Solution: a: Find chip surface temp - Since a line of symmetry exists only half of the heat spreader need to be investigated. b: Find temp distribution using FDM with a grid spacing of 1mm. Find K to achieve 85 C at chip surface. Using a thermal conductivity of 18.4 W/m.k gives a temperature under the center of the chip of 85 C. The resulting temperature distribution within the heat spreader is shown below: C: Provide discretization equations HW#3 Solutions Monday, September 30, 2013 9:27 PM New Section 1 Page 1
Welcome message from author
This document is posted to help you gain knowledge. Please leave a comment to let me know what you think about it! Share it to your friends and learn new things together.
Transcript
Solution:a: Find chip surface temp
- Since a line of symmetry exists only half of the heat spreader need to be investigated.
b: Find temp distribution using FDM with a grid spacing of 1mm. Find K to achieve 85 C at chip surface.
Using a thermal conductivity of 18.4 W/m.k gives a temperature under the center of the chip of 85 C. The resulting temperature distribution within the heat spreader is shown below:
C: Provide discretization equations
HW#3 SolutionsMonday, September 30, 20139:27 PM
New Section 1 Page 1
C: Provide discretization equations
New Section 1 Page 2
New Section 1 Page 3
New Section 1 Page 4
New Section 1 Page 5
New Section 1 Page 6
Related Documents
