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IB Wind and Wave Power Mark Kapron, Luc LaLonde, Scott Johnstun
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IB Wind and Wave Power Mark Kapron, Luc LaLonde, Scott Johnstun.

Jan 12, 2016

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Page 1: IB Wind and Wave Power Mark Kapron, Luc LaLonde, Scott Johnstun.

IB Wind and Wave Power

Mark Kapron, Luc LaLonde, Scott Johnstun

Page 2: IB Wind and Wave Power Mark Kapron, Luc LaLonde, Scott Johnstun.

Wind Power

• A wind generator is commonly know as a wind turbine.

• Unlike a fan, producing wind with the help of electricity, the wind turbines produce electricity with the help of wind.

Page 3: IB Wind and Wave Power Mark Kapron, Luc LaLonde, Scott Johnstun.

How Do They Work?

• A gust of wind blows through the blades of the turbine causing it to rotate, which creates large amounts of kinetic energy.

• This kinetic energy turns a shaft, which in turn turns the generator and creates electrical energy.

Page 4: IB Wind and Wave Power Mark Kapron, Luc LaLonde, Scott Johnstun.
Page 5: IB Wind and Wave Power Mark Kapron, Luc LaLonde, Scott Johnstun.

Power Generated by Wind

• Albert Betz was a German physicist who in 1919 concluded that no wind turbine can convert more than 16/27 (59.3%) of the kinetic energy of the wind into mechanical energy turning a rotor. To this day this is known as the Betz Limit or Betz' Law. This limit has nothing to do with inefficiencies in the generator, but in the very nature of wind turbines themselves.

Page 6: IB Wind and Wave Power Mark Kapron, Luc LaLonde, Scott Johnstun.

Proof?

Page 7: IB Wind and Wave Power Mark Kapron, Luc LaLonde, Scott Johnstun.

But seriously…

• You can’t convert all of the kinetic energy in the area of the circle that the blades cover because some of the wind will pass through without interacting with the system.

Page 8: IB Wind and Wave Power Mark Kapron, Luc LaLonde, Scott Johnstun.

Problem Solving Wind

• Wind power = 1/2 x Swept Area x Air Density x Velocity3 • The world's largest wind turbine generator has a rotor

blade diameter of 126 meters and a rotor sweep area of 12470 m2. The turbines are also moving at a speed of 14m/s. Find the power produced by the turbines.

• The air is situated at sea level, so it equals = 1.23kg/m3

Wind Power = 0.5 x 12,470 m2 x 1.23 kg/m3 x (143) m3/s3

• Wind power = 21,000,000 Watts or 21 MW.

Page 9: IB Wind and Wave Power Mark Kapron, Luc LaLonde, Scott Johnstun.

Not Drawn to Scale

Page 10: IB Wind and Wave Power Mark Kapron, Luc LaLonde, Scott Johnstun.

Part 2: Wave Power

• Clean energy produced by using the power of oceanic waves. Around the world, day and night, waves produce a tremendous amount of untapped energy. Methods of harnessing this energy are being discovered rapidly.

Page 11: IB Wind and Wave Power Mark Kapron, Luc LaLonde, Scott Johnstun.

Various Methods to Harness Wave Energy

Page 12: IB Wind and Wave Power Mark Kapron, Luc LaLonde, Scott Johnstun.

Methods to Harness the Energy

This is the Oscillating Water Column Method

Page 13: IB Wind and Wave Power Mark Kapron, Luc LaLonde, Scott Johnstun.

More on the OWC

• About 36 kW of power potential per 1 meter wave front.

• You must assume a rectangular profile of the wave, since waves are not rectangular this potential cannot be reached.

Page 14: IB Wind and Wave Power Mark Kapron, Luc LaLonde, Scott Johnstun.

Wave Energy Problems• The best place to put these devices is usually in the

areas of the ocean with the strongest waves, but these places are also the most difficult to set up the generators, and maintain them.

• Oceanic waves are generally too slow (frequency) to rotate a turbine efficiently.

• The electric cables that bring the energy to the mainland could also be a possible threat to sea life. Tests on this are currently being conducted to see if it would really be a problem.

• Like wind turbines, wave energy converting devices are currently expensive.

Page 15: IB Wind and Wave Power Mark Kapron, Luc LaLonde, Scott Johnstun.

Yes, that says friction…

Page 16: IB Wind and Wave Power Mark Kapron, Luc LaLonde, Scott Johnstun.

Wave Energy Equation

• Power Per Unit Length=0.5A2ρgv• A= Area of the waves cross-section• ρ= Density of water• g= 9.8 m/s2

• v= Velocity of the wave

• You might also see the potential energy stored in one wavelength as Ep=.5A2λρgL

Page 17: IB Wind and Wave Power Mark Kapron, Luc LaLonde, Scott Johnstun.

Proof

Page 18: IB Wind and Wave Power Mark Kapron, Luc LaLonde, Scott Johnstun.

Sample Problem

Page 19: IB Wind and Wave Power Mark Kapron, Luc LaLonde, Scott Johnstun.

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