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Hướng dẫn phân tích số liệu SPSS

Jul 18, 2015

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Trung Tran Dinh
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Hng dn phn tch s liu SPSS - YTCC Hu - Phn 1: Select caseNgun s liu: S liu DTH BKL lp YTCC4 Kha 07 - 11 Bi 1: Hng dn lc s liu bng lnh Select case: (Bng hnh nh) Mc ch ca bc ny l lc s liu THA v T trong tng s ssos liu Hnh 1: Mc ch ti sao lc

Hnh 2: Thc hin lnh

Hnh 3: Thc hin lnh

Vy l bn thc hin xong lnh lc bng Select case

Hng dn phn tch s liu SPSS - YTCC Hu - Phn 2: X l cu hi nhiu la chnMc ch: To bng 1 chiu: theo 2 phng php To bng 2 chiu: 1 phng php 1. Cu hi nhiu la chn l g: L cu hi m c nhiu p n. Ngi tr li c th chn nhiu p n khc nhau.

"B6: Theo Anh/chi nhung ai de bi tang huyet ap? 1: Nguoi nghien ruou bia xuyen 3: Beo phi 4: Nhung nguoi 40 tuoi man 6: Phu nu co thai 7: Nguoi bi benh tim mach Khac:." Hng dn bng hnh nh: 1. Bng 1 chiu:

2: Nguoi hut thuoc la thuong 5: Nguoi co thoi quen an 8:

a. Dng lnh frequency

Kt qu lnh ny:

b. X l theo Multi Mc ch ca chng ta l khi dng lnh frequency th copy nguyn s liu ca c bng chy ra t SPSS vo file word m mnh c bng d dng, nhanh.

a/ Chng ta s chuyn bin li. Tn bin s m ha li bin c l "b61 n b68" thnh 1 bin mi "Risk1 n risk 8". Nhn bin chung l "Nguoi co nguy c" Chng ta s dng lnh Recode m ha li. Tc t bin: b61 gi tr ca n l "c - khng". Ta s m ha: 1 thnh 1. 2 tr v 0. T na ta s m ha gi tr ca bin: 1 m ha ny thnh "Nguoi nghien ruou bia" Bin b62: Ta s m ha "c - khng". 1 thnh 2. 2 tr v 0. T na ta s m ha gi tr bin.: 2 = "Nguoi hut thuoc la thuong xuyen"

Bin b63 ..........................: 1 thnh 3, 2 tr v 0. 3 = "Beo phi " ....................... Bin b68 ....................: 1 thnh 8, 2 tr v 0. vy 8 = "Khac" Tt c c nhn bin chung l "Nguoi co nguy co" xem hnh nh H1:

H2:

H3:

H4 n hnh cui

b/ To Multi

2. Hng dn x l Multi cho bng 2 chiu