Hour 1: Conductors & Insulators Expt. 2: Electrostatic Force Hour … · 2019-08-15 · P07 - 5 Conductors and Insulators A conductor contains charges that are free to move (electrons

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Class 07: Outline

Hour 1:Conductors & Insulators Expt. 2: Electrostatic Force

Hour 2:Capacitors

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Last Time:Gauss’s Law

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Gauss’s Law

0closedsurface S

encE

Qdε

Φ = ⋅ =∫∫ E A

In practice, use symmetry:• Spherical (r)• Cylindrical (r, )• Planar (Pillbox, A)

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Conductors

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Conductors and InsulatorsA conductor contains charges that are free to move (electrons are weakly bound to atoms)Example: metals

An insulator contains charges that are NOT free to move (electrons are strongly bound to atoms)Examples: plastic, paper, wood

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Conductors

Conductors have free chargesE must be zero inside the conductorConductors are equipotential objects

E

Neutral Conductor

----

++++

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Equipotentials

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Topographic Maps

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Equipotential Curves

All points on equipotential curve are at same potential.Each curve represented by V(x,y) = constant

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PRS Question:Walking down a mountain

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Direction of Electric Field E

E is perpendicular to all equipotentials

Constant E field Point Charge Electric dipole

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Properties of Equipotentials

• E field lines point from high to low potential• E field lines perpendicular to equipotentials

• Have no component along equipotential• No work to move along equipotential

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Conductors in Equilibrium

Conductors are equipotential objects:1) E = 0 inside2) Net charge inside is 03) E perpendicular to surface 4) Excess charge on surface

0εσ=E

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Conductors in EquilibriumPut a net positive charge anywhere inside a

conductor, and it will move to the surface to get as far away as possible from the other charges of like sign.

http://ocw.mit.edu/ans7870/8/8.02T/f04/visualizations/electrostatics/34-pentagon/34-pentagon320.html

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Expt. 2: Electrostatic Force

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Expt. 2: Electrostatic Force

http://ocw.mit.edu/ans7870/8/8.02T/f04/visualizations/electrostatics/36-electrostaticforce/36-esforce320.html

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Experiment 2:Electrostatic Force

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Capacitors and Capacitance

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Capacitors: Store Electric EnergyCapacitor: two isolated conductors with equal and opposite charges Q and potential difference ∆V between them.

QCV

=∆

Units: Coulombs/Volt or Farads

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Parallel Plate Capacitor

0=E

0=E

Q Aσ+ =

Q Aσ− = −

d?E =

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Parallel Plate CapacitorWhen you put opposite charges on plates, charges move to the inner surfaces of the plates to get as close as possible to charges of the opposite sign

http://ocw.mit.edu/ans7870/8/8.02T/f04/visualizations/electrostatics/35-capacitor/35-capacitor320.html

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Calculating E (Gauss’s Law)

0S

inqdε

⋅ =∫∫ E A00 εε

σAQE ==( )

0

GaussGauss

AE A σε

=

Note: We only “consider” a single sheet! Doesn’t the other sheet matter?

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Alternate Calculation Method

+ + + + + + + + + + + + + +Top Sheet:02

E σε

= −

02E σ

ε=

- - - - - - - - - - - - - -Bottom Sheet: 02E σ

ε=

02E σ

ε= −

0 0 0 02 2QE

Aσ σ σε ε ε ε

= + = =

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Parallel Plate Capacitor

top

bottom

V d∆ = − ⋅∫ E S0

Q dAε

=Ed=dA

VQC 0ε=∆

=

C depends only on geometric factors A and d

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Demonstration:Big Capacitor

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Spherical CapacitorTwo concentric spherical shells of radii a and b

What is E?

Gauss’s Law E ≠ 0 only for a < r < b, where it looks like a point charge:

rE ˆ4 2

0rQπε

=

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Spherical Capacitor

For an isolated spherical conductor of radius a:

20

ˆ ˆ4

b

a

Q drrπε

= − ⋅∫r r

( )1104−− −

=∆

=baV

QC πε

outside

inside

V d∆ = − ⋅∫ E S0

1 14Q

b aπε⎛ ⎞= −⎜ ⎟⎝ ⎠

Is this positive or negative? Why?

aC 04πε=

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Capacitance of EarthFor an isolated spherical conductor of radius a:

aC 04πε=

mF1085.8 120

−×=ε m104.6 6×=a

mF7.0F107 4 =×= −C

A Farad is REALLY BIG! We usually use pF (10-12) or nF (10-9)

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1 Farad Capacitor

How much charge?

( )( )1F 12 V12C

Q C V= ∆==

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PRS Question:Changing C Dimensions

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Demonstration:Changing C Dimensions

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Energy Stored in Capacitor

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Energy To Charge Capacitor

1. Capacitor starts uncharged.2. Carry +dq from bottom to top.

Now top has charge q = +dq, bottom -dq3. Repeat4. Finish when top has charge q = +Q, bottom -Q

+q

-q

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Work Done Charging CapacitorAt some point top plate has +q, bottom has –q

Potential difference is ∆V = q / CWork done lifting another dq is dW = dq ∆V

+q

-q

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Work Done Charging CapacitorSo work done to move dq is:

dW dq V= ∆1qdq q dq

C C= =

Total energy to charge to q = Q:

0

1 Q

W dW q dqC

= =∫ ∫ +q

-q212

QC

=

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Energy Stored in CapacitorQCV

=∆

Since

22

21

21

2VCVQ

CQU ∆=∆==

Where is the energy stored???

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Energy Stored in Capacitor

Energy stored in the E field!

ando AC V Eddε

= =Parallel-plate capacitor:

212

U CV= ( )2

21 ( )2 2

o oA EEd Addε ε

= = × ( )Eu volume= ×

2

field energy density2

oE

Eu E ε= =

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1 Farad Capacitor - EnergyHow much energy?

( )( )

2

2

121 1F 12 V272 J

U C V= ∆

=

=

Compare to capacitor charged to 3kV:

( )( )

( )( )

22

24 3

1 1 100µF 3kV2 21 1 10 F 3 10 V 450 J2

U C V

−

= ∆ =

= × × =

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PRS Question:Changing C Dimensions

Energy Stored

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Demonstration:Dissectible Capacitor