I. Polar Equations What you are finding: r · I. Polar Equations What you are finding: Polar equations are in the form r=f(!). This generates a set of points that are at a ... Demystifying
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What you are finding: Polar equations are in the form
r = f !( ). This generates a set of points that are at a radius r from the pole (origin) based on a function of
! , the central angle at the pole. How to find it: We normally need to find slopes of these curves, which means that we need to represent the polar curve parametrically. The formulas to do so are:
x = rcos! and y = rsin! .
To find
dy
dx, you use the formula:
dy
dx=dy d!
dx d!. Horizontal tangents occur when
dy
d!= 0 and vertical
tangents occur when
dx
d!= 0. If
dy
d! and
dx
d! are both zero simultaneously, no conclusion can be made.
Typical AP problems involve finding the area bounded by a polar curve between two angles
! and ".
A =1
2f !( )[ ]
2
"
#
$ d! . This assumes the function f is continuous and non-negative.
Arc length in polar form is given by the formula:
s = f !( )[ ]2
+ " f !( )[ ]2
#
$
% d! = r2
+dr
d!&
'
(
)
2
#
$
% d! .
43. What is the equation of the line tangent to the polar curve
! = 0 when t = 0. The particle moves along the curve such that
dr
dt=dr
d!. Describe the motion of the
particle at
t =!
6.
I. Getting closer to the x-axis II. Getting closer to the y-axis III. Getting closer to the origin A. I only B. II only C. I and II only D. II and III only E. I, II and III
49. (Calc) A path around a park is in the shape of the polar graph of
r = ! as shown in the figure to the right. If a walker starts at the origin and walks around the path and then back to origin along the x-axis, how far does he walk?
What you are finding: Taylor polynomial approximations allow students to write a polynomial that approximates a function. They are important because transcendental functions like trig functions or log functions can be expressed with nothing but addition and multiplication. How to find it: The nth degree Taylor polynomial approximation for a function
f x( ) at x = c is given by:
Pn x( ) = f c( ) + ! f c( ) x " c( ) +! ! f c( ) x " c( )
2
2!+
! ! ! f c( ) x " c( )3
3!+ ...+
fn( )
c( ) x " c( )n
n!
If c = 0, then the Taylor polynomial is a Maclaurin polynomial and is given by:
Pn x( ) = f 0( ) + ! f 0( )x +! ! f 0( )
2!x2
+! ! ! f 0( )
3!x3
+ ...+f
n( )0( )
n!x
n
Typical problems involve giving the Taylor polynomial approximation and asking students to find the values of specific derivatives at some value of c. Sometimes, you will be given a formula for the nth derivative of a function in a Taylor series and you will be asked to write the Taylor polynomial. Taylor polynomial approximation problems go hand-in-hand with the second derivative test. If there is no first-degree x-term in the Taylor polynomial, then the value of c about which the function is centered is a critical value. Thus the coefficient of the
x2 is the second derivative divided by 2! Using the second
derivative test, we can tell whether there is a relative maximum, minimum, or neither at x = c.
51. Let f be a function having derivatives for all orders of real numbers. The first three derivatives of
f at x = 0 are given in the table below. Use the third-degree Taylor polynomial at x = 0 to approximate
What you are finding: When the Taylor polynomial alternates in sign (+ - + - …) and converges to some limit, the error is easily found: it is simply the absolute value of the next term in the series as the terms get smaller and smaller. But when the Taylor polynomial doesn’t alternate in sign, we need to find the Lagrange error. No BC topic fills students (and teachers) with as much dread as the Lagrange Error. Typically there is only one free response question on the BC exam concerning Lagrange and students usually ignore it. When the nth degree Taylor polynomial is found for an approximation to a function
f x( ) at x = c, there is an error – the difference between
f c( ) and the result of the Taylor polynomial approximation. The Lagrange Error Bound gives the maximum error that using the Taylor polynomial approximation will yield. I liken it in my classes to asking instructions to some residential address. There are some detours right around the address. Rather than giving full directions (because you don’t know exactly where the detours are), you give directions to a road that is one mile from your house. You tell the people at that time to get out and ask directions. You know that at worse, they will only be one mile from your house (the error). How to find it: The nth degree Taylor polynomial approximation for a function
f x( ) at x = c is given by
Pn x( ) = f c( ) + ! f c( ) x " c( ) +! ! f c( ) x " c( )
2
2!+
! ! ! f c( ) x " c( )3
3!+ ...+
fn( )
c( ) x " c( )n
n! Remember that this is an approximation for
f x( ) . Stated a different way:
f x( ) = f c( ) + ! f c( ) x " c( ) +! ! f c( ) x " c( )
2
2!+
! ! ! f c( ) x " c( )3
3!+ ...+
fn( )
c( ) x " c( )n
n!+ Rn x( ) where
Rnx( ) is
the error that is created when using the Taylor polynomial. This
Rnx( ) is called the Lagrange form of the
remainder and is found by the formula:
Rn x( ) =f
n+1( ) z( )
n +1( )!x ! c
n+1. The z is some value between x and c.
You will not find z. For any nth degree Taylor Polynomial, you will need to find the maximum value of the (n +1)st derivative to calculate the Lagrange Error. There are generally two types of problems in the AP exam that ask for the Lagrange error. • the maximum value of the (n +1)st derivative is easily determined (usually trig functions). • the maximum value of the (n +1)st derivative is given to you.
56. The function f has derivatives of all orders for all real numbers and
f5( ) x( ) = e
cosx . If the fourth—degree Taylor polynomial for f about x = 0 is used to approximate f on the interval
0,1[ ], what is the Lagrange error bound for the maximum error on the interval
58. (Calc) Let f be a function having derivatives for all orders of real numbers. The function and its first three derivatives of f at x = 0 are given in the table below. The fourth-derivative of f satisfies the inequality
f4( ) x( ) ! 60 for all x in the interval 0,1[ ]. Find the maximum value of
What you are finding: In the multiple-choice section, asking whether a series is convergent makes little sense. Either it is or it isn’t, making five possible answers meaningless. Typically, students will be given a series and asked to find the interval of convergence. That means a range of values of x such that when the infinite series terms are added, the sum converges to some limit rather than diverging to infinity or negative infinity. Overwhelmingly, the test for convergence and thus finding the interval of convergence uses the ratio test but students must also know and recognize the geometric series, p-series and alternating series. How to find it: First, students must know that any series whose terms do not approach zero as n approaches infinity cannot converge. This, the nth term test, can only prove divergence. The most common rules for convergence are the following. Again, the test that is used the most is the ratio test. The only series form that students need to be able to actually sum is geometric.
Type Geometric p ! series Alternating Ratio
Series form arn
n= 0
"
# =a
1! r
1
np
n=1
"
# !1( )nan
n=1
"
# ann= 0
"
#
Convergence r < 1 p > 10 < an+1 < an
and limn$"
an = 0limn$"
an+1
an< 1
Students should also know that the harmonic series
1
nn=1
!
" diverges while the alternating harmonic series
!1( )n 1
nn=1
"
# and p-series
1
n2
n=1
!
" converge. Finally, when students find the interval of convergence, they need
to check out the endpoints to determine convergence or divergence at these values as well.
60. Which of the following series converge?
I.
2
n +13
!
" #
$
% &
2
n=1
'
( II.
e
!"
#
$
%
n
n=0
&
' III.
2n
2n
+1
!
" #
$
% &
n=1
'
(
A. I only B. II only C. III only D. II and III only E. None
What you are finding: There is little distinction between Taylor series problems and Taylor polynomial problems other than the fact that the series is an infinite sum while the Taylor polynomial has a degree and stops at some value of n. Thus the Taylor series is an exact sum, which converges to
f x( ) while the Taylor polynomial will have an error associated with it. How to find it: Students should know the Taylor series for the following functions, the first three of which have an interval of convergence as
!","( ) . These crop up all the time.
sin x = x !x
3
3!+x
5
5!!x
7
7!+ ...+
!1( )n
x2n+1
2n + 1( )!+ ... e
x= 1+ x +
x2
2+x
3
3!+x
4
4!+ ...+
xn
n!+ ...
cos x = 1!x
2
2!+x
4
4!!x
6
6!+ ...+
!1( )n
x2n
2n( )!+ ...
1
1! x= 1+ x + x
2+ x
3+ ...+ x
n+ ... Conv : !1,1( )
Typical problems involve finding the radius or interval of convergence of Taylor series using the general term. Mostly, the ratio test is used.
What you are finding: Power series are similar to polynomials, but since they are series, they have an infinite number of terms. A power series is in the form:
a0
+ a1x + a
2x2
+ a3x3
+ ...+ anxn
+ ... , centered at zero. A power series in the form
a0
+ a1x ! c( ) + a
2x ! c( )
2
+ a3x ! c( )
3
+ ...+ anx ! c( )
n
+ ... is centered at c. How to find it: When you are given a formula for the nth term of a series, write out the first 4 or 5 terms to see if it is in the form of a power series. Taylor series for a function
f x( ) centered at c are special forms of
power series where the coefficient of each term has the special relation:
an =f
n( ) c( )
n!. All Taylor series are
power series but not all power series are Taylor series.
74. Let
f x( ) be the power series for
sin x , centered at x = 0. Which of the following is a power series?
I.
f x2( ) . II.
f x( ) III.
f ex( )
A. I only B. II only C. III only D. I and II only E. I, II and III
What you are finding: When you are given or asked to find a power series (or Taylor series) for some function
f x( ) , you are finding a polynomial with infinite terms using the variable x. That allows you to find the value of the function at any value or variable by replacing that x with that number or variable. When you are asked to find the derivative or integral of
f x( ) , you can take the derivative or integral of the power series allowing you to possibly integrate an expression that might not otherwise be integratable. How to find it: For instance, if you were asked to write a Taylor series for
f x( ) = ex3
centered at 0, rather than go through the tedious process of taking derivatives, you use the fact that