I.E.P. ALFRED NOBEL

ARITMÉTICA.CURSO:

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I.E.P. ALFRED NOBELI.E.P. ALFRED NOBEL

MCD – MCM II

CHARLI JHON PAUCAR GAMARRA.

PRACTICA

1

MCD – MCM II

𝑄 3 2 4 2

𝑅 0

𝑑2𝑑

𝑑

9𝑑

2𝑑

20𝑑

9𝑑

69𝑑

69𝑑 − 20𝑑 = 245

49𝑑 = 245

𝑑 = 5

𝑆 = 69𝑑 + 20𝑑

𝑆 = 89𝑑

𝑆 = 445

2

MCD – MCM II

MCM(A;B) = m

MCD(A;B) = d

d.a = A

d.b = B

m = d.a.b

PESI :a y b

𝐴 ∗ 𝐵 = 960

𝑎. 𝑑 ∗ 𝑑. 𝑏 = 960

𝑚.𝑑 = 960

120 ∗ 𝑑 = 960

𝑑 = 8

MCD(A;B) = d = 8

3

MCD – MCM II

MCM(A;B) = 840

MCD(A;B) = 40

40a = A

40b = B

m = d.a.b

PESI :a y b

840 = 40ab

21 = ab

a= 7; b= 3

A+ B = 40(a+b)

A+ B = 40(10)

A+ B = 400

4

MCD – MCM II

𝑀𝐶𝐷 𝐴;8; 𝐶;𝐷 = 𝑀𝐶𝐷(𝑀𝐶𝐷 𝐴;8 ;𝑀𝐶𝐷 𝐶;𝐷 )

54 = 𝑀𝐶𝐷(15𝑘; 12𝑘)

54 = 3𝑘

18 = 𝑘

5

MCD – MCM II

𝑁 = 30𝑘

𝑀𝐶𝐷 10𝑘; 12𝑘; 35𝑘 = 24

𝑘 = 24

𝑁 = 30𝑘 = 30 ∗ 24 = 720

6

MCD – MCM II

𝑀𝐶𝑀 𝐴;𝐵 = 420

𝐴 𝑦 𝐵 𝑠𝑜𝑛 𝑝𝑒𝑠𝑖.

𝐴 ∗ 𝐵 = 420 = 22 ∗ 3 ∗ 5 ∗ 7

𝐴 ∗ 𝐵 = 12 ∗ 35

𝐴 + 𝐵 = 47

𝐴 = 12;𝐵 = 35

𝐵 − 𝐴 = 35 − 12 = 23

7

MCD – MCM II

𝑀𝐶𝐷 𝐴;𝐵;𝐶 = 6𝑀𝐶𝐷(8;12;20) − 1

𝑀𝐶𝐷 𝐴;𝐵; 𝐶 = 64 − 1

𝑀𝐶𝐷 𝐴;𝐵;𝐶 = 1296 − 1 = 1295

𝑆𝑐 = 1 + 2 + 9+ 5 = 17

8

MCD – MCM II

𝑄 2 3 4 2

𝑅 0

𝑑2𝑑

𝑑

9𝑑

2𝑑

29𝑑

9𝑑

67𝑑

67𝑑 + 29𝑑 = 288

96𝑑 = 288

𝑑 = 3

𝑀𝐶𝑀 67 ∗ 3; 29 ∗ 3 = 67 ∗ 29 ∗ 3

𝑀𝐶𝑀 67 ∗ 3; 29 ∗ 3 = 5829

𝑆𝑐 = 5 + 8 + 2 + 9 = 24

9

MCD – MCM II

MCM(A;B) = m

MCD(A;B) = d

d.a = A

d.b = B

m = d.a.b

PESI :a y b

𝑚

𝑑= 63

𝑎𝑏𝑑

𝑑= 63

𝑎𝑏 = 63

𝑎 = 7; 𝑏 = 9

𝑑 +𝑚 = 960

𝑑 + 𝑎𝑏𝑑 = 960

𝑑 1 + 𝑎𝑏 = 960

𝑑 64 = 960

𝑑 = 15

𝐴 + 𝐵 = 𝑎𝑑 + 𝑏𝑑

𝐴 + 𝐵 = 𝑑(𝑎 + 𝑏)

𝐴 + 𝐵 = 240

10

MCD – MCM II

MCM(A;B) = m

MCD(A;B) = d

d.a = A

d.b = B

m = d.a.b

PESI :a y b

𝐴 + 𝐵 = 325

𝑑(𝑎 + 𝑏) = 325

𝑎𝑑𝑏 = 1000

𝑎 + 𝑏

𝑎𝑏=13

40

𝑎 = 8; 𝑏 = 5

𝑑(𝑎 + 𝑏) = 325

𝑑(13) = 325

𝑑 = 25

𝐴 − 𝐵 = 8𝑑 − 5𝑑

𝐴 − 𝐵 = 3𝑑

𝐴 − 𝐵 = 3 ∗ 25

𝐴 − 𝐵 = 75

PRÁCTICA CALIFICADA

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