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DICKY DERMAWAN www.dickydermawan.net78.net [email protected] ITK-233 Termodinamika Teknik Kimia I 3 SKS 5 – Relations among Thermodynamic Properties & Properties Diagrams
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ITK-233 Termodinamika Teknik Kimia I

Feb 06, 2016

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ITK-233 Termodinamika Teknik Kimia I. Dicky Dermawan www.dickydermawan.net78.net [email protected]. 3 sks. 5 – Relations among Thermodynamic Properties & Properties Diagrams. State Principle. The only measurable property is P, T & V How we can find U, H, S, … from this? - PowerPoint PPT Presentation
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Page 1: ITK-233 Termodinamika Teknik Kimia I

DICKY DERMAWANwww.dickydermawan.net78 .net

d ickydermawan@gmai l .com

ITK-233Termodinamika Teknik

Kimia I

3 SKS

5 – Relations among Thermodynamic Properties & Properties Diagrams

Page 2: ITK-233 Termodinamika Teknik Kimia I

State Principle

The only measurable property is P, T & VHow we can find U, H, S, … from this?

We already have:

.....)orT&SorV&PorV&TorP&T(f)propertyAny( ncompositiophase

PT

V

V

1

TP

V

V

1

VV T

UC

P

P T

HC

Page 3: ITK-233 Termodinamika Teknik Kimia I

Fundamental Relations

TSHG

TSUA

PVUH

U

dPVdTSdG

dVPdTSdA

dPVdSTdH

dVPdSTdU

)P,T(GG

)V,T(AA

)P,S(HH

)V,S(UU

Page 4: ITK-233 Termodinamika Teknik Kimia I

Mathematical Formulation (1)

yx

2

yxxy

x

y

x

N

y

M

yx

z

y

z

xx

z

y

y

zN

x

zM

dyNdxMdz

)y,x(zz

Page 5: ITK-233 Termodinamika Teknik Kimia I

Mathematical Formulation (2)

dzz

ydx

x

ydy)z,x(yy

dzz

xdy

y

xdx)z,y(xx

)y,x(zz)z,x(yy)z,y(xx)z,y,x(ff

xz

yz

Elimination of the differential dy gives:

0dzz

x

z

y

y

xdx1

x

y

y

x

yxzzz

Since dx and dz are independent, the coefficient of dx and dz must be zero, thus:

z

z

xy1

y

x

x

z

y

yz

yx

z

x

and:

Page 6: ITK-233 Termodinamika Teknik Kimia I

Fundamental Relations

dPVdTSdG

dVPdTSdA

dPVdSTdH

dVPdSTdU

...

...

...

PV

U&T

S

U

SV

Page 7: ITK-233 Termodinamika Teknik Kimia I

Fundamental Properties & Maxwell Relations

dPVdTSdG

dVPdTSdA

dPVdSTdH

dVPdSTdU

...

...

....

S

P

V

T

VS

Page 8: ITK-233 Termodinamika Teknik Kimia I

Example H=H(T,P)

a. How does enthalpy affected by temperature and pressure?

b. Prove that c. Use the result of (a) to prove that enthalpy of ideal

gas is affected only by temperature.

d. State H=H(T,P) for virial gas:

e. State H=H(T,P) for real gas:

dPV)T1(dTCdH P

...P'DP'CP'B1(RTPV 32

RT

PVZ

Page 9: ITK-233 Termodinamika Teknik Kimia I

Example: S=S(T,P)

a. How does entropy affected by temperature and pressure?

b. Prove that

c. Show that for ideal gas 1

2

T

T

P

P

PlnRdT

T

CS

2

1

dPVdTT

CdS P

Page 10: ITK-233 Termodinamika Teknik Kimia I

Example: U=U(T,V)

a. How does internal energy affected by temperature and volume?

b. Express the results of (a) in term of β and κ

c. Use the result of (a) to prove that internal energy of ideal gas is not affected by pressure

Page 11: ITK-233 Termodinamika Teknik Kimia I

Example: S=S(T,V)

a. How does entropy affected by temperature and volume?

b. Express the results of (a) in term of β and κ

c. Show that for ideal gas with constant Cv:

1

2

1

2v V

VlnR

T

TlnCS

Page 12: ITK-233 Termodinamika Teknik Kimia I

Gibbs Energy as Generating Function

a. Prove that

b. c.

d.

TP

)RT/G(

RT

V

PT

)RT/G(T

RT

H

RT

G

RT

H

R

S

RT

PV

RT

H

RT

U

Page 13: ITK-233 Termodinamika Teknik Kimia I

Cp, Cv & Pressure Effect

The Joule-Thomson coefficient: is important in refrigeration engineering. Show that it can be calculated using:

Prove that:

Prove that:

P

2

2

T

P

T

VT

P

C

PVVP T

V

T

PTCC

HP

T

PPH T

VTV

C

1

P

T

Page 14: ITK-233 Termodinamika Teknik Kimia I

Example: U = U(T,P)

a. Prove that

b. Prove that the internal energy of ideal gas is not affected by pressure

c. Prove that

V)TP(P

U

T

V)PT(CT

UV

P

Page 15: ITK-233 Termodinamika Teknik Kimia I

Thermodynamic Property Diagrams

Represents properties: P, V, T, H & S of a substance on a single plot.

The most common:T/S DiagramP/H DiagramH/S (Mollier diagram)

Page 16: ITK-233 Termodinamika Teknik Kimia I

T – S Diagram of Air

Page 17: ITK-233 Termodinamika Teknik Kimia I

T – S Diagram of CO

Page 18: ITK-233 Termodinamika Teknik Kimia I

T – S Diagram of CO2

Page 19: ITK-233 Termodinamika Teknik Kimia I

P-H Diagram of Ammonia

Page 20: ITK-233 Termodinamika Teknik Kimia I

P-H Diagram of

Chlorine

Page 21: ITK-233 Termodinamika Teknik Kimia I

H/S (Mollier Diagram) for NO

Page 22: ITK-233 Termodinamika Teknik Kimia I

H/S (Mollier Diagram) for Water

Page 23: ITK-233 Termodinamika Teknik Kimia I

Example 6.6

a. Superheated steam originally at 150 psia & 500 oF expands through a nozzle to an exhaust pressure of 50 psia. Assuming the process is reversible & adiabatic, determine the downstream state of the steam and ΔH.

b. Repeat problem (a) if the process is irreversible with thermodynamic efficiency of 88%.