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Introduction to Nanomechanics (Fall 2010) Martino Poggio
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Introduction to Nanomechanics (Fall 2010)

Jan 01, 2016

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Introduction to Nanomechanics (Fall 2010). Martino Poggio. Equipartition Theorem. 05.10.2009. Introduction to Nanomechanics. L = 2 m w = 100 mm t = 50 mm E SS = 200 GPa. k = 78 k N / m. x rms = 0.2 pm for T = 300 K. 05.10.2009. L = 150 m m w = 40 m m t = 5 m m - PowerPoint PPT Presentation
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Page 1: Introduction to  Nanomechanics (Fall  2010)

Introduction to Nanomechanics(Fall 2010)

Martino Poggio

Page 2: Introduction to  Nanomechanics (Fall  2010)

Introduction to Nanomechanics 2

Equipartition Theorem

05.10.2009 Introduction to Nanomechanics

22

2

1

2

1

2

1xkxmTkB

Tk

kx B2

Tk

kxx B

rms 2

Page 3: Introduction to  Nanomechanics (Fall  2010)

Introduction to Nanomechanics 3

L = 2 mw = 100 mmt = 50 mmESS = 200 GPa

3

3

4L

Ewtk

k = 78 k /N m

Tk

kxx B

rms 2

xrms = 0.2 pm

for T = 300 K

05.10.2009

Page 4: Introduction to  Nanomechanics (Fall  2010)

Introduction to Nanomechanics 4

L = 150 mmw = 40 mmt = 5 mmESi = 169 GPa

3

3

4L

Ewtk

k = 63 /N m

Tk

kxx B

rms 2

xrms = 8 pm

for T = 300 K

05.10.2009

Page 5: Introduction to  Nanomechanics (Fall  2010)

Introduction to Nanomechanics 5

L = 120 mmw = 3 mmt = 100 nmESi = 169 GPa

3

3

4L

Ewtk

k = 73 /mN m

Tk

kxx B

rms 2

xrms = 8 nm

for T = 300 K

05.10.2009

Page 6: Introduction to  Nanomechanics (Fall  2010)

Introduction to Nanomechanics 6

L = 120 mmw = 3 mmt = 100 nmESi = 169 GPa

3

3

4L

Ewtk

k = 73 /mN m

Tk

kxx B

rms 2

xrms = 9 Å

for T = 4.2 K

05.10.2009

Page 7: Introduction to  Nanomechanics (Fall  2010)

Introduction to Nanomechanics 7

3500 3750 4000 4250

1E-5

1E-4

1E-3

0.01

0.1

1

10

100

1000

An

g2 /Hz

Frequency (Hz)

3500 3750 4000

Frequency (Hz)

4250

1000

100

10

1

0.1

0.01

1E-3

1E-4

1E-5

Spre

ctra

l den

sity

(Å2 /

Hz)

05.10.2009