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2013

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[ HOW TO COMPARE MEAN AND MEDIAN IN LESS THAN 20 SECONDS ]

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HOW TO COMPARE MEAN AND MEDIAN IN LESS THAN 20 SECONDS?

Article Title: Compare Mean and Median in less than 20 seconds

In a table analysis question that contains a long list, calculating mean through traditional method takes time. To save time, we will introduce two techniques that will allow you to logically deduce whether mean is greater than or less than the median.

To illustrate my point, let’s review OG 13/#24 question for discussion.

‘The table lists data on the 22 earthquakes of magnitude 7 or greater on the Richter Scale during a recent year. Times are given in hours, minutes, and seconds on the 24-hour Greenwich Mean Time (GMT) clock and correspond to standard time at Greenwich, United Kingdom (UK). Latitude, measured in degrees, is 0 at the equator, increases from 0 to 90 proceeding northward to the North Pole, and decreases from 0 to –90 proceeding southward to the South Pole. Longitude, also measured in degrees, is 0 at Greenwich, UK, increases from 0 to 180 from west to east in the Eastern Hemisphere, and decreases from 0 to –180 from east to west in the Western Hemisphere.’


For each of the following statements, select Yes if the statement is true based on the information provided; otherwise select No.

Yes No

24A. For the 22 earthquakes, the arithmetic mean of the depths is greater than the median of the depths.

24B. More than half of the 22 earthquakes occurred north of the equator.

24C. Exactly half of the earthquakes listed occurred between 10:00:00 and 20:00:00 GMT.

The focus of our discussion will be question # 24A.

STANDARD APPROACH

“For the 22 earthquakes; the arithmetic mean of the depths is greater than the median of the depths.”

In mathematical terms:


The question asks us to compare mean and median. OUR NATURAL INSTINCT WILL BE TO FIRST CALCULATE THE MEAN AND THEN THE MEDIAN.

Mean Mean involves handling 22 data points. Summing up all 22 data points and dividing the sum by 22 is quite time consuming. The mean comes out to be 112.56.

The median

1. Median is the value of the middle-most cell of depth column, when data points are arranged in ascending order.

2. In this dataset, there are 22 elements. 3. So middle most value = mean of 11th and 12th values 4. Median = (25+26)/2=25.5.

Now let’s review the two approaches.

APPROACH 1 – “LIMITED SET OBSERVATION”

Per the approach, we will at first calculate median, since median is less calculation intensive

as compared to mean.

Median = 25.5 (Following the same approach as in “standard approach”)

Mean –

Fundamental principle – In a series of all positive numbers, mean of the series is always greater than the sum of limited data divided by total # of data points in the set

When we glace at the dataset, we find that the last value 641 is disproportionately high. This implies that mean of the all depths must be greater than 1/22 times 641. This equals

Is Mean > Median ?


to 1/22(641) = 293/22 km. Now, 293/22 itself is already greater than the median depth (25.5 km), so the actual mean of the depths must be greater than the median of the depths. So we could arrive at the answer without actually calculating the exact mean of the list.

This approach has also been used by OG.

APPROACH 2

THE SHERLOCK METHOD - LOGICAL DEDUCTION BY OBSERVATION

This approach is along the lines of the approach 1- Limited set Observation approach, but there is no calculation involved. In fact this approach relies on data observation only.

Median- Instead of exactly calculating the median, we will make a few observations. After all to find the exact median, we did have to go through some effort (as shown in standard approach). We know that median is the middle most value.

Just observing this data set, we can be confident that the median will fall between 25 and 31.


Mean- Let us understand a property of mean in relation to ascending order listed dataset.

The given data set of depth is arranged in ascending order, & bottom cell values are disproportionately higher than other cell values. As all the data points lay equal importance for mean, this implies that mean will drift towards heavy values. So it is obvious that mean value will be more than the median. In fact it will be much higher

than the median value in this specific question.

Just to recollect the question, “For the 22 earthquakes; the arithmetic mean of the depths is greater than the median of the depths.” So the answer to the question is YES.

The best thing about this approach is that we don’t need to do any calculation. Mere observation of data & use of basic concept is enough to determine the answer. Table given below presents a few salient features of mean and median. Mean Median Importance of set of observations

1. All data have equal importance. 2. Extreme values can significantly

affect mean.

1. Middle most values matter the most.

2. Least affected by extreme values.

Application

Yields best representation of average, when each value is important and there is less variation in observed values

Yields best representation of average, when few values are too low and/or too high

OTHER SCENARIOS

1. Few top cell values are

disproportionately low


This scenario is opposite of question # 24, we discussed. We can safely infer that mean would be less than the median, because few top cell values are disproportionally low compared to other cell values. This will make mean drift towards low values.

The Logical deduction by observation- Sherlock approach will work fine if data points in other part of the series do not have high variation in values.

2. Few top cell values are disproportionately low and bottom cell values are disproportionately high

In this scenario, we cannot infer mean is less or more than the median. The top 5 cells’ values will drift mean towards lesser value, whereas bottom 4 cells’ values will drift it towards higher value. So it is difficult to infer which way mean will drift more.

So what to do in this scenario?

Well, GMAT is not going to test exactly this kind of scenario. Had this scenario been presented to you in the exam, there would have been some other concept applicable to deduce the answer. GMAT lays more importance on application of concepts than on long calculations.

While calculating mean, first arrange the data in ascending order.

o If values in the bottom cells are too high, then Mean > Median

o If values in the top cells are too low then Mean < Median

o If values at the top are too low, & bottom cells are too high, then

do not apply this approach.


EXERCISE QUESTION

‘13 students from a school were rated for their proficiency in 4 sports - higher the rating, more the proficiency. Table Tennis and Basketball scores are out of 100 points, Lawn Tennis out of 20 points, and badminton out of 50 points.’

Students Table

Tennis (100)

Lawn Tennis

(20)

Badminton (50)

Basket Ball

(100)

Angio 85 10 34 36

Gary 60 14 36 34

Jackson 70 6 40 28

John 65 16 30 32

Karren 75 4 48 84

Kent 90 18 38 38

Luke 80 8 32 30

Mathews 55 20 44 40

Messey 95 12 42 42

Stacey 7 20 48 65

Brent 9 20 49 48

Mary 11 19 5 46

Joe 21 18 4 36

For each of the following statements, select ‘Yes’ if statement is true based solely on the information provided in the table; otherwise select ‘No’.

Yes No

Q 1 o o Table tennis mean score is more than Basketball mean score.

Q 2 o o There are at least 3 sports, whose median scores are greater than their mean scores.

Q 3 o o If 2 new students Manish and Imran are included; whose Lawn Tennis scores are 5 & 19 respectively, then the mean score of Lawn Tennis increases by at least 2 points.

HOW TO COMPARE MEAN AND MEDIAN IN LESS - e-GMAT · ©e-GMAT LLC. Unauthorized copying for commercial and competitive purposes is not allowed. HOW TO COMPARE MEAN AND MEDIAN IN LESS

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