Page 1
READ THE INSTRUCTIONS CAREFULLY
GENERAL :
1. This sealed booklet is your Question Paper. Do not break the seal till you are told
to do so.
2. Use the Optical Response sheet (ORS) provided separately for answering the questions.
3. Blank spaces are provided within this booklet for rough work.
4. Write your name, form number and sign in the space provided on the back cover of this
booklet.
5. After breaking the seal of the booklet, verify that the booklet contains 32 pages and that
all the 20 questions in each subject and along with the options are legible. If not, contact
the invigilator for replacement of the booklet.
6. You are allowed to take away the Question Paper at the end of the examination.
OPTICAL RESPONSE SHEET :
7. The ORS will be collected by the invigilator at the end of the examination.
8. Do not tamper with or mutilate the ORS. Do not use the ORS for rough work.
9. Write your name, form number and sign with pen in the space provided for this purpose on
the ORS. Do not write any of these details anywhere else on the ORS. Darken the
appropriate bubble under each digit of your form number.
DARKENING THE BUBBLES ON THE ORS :
10. Use a BLACK BALL POINT PEN to darken the bubbles on the ORS.
11. Darken the bubble COMPLETELY.
12. The correct way of darkening a bubble is as :
13. The ORS is machine-gradable. Ensure that the bubbles are darkened in the correct
way.
14. Darken the bubbles ONLY IF you are sure of the answer. There is NO WAY to erase
or "un-darken" a darkened bubble.
15. Take g = 10 m/s2 unless otherwise stated.
PAPER – 1
SCORE(ADVANCED)JEE (Main + Advanced) : LEADER & ENTHUSIAST COURSE
Paper Code : *1001CT102116075* (1001CT102116075)
CLASSROOM CONTACT PROGRAMME(Academic Session : 2016 - 2017)
Please see the last page of this booklet for rest of the instructions
Time : 3 Hours Maximum Marks : 180
EN
GL
ISH
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SEA
LS W
ITH
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T B
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ST
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CT
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O D
O S
O B
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HE
INV
IGIL
ATO
R
Test Type : FULL SYLLABUS Test Pattern : JEE-Advanced
TEST DATE : 26 - 04 - 2017
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*1001CT102116075* (1001CT102116075)
Space for Rough Work
SOME USEFUL CONSTANTS
Atomic No. H = 1, B = 5, C = 6, N = 7, O = 8, F = 9, Al = 13, P = 15, S = 16,
Cl = 17, Br = 35, Xe = 54, Ce = 58,
Atomic masses : H = 1, Li = 7, B = 11, C = 12, N = 14, O = 16, F = 19, Na = 23, Mg = 24,
Al = 27, P = 31, S = 32, Cl = 35.5, Ca=40, Fe = 56, Br = 80, I = 127,
Xe = 131, Ba=137, Ce = 140,
Boltzmann constant k = 1.38 × 10–23 JK–1
Coulomb's law constant
9
0
1= 9×10
4
Universal gravitational constant G = 6.67259 × 10–11 N–m2 kg–2
Speed of light in vacuum c = 3 × 108 ms–1
Stefan–Boltzmann constant = 5.67 × 10–8 Wm–2–K–4
Wien's displacement law constant b = 2.89 × 10–3 m–K
Permeability of vacuum µ0 = 4 × 10–7 NA–2
Permittivity of vacuum 0
= 2
0
1
c
Planck constant h = 6.63 × 10–34 J–s
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BEWARE OF NEGATIVE MARKING
HAVE CONTROL HAVE PATIENCE HAVE CONFIDENCE 100% SUCCESS
PART-1 : MATHEMATICS
SECTION–I : (Maximum Marks : 30)
This section contains TEN questions.
Each question has FOUR options (A), (B), (C) and (D). ONE OR MORE THAN ONE of
these four option(s) is (are) correct.
For each question, darken the bubble(s) corresponding to all the correct option(s) in the
ORS
For each question, marks will be awarded in one of the following categories :
Full Marks : +3 If only the bubble(s) corresponding to all the correct option(s) is (are)
darkened.
Zero Marks : 0 In all other cases.
1. If the lengths of each of the segments of a focal chord of the parabola y2 = 8x, which are
divided by the focus of the parabola, are integers then the length of the focal chord may
be
(A) 8 (B) 9 (C) 12 (D) 15
2. Each of the circles z 1 i 1 and z 1 i 1 touches internally a circle of radius 2 units.
The equation of the circle touching all the above three circles can be
(A) 3zz z z 1 0 (B) 3zz 7z 7z 15 0
(C) zz z z 3 0 (D) 3zz z z 1 0
3. Let ' S ' represents the complete set of values of the angle which satisfy the inequality:
cos3 + sin3 + (2sin2 – 3) (sin – cos) > 0, then a subset of ' S ' is
(A) 3
2n ,2n4 6
, n I (B) 2n ,2n
3 4
, n I
(C) 3
2n ,2n4 4
, n I (D)
3 52n ,2n
4 4
, n I
Space for Rough Work
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MAT
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*1001CT102116075* (1001CT102116075)
Space for Rough Work
4. Let 1 x
1 xg(x) t f '(t) dt
where f(x) does not behave like a constant function in any interval
(a, b) and the graph of y = f '(x) is symmetrical about the line x = 1 then
(A) g(x) is increasing x R (B) g(x) is increasing only for x > 1
(C) g'(x) is an even function (D) g'(x) is symmetrical about the line x = 2
5. Consider the function
2
x 1, x [0,1]
2xf (x) , x (1,2)
x
x 3x 3, x [2,3]
. Now choose the correct statement(s) :
({·} denotes fractional part function)
(A) The range of f(x) is [0, 3]
(B) Number of points where f(x) is not differentiable is 3
(C) f(x) is not differentiable at x = 2
(D) The range of f '(x) is [1, 4)
6. A cube root of i 1 , may be
(A) i (B) 3 i
2
(C)
3 i
2
(D)
i 3
2
7. Let ƒ be a real valued function and satisfies1 1
ƒ(x) ƒ(y) x, y R {0}x y
.
If
3 5
4
2
3(ƒ(x)) ƒ(x) 1 2dx log
1 (ƒ(x)) 2 3
, then
(A) (B) < 17
(C) 1 1tan sec5
(D) () is not a prime number
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Space for Rough Work
8. Three students A, B and C appear for IITJEE ADVANCED examination and their respective
probabilities of clearing the examination being 3 1
,10 2
and 2
5. Each student clearing or not
clearing the examination is independent of the other. If the probability of A passing the
examination be m
n (m, n N) given that only one of the student has cleared the examination,
then the least value of (m + n) is greater than
(A) 10 (B) 20 (C) 40 (D) 80
9. Let n
nk
k 0
2kf (n) C cos
n
and
n 1n 1
kk 0
2kg(n) C cos ,
n
then
(A) f(6) is a rational number (B) g(8) is an irrational number
(C) f(n) = 2g(n + 2) (D) f(n) = 2g(n)
10. A fair coin is tossed 10 times and the outcomes are listed. Let Hi be the event that the ith
outcome is a head and Am be the event that the list contains exactly m heads, then which
of the following pair(s) of events are independent :
(A) H4 and H
8(B) A
1 and A
9(C) H
3 and A
4(D) H
2 and A
5
SECTION –II : Matrix-Match Type & SECTION –III : Integer Value Correct Type
No question will be asked in section II and III
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MAT
HEM
ATIC
S
Target : JEE (Main + Advanced) 2017/26-04-2017/Paper-1
*1001CT102116075* (1001CT102116075)
SECTION–IV : (Maximum Marks : 30)
This section contains TEN questions.
The answer to each question is a SINGLE DIGIT INTEGER ranging from 0 to 9, both
inclusive.
For each question, darken the bubble corresponding to the correct integer in the ORS.
For each question, marks will be awarded in one of the following categories :
Full Marks : +3 If only the bubble corresponding to the correct answer is darkened.
Zero Marks : 0 In all other cases.
1. The value of 2 2
nlimsin 4(n!) 4(n!) 1
2
, (n N), is
2. Let M be the mid-point of the side AB of the equilateral triangle ABC having side length
2 units. P is a point on BC such that 'AP + PM ' is minimum. If the value of ' AP + PM ' is
b then the value of ' b ' is
3. Let 1 n
n 2012
0
xI dx
x 1
and 1 n
n 2013
0
xJ dx
x 1
, where n N. If matrix A = [aij]
3×3, where
2012 i i
ij
I I , i ja
0 , i j
and matrix B = [b
ij]
3×3, where
2016 j j 3
ij
J J , i jb
0 , i j
, then
1 11det(B ) 2trace(A )
10 is equal to
Space for Rough Work
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4. The radius of the inscribed circle of a triangle whose side-lengths are three consecutive
natural numbers, is 4 units. If the circumradius of the triangle is R, then the value of
8R
13
is
5. The value of 2 4
0
32 dx,
(1 x )
is
Space for Rough Work
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Space for Rough Work
6. Let the function g : R R be a differentiable function and satisfies x.g(0) + g(x) =
ex–1g'(1) +
2x
2 for all x R. The global minimum value of g(x) is equal to
[Note : e denotes Napier's constant]
7. The least possible integral value of ' a ' for which f(x) = 5sin2x – 2cos2x + 3ax – 4 is
increasing for all x R, is
8. Let ' n ' represents the number of Lattice points (x, y, z all being integers) inside the
tetrahedron (not on the surface) having vertices (0, 0, 0), (8, 0, 0), (0, 8, 0) and (0, 0, 8) then
the value of n
7
is
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9. If the equation in x, 2 22 2
1 1 2 1x x xcos sin (x 6x 8) sin (2k 1)
2 2 12 2 4
possesses solution, then number of integral values of k is equal to
10. A curve satisfying the differential equation (x2y2 – 1) dy + 2xy3dx = 0, is passing through
the points (1, 1) and (k, 2) then the value of (8k2) is
Space for Rough Work
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PHYS
ICS
Target : JEE (Main + Advanced) 2017/26-04-2017/Paper-1
*1001CT102116075* (1001CT102116075)
PART-2 : PHYSICS
SECTION–I : (Maximum Marks : 30)
This section contains TEN questions.
Each question has FOUR options (A), (B), (C) and (D). ONE OR MORE THAN ONE of these
four option(s) is (are) correct.
For each question, darken the bubble(s) corresponding to all the correct option(s) in the ORS
For each question, marks will be awarded in one of the following categories :
Full Marks : +3 If only the bubble(s) corresponding to all the correct option(s) is (are)
darkened.
Zero Marks : 0 In all other cases.
1. A semicircular wire of radius r is supported in its own vertical plane by a hinge at O and smooth
peg P as shown. If peg starts from O and moves with constant speed v along horizontal axisthrough O. The angular speed of wire is
O P
v
(A) 2 2 2
v
4r v t(B)
v
2r(C)
2 2
v
2r v t(D) None of these
Space for Rough Work
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Space for Rough Work
2. A small hole of area a is at the bottom of a container of area A. The liquid is filled up to height
h from base. As liquid comes out then A
a .3
h
(A) level of liquid in container falls at rate of gh
m/s4
(B) magnitude of acceleration of top surface of liquid is2g
m/s8
(C) acceleration of top surface of liquid is g
3 m/s
2
(D) None of these
3. A small solid ball of density is held inside at point A of a cubical container of side L, filled with
an ideal liquid of density 4 as shown. The container is closed at the top. Now, if the container
starts moving with constant acceleration a horizontally and the ball is released from point A,
simultaneously, then :-
P Q
A a
L
L2
L2
(A) For the ball to hit top of container at end Q, a = 3g
(B) For the ball to hit top of container at end Q, a = 2g
(C) Ball hits the top of container at end Q after a time L
t3g
(D) Ball hits the top of container at end Q after a time L
t2g
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PHYS
ICS
Target : JEE (Main + Advanced) 2017/26-04-2017/Paper-1
*1001CT102116075* (1001CT102116075)
Space for Rough Work
4. One end of a heavy uniform rod AB can slide along a rough horizontal rod CD to which it is
attached by a ring, B and C are joined by a string. If ABC is right angle and be the angle
between AB and vertical. What will be the coefficient of friction between ring and horizontal
rod ?
(system just in equilibrium)
DC
B
A
(A) tan (B) tan
2
(C) 2
tan
2 tan
(D) 2
tan 2
tan
5. In the circtuit shown , which of the following statement is/are CORRECT :
X =50C X =100L V=100 2 sin (377t)
R=100 X =100L
(A) Power factor of the circuit is 1
2
(B) Reactance of the circuit is equal to resistance of the circuit.
(C) Circuit is in a state of resonance
(D) Average power dissipated in the circuit is 100 W.
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6. A source of sound and an observer are located in space. The apparent frequency of sound received
by observer varies with time as shown in graph. Which of the following statements may be
TRUE :
vapp
t
(A) Only source is moving with constant velocity
(B) Only observer is moving with constant velocity
(C) Either source or observer or both are moving with constant velocity and their velocities are
always along the line joining source and observer
(D) When source and observer are moving with constant velocity and their velocities are not
directed along the line joining source and observer.7. A semi-circular disc rests in a vertical plane with its curved edge on rough horizontal and equally
rough vertical surface. The coefficient of friction is for both surfaces, then
B
A
(A) friction acts upwards at A and towards left at B
(B) for greatest value of (for no slipping) normal contact force at A is 2
w,
1
where w = weight
of disc
(C) greatest value of will be 2
1
2
3sin
4 1
(D) None of the above
Space for Rough Work
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PHYS
ICS
Target : JEE (Main + Advanced) 2017/26-04-2017/Paper-1
*1001CT102116075* (1001CT102116075)
8. Nucleus A decays to B with decay constant 1 and B decays to C with a decay constant
2.
Initially at t = 0 number of nuclei of A and B are 2 N0 and N
0 respectively. At t = t
0, number of
nuclie of B stops changing. If at this instant number of nuclei of B are 03N
2, then :-
(A) 1
0
1 2
1 4t n
3
(B)
10
2 2
1 4t n
3
(C) 0 2
A
1
3NN
2
at t = t0
(D) 0 2
A
1
2NN
3
at t = t0
9. A conducting ring is placed in a uniform external magnetic field present in the space within the
ring and perpendicular to plane of ring. The magnetic field changes at a constant rate due to
which a current of magnitude 4 amp flows in the ring. The resistance of parts PQR and PSR are
4 and 8 respectively. Then :-
× ××× ×
× ××
××
×
××
×
××
××
××
×
R
S Q
P
(A) The emf induced in the ring 48 V
(B) Potential difference between P & R is 24 V
(C) Potential difference between P & R is 8V
(D) Potential difference between P & R is zero as conservative electric field in the ring wire is
zero
Space for Rough Work
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10. ABCD is plane glass cube. A nearly horizontal beam of light enters the face AB at grazing
incidence. Then,
B
CD
A
(A) sin cot , where is critical angle
(B) Critical angle 45º , for TIR at second surface
(C) Refracting index 2 for TIR at second surface
(D) None of these
SECTION –II : Matrix-Match Type & SECTION –III : Integer Value Correct Type
No question will be asked in section II and III
Space for Rough Work
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PHYS
ICS
Target : JEE (Main + Advanced) 2017/26-04-2017/Paper-1
*1001CT102116075* (1001CT102116075)
SECTION–IV : (Maximum Marks : 30)
This section contains TEN questions.
The answer to each question is a SINGLE DIGIT INTEGER ranging from 0 to 9, both inclusive.
For each question, darken the bubble corresponding to the correct integer in the ORS.
For each question, marks will be awarded in one of the following categories :
Full Marks : +3 If only the bubble corresponding to the correct answer is darkened.
Zero Marks : 0 In all other cases.
1. The moment of inertia about x-axis of the solid spherical segment of mass M (see figure) is
253MR.
40XThe value of x is
Ox
R/2R/2
Space for Rough Work
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2. Figure shows a Meter bridge wire AC has uniform cross-section. The length of wire AC is
100 cm. X is a standard resistor of 4 and Y is a coil. When Y is immersed in melting ice the
null point is at 40 cm from point A. When the coil Y is heated to 100ºC, a 12 resistor has to
be connected in parallel with Y in order to keep the bridge balanced at the same point. The
temperature coefficient of resistance of the coil is 2x 10 SI units . Find the value of x.
lA C
G
D
x =4 Y
3. A steel bar of length L is held between rigid supports and heated non-uniformly in such a manner
that the temperature increase T at distance x from one end is given by T = T0x2/L
2 as shown
in the figure The average stress in the bar, (assume that modulus of elasticity for steel is E
and thermal expansion coefficient is ) is given as 0E T
.n
Find the value of n.
L
x
x
Temperature
T
Space for Rough Work
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PHYS
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*1001CT102116075* (1001CT102116075)
4. A ring of radius 9m is rolling on a horizontal rough surface with a velocity v0 = 2 m/s. A point ismarked X on the body of ring. Initially X is at the position shown. How soon (in second) speed ofX will become equal to v0. :-
C
X
v = 2 m/s0
5. A photoelectric plate is initially exposed to a spectrum of hydrogen gas excited to second energy
level. Later when the same photoelectric plate is exposed to a spectrum of some unknown hydrogen
like gas, excited to second energy level, it is found that the de-Broglie wavelength of the
photoelectrons now ejected has decreased 6.1 times. For this new gas difference of energies
of first Lyman line and series limit of Balmer series is found to be two times the ionization potential
of the hydrogen atom. find value of Z.
Space for Rough Work
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6. Two thin lens are arranged as shown in figure. The separation between them is 2f, where f is
focal length for each lens, x-coordinate of final image for 30º is Nf
.3
Find value of N.
=30° x
y
2f
90°
Space for Rough Work
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PHYS
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*1001CT102116075* (1001CT102116075)
7. A small ball of mass 1kg carrying charge 1C is dropped in a space having uniform horizontal
magnetic field B = 2T and uniform gravity g = 10 m/s2 in vertically downward direction. Maximum
displacement of ball in vertical direction is :-
8. The velocity of block m at an instant = 60° and v is equal to 18 m/s is (in m/s) :
v
m
Space for Rough Work
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9. A circular disc of a diameter d is slowly rotated in a liquid of large viscosity at a small distance
h from a fixed surface. An expression for torque necessary to maintain an angular
velocity4d
is .8hX
Find the value of X.
Liquid
Fixed surface
10. When the voltage applied to an X-ray tube is increased from 10 kV to 20 kV, the wavelength
interval between the K line and the short wave cut off of the continuous X-rays spectrum
increased by a factor 3. Find the atomic number of element of which the tube anode is made.
Fill second digit (tens) of your answer.
Space for Rough Work
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CHEM
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Target : JEE (Main + Advanced) 2017/26-04-2017/Paper-1
*1001CT102116075* (1001CT102116075)
PART-3 : CHEMISTRY
SECTION–I : (Maximum Marks : 30)
This section contains TEN questions.
Each question has FOUR options (A), (B), (C) and (D). ONE OR MORE THAN ONE of
these four option(s) is (are) correct.
For each question, darken the bubble(s) corresponding to all the correct option(s) in the
ORS
For each question, marks will be awarded in one of the following categories :
Full Marks : +3 If only the bubble(s) corresponding to all the correct option(s) is (are)
darkened.
Zero Marks : 0 In all other cases.
1. Select the correct statements
(A) [Fe(C2O
4)3]3– is optically active even though it has simple axis of rotation other than one
fold.
(B) In the complex ion, [Fe(CN)6]4–, the total number of valence electrons around Fe and
formal charge on Fe are respectively 18 & –4
(C) Fac and Mer geometrical isomerism is not possibe in [Co(en)3]3+ , where en is H
2N-CH
2CH
2-
NH2
(D) All of these
2. Select the correct statements :
(A) The density of copper matte is less than molten FeSiO3
(B) CO2(g) + C(s) 2CO(g) is an endothermic reaction
(C) In preparation of wrought iron from cast iron, main slag is FePO4, if limestone is added as
flux
(D) Impurites of S, P, C, Si bring brittleness and lowers the melting point of Fe
3. Al2O
3 can be obtained from which of the following reaction :-
(A) Al(OH)3
ignited (B) AlCl
36H
2O
heated strongly
in absence of dry HCl vapour
(C) Ammonium alum
(D) Bauxite dissolved in
NaOH
Space for Rough Work
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Space for Rough Work
4. Consider following reaction sequence
2CH COOH3
Ca(OH)2 X
organic compound(Y).
Which of the following statement(s) is/are correct about compound Y ?
(A) Compound Y can also be produced by ozonolysis of 2, 3-Dimethylbut-2-ene.
(B) Compound Y can undergo aldol condensation.
(C) Mesitylene is produced when compound Y reacts with conc.H2SO4.
(D) Compound Y forms only one type of oxime when reacts with NH2OH(at pH = 4.5).
5. Consider following reaction
OO
O
HO3+
X + Y (aromatic)Organic compounds
Which of the following statement(s) is/are correct?
(A) Both compounds X and Y are alcohol.
(B) Compound Y on oxidation can produce p-Benzoquinone.
(C) One of the formed product in above reaction can be used for the protection of carbonyl
group.
(D) Compound Y is having non zero dipole moment.
6. How many of the following compound(s) have more than four configurational isomers ?
(A) CH – CH = CH – CH – CHD – CH = CH – CH3 2 3
(B)
CH = CH – CH = CH2
Et
(C)
Et
CH CH2 3
Cl
(D) H – C C– CHD – CH = CCH – CH2 3
CHClBr
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*1001CT102116075* (1001CT102116075)
Space for Rough Work
7. In which of following reaction(s), compound
O
is produced?
(A)
OH
KMnO /H4
+
(B)
OH
MnO2 (C)
CH2
O3
Zn/H O2
(D) HIO4
OHOH
8. Which of the following statement are correct -
(A) If a body centred cubic lattice is made up of hollow sphere of B in which sphere of solid A
having radius half of B are present then ratio of total volume of spheres of B unoccupied
by A in a unit cell and volume of unit cell is 7 3 /64
(B) If distance between next to next nearest neighbour in FCC unit cell is 4.8 Å then distance
between corner to it's nearest tetrahedral void will be 1.7 Å. [ 1.5 1.2 , 3 1.7 ]
(C) If distance between two nearest parallel planes in graphite is 3.4Å then density of graphite
will be 1.37 gm/cc [ 3 1.7 ]
(D) In the configuration shown, the size of the smallest circle is 2
13
times the size of the
highest circles.
Page 25
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Space for Rough Work
9. The standard electrode potentials of some of the alkali metals are :-
Li+/Li = –3.05V Na+/Na = –2.71V K+/K = –2.93V
Alkali metals react with water according to the following reaction. (M = alkali metal)
2M +H2O 2MOH + H
2
It is found that Li reacts gently with water whereas potassium reacts violently with water.
Which of the following statement(s) is/are correct regarding the above two experimental
facts ?
(A) G values have nothing to do with the kinetics of a reaction
(B) The metal having large standard oxidation potential will have lesser reactivity
(C) K has a low melting point, and the heat of reaction is sufficient to make it melt or even
vaporize. This leads to exponential increase in its surface area
(D) The ionization potential of K is smaller than that of Li.
10. The following graph shown the variation in vapour pressure of a solution of two liquids X
and Y as a function of molar composition
X = 100%Y = 0%
X = 0%Y = 100%
Molarcomposition
Vapour pressure (mm of Hg)
It can be deduced that
(A) Hmixing
> 0
(B) The curve shows positive deviation from Raoult’s law
(C) Y has higher boiling point than X
(D) The two liquids could be ethanol and cyclohexane
SECTION –II : Matrix-Match Type & SECTION –III : Integer Value Correct Type
No question will be asked in section II and III
Page 26
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*1001CT102116075* (1001CT102116075)
Space for Rough Work
SECTION–IV : (Maximum Marks : 30)
This section contains TEN questions.
The answer to each question is a SINGLE DIGIT INTEGER ranging from 0 to 9, both
inclusive.
For each question, darken the bubble corresponding to the correct integer in the ORS.
For each question, marks will be awarded in one of the following categories :
Full Marks : +3 If only the bubble corresponding to the correct answer is darkened.
Zero Marks : 0 In all other cases.
1. Consider following compounds :
H2S, MnO
2, PbO
2, Pb
3O
4 , acidic sol. KMnO
4, NaClO, O
3, SO
2. How many of these can oxidize
HCl to Cl2 ?
2. Find the total number of sulphide ppt that dissolve in dil. HCl among the following
ZnS , Ag2S , CaS , CuS , FeS , HgS
3. Find the total number of species which are polar and optically active
XeF4, ClF
3, SO
2, S
2Cl
2 , H
2O
2 , BrF
5 , BI
3 , NF
3
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E-27/32*1001CT102116075* (1001CT102116075)
Space for Rough Work
4. Find the number of correct statement from the given
(i) Compound O can form stable hydrate.
(ii) Compounds
OH
&
OH
can be differentiated by NaOH + I2.
(iii) Compounds
OH
&
OCH3
can be differentiated by using cerric ammonium nitrate test.
(iv) Compounds Ph & Ph can be differentiated by using Bayers reagent.
(v) Compounds
OH
OH
&
OH
OH can be differentiated by using HIO4 followed by
treatment with AgNO3.
(vi) Compounds Cl & Cl can be differentiated by aqueous AgNO3.
(vii) Acetaldehyde and Benzaldehyde can be differentiated by Tollen’s test
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*1001CT102116075* (1001CT102116075)
Space for Rough Work
5. How many of the following compounds on hydrolysis produce glucose?
(i) Sucrose (ii) Lactose (iii) Maltose (iv) Ribose
(v) Starch (vi) Glycogen (vii) Cellulose
6. In how many of the following reactions correct product formed?
(i)
O14
14
OH
T > 100ºC (ii) CH Cl(excess)/Anhy.AlCl3 3
CH3
(iii) C–NH2
O
Br /KOH2
NH2 (iv) NO2 Sn/HCl
NH2
(v) CH Cl2
Mg/dry ether CH MgCl2
HOHO
(vi)
ClCl
ClCl
4Na/dry ether
Page 29
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E-29/32*1001CT102116075* (1001CT102116075)
7. Consider the galvanic cell (H0 = –247.25 kJ , S0 = –20 J/K ; Ksp
of AgCl = 1.8 × 10–10 , Kf of
Ag(NH3)2
+ = 1.7 ×107) that utilizes the following half reaction
Anode : Zn(s) + H2O(l) ZnO(s) + 2H+(aq) + 2e–
Cathode : 2Ag+(aq.) + 2e– 2Ag(s)
If ionic product of AgCl in a solution prepared by mixing 50 ml of 0.1 M AgNO3 and 50 ml of
4M NH3 and adding 10 ml of 0.22M NaCl solution in cathodic compartment is x × 10–y and
standard emf of cell is z then calcualte value of y- 4z.
8. A salt BCl is dissolved in water having concentration 5000 ppm which depresses the freezing
point of the aqueous solution by 0.155K. If distance of next nearest neighbour for Cl– is x pm
then calculate value of x
200 2.
Given that BCl forms NaCl type crystal and density of BCl crystal is 1.25 gm/cc. Degree of
dissociation of BCl is 60% and density of water is 1gm/ ml
Space for Rough Work
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*1001CT102116075* (1001CT102116075)
9. 'n' factor of PCl5 when it reacts with NaOH is x
'n' factor of SO2Cl
2 when it reacts with KOH is y
'n' factor of H2C
2O
4.2NaHC
2O
4.2K
2C
2O
4.3Al
2(C
2O
4)
3.4FeC
2O
4.5SnC
2O
4
when it reacts with KMnO4 is Z, then calculate value of
1(Z X.Y)
4
10. pH of 0.1M NH4Cl solution (K
b = 1× 10–5).
Space for Rough Work
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E-31/32*1001CT102116075* (1001CT102116075)
Space for Rough Work
Page 32
Target : JEE (Main + Advanced) 2017/26-04-2017/Paper-1
Corporate Office : CAREER INSTITUTE, “SANKALP”, CP-6, Indra Vihar, Kota (Rajasthan)-324005
+91-744-5156100 [email protected] www.allen.ac.in
QUESTION PAPER FORMAT AND MARKING SCHEME :
16. The question paper has three parts : Mathematics, Physics and Chemistry.
17. Each part has two sections as detailed in the following table.
I have read all the instructions
and shall abide by them.
____________________________
Signature of the Candidate
I have verified the identity, name and Formnumber of the candidate, and that questionpaper and ORS codes are the same.
____________________________
Signature of the invigilator
NAME OF THE CANDIDATE ................................................................................................
FORM NO. .............................................
Que. No. Category-wise Marks for Each Question Maximum
Section Type of Full Partial Zero Negative Marks of theQue. Marks Marks Marks Marks section
+3 0One or more If only the bubble(s) In all
I correct10
corresponding—
other— 30option(s) to all the correct cases
option(s) is(are)darkened
+3 0Single digit If only the bubble In all
IV Integer 10 corresponding — other — 30(0-9) to correct answer cases
is darkened
Your Target is to secure Good Rank in JEE 2017 *1001CT102116075* (1001CT102116075)E-32/32
Page 33
1.
2. (ORS)
3.
4.
5. 32 20
6.
7.
8.
9.
:
10.
11.
12. :
13.
14.
15. g = 10 m/s2
PAPER – 1
SCORE(ADVANCED)
JEE (Main + Advanced) : LEADER & ENTHUSIAST COURSE
Paper Code : *1001CT102116075* (1001CT102116075)
CLASSROOM CONTACT PROGRAMME(Academic Session : 2016 - 2017)
Time : 3 Hours Maximum Marks : 180
HIN
DI
Test Type : FULL SYLLABUS Test Pattern : JEE-Advanced
TEST DATE : 26 - 04 - 2017
Page 34
Target : JEE (Main + Advanced) 2017/26-04-2017/Paper-1
SOME USEFUL CONSTANTS
Atomic No. H = 1, B = 5, C = 6, N = 7, O = 8, F = 9, Al = 13, P = 15, S = 16,
Cl = 17, Br = 35, Xe = 54, Ce = 58,
Atomic masses : H = 1, Li = 7, B = 11, C = 12, N = 14, O = 16, F = 19, Na = 23, Mg = 24,
Al = 27, P = 31, S = 32, Cl = 35.5, Ca=40, Fe = 56, Br = 80, I = 127,
Xe = 131, Ba=137, Ce = 140,
Boltzmann constant k = 1.38 × 10–23 JK–1
Coulomb's law constant
9
0
1= 9×10
4
Universal gravitational constant G = 6.67259 × 10–11 N–m2 kg–2
Speed of light in vacuum c = 3 × 108 ms–1
Stefan–Boltzmann constant = 5.67 × 10–8 Wm–2–K–4
Wien's displacement law constant b = 2.89 × 10–3 m–K
Permeability of vacuum µ0 = 4 × 10–7 NA–2
Permittivity of vacuum 0 =
20
1
c
Planck constant h = 6.63 × 10–34 J–s
H-2/32 *1001CT102116075* (1001CT102116075)
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H-3/32*1001CT102116075* (1001CT102116075)
BEWARE OF NEGATIVE MARKING
HAVE CONTROL HAVE PATIENCE HAVE CONFIDENCE 100% SUCCESS
-1 : –I : ( : 30)
(A), (B), (C) (D)
: +3
: 0
1. y2 = 8x
(A) 8 (B) 9 (C) 12 (D) 15
2. z 1 i 1 z 1 i 1 2
(A) 3zz z z 1 0 (B) 3zz 7z 7z 15 0
(C) zz z z 3 0 (D) 3zz z z 1 0
3. ' S ',
cos3 + sin3 + (2sin2 – 3) (sin – cos) > 0 ' S '
(A) 3
2n ,2n4 6
, n I (B) 2n ,2n
3 4
, n I
(C) 3
2n ,2n4 4
, n I (D)
3 52n ,2n
4 4
, n I
Page 36
H-4/32
MAT
HEM
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S
Target : JEE (Main + Advanced) 2017/26-04-2017/Paper-1
*1001CT102116075* (1001CT102116075)
4. 1 x
1 xg(x) t f '(t) dt
f(x) (a, b)
y = f '(x) x = 1
(A) x R g(x) (B) x > 1 g(x)
(C) g'(x) (D) g'(x), x = 2
5.
2
x 1, x [0,1]
2xf (x) , x (1,2)
x
x 3x 3, x [2,3]
({·} )
(A) f(x) [0, 3]
(B) f(x) 3
(C) f(x), x = 2
(D) f '(x) [1, 4)
6. i 1
(A) i (B) 3 i
2
(C)
3 i
2
(D)
i 3
2
7. ƒ 1 1ƒ(x) ƒ(y) x, y R {0}
x y
3 5
4
2
3(ƒ(x)) ƒ(x) 1 2dx log
1 (ƒ(x)) 2 3
(A) (B) < 17
(C) 1 1tan sec5
(D) ()
Page 37
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ATIC
S
H-5/32*1001CT102116075* (1001CT102116075)
8. IITJEE ADVANCED A, B C
3 1
,10 2
2
5 A
m
n (m, n N) (m + n)
(A) 10 (B) 20 (C) 40 (D) 80
9. n
nk
k 0
2kf (n) C cos
n
n 1n 1
kk 0
2kg(n) C cos
n
(A) f(6) (B) g(8)
(C) f(n) = 2g(n + 2) (D) f(n) = 2g(n)
10. 10 Hi
i Am m
(A) H4 H
8(B) A
1 A
9(C) H
3 A
4(D) H
2 A
5
–II : & –III :
II III
Page 38
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MAT
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S
Target : JEE (Main + Advanced) 2017/26-04-2017/Paper-1
*1001CT102116075* (1001CT102116075)
–IV : ( : 30)
0 9
: +3
: 0
1.2 2
nlimsin 4(n!) 4(n!) 1
2
, (n N)
2. M, ABC AB 2 P
BC 'AP + PM ' 'AP + PM ' b 'b'
3. 1 n
n 2012
0
xI dx
x 1
1 n
n 2013
0
xJ dx
x 1
n N A = [aij]
3×3
2012 i i
ij
I I , i ja
0 , i j
B = [b
ij]
3×3, 2016 j j 3
ij
J J , i jb
0 , i j
1 11det(B ) 2trace(A )
10
Page 39
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H-7/32*1001CT102116075* (1001CT102116075)
4. 4
R 8R
13
5. 2 4
0
32 dx
(1 x )
Page 40
H-8/32
MAT
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Target : JEE (Main + Advanced) 2017/26-04-2017/Paper-1
*1001CT102116075* (1001CT102116075)
6. g : R R x R x.g(0) + g(x) = ex–1g'(1) +2x
2
g(x)
[ : e ]
7. ' a ' f(x) = 5sin2x – 2cos2x + 3ax – 4, x R
8. ' n ' (x, y, z )
(0, 0, 0), (8, 0, 0), (0, 8, 0) (0, 0, 8) n
7
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S
H-9/32*1001CT102116075* (1001CT102116075)
9. x 2 22 2
1 1 2 1x x xcos sin (x 6x 8) sin (2k 1)
2 2 12 2 4
k
10. (x2y2 – 1) dy + 2xy3dx = 0 (1, 1) (k, 2)
(8k2)
Page 42
H-10/32
PHYS
ICS
Target : JEE (Main + Advanced) 2017/26-04-2017/Paper-1
*1001CT102116075* (1001CT102116075)
-2 : –I : ( : 30)
(A), (B), (C) (D)
: +3
: 0
1. r O P OO v
O P
v
(A) 2 2 2
v
4r v t(B)
v
2r(C) 2 2
v
2r v t(D)
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Leader & Enthusiast Course/Score(Advanced)/26-04-2017/Paper-1
PHYS
ICS
H-11/32*1001CT102116075* (1001CT102116075)
2. A a h
A
a .3
h
(A) gh
m/s4
(B) 2gm/s
8
(C) g
3 m/s2 (D)
3. L 4
A a
A :-
P Q
A a
L
L2
L2
(A) Q a = 3g
(B) Q a = 2g
(C) Q L
t3g
(D) Q L
t2g
Page 44
H-12/32
PHYS
ICS
Target : JEE (Main + Advanced) 2017/26-04-2017/Paper-1
*1001CT102116075* (1001CT102116075)
4. AB CD B C ABC , AB ( )
DC
B
A
(A) tan (B) tan
2
(C) 2
tan
2 tan
(D) 2
tan 2
tan
5.
X =50C X =100L V=100 2 sin (377t)
R=100 X =100L
(A) 1
2 (B)
(C) (D) 100 W
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ICS
H-13/32*1001CT102116075* (1001CT102116075)
6.
vapp
t
(A)
(B)
(C)
(D)
7.
B
A
(A) A B
(B) () A 2
w
1
w =
(C) 2
1
2
3sin
4 1
(D)
Page 46
H-14/32
PHYS
ICS
Target : JEE (Main + Advanced) 2017/26-04-2017/Paper-1
*1001CT102116075* (1001CT102116075)
8. A B 1 B C
2
t = 0 A B 2 N0 N
0 t = t
0 B
B 03N
2
(A) 10
1 2
1 4t n
3
(B)
10
2 2
1 4t n
3
(C) t = t0 0 2
A
1
3NN
2
(D) t = t
0 0 2
A
1
2NN
3
9.
4
PQR PSR 4 8
× ××× ×
× ××
××
×
××
×
××
××
××
×
R
S Q
P
(A) 48 V
(B) P R 24 V
(C) P R 8 V
(D) P R
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PHYS
ICS
H-15/32*1001CT102116075* (1001CT102116075)
10. ABCD AB
B
CD
A
(A) sin cot
(B) 45º
(C) 2
(D)
–II : & –III :
II III
Page 48
H-16/32
PHYS
ICS
Target : JEE (Main + Advanced) 2017/26-04-2017/Paper-1
*1001CT102116075* (1001CT102116075)
–IV : ( : 30)
0 9
: +3
: 0
1. M x- 253MR
40X x
Ox
R/2R/2
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ICS
H-17/32*1001CT102116075* (1001CT102116075)
2. AC 100 cm X
4 Y Y
A 40 cm Y 100ºC
12 Y
2x 10 SI x
lA C
G
D
x =4 Y
3. L
x T = T0x2/L2
E 0E T
n
n
L
x
x
Temperature
T
Page 50
H-18/32
PHYS
ICS
Target : JEE (Main + Advanced) 2017/26-04-2017/Paper-1
*1001CT102116075* (1001CT102116075)
4. 9m v0 = 2 m/s X X X v0 :-
C
X
v = 2 m/s0
5.
6.1
Z
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PHYS
ICS
H-19/32*1001CT102116075* (1001CT102116075)
6. 2f f
gSA ;fn 30º x Nf
3 N
=30° x
y
2f
90°
Page 52
H-20/32
PHYS
ICS
Target : JEE (Main + Advanced) 2017/26-04-2017/Paper-1
*1001CT102116075* (1001CT102116075)
7. 1kg 1C
B = 2T g = 10 m/s2
8. v 18 m/s = 60° m (m/s ) :
v
m
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ICS
H-21/32*1001CT102116075* (1001CT102116075)
9. d h
djk;k tkrk gSA dks.kh; osx 4d
8hX
X
Liquid
Fixed surface
10. X- 10 kV 20 kV X-
K
Page 54
H-22/32
CHEM
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Target : JEE (Main + Advanced) 2017/26-04-2017/Paper-1
*1001CT102116075* (1001CT102116075)
-3 : –I : ( : 30)
(A), (B), (C) (D)
: +3
: 0
1.
(A) [Fe(C2O
4)
3]3–
(B) [Fe(CN)6]4– Fe Fe
18 –4
(C) [Co(en)3]3+ (Fac) (Mer) en, H
2N-CH
2CH
2-NH
2
(D)
2.
(A) FeSiO3
(B) CO2(g) + C(s) 2CO(g)
(C) FePO4
(D) S, P, C, Si Fe Fe
3. Al2O
3 :-
(A) Al(OH)3
(B) AlCl36H
2O
HCl
(C)
(D) NaOH
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H-23/32*1001CT102116075* (1001CT102116075)
4.
2CH COOH3
Ca(OH)2 X (Y).
Y
(A) Y 2, 3--2-
(B) Y
(C) Y H2SO4
(D) Y, NH2OH(pH = 4.5 )
5.
OO
O
HO3+
X + Y ( )
(A) X Y,
(B) Y, p-
(C) (Protection)
(D) Y
6.
(A) CH – CH = CH – CH – CHD – CH = CH – CH3 2 3(B)
CH = CH – CH = CH2
Et
(C)
Et
CH CH2 3
Cl
(D) H – C C– CHD – CH = CCH – CH2 3
CHClBr
Page 56
H-24/32
CHEM
ISTR
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Target : JEE (Main + Advanced) 2017/26-04-2017/Paper-1
*1001CT102116075* (1001CT102116075)
7.
O
(A)
OH
KMnO /H4
+
(B)
OH
MnO2 (C)
CH2
O3
Zn/H O2
(D) HIO4
OHOH
8.
(A) B B
A A B
7 3 /64
(B) FCC 4.8 Å
1.7 Å. [ 1.5 1.2 , 3 1.7 ]
(C) 3.4Å 1.37 gm/cc [ 3 1.7 ]
(D) 2
13
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Y
H-25/32*1001CT102116075* (1001CT102116075)
9.
Li+/Li = –3.05V Na+/Na = –2.71V K+/K = –2.93V
(M = )
2M +H2O 2MOH + H
2
Li (gently)
(A) G
(B)
(C) K
(exponential)
(D) Li K
10. X Y
X = 100%Y = 0%
X = 0%Y = 100%
Molarcomposition
Vapour pressure (mm of Hg)
(A) Hmixing
> 0
(B)
(C) X Y
(D)
–II : & –III :
II III
Page 58
H-26/32
CHEM
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*1001CT102116075* (1001CT102116075)
–IV : ( : 30)
0 9
: +3
: 0
1.
H2S, MnO
2, PbO
2, Pb
3O
4, KMnO
4, NaClO, O
3, SO
2. HCl Cl
2
2. HCl :
ZnS , Ag2S , CaS , CuS , FeS , HgS
3.
XeF4, ClF
3, SO
2, S
2Cl
2 , H
2O
2 , BrF
5 , BI
3 , NF
3
Page 59
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ISTR
Y
H-27/32*1001CT102116075* (1001CT102116075)
4.
(i) O
(ii) OH
OH
NaOH + I2
(iii) OH
OCH3
(iv) Ph Ph
(v)
OH
OH
OH
OH HIO4 AgNO3
(vi) Cl Cl AgNO3
(vii)
Page 60
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CHEM
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Target : JEE (Main + Advanced) 2017/26-04-2017/Paper-1
*1001CT102116075* (1001CT102116075)
5.
(i) (ii) (iii) (iv)
(v) (vi) (vii)
6.
(i)
O14
14
OH
T > 100ºC (ii) CH Cl(excess)/Anhy.AlCl3 3
CH3
(iii) C–NH2
O
Br /KOH2
NH2
(iv) NO2 Sn/HCl
NH2
(v) CH Cl2
Mg/dry ether CH MgCl2
HOHO
(vi) Cl
Cl
ClCl
4Na/dry ether
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CHEM
ISTR
Y
H-29/32*1001CT102116075* (1001CT102116075)
7. (H0 = –247.25 kJ , S0 = –20 J/K
AgCl Ksp = 1.8 × 10–10 , Ag(NH3)
2
+ Kf = 1.7 ×107) :
Zn(s) + H2O(l) ZnO(s) + 2H+(aq) + 2e–
: 2Ag+(aq.) + 2e– 2Ag(s)
50 ml 0.1 M AgNO3 50 ml 4M NH
3 10 ml of 0.22M NaCl
AgCl x × 10–y emf z
y- 4z
8. BCl 5000 ppm 0.155K
Cl– xÅ x
200 2
BCl NaCl BCl 1.25 gm/cc BCl
60% 1gm/ ml
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H-30/32
CHEM
ISTR
Y
Target : JEE (Main + Advanced) 2017/26-04-2017/Paper-1
*1001CT102116075* (1001CT102116075)
9. PCl5 NaOH 'n' x
SO2Cl
2 KOH 'n' y
H2C
2O
4.2NaHC
2O
4.2K
2C
2O
4.3Al
2(C
2O
4)
3.4FeC
2O
4.5SnC
2O
4 KMnO
4 'n'
Z 1(Z X.Y)
4
10. 0.1M NH4Cl (K
b = 1× 10–5) pH
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H-31/32*1001CT102116075* (1001CT102116075)
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Target : JEE (Main + Advanced) 2017/26-04-2017/Paper-1
16. 17.
____________________________
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+3 0
I 10 — — 30
+3 0
IV (0-9)
10 — — 30
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