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Hypothesis Tests Hypothesis Tests One Sample Means
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Hypothesis Tests One Sample Means

Jan 03, 2016

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Hypothesis Tests One Sample Means. Take a sample & find x. But how do I know if this x is one that I expect to happen or is it one that is unlikely to happen?. How can I tell if they really are underweight?. - PowerPoint PPT Presentation
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Page 1: Hypothesis Tests One Sample Means

Hypothesis TestsHypothesis Tests

One Sample Means

Page 2: Hypothesis Tests One Sample Means

A government agency has received numerous complaints that a particular restaurant has been selling underweight hamburgers. The restaurant advertises that it’s patties are “a quarter pound” (4 ounces).

How can I tell if they really are underweight?

Take a sample & find x.

But how do I know if this x is one that I expectexpect to happen or

is it one that is unlikelyunlikely to happen?

A hypothesis test will allow me to

decide if the claim is true or not!

Page 3: Hypothesis Tests One Sample Means

Steps for doing a hypothesis test

1) Assumptions

2) Write hypotheses & define parameter

3) Calculate the test statistic & p-value

4) Write a statement in the context of the problem.

H0: = 12 vs Ha: (<, >, or ≠) 12

“Since the p-value < (>) , I reject (fail to reject) the H0. There is (is not) sufficient evidence to suggest that Ha (in context).”

Page 4: Hypothesis Tests One Sample Means

Assumptions for t-inference• Have an SRS from population (or

randomly assigned treatments)• unknown• Normal (or approx. normal)

distribution– Given– Large sample size– Check graph of data

Use only one of these methods to check normality

Page 5: Hypothesis Tests One Sample Means

Formulas:

unknown:

statistic of deviation standard

parameter - statisticstatistic test

t =

x

ns

Page 6: Hypothesis Tests One Sample Means

Calculating p-values

• For z-test statistic –– Use normalcdf(lb,rb) – [using standard normal curve]

• For t-test statistic –– Use tcdf(lb, rb, df)

Page 7: Hypothesis Tests One Sample Means

Draw & shade a curve & calculate the p-value:1) right-tail test t = 1.6; n = 20

2) two-tail test t = 2.3; n = 25

P-value = .0630

P-value = (.0152)2 = .0304

Page 8: Hypothesis Tests One Sample Means

Example 1: Bottles of a popular cola are supposed to contain 300 mL of cola. There is some variation from bottle to bottle. An inspector, who suspects that the bottler is under-filling, measures the contents of six randomly selected bottles. Is there sufficient evidence that the bottler is under-filling the bottles? Use = .1

299.4 297.7 298.9 300.2 297 301

Page 9: Hypothesis Tests One Sample Means

• I have an SRS of bottles•Since the boxplot is approximately symmetrical with no outliers, the sampling distribution is approximately normally distributed• is unknown

SRS?

576.1

6503.1

30003.299

t p-value =.0880 = .1

Normal?How do

you know?

H0: = 300 where is the true mean amount

Ha: < 300 of cola in bottles

What are your hypothesis

statements? Is there a key word?

Plug values into formula.

Do you know ?

Since p-value < , I reject the null hypothesis.There is sufficient evidence to suggest that the true mean cola in the bottles is less than 300 mL.

Compare your p-value to & make decision

Write conclusion in context in terms of Ha.

Page 10: Hypothesis Tests One Sample Means

Example 3: The Wall Street Journal (January 27, 1994) reported that based on sales in a chain of Midwestern grocery stores, President’s Choice Chocolate Chip Cookies were selling at a mean rate of $1323 per week. Suppose a random sample of 30 weeks in 1995 in the same stores showed that the cookies were selling at the average rate of $1208 with standard deviation of $275. Does this indicate that the sales of the cookies is lower than the earlier figure?

Page 11: Hypothesis Tests One Sample Means

Assume:

•Have an SRS of weeks

•Distribution of sales is approximately normal due to large sample size

• unknown

H0: = 1323 where is the true mean cookie sales

Ha: < 1323 per week

Since p-value < of 0.05, I reject the null hypothesis. There is sufficient evidence to suggest that the sales of cookies are lower than the earlier figure.

0147.29.2

30275

13231208

valuept

What is the potential error in context?

What is a consequence of that error?

Page 12: Hypothesis Tests One Sample Means

Example 9: President’s Choice Chocolate Chip Cookies were selling at a mean rate of $1323 per week. Suppose a random sample of 30 weeks in 1995 in the same stores showed that the cookies were selling at the average rate of $1208 with standard deviation of $275. Compute a 90% confidence interval for the mean weekly sales rate.CI = ($1122.70, $1293.30)Based on this interval, is the mean weekly sales rate statistically less than the reported $1323?

Page 13: Hypothesis Tests One Sample Means

Matched Pairs Test

A special type of t-inference

Page 14: Hypothesis Tests One Sample Means

Matched Pairs – two forms

• Pair individuals by certain characteristics

• Randomly select treatment for individual A

• Individual B is assigned to other treatment

• Assignment of B is dependent on assignment of A

• Individual persons or items receive both treatments

• Order of treatments are randomly assigned before & after measurements are taken

• The two measures are dependent on the individual

Page 15: Hypothesis Tests One Sample Means

Is this an example of matched pairs?

1)A college wants to see if there’s a difference in time it took last year’s class to find a job after graduation and the time it took the class from five years ago to find work after graduation. Researchers take a random sample from both classes and measure the number of days between graduation and first day of employmentNo, there is no pairing of individuals, you have two independent samples

Page 16: Hypothesis Tests One Sample Means

Is this an example of matched pairs?

2) In a taste test, a researcher asks people in a random sample to taste a certain brand of spring water and rate it. Another random sample of people is asked to taste a different brand of water and rate it. The researcher wants to compare these samples

No, there is no pairing of individuals, you have two independent samples – If you would have the same people taste both brands in random order, then it would be an example of matched pairs.

Page 17: Hypothesis Tests One Sample Means

Is this an example of matched pairs?

3) A pharmaceutical company wants to test its new weight-loss drug. Before giving the drug to a random sample, company researchers take a weight measurement on each person. After a month of using the drug, each person’s weight is measured again.

Yes, you have two measurements that are dependent on each individual.

Page 18: Hypothesis Tests One Sample Means

Stroop Test

Is there an interaction between color & word?

Or in other words … is there a significant increase in time?

Page 19: Hypothesis Tests One Sample Means

A whale-watching company noticed that many customers wanted to know whether it was better to book an excursion in the morning or the afternoon. To test this question, the company collected the following data on 15 randomly selected days over the past month. (Note: days were not consecutive.)

Day 1 2 3 4 5 6 7 8 9 1011

12

13

14

15

Morning 8 9 7 9

10

13

10 8 2 5 7 7 6 8 7

After-noon 8 10 9 8 9

11

8 10 4 7 8 9 6 6 9First, you must find the differences for

each day.

Since you have two values for each day, they are dependent on the day – making this data

matched pairs

You may subtract either way – just be careful

when writing Ha

Page 20: Hypothesis Tests One Sample Means

Day 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15

Morning 8 9 7 9 10 13 10 8 2 5 7 7 6 8 7After-noon 8 10 9 8 9 11 8 10 4 7 8 9 6 6 9

Differences 0 -1 -2 1 1 2 2 -2 -2 -2 -1 -2 0 2 -2

Assumptions:

• Have an SRS of days for whale-watching

• unknown

•Since the normal probability plot is approximately linear, the distribution of difference is approximately normal.

I subtracted:Morning – afternoon

You could subtract the other way!

You need to state assumptions using the differences!

Notice the granularity in this plot, it is still displays a nice linear relationship!

Page 21: Hypothesis Tests One Sample Means

Differences 0 -1 -2 1 1 2 2 -2 -2 -2 -1 -2 0 2 -2

Is there sufficient evidence that more whales are sighted in the afternoon?

Be careful writing your Ha!Think about how you

subtracted: M-AIf afternoon is more should the differences be + or -?

Don’t look at numbers!!!!

H0: D = 0

Ha: D < 0

Where D is the true mean difference in whale sightings from morning minus afternoon

Notice we used D for differences& it equals 0 since the null should be that there is NO

difference.

If you subtract afternoon –

morning; then Ha: D>0

Page 22: Hypothesis Tests One Sample Means

finishing the hypothesis test:

Since p-value > , I fail to reject H0. There is insufficient evidence to suggest that more whales are sighted in the afternoon than in the morning.

05.14

1803.

945.

15639.1

04.

df

p

nsx

t Notice that if you subtracted A-M, then your test statistic

t = + .945, but p-value would be the same

In your calculator, perform a t-test

using the differences (L3)

Differences 0 -1 -2 1 1 2 2 -2 -2 -2 -1 -2 0 2 -2

How could I increase the power of this

test?

Page 23: Hypothesis Tests One Sample Means

Example 2: The Degree of Reading Power (DRP) is a test of the reading ability of children. Here are DRP scores for a random sample of 44 third-grade students in a suburban district:

(data on note page)

At the = .1, is there sufficient evidence to suggest that this district’s third graders reading ability is different than the national mean of 34?

Page 24: Hypothesis Tests One Sample Means

• I have an SRS of third-graders•Since the sample size is large, the sampling distribution is approximately normally distributed

OR

•Since the histogram is unimodal with no outliers, the sampling distribution is approximately normally distributed• is unknown

SRS?

6467.

44189.11

34091.35

t

p-value = tcdf(.6467,1E99,43)=.2606(2)=.5212 = .1

Do you know ?

Normal?How do

you know?

Use tcdf to calculate p-value.

H0: = 34 where is the true mean reading

Ha: ≠ 34 ability of the district’s third-graders

What are your hypothesis

statements? Is there a key word?

Plug values into formula.

Page 25: Hypothesis Tests One Sample Means

A type II error – We decide that the true mean reading ability is not different from the national average when it really is different.

Conclusion:

Since p-value > , I fail to reject the null hypothesis.

There is not sufficient evidence to suggest that the true mean reading ability of the district’s third-graders is different than the national mean of 34.

Write conclusion in context in terms of Ha.

Compare your p-value to & make decision

What type of error could you potentially have made with this decision? State it in context.

Page 26: Hypothesis Tests One Sample Means

What confidence level should you use so that the results match this hypothesis test?

90%

Compute the interval.

What do you notice about the hypothesized mean?

(32.255, 37.927)