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Hess’s Law: The algebraic addition of chemical equations yields a net equation whose enthalpy of reaction is the algebraic sum of the individual enthalpies.

Jan 19, 2016

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Page 1: Hess’s Law: The algebraic addition of chemical equations yields a net equation whose enthalpy of reaction is the algebraic sum of the individual enthalpies.
Page 2: Hess’s Law: The algebraic addition of chemical equations yields a net equation whose enthalpy of reaction is the algebraic sum of the individual enthalpies.

Hess’s Law:

The algebraic addition of chemical equations yields a net equation whose enthalpy of reaction is the algebraic sum of the individual enthalpies of reaction.

Hnet = Hr

Page 3: Hess’s Law: The algebraic addition of chemical equations yields a net equation whose enthalpy of reaction is the algebraic sum of the individual enthalpies.
Page 4: Hess’s Law: The algebraic addition of chemical equations yields a net equation whose enthalpy of reaction is the algebraic sum of the individual enthalpies.

1. If the reaction equation is reversed, the sign of the Hr also reverses.

2. If the coefficients of a reaction equation are changed by multiplying or dividing, then the value of Hr is changed in the same way.

Page 5: Hess’s Law: The algebraic addition of chemical equations yields a net equation whose enthalpy of reaction is the algebraic sum of the individual enthalpies.

1. Write the balanced chemical equation.

2. Manipulate the given equations so they will add to the net equation.

3. Cancel and Add the remaining reactants and products.

4. Add the component enthalpy changes to obtain the net enthalpy.

5. Determine the molar enthalpy of reaction if required.

Page 6: Hess’s Law: The algebraic addition of chemical equations yields a net equation whose enthalpy of reaction is the algebraic sum of the individual enthalpies.
Page 7: Hess’s Law: The algebraic addition of chemical equations yields a net equation whose enthalpy of reaction is the algebraic sum of the individual enthalpies.

a) Using the reactions given below, determine the heat of reaction for the equation:

2U(s) + 3O2(g) 2UO3(s)

1) 2UO3(s) 2UO2(s) + O2(g) Hr = 260 kJ

2) U(s) + O2(g) UO2(g) Hr = -1130 kJ

b) Determine the molar heat of reaction

Practice

Page 8: Hess’s Law: The algebraic addition of chemical equations yields a net equation whose enthalpy of reaction is the algebraic sum of the individual enthalpies.

elements are set as the reference energy state where the potential energy is 0.

formation reactions can be endothermic (+H) or exothermic (-H) (p 4-5 data book)

simple decomposition is the reverse of a formation reaction so reverse the sign of H

Page 9: Hess’s Law: The algebraic addition of chemical equations yields a net equation whose enthalpy of reaction is the algebraic sum of the individual enthalpies.

thermal stability: ability to resist decomposition

the more exothermic a formation reaction, the more endothermic the decomposition= greater thermal stability

Compound Molar Enthalpy of Formation kJ/mol

aluminum oxide -1675.7

copper (I) oxide -168.6

nitrogen monoxide +91.3

Most stable: aluminum oxideLeast stable: nitrogen monoxide

Page 10: Hess’s Law: The algebraic addition of chemical equations yields a net equation whose enthalpy of reaction is the algebraic sum of the individual enthalpies.

To determine the standard enthalpy of a reaction, the sum of the enthalpies of formation of the reactants is subtracted from the sum of the enthalpies of formation of the products.

Mathematically, this can be written as:Hnet = nHf(prod) - nHf(react))

Page 11: Hess’s Law: The algebraic addition of chemical equations yields a net equation whose enthalpy of reaction is the algebraic sum of the individual enthalpies.

watch state of the compound as this affects the molar enthalpy of formation

◦Ex) H20(l) Ho = -285.8 kJ/mol

H20(g) Ho = -241.8 kJ/mol

-combustion in bomb calorimeter produces H20(l)

Page 12: Hess’s Law: The algebraic addition of chemical equations yields a net equation whose enthalpy of reaction is the algebraic sum of the individual enthalpies.

Examples:

1. Show the decomposition and formation reactions, with their respective enthalpies for the combustion of propane.

2. Determine the heat of reaction for the reaction of sulfuric acid with magnesium chloride.

3. Determine the enthalpy of reaction for the combustion of 100 g of sucrose.

Page 13: Hess’s Law: The algebraic addition of chemical equations yields a net equation whose enthalpy of reaction is the algebraic sum of the individual enthalpies.

4. What mass of nitrogen monoxide must react to release 1.00 MJ of energy for the following reaction:2NO(g) + O2(g) 2NO2(g)

5. The molar enthalpy of combustion of octane

is -5047.1kJ/mol. Determine the molar enthalpy of formation of octane.