IMM - DTU 02405 Probability 2006-9-19 BFN/bfn A special case of a problem, which we will treat in full generality later. Question a) count the possibilitites
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IMM - DTU 02405 Probability
2006-9-19BFN/bfn
A special case of a problem, which we will treat in full generality later.
Question a) count the possibilitites
4 out of 36, 19
Question b) count the possibilitites 9 out of 36, 14
Question c) From a) and b) 14− 1
9= 5
36
Question d) b) in general x2
36c) in general 2x−1
36
Question e) The sum is over all possible outcomes, and should thus be 1.Inserting x = 6 we get 62
36= 1 q.e.d.
IMM - DTU 02405 Probability
2006-9-19BFN/bfn
A special case of a problem, which we will treat in full generality later.
Question a) count the possibilitites 4
out of 36, 19
Question b) count the possibilitites 9 out of 36, 14
Question c) From a) and b) 14− 1
9= 5
36
Question d) b) in general x2
36c) in general 2x−1
36
Question e) The sum is over all possible outcomes, and should thus be 1.Inserting x = 6 we get 62
36= 1 q.e.d.
IMM - DTU 02405 Probability
2006-9-19BFN/bfn
A special case of a problem, which we will treat in full generality later.
Question a) count the possibilitites 4 out of
36, 19
Question b) count the possibilitites 9 out of 36, 14
Question c) From a) and b) 14− 1
9= 5
36
Question d) b) in general x2
36c) in general 2x−1
36
Question e) The sum is over all possible outcomes, and should thus be 1.Inserting x = 6 we get 62
36= 1 q.e.d.
IMM - DTU 02405 Probability
2006-9-19BFN/bfn
A special case of a problem, which we will treat in full generality later.
Question a) count the possibilitites 4 out of 36,
19
Question b) count the possibilitites 9 out of 36, 14
Question c) From a) and b) 14− 1
9= 5
36
Question d) b) in general x2
36c) in general 2x−1
36
Question e) The sum is over all possible outcomes, and should thus be 1.Inserting x = 6 we get 62
36= 1 q.e.d.
IMM - DTU 02405 Probability
2006-9-19BFN/bfn
A special case of a problem, which we will treat in full generality later.
Question a) count the possibilitites 4 out of 36, 19
Question b) count the possibilitites 9 out of 36, 14
Question c) From a) and b) 14− 1
9= 5
36
Question d) b) in general x2
36c) in general 2x−1
36
Question e) The sum is over all possible outcomes, and should thus be 1.Inserting x = 6 we get 62
36= 1 q.e.d.
IMM - DTU 02405 Probability
2006-9-19BFN/bfn
A special case of a problem, which we will treat in full generality later.
Question a) count the possibilitites 4 out of 36, 19
Question b) count the possibilitites
9 out of 36, 14
Question c) From a) and b) 14− 1
9= 5
36
Question d) b) in general x2
36c) in general 2x−1
36
Question e) The sum is over all possible outcomes, and should thus be 1.Inserting x = 6 we get 62
36= 1 q.e.d.
IMM - DTU 02405 Probability
2006-9-19BFN/bfn
A special case of a problem, which we will treat in full generality later.
Question a) count the possibilitites 4 out of 36, 19
Question b) count the possibilitites 9 out of
36, 14
Question c) From a) and b) 14− 1
9= 5
36
Question d) b) in general x2
36c) in general 2x−1
36
Question e) The sum is over all possible outcomes, and should thus be 1.Inserting x = 6 we get 62
36= 1 q.e.d.
IMM - DTU 02405 Probability
2006-9-19BFN/bfn
A special case of a problem, which we will treat in full generality later.
Question a) count the possibilitites 4 out of 36, 19
Question b) count the possibilitites 9 out of 36,
14
Question c) From a) and b) 14− 1
9= 5
36
Question d) b) in general x2
36c) in general 2x−1
36
Question e) The sum is over all possible outcomes, and should thus be 1.Inserting x = 6 we get 62
36= 1 q.e.d.
IMM - DTU 02405 Probability
2006-9-19BFN/bfn
A special case of a problem, which we will treat in full generality later.
Question a) count the possibilitites 4 out of 36, 19
Question b) count the possibilitites 9 out of 36, 14
Question c) From a) and b) 14− 1
9= 5
36
Question d) b) in general x2
36c) in general 2x−1
36
Question e) The sum is over all possible outcomes, and should thus be 1.Inserting x = 6 we get 62
36= 1 q.e.d.
IMM - DTU 02405 Probability
2006-9-19BFN/bfn
A special case of a problem, which we will treat in full generality later.
Question a) count the possibilitites 4 out of 36, 19
Question b) count the possibilitites 9 out of 36, 14
Question c) From a)
and b) 14− 1
9= 5
36
Question d) b) in general x2
36c) in general 2x−1
36
Question e) The sum is over all possible outcomes, and should thus be 1.Inserting x = 6 we get 62
36= 1 q.e.d.
IMM - DTU 02405 Probability
2006-9-19BFN/bfn
A special case of a problem, which we will treat in full generality later.
Question a) count the possibilitites 4 out of 36, 19
Question b) count the possibilitites 9 out of 36, 14
Question c) From a) and b)
14− 1
9= 5
36
Question d) b) in general x2
36c) in general 2x−1
36
Question e) The sum is over all possible outcomes, and should thus be 1.Inserting x = 6 we get 62
36= 1 q.e.d.
IMM - DTU 02405 Probability
2006-9-19BFN/bfn
A special case of a problem, which we will treat in full generality later.
Question a) count the possibilitites 4 out of 36, 19
Question b) count the possibilitites 9 out of 36, 14
Question c) From a) and b) 14
− 19= 5
36
Question d) b) in general x2
36c) in general 2x−1
36
Question e) The sum is over all possible outcomes, and should thus be 1.Inserting x = 6 we get 62
36= 1 q.e.d.
IMM - DTU 02405 Probability
2006-9-19BFN/bfn
A special case of a problem, which we will treat in full generality later.
Question a) count the possibilitites 4 out of 36, 19
Question b) count the possibilitites 9 out of 36, 14
Question c) From a) and b) 14− 1
9
= 536
Question d) b) in general x2
36c) in general 2x−1
36
Question e) The sum is over all possible outcomes, and should thus be 1.Inserting x = 6 we get 62
36= 1 q.e.d.
IMM - DTU 02405 Probability
2006-9-19BFN/bfn
A special case of a problem, which we will treat in full generality later.
Question a) count the possibilitites 4 out of 36, 19
Question b) count the possibilitites 9 out of 36, 14
Question c) From a) and b) 14− 1
9= 5
36
Question d) b) in general x2
36c) in general 2x−1
36
Question e) The sum is over all possible outcomes, and should thus be 1.Inserting x = 6 we get 62
36= 1 q.e.d.
IMM - DTU 02405 Probability
2006-9-19BFN/bfn
A special case of a problem, which we will treat in full generality later.
Question a) count the possibilitites 4 out of 36, 19
Question b) count the possibilitites 9 out of 36, 14
Question c) From a) and b) 14− 1
9= 5
36
Question d) b) in general
x2
36c) in general 2x−1
36
Question e) The sum is over all possible outcomes, and should thus be 1.Inserting x = 6 we get 62
36= 1 q.e.d.
IMM - DTU 02405 Probability
2006-9-19BFN/bfn
A special case of a problem, which we will treat in full generality later.
Question a) count the possibilitites 4 out of 36, 19
Question b) count the possibilitites 9 out of 36, 14
Question c) From a) and b) 14− 1
9= 5
36
Question d) b) in general x2
36
c) in general 2x−136
Question e) The sum is over all possible outcomes, and should thus be 1.Inserting x = 6 we get 62
36= 1 q.e.d.
IMM - DTU 02405 Probability
2006-9-19BFN/bfn
A special case of a problem, which we will treat in full generality later.
Question a) count the possibilitites 4 out of 36, 19
Question b) count the possibilitites 9 out of 36, 14
Question c) From a) and b) 14− 1
9= 5
36
Question d) b) in general x2
36c) in general
2x−136
Question e) The sum is over all possible outcomes, and should thus be 1.Inserting x = 6 we get 62
36= 1 q.e.d.
IMM - DTU 02405 Probability
2006-9-19BFN/bfn
A special case of a problem, which we will treat in full generality later.
Question a) count the possibilitites 4 out of 36, 19
Question b) count the possibilitites 9 out of 36, 14
Question c) From a) and b) 14− 1
9= 5
36
Question d) b) in general x2
36c) in general 2x−1
36
Question e) The sum is over all possible outcomes, and should thus be 1.Inserting x = 6 we get 62
36= 1 q.e.d.
IMM - DTU 02405 Probability
2006-9-19BFN/bfn
A special case of a problem, which we will treat in full generality later.
Question a) count the possibilitites 4 out of 36, 19
Question b) count the possibilitites 9 out of 36, 14
Question c) From a) and b) 14− 1
9= 5
36
Question d) b) in general x2
36c) in general 2x−1
36
Question e) The sum is over all possible outcomes, and should thus be
1.Inserting x = 6 we get 62
36= 1 q.e.d.
IMM - DTU 02405 Probability
2006-9-19BFN/bfn
A special case of a problem, which we will treat in full generality later.
Question a) count the possibilitites 4 out of 36, 19
Question b) count the possibilitites 9 out of 36, 14
Question c) From a) and b) 14− 1
9= 5
36
Question d) b) in general x2
36c) in general 2x−1
36
Question e) The sum is over all possible outcomes, and should thus be 1.
Inserting x = 6 we get 62
36= 1 q.e.d.
IMM - DTU 02405 Probability
2006-9-19BFN/bfn
A special case of a problem, which we will treat in full generality later.
Question a) count the possibilitites 4 out of 36, 19
Question b) count the possibilitites 9 out of 36, 14
Question c) From a) and b) 14− 1
9= 5
36
Question d) b) in general x2
36c) in general 2x−1
36
Question e) The sum is over all possible outcomes, and should thus be 1.Inserting x = 6 we get 62
36= 1 q.e.d.
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