhm m bo h.
d) Yu cu vvp hnh khi kin trc: to ra cc ng mi thng, cong, hay un.
e) Yu cu vkinh t: dchto v dng lp, tit kim vt liu.
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5.1. I CNG V GIN THP
a) Gin tam gic (a, b):
d
h h=
450
a
0 ,2 0 ,288
L L
h0
vi ct
d1 /8
c)
h
h
o
cim cu
to, chu lc v
Gin lin kt ngm vi cts dng ca cc
loi gin?
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1 C G G
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5.1. I CNG V GIN THP
d
h
L
d) Gin a gic, gin cnh cung (h, k):
h ) k
h h
LL
cim cuto, chu lc vs dng ca cc
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loi gin?13
5 1 I CNG V GIN THP
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5.1. I CNG V GIN THP
3. Hthanh bng ca gin
Yu cu vcu to cc nt gin:n gin, c nhiu nt ging nhau => dCc yu c u khi b tr thanh bng:
ng n rong c o.Yu cu tng chiu di thanh bng: nh.
.Yu cu thanh cnh trn: khng bun cc bdo ti t ngoi nt gin.
a ) b ) dd
b) Hthanh bng xin cu to, sdng?
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5 1 I CNG V GIN THP
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5.1. I CNG V GIN THP
c) Hthanh bng phn nh:
d)Ti trng tp trung tc dng ti nt gin
c cs dng?
L
g) h)
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5 1 I CNG V GIN THP
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5.1. I CNG V GIN THP
4. Kch thc chnh ca in thn
a) Nhp gin L :
=ta.
2 u ct.
~
36 m.
, , , , , ,
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5 1 I CNG V GIN THP
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5.1. I CNG V GIN THP
b) Chiu cao gia gin h, chiu cao u gin h0:Gin hnh thang, Gin cnh song song:
a ) b ) dd
eo u n n :
Theo iu kin vn chuyn :
h
65
Lh
11
Gin hnh tam gic:d
0
a ) b )
0 ,2 0 ,288
L
h
L
h
h0=
4
chiu cao hphthuc vo loi vt liu lp. 11
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g c c c n r n c a g n ~ o ng yC th ly chiu caou gin h0 = 450 mm d lin kt.
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5 1 I CNG V GIN THP
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5.1. I CNG V GIN THP
4. Kch thc chnh ca gin (thng)
c) Khong cch tm cc nt gin d:thanh cnh trn : d= 3 m hoc 1 5 khi sdn h in hn nh bng khong cch gia cc x g.
=
Ti sao d
cnh di c , .
d
th ln hncnh trn?
hh
o
i
L
d) Bc gin :Khong cch gia cc gin (bc gin) phthuc vo yu cu cngngh, kin trc.
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Thng ly B = 6 m.18
5 1 I CNG V GIN THP
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5.1. I CNG V GIN THP
5. H in khn ian
Nguyn tc cu to:
,gin. Kt cu gin phng dmt n nh theo phng ngoi mt phng ca gin.
Khi chu ti trng TT v HT tc dng theo phng ng => cc thanh cnh trn, v mtsthanh bng chu nn => Cn btr cc thanh chng dc nh tt ccc nt gin thucthanh cnh trn (v chu nn) ngn cn (hay ckt) cc nt gin khng cho chuyn
dch ra ngoi mt phng gin;-i vi kt cu mi panen BTCT th cc tm panen cng c tc dng nhcc thanh
dng.
- Cn btr cc thanh chng dc nh trong tt ccc khoang vtr nt nh gin, nt u, .
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5 1 I CNG V GIN THP
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5.1. I CNG V GIN THP
Khi ti tr n i tc d n vun c vi m t hn in => Ti tr n i tru nvo cc nt gin ca cthanh cnh trn v cnh di ca gin u hi.
- Cn lin kt 2 gin phng thuc ca cc khoang u hi vi nhau => sdngcc thanh cho chthp => nhm to ra mt khi kt cu khng gian n nh
2 ha u hi nh ch u ti tr n i n an .
- Bng cch btr cc thanh chthp v thanh chng dc lin kt gia cc ntgin 2 gian u hi (2 khoang u hi).
Gi l h ging khng gian nhm lin kt cc gin phng li vi nhau => toc c c u ng g an n n .
Hging khng gian gm c 3 loi:- Hgi ng cnh trn n m trong MP thanh cnh trn;
- Hging cnh di nm trong MP thanh cnh di;
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- Hgi ng ng n m trong MP cc thanh ng.
20
5.1. I CNG V GIN THP
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5.1. I CNG V GIN THP
a) Hging cnh trn:
H ging cnhtrn l g, c u
to, b tr v
b''
tc dng?
b
a ce' g' a'
a'
c
dge
Cc gin
ginhthno?
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5.1. I CNG V GIN THP
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5.1. I CNG V GIN THP
b) Hging cnh di:
H ging cnhdi l g, c u
to, b tr v
b''
tc dng?
ba
ce' g' a'
a
dge
Khi no cnb tr h
ging dc?Ti sao
cn gi l
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gin gi?22
5.1. I CNG V GIN THP
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c) Hging ng:
H in n
bc' ' '
a' b' c' l g, cu to,b tr v tc
a
dge
adng?
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5.2 TNH TON GIN THP
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. n g n
2. Ti tr n tc d n ln in3. Ni lc trong gin
4. Chiu di tnh ton cc thanh gin. n p c a c c an g n
6. Ch n v kim tra tit di n thanh in
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5.2 TNH TON GIN THP
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- Gm cc thanh gin c xp t c cc trc thanh ng qui ti mt im
, .- Cu to cc ti trng t tp trung ti nt gin.
- Trnh ti trng tc dng lm cong cc bcho cc thanh gin.
- n to n g n t ng v c c t an g m t p g c .
- =gin l lien kt khp v sdng cc phng php trong CHKC tnh.-i vi gin nng c thanh gin tit din hnh hp, chI, th c M kh
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ln.25
5.2 TNH TON GIN THP
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2. Ti trng tc dng ln gin
Ti trng thng xuyn (tnh ti)
3. Ni lc tron in Cn tnh rin r cho tn trn h ti tr n :
Ti trng tm thi
Tnh ti:Ho t ti sa cha mi: xt 3 tr n h : Tc d n ln ton in Tc d n
na tri gin (gy bt li cho thanh bng chu ct); v Tc dng na phigin.Ti trng gi: Tc dng ttri, Tc dng tphi. => Gi gy b t li cho nh
mi nh.
thanh cnh di. => Tnh gi trti trng ln nht ca cn trc treo tcd n ln nt in.
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5.2 TNH TON GIN THP
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4. Chiu di tnh ton cc thanh gin
a)
i v
i cc thanh chu N ko:
- Bph hovbn, vt liu t ti
- Cn xc nh mnh kim tra vmnh ln nht, m bocng chy ca thp.
.b)i vi cc thanh chu N nn:
an g n c u n n cong rong m p ng g n o c cong v nra ngoi mt phng gin;
=
N
.chu nn ng tm
cmin
Cn xc nh mnh ln nht ca cc thanh: );(max xMax
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5.2 TNH TON GIN THP
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Tit di n thanh in:
x
y
x z
Cn xc nh mnh ln nht ca cc thanh gin: );(max yxMax y
xxx il ll xx AIi xx trong :
yyy
yy
yy
Cn xc nh chiu di tnh ton ca cc thanh gin lx v ly, hoc hsc u tn ton. x y
cng ca bn mphthuc vophthuc vou tno?u tno?
u n trong vngoi mt phng c
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5.2 TNH TON GIN THP
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y
cong trong mt phng gin lx. lNt gin c lkhp l tng
khng, ti sao?
x yz
l
nt gin ph thucu t no? _
_c
d=l
_
__ +
__
++ae
xem l lin ktkhp, ngmn
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lhi?29
5.2 TNH TON GIN THP
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i vi gin khng c hbng phn l
V d: nh:
- Thanh xin u in: lx = l. _ _ _
b c d
l=lx
-Thanh xin th2: lx = 0,8 l __ + __
- i vi gin c hbng phn nh:
thanh xin u gin : lx = 0,5l
e
l
Thanh xin th2: lx = 0,5l
Bn m khi bun ra ngoi mt phng => c cng ngoi mt phng, .
Thanh xin u gin: ly = l.i vi thanh gin khng c hbng
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Thanh xin th2: ly = l.
30
5.2 TNH TON GIN THP
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i vi thanh gin c hbng phn nh:l
N2
- Cc thanh xin (thanh xin u gin): C ni lc nn N1 vN2 vi N1 > N2.
llN
ly
1
225,075,0x y
z
N1
- Thanh cnh trn v thanh cnh di: ly = khong cch gia 2im c kt ngn cn thanhcnh chuyn v ra khi mt phng gin
. Thanh cnh trn: ly = khong cch gia cc x g, thanh chng dc nh, khongcch chn panen,
. T an c n : y = o ng c c c c g ng c n ,
c) mnh gii hn ca cc thanh gin:
T an c u nn
Thanh chu ko
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5.2 TNH TON GIN THP
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5. Tit din hp l ca cc thanh gin
Tit din ca cc thanh gin thng bao gm 2 thp gc ghp li, thp gc u cnh haykhng u cnh.
Thanh gin chu nn ng tm. Mt n nh theo phng c mnh ln nht max
Tiu ch lm vic hp l ca cc thanh gin l (iu kin ng n nh):
yx y
x
x
ii
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5.2 TNH TON GIN THP
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5. Tit din hp l ca cc thanh gin
Cc dng tit din ca thanh gin:
a) b)
x
y y c) d)y
x
y
x
a c
C tlbn knh qun tnh ca tit din:
yx ii yx ii 5,0
yx ii 75,0 yx ii
Sdng thch hp khi ct c chiu cao tnh ton:
yx ll yx ll 8,0 yx ll yx ll 5,0
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5.2 TNH TON GIN THP
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a. Nguyn tc chn tit din:
- Tit din nhnht l L50 5.
- Khng chn qu 6~8 loi thp trong 1 ginL 36 m.
- KhiL 24 m : khng cn thay i tit din thanh cnh.
- KhiL > 24 m : khng qu 2 loi tit din khi 24 36 m.-dy bn m chn theo ni lc ln nht ca thanh xin u gin, ( 6 mm)
b) Chn v kim tra tit din thanh chu nn:
Din tch tit din yu cu:c
ycf
NA min
min cha bit, sbgithit
gt = 60 80 i vi thanh cnh ; gt = 100 120 i vi thanh bng.
TAyc , tra bng thp hnh chn shiu tit din v cc c trng hnh hc catit din: ix, iy,Ag
Kim tra tit din chn: cfA
N
min
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min theo yx ;maxmax 34
5.2 TNH TON GIN THP
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6. Chn v kim tra tit din thanh ginc) Chn v kim tra tit din thanh chu ko:
N
c
ycf
T c tra bn th hnh ch n s hi u v cc c trn hnhhc: ix, iy,Ag
Kim tra tit din chn: cfN
vn
d) Chn tit din thanh theo mnh gii hn:
,
x
ycx
l
i ,y
ycy
l
i
Tra bng thp hnh chn shiu.
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5.3 NT GIN THP
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1. N u n tc chun
Cc thanh gin c chn theo tit din hp l.
Khi thanh cnh khng c thay i tit din m:im hi tca cc thanh gin nm trn trc ca thanh cnh.
24L
Khi thanh cnh c thay i tit din (khi ni thanh cnh) 3624 L ,
trc ca thanh ln nu khong cch gia 2 trc thanh khng ln hn1,5% chiu cao ca cnh thp gc.
Bn m nn chn c hnh dng n gin v m bo truyn lc tt:n c n , n ang, am g c, a g c .
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,
lc gia thanh v bn m.36
5.3 NT GIN THP
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1. N u n tc chun
Bdy ca bn m c chn theo ni lc ln nht trong cc thanh, . .
Khe hgia cc u thanh bng v thanh cnh:206 bmtc mm
80c mm
Khe hgia 2 thanh cnh khi ni ly bng 50 mm.
f
chiu di l 50 mm (cho cng hn khng lin tc).
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n c u p g c.37
5.3 NT GIN THP
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2. Nt trung gian
a) b)
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