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Part I FyANVC08 Ch 3, 4, 8.4, 9.2-5, 10.1-6 Vectors, Newton's laws, Torque, Pressure NV-College
Directions Please Write your name on all of the papers on your table, NOW!
Test time 8:10-10:40
Resources Calculators, and “Formulas for the National Test in Mathematics Courses A &
B”, and the formula sheet for Physics A, FYANV-College. You may also use
one page of your own formula sheet. The page must have your name and nocalculations or solution to any problem are supposed to be on the paper .
The test: The test consists of a total of 18 problems.
For the problems short answers are not enough. They require:
• that you write down what you do, that you explain your train of thought,
• that you, when necessary, draw figures.
• When you solve problems graphically/numerically please indicate how
you have used your resources.
Problem 17 and 18 are larger problems which may take up to 60 minutes to
solve completely. These problems are of the greatest importance for the
highest grade, MVG. It is important that you try to solve them. A description
of what I will consider when evaluating your work, is attached to the problem.Try all of the problems. It can be relatively easy, even towards the end of the
test, to receive some points for partial solutions. A positive evaluation can be
given even for unfinished solutions.
Score The maximum score is 87 points 4 o6f them VG points and 3¤ Problems.
mark levels The maximum number of points you can receive for each solution is indicated
after each problem. If a problem can give 2 “Pass”-points and 1 “Pass with
distinction”- point this is written (2/1). Some problems are marked with ¤ ,
which means that they more than other problems offer opportunities to show
knowledge that can be related to the criteria for Pass with Special Distinction inAssessment Criteria 2000.
Lower limit for the mark on the test
Pass (G): 29 points
Pass with distinction (VG) : 58 points of which at least 15 “Pass with
distinction points” (VG).
Pass with special distinction (MVG): 60 points of which at least 46 VG “Pass
with distinction points”. The requirements for Pass with distinction must be
well satisfied. Your teacher will also consider how well you solve the ¤- problems. Have Fun Behzad
Part I FyANVC08 Ch 3, 4, 8.4, 9.2-5, 10.1-6 Vectors, Newton's laws, Torque, Pressure NV-College
Base your answers to the questions 7 to 9 on the information and the diagram below. Note
that the VG-points are given to your explanations that give you the opportunity to
demonstrate the depth of your understandings of the physics of the problem. The
explanations must be written clearly in the space provided.
An object suspended from a dynamometer is lowered into a container filled with water.When the object is completely immersed into the water, volume of the water in the
container increases by 3.250 cm . The dynamometer’s reading on the air is N 805.21 .
You may need the following information:2 / 8.9 smg = , and density of water
Part I FyANVC08 Ch 3, 4, 8.4, 9.2-5, 10.1-6 Vectors, Newton's laws, Torque, Pressure NV-College
Base your answers to the questions 11 to 13 on the information and the diagram below.
Note that the VG-points are given to your explanations that give you the opportunity to
demonstrate the depth of your understandings of the physics of the problem. The
explanations must be written clearly in the space provided.
Maximilian stands on a digital bathroom scale in an elevator. The elevator does not haveany window and is in general very quiet and is very difficult without hearing the bell and
seeing the floor-number to know if it is moving or not. Maximilian has designed an
experiment which by using it, you can calculate not only the magnitude of the acceleration
of the elevator, but you can say if it is accelerating up or down.
Maximilian weights kg0.70 .
11. The scale reads kg0.80 .
a) The elevator accelerates upwards at the rate of 2 / 8.9 sma =
b) The elevator accelerates downwards at the rate of 2 / 8.9 sma =
c) The elevator accelerates upwards at the rate of 2 / 4.1 sma =
d) The elevator accelerates downwards at the rate of 2 / 4.1 sma =