Top Banner
http://lawrencekok.blogs pot.com Prepared by Lawrence Kok Video Tutorial on Uncertainty Calculation, standard deviation and Error analysis in Enthalpy Change
16

IB Chemistry, IB Biology on Uncertainty calculation, error analysis and standard deviation on enthalpy change

Dec 22, 2014

Download

Education

Lawrence Kok

IB Chemistry, IB Biology on Uncertainty calculation, error analysis and standard deviation on enthalpy change
Welcome message from author
This document is posted to help you gain knowledge. Please leave a comment to let me know what you think about it! Share it to your friends and learn new things together.
Transcript
Page 1: IB Chemistry, IB Biology on Uncertainty calculation, error analysis and standard deviation on enthalpy change

http://lawrencekok.blogspot.com

Prepared by Lawrence Kok

Video Tutorial on Uncertainty Calculation, standard deviation and Error analysis in Enthalpy Change

Page 2: IB Chemistry, IB Biology on Uncertainty calculation, error analysis and standard deviation on enthalpy change

IB Chemistry, Uncertainty Calculation, Error analysis, Standard Deviation

Enthalpy change for displacement Zn + CuSO4

2 methods for Uncertainty Calculation• 1st Method using % Uncertainty

Zinc excess, Copper limitingConc CuSO4 = (1M ± 0)Vol = (20.0 ± 0.3) mlMol of Cu ions= M x V= 0.02 mol△t = (68.0±0.2) - (25.1±0.2) = (42.9±0.4)m = 20.0 ± 0.3ml

Q = mc t△Q = 20.00 x 4.184 x  t△Q = 20.00 x 4.184 x 42.9Q = 3589.8J ----------0.02 molQ = 3589.9/0.02------ 1molQ = 179.5kJ/mol

Page 3: IB Chemistry, IB Biology on Uncertainty calculation, error analysis and standard deviation on enthalpy change

Extrapolation for Temp increase, 68.0 - 25.1= 42.9

%Uncertainty Q = % Uncertainty m + % Uncertainty  t△%Uncertainty m = (0.3/20) x 100% = 1.5%%Uncertainty  t = (0.2+0.2) / 42.9 x 100% = 0.93%△

%Total Uncertainty = (0.93 + 1.5) = 2.43%

Q = (179.5 ± 2.43%)Q = (179.5 ± 4.36) = (180 ± 4)kJ/mol

Page 4: IB Chemistry, IB Biology on Uncertainty calculation, error analysis and standard deviation on enthalpy change

•2nd Method Using Max/Min

Q = mc t△Q = 20.00 x 4.184 x 42.9Q = 3589.8J ----------0.02 molQ = 3589.9/0.02------1molQ = 179.5kJ/mol

Q = mc t△△t = 42.9 ± (0.2+02) = (42.9±0.4)   Max t = 42.9+ 0.4 = 43.3   Min t = 42.9- 0.4 = 42.5m = 20.0 ± 0.3ml                             Max m = 20.0+ 0.3=20.3     Min m = 20.0- 0.3 = 19.7

Max   Q = Maximum   m and Maximum  t△ △ △Max   Q = m c t = 20.3 x 4.184 x 43.3 = 3677.7J△ △Max Q = 3677.7J -----------0.02molMax Q = 3677.7/0.02-------1molMax Q = 183.3kJ/mol

Min  Q = Minimum   m and Minimum  t△ △ △Min  Q = mc t = 19.7 x 4.184 x 42.5 = 3503.0J△ △Min Q = 3503.0J------------0.02molMin Q = 3503.0J/0.02-------1molMin Q = 175.1kJ/molUsing Max/Min Method                          Using %Uncertainty MethodQ = 179.5 ± ( 183.3--175.1)kJ/mol          Q = (179.5 ± 2.43%) = (180 ± 4)kJ/molQ = (183.3---175.1)                     Q = (184---176)

Page 5: IB Chemistry, IB Biology on Uncertainty calculation, error analysis and standard deviation on enthalpy change

More Accurate way by taking Uncertainty in Moles Cu1st Method Using %Uncertainty

%Uncertainty moles of Cu usedConc CuSO4 = (1M±0) , Vol = (20.0 ± 0.3) mlMoles of Cu ions = M x V= 0.02 mol

%Uncertainty moles Cu = %Uncertainty in M + %Uncertainty in Vol %Uncertainty Cu = 0% + (0.3/ 20) x 100% = 0% +1.5% = 1.5%

Total %Uncertainty Q = %Uncertainty m + %Uncertainty  t + %Uncertainty mol Cu△Total %Uncertainty Q = 1.5% + 0.93% + 1.5% = 3.93%

Q = (179.5 ± 3.93%)= (179.5 ± 7.05) = (179 ± 7)Q = ( 186 ----172 )kJ/mol

Page 6: IB Chemistry, IB Biology on Uncertainty calculation, error analysis and standard deviation on enthalpy change

2nd Method Using Max/Min

Conc CuSO4 = (1M±0) , Vol = (20.0 ± 0.3)mlMoles of Cu ions = M x V = 0.02 mol

△t = 42.9 ± (0.2+02) = (42.9±0.4)    Max t= 42.9+0.4 = 43.3     Min t= 42.9- 0.4= 42.5m = 20.0 ± 0.3ml                             Max m= 20.0+ 0.3=20.3    Min m= 20.0- 0.3= 19.7

Max Vol = 20.3ml, Min Vol = 19.7ml        Molarity = (1M±0)

Max moles Cu = Max M x Max Vol = 1 x 20.3 = 0.0203Min moles Cu = Min M x Min Vol = 1 x 19.7 = 0.0197

Uncertainty moles of Cu = 0.020 ± (0.0203--0.0197)

Max Uncertainty Q = mc t = 20.3 x 4.184 x 43.3 = 3677.7J△Min Uncertainty Q = mc t = 19.7 x 4.184 x 42.5 = 3503.0J△

Max Q = 3677.7J----------0.02molMin Q = 3503.0J-----------0.02mol

Uncertainty moles of Cu = 0.02 ± (0.0203--0.0197)Max moles Cu = 0.0203Min moles Cu = 0.0197

Page 7: IB Chemistry, IB Biology on Uncertainty calculation, error analysis and standard deviation on enthalpy change

Max Q = Max Uncertainty Q + Min Uncertainty mol Cu ( will give greatest error )Min Q = Min Uncertainty Q + Max Uncertainty mol Cu ( will give least error )

Max Q = 3677.7---------------0.0197 mol Cu      Min Q = 3503.0-----------------0.0023mol CuMax Q = 3677.7/0.0197------1 mol                  Min Q = 3503.0/0.023--------1molMax Q = 186.7kJ/mol                                      Min Q = 152.3kJ/mol

Q = 179.5 ± ( 186.7---152.3 )kJ/mol

% Uncertainty Method                                      Max/Min MethodQ = ( 186 ----172 )kJ/mol                                   Q = ( 186.7---152.3 )kJ/mol

Page 8: IB Chemistry, IB Biology on Uncertainty calculation, error analysis and standard deviation on enthalpy change

IA must be done with minimum 3 trials, for valid conclusion.

Displacement of Zinc + CuSO4

Displacement done with 3 trials.

• Zinc excess, Copper limiting

• Conc CuSO4 = (1M±0)

• Vol = (20.0 ± 0.3) ml

• Mol of Cu ions = M x V = 0.02 mol

Click HERE for Data

Page 9: IB Chemistry, IB Biology on Uncertainty calculation, error analysis and standard deviation on enthalpy change

Two Methods used1st MethodAverage Q for 3 trials and using Standard deviation as uncertainty

Temp change for 3 trials△t1 =( 26.2 ± 0.2)- (21.7± 0.2)=(4.5± 0.4)

△t2 = (26.1 ± 0.2)- (21.6± 0.2)=(4.5± 0.4)

△t3 = (25.8 ± 0.2)- (21.7± 0.2)=(4.1± 0.4)

Q1 = mc t1 = 20.0 x 4.184 x 4.5 = 376.5△

Q2 = mc t2 = 20.0 x 4.184 x 4.5 = 376.5△

Q3 = mc t3 = 20.0 x 4.184 x 4.1= 343.1△

Page 10: IB Chemistry, IB Biology on Uncertainty calculation, error analysis and standard deviation on enthalpy change

Average Q = (376.5 + 376.5 + 343.1)/3 = 365.4J    Average Q = 365.4J ----------0.02 mol                      Average Q = 365.4/0.02------1 mol                        Average Q = 18.3kJ/mol                                                  

Uncertainty Q = Standard Deviation Q= (19.28)

Uncertainty Q = 19.28-----------0.02 mol

Uncertainty Q = 19.28/0.02-----1 mol

Uncertainty Q = 0.96kJ/mol

Average Q = (18.3 ± 0.96)kJ/mol     

Page 11: IB Chemistry, IB Biology on Uncertainty calculation, error analysis and standard deviation on enthalpy change

2nd Method 

Taking average Temp changeClick HERE for data

Average Temp data is taken.Displacement for Zinc + CuSO4

Zinc excess, Copper limiting,Conc CuSO4 = (1M± 0)Vol = 20.0 ± 0.3 mlMol of Cu ions= M x V = 0.02 mol△t = (25.7 ± 0.2) - (21.6 ± 0.2)= (4.1 ± 0.4)

Page 12: IB Chemistry, IB Biology on Uncertainty calculation, error analysis and standard deviation on enthalpy change

By extrapolation using average temp△t = (25.7 ± 0.2) - (21.6 ± 0.2)= (4.1 ± 0.4)

Q = mc t△Q = 20.0 x 4.184 x  t△Q = 20.0 x 4.184 x 4.1Q = 343.1J ---------0.02 molQ = 343.1/0.02------1 mol

Q = 17.155kJ/mol

Page 13: IB Chemistry, IB Biology on Uncertainty calculation, error analysis and standard deviation on enthalpy change

More accurate way is to consider Uncertainty for moles Cu

Conc CuSO4 = (1M± 0), Vol = (20.0 ± 0.3) mlMol of Cu ions = M x V

%Uncertainty moles Cu = %Uncertainty in M + %Uncertainty in Vol %Uncertainty Cu = 0% + (0.3/ 20) x 100% = 0% +1.5% = 1.5%

%Total Uncertainty Q = %Uncertainty m + %Uncertainty  t + %Uncertainty mol Cu△

%Total Uncertainty Q = 1.5% + 9.75% + 1.5% = 12.75%

Q = (17.15± 12.75%) = (17.15± 2.18)kJ/mol

Page 14: IB Chemistry, IB Biology on Uncertainty calculation, error analysis and standard deviation on enthalpy change

Using %Uncertainty Method 

Temp increase = (25.7 ± 0.2) - (21.6 ± 0.2)= (4.1 ± 0.4)%Uncertainty Q = % Uncertainty m + % Uncertainty  t△%Uncertainty m = (0.3/20) x 100% = 1.5%%Uncertainty  t = (0.4 / 4.1) x 100% = 9.75%△

%Total Uncertainty = (1.5 + 9.75)% = 11.25%

Q = (17.155± 11.25%)= (17.15±1.92)kJ/mol

Page 15: IB Chemistry, IB Biology on Uncertainty calculation, error analysis and standard deviation on enthalpy change

In short, 

• Make sure you perform 3 trials and compute the average or use std deviation

• Use %Uncertainty or Max/min Method of your choice

• Use lots of common sense for error treatment

• The only certainty in life is continual uncertainty

• Have fun with uncertainty

Page 16: IB Chemistry, IB Biology on Uncertainty calculation, error analysis and standard deviation on enthalpy change

Acknowledgements

Thanks to source of pictures and video used in this presentation

Thanks to Creative Commons for excellent contribution on licenseshttp://creativecommons.org/licenses/

Prepared by Lawrence Kok

Check out more video tutorials from my site and hope you enjoy this tutorialhttp://lawrencekok.blogspot.com