Jee Main GTM Total Syllabus

Sri Chaitanya IIT Academy., India. AP, TELANGANA, KARNATAKA, TAMILNADU, MAHARASHTRA, DELHI, RANCHI

A right Choice for the Real Aspirant

ICON Central Office , Madhapur – Hyderabad

Sec: Sr.Icon All GTM Date: 24-04-2020

Time: 09.00am to 12.00 Jee Main Max.Marks:300

IMPORTANT INSTRUCTIONS:

Mathematics : Question No. 1 to 20 Consists Four (4) marks & Negative (-1), 21 to 25 No Negative Marks

Physics : Question No. 26 to 45 Consists Four (4) marks & Negative (-1), 46 to 50 No Negative Marks

Chemistry : Question No. 51 to 70 Consists Four (4) marks & Negative (-1), 71 to 75 No Negative Marks

Jee Main_GTM

Total Syllabus

Sec:Sr.Icon All Space for Rough Work 2

MATHS Max Marks: 100

(SINGLE CORRECT ANSWER TYPE) This section contains 20 multiple choice questions. Each question has 4 options (1), (2), (3) and (4) for its answer, out of which ONLY ONE option can be correct. Marking scheme: +4 for correct answer, 0 if not attempted and –1 in all other cases.

1i = -

12 cot 1

1

m

m i x xie

xi

- +æ ö=ç ÷

-è ø

1 3 1, ,

2 4 4

1

8

235

256

21

256

3

256

253

256


( )

5

11

sinsin log sin

sin cos

8 1log

15 2 2 4

n n

Kk

xx x

x x

f x n K K

p p

==

+

= P

æ öç ÷è ø

å ( )/2

0

f x dxp

ò

1log

2 2

p æ öç ÷è ø

8

15 4

p

l

4 2 3 2 4 5x y z and x y zl l l+ - = - + - = - l

2 3 4 0l l- - = 2 3 4 0l l+ - = 2 6 0l l- - = 2 6 0l l+ - =

( )1

10

12

log xy x

-= + +

[ 2,1)-

5,0

2

æ ö-ç ÷è ø

5,0

2

æ öç ÷è ø

5,0

3

æ öç ÷è ø

5,0

3

æ ö-ç ÷è ø

2 2 28 6 0x y x y n+ - - + = n IÎ


2 4y x=

1 1 1

4AP AQ+ <

1

3<

1

3> 2> 3>

iP 'iP

( ) ( )10

1 1

1

2560i ii

SP S P=

=å

1

5

2

5

3

5

4

5

, ,a b c1

. . .2

a b b c c a= = =

1

2

1

2 2

3

2

1

3

( )1, 0, 3-

2 2 6

2 3 6

x y z- + -= =

-

10 10 429sin cos cos 2

16x x x+ =

,4 8

nn I

p p+ Î ,

8n n I

pp + Î ,

8 4

nn I

p p+ Î ,

4n n I

pp + Î


4 6 8 121 2 1 4......... cos .....

3 9 3 9 2

x x x xSin x x

p- -æ ö æ ö- + - + - + - =ç ÷ ç ÷

è ø è ø| | 3O x£ <

( )p q rÞ Ú , ,p q r

20

1 cos 2lim

x xx

x

e e x®

-=

- +

( ) ( )2 2

f x f yx yf

++æ ö=ç ÷

è ø

3

a 5

3

a 7

3

a 2

3

a


(NUMERICAL VALUE TYPE)

This section contains 5 questions. Each question is numerical value type. For each question, enter the correct numerical value (in decimal notation, truncated/rounded-off to second decimal place. (e.g. 6.25, 7.00, �0.33, �.30, 30.27, �127.30). Marking scheme: +4 for correct answer, 0 if not attempted and 0 in all other cases.

( )

4 5

25

5 4

1

x xdx

x x

+

+ +ò ( )1f =

{ }9

0

x dxò { }x

( ){ }2, : 0 1, 0 1, 0 2x y y x y x x£ £ + £ £ + £ £

( )y f x=

( ) ( ) ( )2.sin 2 cos 1 sin ' 0f x x x x f x- + + = ( )0 0y =

( )/ 6f p =

3y x ax= + 2y bx c= + ( )1,0-

3a b c- + =


PHYSICS Max Marks: 100 (SINGLE CORRECT ANSWER TYPE)

This section contains 20 multiple choice questions. Each question has 4 options (1), (2), (3) and (4) for its answer, out of which ONLY ONE option can be correct. Marking scheme: +4 for correct answer, 0 if not attempted and –1 in all other cases.

9kg 9kg

50Hz 70Hz 100Hz 10Hz

2.0 , 32L H C Fm= = 10R = W

02480A

5110

17T-´ ( 111.7 10

e C

m kg= ´ )

2eV 4eV 1.5eV 4.5eV


1n

2n1

2

n

n

1

2m =

2kg1 2F N=

20N 4kg

dqr

r

L

m 2

L

m

2L

m 4

L

m


10W 3 23.5 10 m-´

( )0.4sin 50B tp= 0t =

10t ms=

70 cm 280 cm 140 cm 100 cm

28 38 10 m´ 25mm

0.02 /mm s 2 /mm s 0.2 /mm s 1 /mm s

276.3 10 /E Volt m= ´

195 10 T-´ 202.1 10 T´ 205 10 T-´ 192.1 10 T´

r

2gh

B

rB ghr

2B

gh

r gh

B

r

19 310 /m

4 mW 0.2 mW 2 mW 0.4 mW


3

2

F

MR

2

3

F

MR 2

F

MR

3

4

F

MR

$( )3 6F i j N= +$

4im$

( ) ( ) ( ) ( )0, 2 , 0, 2 , 4, 2 4, 2and- -

2

04

Q

p Î

2

0

11

4 5

Q

p

æ ö-ç ÷Î è ø

2

0

11

4 5

Q

p

æ ö+ç ÷Î è ø

2

0

11

4 5

Q

p

æ ö- -ç ÷Î è ø

2 4V t= - 2t s£

4 2V t= - 2t s> 0t =

4t s=

4m 6m 8m 12m

1K

2K

1K 2K

2 12K K= 1 22K K= 2 1K K= 1 24K K=


0X0

3

X

0

2

X

0100 C 075 C 050 C 025 C

( )1.5gm =

4W

R2W 4W

6V

4V10V

4W 3W 1W 2W


(NUMERICAL VALUE TYPE) This section contains 5 questions. Each question is numerical value type. For each question, enter the correct numerical value (in decimal notation, truncated/rounded-off to second decimal place. (e.g. 6.25, 7.00, �0.33, �.30, 30.27, �127.30). Marking scheme: +4 for correct answer, 0 if not attempted and 0 in all other cases.

2n =

1n = 74.8eV 3n = 2n =

100W

W

02000Al =

07000d A=

0.005r cm=

( )2/N m 2 3 37 10 10 /N

T and kg mm

r-æ ö= ´ =ç ÷

è ø

( )29.8 /g m s=


CHEMISTRY Max Marks: 100 (SINGLE CORRECT ANSWER TYPE)

This section contains 20 multiple choice questions. Each question has 4 options (1), (2), (3) and (4) for its answer, out of which ONLY ONE option can be correct. Marking scheme: +4 for correct answer, 0 if not attempted and –1 in all other cases.

Ketone

(A)

1.C2H5MgBr2.H2O

BH2SO4,heat

-H2OC

1.O3

2.Zn/H2O O

+ O

H

O O O O

CH2-C-NH2

C-O-CH3

O

O

(A)KOBr

;Product (A) is

O

O

O

O

O

NH


O

O

O

NH

Cl-C-OEt

O

PhMgBr(Excess)

H3O+ Product

Ph-C-Ph

Ph

OH

Ph-C-C l

O

Ph-C-Ph

O Ph-CH-Ph

OH

1SN

Br

(P)

Br

(Q) (R)

Ph

Br

P Q R> > P R Q> > R P Q> > R Q P> >


CH2O

Br

CH2O Br

CH2OBr

CH2O

Br

OH

Ni/3H2 A Cu BNH2OH

C DH+ OH-E

High temp & pressure


CH3

NO2

Br2

Fe

ASn /HCl B NaNO2+HC l C

H3PO2D E

KMnO4

OH -

CO2H

Br

CO2H

Br

CO2H

Br

CO2H

CO2H

CH2 - C = CH - CH2OH

C l CH3

5d 3d

4d 4d


( )2 24H O BrCo Bré ùë û ( )2 33

H O CC loé ùë û

( ) 22C O Br Bo X ré ùë û ( ) 22

C O Br Bo X ré ùë û

2

h

p

æ öç ÷è ø

22

h

p

æ öç ÷ç ÷è ø 2

h

p

æ öç ÷è ø

22

h

p

æ öç ÷è ø

23 2, ,CO CO CO-

23 2CO CO CO- < < 2

2 3CO CO CO-< <

23 2CO CO CO-< < 2

2 3CO CO CO -< <

( ) ( ) ( )2 2 33 2N g H g NH g+ ˆ †̂‡ˆ̂0500 C

pK52.88 10-´

cK

( )

5

2

2.88 10

0.082 500

-

-

´

´ ( )

5

2

1.44 10

8.314 773

-

-

´

´ ( )

5

2

1.44 10

0.082 773

-´

´ ( )

5

2

2.88 10

0.082 773

-

-

´

´


0.94M O

2M + 3M + 3M +

7.01% 12.76% 6.05% 5.08%

1M A-

1M B - 025 C B A C> >

( ) ( ) ( ) ( )2 3 3 3 3, , ,K CO I MgCO II CaCO III BeCO IV

I II III IV< < < IV II III I< < < IV II I III< < < II IV III I< < <

2PbO 3HNO

2NO 2O 2N 2N O

2H S

2Pb + Cu+ Ag + 2Sn +


(NUMERICAL VALUE TYPE) This section contains 5 questions. Each question is numerical value type. For each question, enter the correct numerical value (in decimal notation, truncated/rounded-off to second decimal place. (e.g. 6.25, 7.00, �0.33, �.30, 30.27, �127.30). Marking scheme: +4 for correct answer, 0 if not attempted and 0 in all other cases.

CH3 - C - C - CH3

Br

(A) NaNH2X (B) CH3 - I CH3 -C C - C C - CH3

Br

Br Br

________________A B+ =

O-CH3

CH2-O-CH3

Con HI (A) Mole HI is consumed

O-CH3

Con HI

( )B HI

_____________A B+ =

xG yH+ ®

3NH 030 C 1.gmL-

30 /vapH is kJ molD 1 175vapS is Jmol K- -D

Jee Main GTM Total Syllabus

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