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    1 . Therm odynam ics is n o t concern ed ab ou t______.

    (i) energy cha nges involved in a chemical reaction.

    (ii) the extent to which a chemical reaction proceeds.

    (iii) the ra te a t which a react ion proceeds .

    (iv) the feasibility of a ch emical reaction.

    2 . Wh ich of th e followin g sta tem ent s is corr ect?

    (i) The presence of reacting species in a covered beaker is an examp le of open system.

    (ii) There is an exchan ge of energy as well as m atter between the systemand the su r roun dings in a c losed sys tem.

    (iii) The presence of reactants in a c losed vessel ma de up of copper is an

    examp le of a closed s ystem.

    (iv) The presence of reactants in a therm os flask or any other closed ins u lated

    vess el is a n example of a closed system .

    3 . The s tate of a gas can be described by qu oting th e relations hip b etween___.

    (i) p r es su r e , vo lum e , tem pe ra tu r e

    (ii) t em pe ra tu r e, a m oun t , p r es su r e

    (iii) a m oun t , volum e , t em pe ra tu r e

    (iv) p r es su r e , volum e , t em pe ra tu r e, a m oun t

    4 . The volume of gas is reduced to half from its original volume. The specific

    h ea t will be ______.

    (i) r ed u ce t o h a lf

    (ii) b e dou b led

    I. Multiple Choice Questions (Type-I)

    U nitU nitU nitU nitU nit

    66THERM ODYNAM ICSTHERM ODYNAM ICSTHERM ODYNAM ICSTHERM ODYNAM ICSTHERM ODYNAM ICSTHERM ODYNAM ICSTHERM ODYNAM ICSTHERM ODYNAM ICSTHERM ODYNAM ICSTHERM ODYNAM ICS

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    (iii) r em a in c on s t a n t

    (iv) inc re ase fou r t im e s

    5 . Du ring complete comb u stion of one mole of bu tan e, 2658 kJ of hea t is released.Th e th ermochem ical reaction for ab ove cha n ge is

    (i) 2C4H

    1 0(g) + 13O

    2(g) 8CO

    2(g) + 10H

    2O(l )

    cH = 2658.0 kJ mol

    1

    (ii) C4H

    1 0(g) +

    1 3

    2O

    2(g) 4CO

    2(g) + 5H

    2O (g)

    cH= 1329 .0 kJ mol

    1

    (iii) C4H

    1 0(g) +

    1 3

    2O

    2(g) 4CO

    2(g) + 5H

    2O (l )

    cH= 2658.0 k J mol

    1

    (iv) C4H

    10(g) +

    1 3

    2O

    2(g) 4 CO

    2(g) + 5 H

    2O (l)

    cH= +2658.0 kJ mol

    1

    6 . fU

    V

    of formation of CH4

    (g) at certain temperature is 393 kJ mol1. Thevalue of

    fH

    Vis

    (i) zero

    (ii) < f

    UV

    (iii) > f

    UV

    (iv) equ a l to f

    UV

    7 . In an adiabatic process, n o tran sfer of heat takes p lace between system a nd

    su rrou n dings. Choose th e correct option for free expa ns ion of an ideal gasu n der a diaba tic con dition from th e following.

    (i) q = 0 , T 0, w = 0

    (ii) q 0, T = 0, w = 0

    (iii) q = 0 , T = 0, w = 0

    (iv) q = 0 , T < 0, w 0

    8 . The pressure-volume work for an ideal gas can be calculated by using the

    expression = wf

    i

    V

    ex

    V

    p dV . Th e work can also be calcu lated from th epV plot

    by us ing the area u nd er the cu rve with in the sp ecified limits. Wh en an ideal

    gas is comp res sed (a) reversibly or (b) irrevers ibly from volum e Vito V

    f. choose

    th e correct option.

    (i) w (reversible) = w (irreversible)

    (ii) w (revers ible) < w (irreversible)

    (iii) w (revers ible) > w (irreversible)

    (iv) w (reversible) = w (irreversible) +pe x

    .V

    6 9 Therm odynam ics

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    7 0Exemplar Problems, Chemis t ry

    9 . The en tropy cha nge can be calcu la ted b y us ing th e expression S =rev

    q

    T.

    When water freezes in a glas s bea ker, choose the correct statem ent a mon gst

    th e following :

    (i) S (system ) decreases bu t S (su rroun dings) remains th e same.

    (ii) S (system ) increases bu t S (surroundings) decreases.

    (iii) S (system ) decreases b u t S (surroundings) increases.

    (iv) S (system ) decreases an d S (su rrou n dings) also decreas es.

    1 0 . On t h e bas is of th erm ochem ical equ at ion s (a), (b) an d (c), find ou t wh ich of th e

    algebr ic relation sh ips given in op tion s (i) to (iv) is corr ect.

    (a ) C (gr a ph it e) + O2

    (g) CO2

    (g) ; rH=x kJ m ol

    1

    (b ) C (gr ap h it e) +1

    2O

    2(g) CO (g) ;

    rH=y kJ m ol

    1

    (c) CO (g) +1

    2O

    2(g) CO

    2(g) ;

    rH=z kJ m ol

    1

    (i) z =x + y

    (ii) x =y z

    (iii) x =y +z

    (iv) y = 2z x

    1 1 . Consider th e reaction s given b elow. On t h e bas is of th ese reactions fin d ou t

    wh ich of th e algebric relat ions given in op tion s (i) to (iv) is corre ct?

    (a ) C (g) + 4 H (g) CH4

    (g); rH=x k J m ol

    1

    (b ) C (gr a ph it e,s ) + 2 H2

    (g) CH4

    (g); rH=y kJ m ol

    1

    (i) x =y

    (ii) x = 2 y

    (iii) x >y

    (iv) x

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    7 1 Therm odynam ics

    1 3 . Enth alpy of su blima tion of a s u bsta nce is equal to

    (i) enth alpy of fu sion + enth alpy of vapou risa t ion

    (ii) e n tha lpy o f fu s ion

    (iii) en tha lpy of vapour isa t ion

    (iv) twice the entha lpy of vapourisa t ion

    1 4 . Which of th e followin g is n o t correct?

    (i) G is zero for a reversible react ion

    (ii) G is positive for a s pont an eous reaction

    (iii) G is negative for a s pont an eous reaction

    (iv) G is positive for a n on-sp onta neou s rea ction

    II. Multiple Choice Questions (Type-II)In th e fol lowing quest ions two or more opt ions may be c orrect .

    1 5 . Th ermodyna mics m ainly deals with

    (i) interre la t ion of var iou s forms of energy and th eir t ran sformation f rom

    one for m to an other.

    (ii) energy cha nges in th e processes which depend only on ini t ia l and fina l

    sta tes of the m icroscopic system s containing a few molecules.

    (iii) how and a t wha t ra te these energy t rans format ions a re ca r r ied out .

    (iv) the system in equilibr ium sta te or moving from one equ ilibr iu m s ta te toan other equ ilibrium s tate.

    1 6 . In an exothermic reaction, heat is evolved, and system loses heat to the

    su r rou nding. For su ch sys tem

    (i) qp

    will be n egat ive

    (ii) rHwill be n egat ive

    (iii) qp

    will be p osit ive

    (iv) rH will be p osit ive

    1 7 . The sp onta neity mean s, ha ving the potential to proceed with out th e assista nce

    of external agency. Th e processes which occur s pon tan eous ly are

    (i) flow of heat f rom colder to warm er body.

    (ii) gas in a conta iner cont rac t ing in to one corner.

    (iii) gas expanding to fill the available volu me.

    (iv) bu rning carbon in oxygen to give carbon d ioxide.

    1 8 . For an ideal gas, th e work of reversible expan sion u nd er isoth erma l cond ition

    can b e calculated by u sing the express ion w = nRTlnf

    i

    V

    V

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    7 2Exemplar Problems, Chemis t ry

    A sa mp le con taining 1.0 m ol of an ideal gas is expan ded isotherm ally and

    reversibly to ten times of its original volum e, in two sepa rate experimen ts.

    Th e expan sion is carried out a t 30 0 K an d at 600 K respectively. Choose th ecorrect option .

    (i) Work done a t 600 K is 20 t imes the work done a t 300 K.

    (ii) Work done a t 300 K is twice the work done a t 600 K.

    (iii) Work done a t 600 K is twice the work done a t 30 0 K.

    (iv) U= 0 in b oth cases.

    1 9 . Consider th e following reaction b etween zinc an d oxygen an d ch oose the correct

    option s ou t of th e option s given b elow :

    2 Zn (s) + O2

    (g) 2 ZnO (s ) ; H = 693.8 kJ mol1

    (i) The enth alpy of two moles of ZnO is less th an the tota l enth alpy of two

    moles of Zn an d on e mole of oxygen by 693 .8 kJ .

    (ii) The enth alpy of two moles of ZnO is more than the total ent ha lpy of two

    moles of Zn an d on e mole of oxygen by 693 .8 kJ .

    (iii) 6 93 .8 kJ m ol1

    en ergy is evolved in th e reaction .

    (iv) 6 93 .8 kJ m ol1

    energy is abs orbed in the reaction.

    III. Short Answer Type

    2 0 . 18.0 g of water completely vapou rises a t 100 C an d 1 bar pressu re an d th e

    enth alpy chan ge in th e process is 40.79 kJ mol1

    . Wha t will be the ent h alpycha nge for vapou risin g two moles of water u nd er th e sam e conditions? Wh at

    is the s tan dard enth alphy of vapou risa t ion for water?

    2 1 . On e mole of aceton e requ ires less h eat to vapou rise th an 1 m ol of water. Wh ichof th e two liqu ids h as higher ent ha lpy of vap our isation?

    2 2 . Stan dard molar enth alpy of formation, fH

    V

    is ju st a s pecial case of enth alpyof r eaction,

    rH

    V. Is th e

    rH

    Vfor th e following r eaction s am e as

    fH

    V? Give

    reason for your an swer .

    CaO(s) + CO2(g) CaCO

    3(s);

    fH

    V

    = 178.3 kJ mol1

    2 3 .Th e valu e of

    fH

    V

    for NH3 is 91.8 kJ mol

    1

    . Calculate ent ha lpy cha n ge for thefollowing rea ction :

    2 NH3(g) N

    2(g) + 3 H

    2(g)

    2 4 . En th alpy is a n exten sive prop erty. In gen eral, if ent h alpy of an overall reaction

    AB along one rou te is rHa n d

    rH

    1,

    rH

    2,

    rH

    3. . . .. represent en th alpies of

    intermediate rea ctions leadin g to produ ct B. Wha t will be th e relation b etween

    rHfor overall reaction a n d

    rH

    1,

    rH

    2..... etc. for in term ediate rea ctions.

    2 5 . The enthalpy of a tomisation for the reaction CH4(g) C(g) + 4H (g) is

    1665 kJ m ol1 . Wha t is th e bond energy of CH bon d?

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    7 3 Therm odynam ics

    2 6 . Use th e followin g data to calculat e lattice

    HV for NaBr.

    sub

    HV for sodiu m m etal = 108.4 kJ mol

    1

    Ionizat ion enth alpy of sodium = 496 k J mol1

    Electron gain enth alpy of bromine = 325 kJ mol1

    Bond dissociation en th alpy of brom in e = 192 k J mol1

    f

    HV

    for NaBr (s) = 36 0.1 kJ m ol1

    2 7 . Given th at H= 0 for m ixing of two gases. E xplain wheth er th e diffu sion of these

    gases into each other in a closed conta iner is a sp ontan eou s process or not?

    2 8 . Heat h as ra ndomising influ ence on a system an d temperature is the m easure

    of average ch aotic motion of particles in t he s ystem. Write th e ma th ema ticalrelation which r elates th ese three para meters.

    2 9 . Increase in enth alpy of the s u rroun dings is equ al to decrease in enth alpy of

    the system. Will the temperatu re of system an d su rroun dings be the sam ewhen t hey are in th ermal equilibr ium ?

    3 0 . At 2 98 K. Kp

    for th e reaction N2O

    4(g) U 2NO

    2(g) is 0.98 . Predict wheth er th e

    reaction is spontan eou s or not .

    3 1 . A sample of 1.0 mol of a monoatomic ideal gas is taken through a cyclicprocess of expan sion an d compres sion as sh own in Fig. 6.1. What will be the

    value ofH for th e cycle as a wh ole?

    Fig . : 6 .1

    3 2 . The standard molar entropy of H2O (l) is 70 J K1 m ol1 . Will the standard

    m olar en trop y of H2O(s) be more, or less th an 70 J K1 m ol1?

    3 3 . Iden tify the s tate fun ctions an d p ath fu nctions out of th e followin g :

    enth alpy, entr opy, hea t, temp eratu re, work, free energy.

    3 4 . Th e molar enth alpy of vap our isation of aceton e is less th an th at of water. Wh y?

    3 5 . Which qu an tity out of rG a nd

    rGV will be zero at equ ilibriu m?

    3 6 . Predict the ch an ge in int erna l energy for an isolated system a t const an t volum e.

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    7 4Exemplar Problems, Chemis t ry

    3 7 . Although heat is a path function but heat absorbed by the system under

    certain s pecific condition s is indepen den t of pat h . Wh at a re th ose con ditions ?

    Explain.

    3 8 . Expan sion of a gas in vacuu m is ca lled free expan sion. Calcu late the workdone and the change in internal energy when 1 litre of ideal gas expandsisotherm ally int o vacu u m u n til its total volu me is 5 litre?

    3 9 . Heat cap acity (Cp

    ) is an extens ive propert y bu t s pecific heat (c) is an inten sive

    property. What will be t h e relation between Cp

    an d c for 1 m ol of water?

    4 0 . The difference between CP

    and CV

    can be derived using the empirical relation

    H= U+pV. Calculate th e difference between CPand C

    Vfor 10 m oles of an ideal gas.

    4 1 . If th e comb u stion of 1g of graph ite produ ces 20.7 k J of hea t, what will be

    m olar en th alpy cha n ge? Give th e sign ifican ce of sign also.

    4 2 . The net enthalpy change of a reaction is the amount of energy required tobreak a ll the bonds in reactant m olecu les minu s a mou nt of energy required

    to form all the bonds in the product molecules. What will be the enthalpych an ge for th e followin g reaction.

    H2(g) + Br

    2(g) 2HBr(g)

    Given th at Bond en ergy of H2, Br

    2and HBr is 435 kJ mol

    1, 192 kJ mol

    1a n d

    368 kJ m ol1

    respectively.

    4 3 . The enthalpy of vapourisation of CCl4

    is 30 .5 kJ mol1

    . Calcula te the h eatrequ ired for th e vap ou risa tion of 28 4 g of CCl

    4at cons tan t press u re . (Molar

    ma ss of CCl4

    = 154 g mol1

    ).

    4 4 . Th e enth alpy of react ion for th e reaction :

    2H2(g) + O

    2(g) 2H

    2O(l) is

    rHV = 572 k J mol

    1.

    What will be standard enthalpy of formation ofH

    2O (l ) ?

    4 5 . Wh at will be the work d one on an ideal gas en closed

    in a cylind er , when it is compressed by a cons tan texternal pressu re ,p

    ex tin a s ingle s tep as sh own in

    Fig. 6.2. Exp lain grap h ically.

    4 6 . How will you calculate work done on an ideal gas

    in a compress ion , when change in pressure i scarried out in infinite steps?

    4 7 . Represent t he potential energy/ enth alpy chan ge in

    th e followin g process es gra ph ically.

    (a ) Throwing a s tone from the grou nd to roof.

    (b)1

    2H

    2(g) +

    1

    2Cl

    2(g) U HCl(g)

    rH

    V= 92.32 kJ mol1

    In which of the processes potentia l energy/ enth alpy cha nge is contr ibut ing

    factor to th e spon tan eity?

    Fig . : 6 .2

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    7 6Exemplar Problems, Chemis t ry

    5 2 . Match th e following p rocesses with entropy ch an ge:

    Re ac t io n En tro py c h ange

    (i) A liqu id va pou rises (a) S = 0

    (ii) Rea ction is n on -spon ta n eou s (b ) S = posit ive

    at a l l temperatu res and H

    is pos itive

    (iii) Revers ib le expa n s ion of a n (c) S = negat ive

    ideal gas

    5 3 . Match th e following p ara meters with description for sp onta neity :

    (Param e t e rs ) Desc ript ion

    r

    HVVVVV

    r

    SVVVVV

    r

    GVVVVV

    (i) + + (a) Non -spon ta n eou s a t h igh

    temperature.

    (ii) + a t h igh T (b ) S pon ta ne ous a t a l l t em pe ra tu r e s

    (iii) + (c) Non -s pon ta n eou s a t a lltemperatures

    5 4 . Match th e followin g :

    (i) En tropy of va pou risa t ion (a ) decrea ses

    (ii) Kfor s pon ta n eou s proces s (b ) is a lwa ys pos it ive

    (iii) Crys ta llin e solid s ta te (c) lowes t en tropy

    (iv) Uin a d ia ba tic expa n s ion (d )va p

    b

    H

    T

    of idea l gas

    V. Assert ion and Reas on Type

    In th e following ques tion s a st atem ent of Ass ertion (A) followed by a state me nt

    of Reason (R) is given. Choose t he c orrect opt ion o ut of the c hoice s given

    below each quest ion.

    5 5 . As s er t ion (A): Combustion of a l l organic compounds is an exothermic

    reaction.

    Rea s on (R) : The en th alpies of all elemen ts in th eir sta nd ard sta te are zero.

    (i) Both A and R a re t rue an d R is th e cor rect explana t ion of A.

    (ii) Both A an d R are true bu t R is n ot the correct explan ation of A.

    (iii) A is t rue but R is fa lse .

    (iv) A is fa ls e bu t R is t r ue .

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    7 7 Therm odynam ics

    5 6 . As s ert ion (A) : Spontan eou s p rocess is an ir reversible process an d m ay be

    reversed b y some externa l agen cy.

    Rea s on (R) : Decrease in en th alpy is a con tribu tory factor for spon tan eity.

    (i) Both A and R a re t rue an d R is th e cor rect explana t ion of A.(ii) Both A an d R are true bu t R is n ot the correct explan ation of A.

    (iii) A is t rue but R is fa lse .

    (iv) A is fa ls e bu t R is t r ue .

    5 7. As s ert ion (A) : A liquid crystallises into a solid and is accompanied bydecrease in entropy.

    Re a s on (R) : In crysta ls, m olecules organ ise in a n ordered ma n ner.

    (i) Both A and R a re t rue an d R is th e cor rect explana t ion of A.

    (ii) Both A an d R are true bu t R is not th e correct explanation of A.

    (iii) A is t rue but R is fa lse .

    (iv) A is fa ls e bu t R is t r ue .

    VI. Long Answe r Type

    5 8 . Derive the relationsh ip between H a n d Ufor an ideal gas . Explain each

    term involved in t he equa tion .

    5 9 . Extensive properties depen d on th e qua nt ity of ma tter bu t intens ive propertiesdo not . Explain wheth er th e followin g properties ar e exten sive or in ten sive.

    Mas s, intern al energy, press u re, heat capacity, molar hea t capa city, density,mole fraction, specific heat, t empera tu re a nd molarity.

    6 0 . The lattice en th alpy of an ion ic compou n d is th e enth alpy wh en on e mole of

    an ionic compou nd presen t in its gaseous sta te, diss ociates into its ions . It isimp ossible to determ ine it directly by experimen t. Su ggest a n d explain an

    indirect met h od to mea su re lattice en th alpy of NaCl(s).

    6 1 . G is net en ergy availab le to do u sefu l work an d is th u s a mea su re of free

    energy. Sh ow mat hem atically tha t G is a m easu re of free energy. Fin d th e

    un it of G. If a rea ction h as positive enth alpy chan ge an d pos itive entropychan ge, u nder wh at condit ion will the reaction be s pontan eou s?

    6 2 . Graph ically show the total work done in an expan sion when t he st ate of anideal gas is cha n ged reversibly an d isoth erm ally from (p

    i, V

    i) to (p

    f, V

    f). With

    the help of a pV plot compare the work done in the above case with that

    carr ied out agains t a constan t external pressu re pf

    .

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    7 8Exemplar Problems, Chemis t ry

    ANSWERS

    I. Mult ip le Ch oice Qu es t ions (T y p e-I)

    1. (iii) 2. (iii) 3. (iv) 4. (iii) 5 . (iii) 6. (ii)

    7 . (iii)

    Jus tifica tion : free expa n sion w = 0

    ad iab atic process q = 0

    U= q + w = 0, this m eans tha t internal energy remains

    consta nt . Therefore, T= 0 .

    In ideal gas there is no intermolecular attraction. Hence when such a gas

    expan ds u nder a diabatic cond it ions into a vaccu m n o heat is abs orbed or

    evolved sin ce no externa l work is don e to sepa rat e th e molecu les.

    8 . (ii) w (rever s ible) < w (irre vers ible)

    Jus tifica tion : Ar e a unde r the c u r ve i s a lwa ys m or e in i r r e ve r s ib l ecompres sion a s ca n be s een from Fig. 6.5 (a) and (b).

    (a ) Revers ib le com press ion (b) Ir revers ib le com pres s ion

    Fig . : 6 .5

    9. (iii)

    Jus tifica tion : Freezing is exotherm ic process. The h eat released in creasesthe en tropy of su rroun ding.

    1 0. (iii)

    11 . (iii)

    Jus tifica tion : Same bonds are formed in reaction (a) and (b) but bonds

    between reactan t m olecules are b roken on ly in reaction (b).

    12 . (iii ) 13 . (i ) 14 . (ii )

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    7 9 Therm odynam ics

    II. Mul t ip le Ch oice Qu es t ion s (Ty p e-II)

    15. (i), (iv) 16 . (i), (ii) 17 . (iii), (iv)

    18 . (iii), (iv)

    Jus tif ica tion :600K

    300K

    1 01 R 6 00 lnw 60 01= 2

    1 0w 30 01 R 30 0 ln

    1

    K

    K

    = =

    For isoth erma l expan sion of ideal gas es, U= 0

    since temperatu re is consta nt this mean s th ere is n o chan ge in interna l energy.Therefore, U= 0

    19. (i), (iii)

    III. S h or t An s w er Ty p e

    20. + 81 .58 kJ , va p

    HV

    = + 40.79 kJ mol1

    2 1 . Water

    2 2 . No, sin ce Ca CO3

    ha s been formed from oth er compou nd s a nd not from itscons titu ent elements .

    2 3 . rH

    V = +91.8 kJ mol1

    2 4 . r

    H= r

    H1

    + r

    H2

    + r

    H3

    .....

    2 5 .1 6 6 5

    4k J m o l

    1= 416.2 kJ mol

    1

    2 6. +735.5 kJ m ol1

    2 7 . It is s p o n t a n e ou s p r oc es s . Alt h o u g h e n t h a l p y c h a n g e is ze r o b u t

    randomness or disorder ( i .e . , S) increases. Therefore, in equationG = H TS, the term TS will be n egative. Hen ce, G will be n egat ive.

    2 8 . S=re v

    q

    T

    2 9 . Yes

    3 0 . Th e r ea ct ion is s pon t a n eou s

    rGV

    = RTln Kp

    31. H(cycle) = 0

    32 . Le ss , bec a use ic e is m ore or der ed tha n H2O (l ).

    33 . S ta te Func t ions : Entha lpy, Ent ropy, Tempera ture , F ree energy

    Path Fu n ctions : Heat, Work

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    8 0Exemplar Problems, Chemis t ry

    3 4 . B ec a u s e o f s t r o n g h yd r o ge n b o n d in g in w a t e r, it s e n t h a l p y o f

    vapourisa tion is more.

    3 5 . rG will always be zero.

    rGV is zero for K= 1 becaus e GV = RT lnK, GV will be non zero for

    oth er values of K.

    36 . For isola ted system, there is no tran sfer of energy as h eat or as work i.e .,

    w=0 a nd q=0. According to th e first law of th ermodyn am ics.U = q + w

    = 0 + 0 = 0

    U = 0

    3 7 . At constant volume

    By first law of th erm odyna mics:

    q = U+ (w)

    (w) = p V

    q = U+ pV

    V = 0, s ince volum e is cons tan t .

    qV

    = U+ 0

    qV

    = U= cha nge in int erna l energy

    At co nst ant press ure

    qp

    = U+ pV

    But , U+ pV = H

    qp

    = H = chan ge in enth alpy.

    So, a t a constan t volum e and a t cons tan t pressu re heat chan ge is a s ta tefu nction becaus e i t is equ al to chan ge in intern al energy and chan ge in

    enth alpy respectively wh ich are s tate fun ctions.

    3 8 . (w) =pex t

    (V2V

    1) = 0 (5 1 ) = 0

    For isoth erma l expan sion q = 0

    By first law of th erm odyna mics

    q = U+ (w)

    0 = U+ 0 so U= 0

    39. For wa te r, hea t capac ity = 18 spec ific hea t

    or Cp

    = 18 c

    Specific h eat = c = 4.18 J g1

    K1

    Heat cap acity = Cp

    =18 4 .18 J K

    1=

    75 .3 J K

    1

    4 0 . CP

    CV

    = nR

    = 10 4.184 J

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    8 1 Therm odynam ics

    4 1 . Mola r en th a lp y

    cha n ge of graph ite= enth alpy chan ge for 1 g carbon molar m as s of carbon

    = 20.7 kJ g1

    12g mol1

    H = 2.48 102k J m ol

    1

    Negat ive valu e ofH exoth ermic reaction .

    4 2 . rH

    V= Bond energy of H

    2+ Bond en ergy of Br

    2 2 Bond en ergy of HBr

    = 435 + 192 (2 368) kJ mol1

    rH

    V= 1 09 kJ m o l

    1

    4 3 . qp

    = H = 30.5 kJ mol1

    Heat requ ired for vapour isation of 284 g of CCl4 = 12 8 4 g

    30 .5154g mol

    kJ m ol

    1

    = 56.2 kJ

    44 . According to the definition of stan dard enth alpy of formation, the enth alpych an ge for th e followin g reaction will be st an da rd en th alpy of form at ion

    of H2O (l)

    H2(g) +

    1

    2O

    2(g) H

    2O(l ).

    or the s tan dar d en th alpy of forma tion of H2O(l ) will be h alf of th e en th alpy

    of th e given equ at ion i.e., rH

    V

    is also h alved.

    fH

    V

    H2O(l ) =

    1

    2

    rH

    V=

    1

    572 kJ mol

    2= 286 kJ / m ol.

    45 . Work done on an idea l gas can be ca lcula ted from p-V graph sh own inFig. 6.6. Work done is equal to the sh ad ed area ABV

    IV

    II.

    Fig . : 6 .6

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    8 2Exemplar Problems, Chemis t ry

    46 . The work done ca n be c a lc u la t ed with the he lp o f pVplot. ApVplot of

    th e work of compres sion which is carr ied out b y cha n ge in press u re in

    infin ite steps , is given in Fig. 6.7. Sha ded ar ea represen ts t he work doneon the gas .

    Fig . : 6 .7

    4 7 .

    Fig . : 6.8 Enthalpy change in processes (a) and (b)

    4 8 . No.

    En th alpy is on e of th e contribut ory factors in deciding spon tan eity bu t it

    is not t he on ly factor. One m u st look for contribu tion of an other factori.e., entr opy also, for gettin g the correct resu lt.

    49 . It is c lear from the figu re that the process ha s been carr ied out in infini testeps , h ence it is isoth ermal reversible expans ion.

    w = 2.303 nRTlogV

    V

    2

    1

    But , p1V

    1= p

    2V

    2

    V

    V

    2

    1

    =p

    p

    1

    2

    =2

    1= 2

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    8 3 Therm odynam ics

    w = 2.303 nRT logp

    p

    1

    2

    = 2.303 1 mol 8.314 J mol1 K1 298 K1 log 2

    = 2.303 8.314 298 0.3010 J = 1717.46 J

    5 0 . w = pe x

    (Vf

    Vi) = 2 4 0 = 80 L ba r = 8 k J

    The nega t ive s ign shows tha t work i s done by the sys tem on the

    su rr oun ding. Work don e will be more in t h e reversible expan sion becau seintern al pressure an d exerna l pressu re are a lmost s am e at every step.

    IV. Ma t ch ing T y p e

    51. (i) (e) (ii) (d ) (iii) (f) (iv) (a)

    (v) (g), (k), (l) (vi) (b ) (vii) (c) (viii) (j)

    (ix) (h ) (x) (i) (xi) (a ), (l), (m ) (xii) (g), (k)

    52 . (i) (b ) (ii) (c) (iii) (a)

    53 . (i) (c) (ii) (a ) (iii) (b)

    54 . (i) (b), (d) (ii) (b ) (iii) (c) (iv) (a)

    V. Asser t ion and Reason Type

    55 . (ii) 56 . (ii) 57 . (i)

    VI. Long Answer Type

    5 9 . Hint : Ratio of two extens ive proper ties is always int en sive

    Extensive= In tens ive

    Extensive.

    e.g., Mole fra ction =Mole s (Extens ive )

    =To ta l n u m b er of m o le s (Ext e ns ive )

    6 0. Na (s ) +1

    2Cl

    2(g) Na +(g) + Cl

    (g) ;

    latticeH

    V

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    8 4Exemplar Problems, Chemis t ry

    Bonn - Haber Cycle

    Steps to mea su re lattice ent ha lpy from Bonn - Haber cycle

    Sub lima tion of sodiu m metal

    (1 ) Na (s ) Na (g) ; s ub

    HV

    (2) Ionisa t ion of sodium a toms

    Na(g) Na +(g) + e(g) ; tH

    Vi.e. , ionisation en th alpy

    (3) Dissocia t ion of chlor ine m olecule

    1

    2Cl

    2(g) Cl(g) ;

    1

    2

    b o n dH

    Vi.e., On e-ha lf of bon d diss ociat ion

    enthalpy.

    (4 ) C l(g) + e(g) Cl(g) ; egHV i .e. , electron gain ent ha lpy.

    6 1 . STotal = Ssy s + Ssurr

    STotal

    = Ssy s

    +sys

    - H

    T

    TSTotal

    = TSsys

    Hsy s

    For spontan eou s chan ge, Stotal

    > 0

    T Ssy s

    Hsy s

    > 0

    (Hsy s

    T Ssy s

    ) > 0

    iH

    V

    Na(g) +1

    2 Cl2(g)

    NaCl(s)

    s ub

    HV

    Na(s) +1

    2Cl

    2(g)

    e gH

    V

    Na +(g) + Cl(g)

    lattice

    HV

    Na+(g) +

    1

    2Cl

    2(g)

    1

    2

    bondH

    V

    Na+

    (g) + Cl (g)

    fH

    V

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    8 5 Therm odynam ics

    But , Hsys

    T Ssy s

    = Gsys

    Gsy s

    > 0

    Gsys = Hsy s TSs y s < 0

    Hsys

    = Enth alpy cha n ge of a reaction.

    TSsys

    = Energy which is n ot available to do u sefu l work.

    Gsys

    = En ergy available for doing u seful work.

    Unit ofG is J oule

    The reaction will be sponta neous a t h igh temperatu re .

    62 .

    Fig . : 6 .9

    (i) Reversible Work is r epresented by the combined areas an d .(ii) Work aga ins t cons tan t pressu re,p

    fis represented by the a rea

    Wor k (i) > Wor k (ii)