Heat Exchanger

shell side tube sideID = 21.25 in jumlah tube = 157.7863964 158baffle space = 5 in lenght = 16 ftpasses = 1 OD = 1 in

BWG = 13 BWGID = 0.81 inpitch = 1.25 in^2passes = 4a" = 0.2618 ft^2/ln ft

asumsi Ud = 50.7A = 660.935657110088 pers 5.13a

1 heat balancefluida 1 W= 43800 lb/jam Q =fluida2 w= 149000 lb/jam

2hot fluid cold fluid diff

390 higher temperature 170 220200 lower temperature 100 100190 differences 70 120

T1 - T2 t2 - t1LMTD = 152.195928445084R= 2.71428571428571

S = 0.241379310344828ft = 0.905 fig 18

137.737315242801 pers 7.423 Tc dan tc

0.454545454545455 fig 17Kc = 0.2Fc = 0.42Tc = 279.8 pers 5.28tc = 129.4 pers 5.29

shell side : hot fluid4' flow area

as = 0.147569444444444 ft^2 pers 7.15' mass velocity

Gs = 296809.411764706 lb/(jam.ft^2) pers 7.26' Res

De = 0.0825 ft fig 28pada Tc = 279.8

0.968 lb/(ft.jam) fig 14Res = 25296.256684492 pers 7.3

7' jH = 93 fig 288' pada Tc = 279.8

c = 0.59 Btu/(lb.F) fig 4k = 0.0765 Btu/(jam.ft^2.(F/Ft)) fig 1

1.954438359696349' 168.543657091632 pers 6.15b10' tube wall temperature

tw = 220.660429385474 pers 5.31

∆t :

∆t2 - ∆t1

∆t =

∆tc/∆th =

μ =

(cμ/k)^(1/3) =ho/Øs =

11' pada tw = 220.6604293854741.3552 lb/(ft.jam) fig 14

0.953789628535757 fig 24 insert12' corrected coefficient

h0 = 160.755192089486 Btu/(jam.ft^2.F) pers 6.3613' clean overall Uc

Uc = 69.8237263957073 Btu/(jam.ft^2.F) pers 6.3814 design overall coefficient

Ud A = 661.8304 ft^2Ud = 55.9463619547081 Btu/(jam.ft^2.F)

15 dirt factorRd = 0.0035524839145243 jam.ft^2.F/Btu

160.75519208949 h outside 123.439410807975Uc 69.8237263957073Ud 55.9463619547081Rd calculated 0.00348Rd required 0.003

1' untuk Res = 25296.256684492f = 0.00175 ft^2/in^2 fig 29s = 0.73 fig 6Ds = 1.77083333333333 ft

2' no. Of crossesN + 1 = 38.4 pers 7.43

393' 3.55087817972021 psi pers 7.44

10 psi

μw =Øs =

∆Ps =allowable ∆ps =

5100000 Btu/jam

4 flow areaat' = 0.515 in tabel 10at= 0.141267 ft^2 pers 7.48

5 mass velocityGt = 1054738 lb/(ft.jam)

6 Ret pada tc = 129.4

8.712 lb/(ft.jam) fig 14D = 0.0675 ft^2 tabel 10Ret = 8172.037

7 L/D = 237.037jH = 31 fig 24

8 pada tc = 129.4c = 0.49 Btu/(lb.F) fig 4k = 0.077 Btu/(jam.ft^2.(F/ft)) fig 1

3.8130679 hi

μ =

(cμ/k)^(1/3) =

134.8413 pers 6.15a10 109.2215 pers 6.511 pada tw = 220.6604

3.63 lb/(ft.jam) fig 14Øt = 1.130175 fig 24 insert

12 corrected coeficienthi0 = 123.4394 Btu/(jam.ft^2.(F/ft)) pers 6.37

1 untuk Ret = 8172.037f = 0.000285 ft^2/in^2 fig 26s = 0.83 fig 6

2 6.139254 psi pers 7.453 Gt = 1054738

V^2/2g' = 0.15 fig 272.891566 psi pers 7.46

4 9.03082 psi pers 7.47allowable ∆PT = 10 psi

hi/Øt =hio/Øt =

μw =

∆Pt =

∆Pr =∆PT =

shell side tube sideID = 21.25 in jumlah tub 8.480749 9baffle spac 5 in lenght = 16 ftpasses = 1 OD = 1 in

BWG = 18 BWGID = 0.902 inpitch = 1.25 in^2passes = 2a" = 0.2618 ft^2/ln ft

asumsi Ud 400A = 35.5241611354698 pers 5.13a

1 heat balancefluida 1 W= 14620 lb/jam Q = 1309896 Btu/jamfluida2 w= 4172.524 lb/jam 1381940 kJ/jam

panas laten uap pada 350 C = 736 kJ/kg2 313.9336 Btu/lb

hot fluid cold fluid diff680 higher temperature 662 18680 lower temperature 413.6 266.4

0 differences 248.4 -248.4T1 - T2 t2 - t1

LMTD = 92.1834388715R= 0

S = 0.600580270793037ft = 0.905 fig 18

83.4260121787075 pers 7.423 Tc dan tc

14.8 fig 17Kc = 0.2Fc = 0.42Tc = 680 pers 5.28tc = 517.928 pers 5.29

shell side : hot fluid4' flow area 4 flow area

as = 0.295138888888889 ft^2 pers 7.1 at' =5' mass velocity at=

Gs = 49536 lb/(jam.ft^pers 7.2 5 mass velocity6' Res Gt =

De = 0.0825 ft fig 28 6 Ret pada Tc = 680 pada tc =

0.0605 lb/(ft.jam) fig 14Res = 67549.0909090909 pers 7.3 D =

7' jH = 140 fig 28 Ret =8' pada Tc = 680 7 L/D =

c = 2.3 Btu/(lb.F) fig 4 jH =k = 0.028 Btu/(jam.ftfig 1 8 pada tc =

1.70650825362258 c =9' 81.0849982327336 pers 6.15b k =10' tube wall temperature

∆t :

∆t2 - ∆t1

∆t =

∆tc/∆th =

μ = μ =

(cμ/k)^(1/3) =ho/Øs =

(cμ/k)^(1/3) =

tw = 550.011533878626 pers 5.31 9 hi11' pada tw = 550.011533878626

0.0605 lb/(ft.jam) fig 14 100.953789628535757 fig 24 insert 11 pada tw =

12' corrected coefficienth0 = 1500 Btu/(jam.ftpers 6.36 Øt =

13' clean overall Uc 12 corrected coeficientUc = 297.618501830613 Btu/(jam.ftpers 6.38 hi0 =

14 design overall coefficientUd A = 37.6992 ft^2Ud = 416.488590996901 Btu/(jam.ft^2.F)

15 dirt factorRd = -0.000958980007327043 jam.ft^2.F/Btu

1500 h outside 371.2863Uc 297.618501830613Ud 416.488590996901Rd calcula -0.000958980007327043Rd require 0.003

1' untuk Res 67549.0909090909 1 untuk Ret f = 0.00175 ft^2/in^2 fig 29 f =s = 0.73 fig 6 s =Ds = 1.77083333333333 ft 2

2' no. Of crosses 3 Gt =N + 1 = 38.4 pers 7.43 V^2/2g' =

393' 0.0989059243444398 psi pers 7.44 4

10 psi allowable

hi/Øt =μw = hio/Øt =Øs =

μw =

∆Pt =

∆Pr =∆Ps = ∆PT =allowable ∆ps =

0.515 in tabel 100.016094 ft^2 pers 7.48

mass velocity259263.6 lb/(ft.jam)

517.9280.04356 lb/(ft.jam) fig 14

0.075167 ft^2 tabel 10447382.5212.8603

800 fig 24517.928

2.3 Btu/(lb.F) fig 40.02 Btu/(jam.ftfig 1

1.711047

364.214 pers 6.15a328.521 pers 6.5

550.01153.63 lb/(ft.jam) fig 14

1.130175 fig 24 insertcorrected coeficient

371.2863 Btu/(jam.ftpers 6.37

447382.50.000285 ft^2/in^2 fig 26

0.83 fig 60.166555 psi pers 7.45259263.6

0.15 fig 271.445783 psi pers 7.461.612338 psi pers 7.47

10 psi

shell side tube sideID = 21.25 in jumlah tub 62.31225 63baffle spac 5 in lenght = 16 ftpasses = 1 OD = 1 in

BWG = 18 BWGID = 0.902 inpitch = 1.25 in^2passes = 2a" = 0.2618 ft^2/ln ft

asumsi Ud 20A = 261.0136 pers 5.13a

Cp air1 heat balance a

fluida 1 W= 14620 lb/jam Q = 2003244 Btu/jam 18.3fluida2 w= 96283.9 lb/jam 2113422 kJ/jam

Cp air = 35.11984 kJ/kmol.C1.849386 Btu/kg.C0.832224 Btu/lb.C

2hot fluid cold fluid diff

662 higher tem 122 540338 lower temp 77 261324 differences 45 279

T1 - T2 t2 - t1LMTD = 383.7432R= 7.2

S = 0.112219ft = 0.905 fig 18

347.2876 pers 7.423 Tc dan tc

0.483333 fig 17Kc = 0.2Fc = 0.42Tc = 474.08 pers 5.28tc = 95.9 pers 5.29

shell side : hot fluid4' flow area 4 flow area

as = 0.295139 ft^2 pers 7.1 at' = 0.515 in5' mass velocity at= 0.112656 ft^2

Gs = 49536 lb/(jam.ft^pers 7.2 5 mass velocity6' Res Gt = 854669.9 lb/(ft.jam)

De = 0.0825 ft fig 28 6 Ret pada Tc = 474.08 pada tc = 95.9

0.0605 lb/(ft.jam) fig 14 0.04356 lb/(ft.jam)Res = 67549.09 pers 7.3 D = 0.075167 ft^2

7' jH = 140 fig 28 Ret = 14748098' pada Tc = 474.08 7 L/D = 212.8603

c = 2.3 Btu/(lb.F) fig 4 jH = 800k = 0.028 Btu/(jam.ftfig 1 8 pada tc = 95.9

1.706508 c = 2.3 Btu/(lb.F)

∆t :

∆t2 - ∆t1

∆t =

∆tc/∆th =

μ = μ =

(cμ/k)^(1/3) =

9' 81.085 pers 6.15b k = 0.02 Btu/(jam.ft10' tube wall temperature 1.711047

tw = 170.764 pers 5.31 9 hi11' pada tw = 170.764 364.214

0.0605 lb/(ft.jam) fig 14 10 328.5210.95379 fig 24 insert 11 pada tw = 170.764

12' corrected coefficient 3.63 lb/(ft.jam)h0 = 77.33803 Btu/(jam.ftpers 6.36 Øt = 1.130175

13' clean overall Uc 12 corrected coeficientUc = 64.00578 Btu/(jam.ftpers 6.38 hi0 = 371.2863 Btu/(jam.ft

14 design overall coefficientUd A = 263.8944 ft^2Ud = 21.8582 Btu/(jam.ft^2.F)

15 dirt factorRd = 0.030126 jam.ft^2.F/Btu

77.33803 h outside 371.2863Uc 64.0057814913631Ud 21.8581966599404Rd calcula 0.030125839630016Rd require 0.003

1' untuk Res 67549.09 1 untuk Ret 1474809f = 0.00175 ft^2/in^2 fig 29 f = 0.000285 ft^2/in^2s = 0.73 fig 6 s = 0.83Ds = 1.770833 ft 2 1.809972 psi

2' no. Of crosses 3 Gt = 854669.9N + 1 = 38.4 pers 7.43 V^2/2g' = 0.15

39 1.445783 psi3' 0.098906 psi pers 7.44 4 3.255756 psi

10 psi allowable 10 psi

ho/Øs =(cμ/k)^(1/3) =

hi/Øt =μw = hio/Øt =Øs =

μw =

∆Pt =

∆Pr =∆Ps = ∆PT =allowable ∆ps =

bT cT^2 dT30.472 -0.00134 0.00000131

tabel 10pers 7.48

fig 14tabel 10

fig 24

fig 4

fig 1

pers 6.15apers 6.5

fig 14fig 24 insert

pers 6.37

fig 26fig 6pers 7.45

fig 27pers 7.46pers 7.47

shell side tube sideID = 21.25 in jumlah tub 4.743003 9baffle spac 5 in lenght = 16 ftpasses = 1 OD = 1 in

BWG = 18 BWGID = 0.902 inpitch = 1.25 in^2passes = 2a" = 0.2618 ft^2/ln ft

asumsi Ud 350A = 19.86749 pers 5.13a

1 heat balancefluida 1 W= 14620 lb/jam Q = 1042831 Btu/jamfluida2 w= 8377.858 lb/jam 1100187 kJ/jam

kJ/kg2 0.83 Btu/lb

hot fluid cold fluid diff338 higher tem 122 216176 lower temp 77 99162 differences 45 117

T1 - T2 t2 - t1LMTD = 149.9695R= 3.6

S = 0.188285ft = 0.905 fig 18

135.7224 pers 7.423 Tc dan tc

0.458333 fig 17Kc = 0.2Fc = 0.42Tc = 244.04 pers 5.28tc = 95.9 pers 5.29

shell side : hot fluid4' flow area 4 flow area

as = 0.295139 ft^2 pers 7.1 at' = 0.515 in5' mass velocity at= 0.016094 ft^2

Gs = 49536 lb/(jam.ft^pers 7.2 5 mass velocity6' Res Gt = 520565.9 lb/(ft.jam)

De = 0.0825 ft fig 28 6 Ret pada Tc = 244.04 pada tc = 95.9

0.0605 lb/(ft.jam) fig 14 0.04356 lb/(ft.jam)Res = 67549.09 pers 7.3 D = 0.075167 ft^2

7' jH = 140 fig 28 Ret = 898282.98' pada Tc = 244.04 7 L/D = 212.8603

c = 2.3 Btu/(lb.F) fig 4 jH = 800k = 0.028 Btu/(jam.ftfig 1 8 pada tc = 95.9

1.706508 c = 2.3 Btu/(lb.F)9' 81.085 pers 6.15b k = 0.02 Btu/(jam.ft10' tube wall temperature 1.711047

∆t :

∆t2 - ∆t1

∆t =

∆tc/∆th =

μ = μ =

(cμ/k)^(1/3) =ho/Øs =

(cμ/k)^(1/3) =

tw = 125.2256 pers 5.31 9 hi11' pada tw = 125.2256 364.214

0.0605 lb/(ft.jam) fig 14 10 328.5210.95379 fig 24 insert 11 pada tw = 125.2256

12' corrected coefficient 3.63 lb/(ft.jam)h0 = 77.33803 Btu/(jam.ftpers 6.36 Øt = 1.130175

13' clean overall Uc 12 corrected coeficientUc = 64.00578 Btu/(jam.ftpers 6.38 hi0 = 371.2863 Btu/(jam.ft

14 design overall coefficientUd A = 37.6992 ft^2Ud = 203.8123 Btu/(jam.ft^2.F)

15 dirt factorRd = -0.010717 jam.ft^2.F/Btu

77.33803 h outside 371.2863Uc 64.0057814913631Ud 203.812281555982Rd calcula -0.01071711296402Rd require 0.003

1' untuk Res 67549.09 1 untuk Ret 898282.9f = 0.00175 ft^2/in^2 fig 29 f = 0.000285 ft^2/in^2s = 0.73 fig 6 s = 0.83Ds = 1.770833 ft 2 0.67147 psi

2' no. Of crosses 3 Gt = 520565.9N + 1 = 38.4 pers 7.43 V^2/2g' = 0.15

39 1.445783 psi3' 0.098906 psi pers 7.44 4 2.117253 psi

10 psi allowable 10 psi

hi/Øt =μw = hio/Øt =Øs =

μw =

∆Pt =

∆Pr =∆Ps = ∆PT =allowable ∆ps =

tabel 10pers 7.48

fig 14tabel 10

fig 24

fig 4fig 1

pers 6.15apers 6.5

fig 14fig 24 insert

pers 6.37

fig 26fig 6pers 7.45

fig 27pers 7.46pers 7.47

shell side tube sideID = 21.25 in jumlah tub 41.257 9baffle spac 5 in lenght = 16 ftpasses = 1 OD = 1 in

BWG = 18 BWGID = 0.902 inpitch = 1.25 in^2passes = 2a" = 0.2618 ft^2/ln ft

asumsi Ud 100A = 172.8173 pers 5.13a

1 heat balancefluida 1 W= 14620 lb/jam Q = 434030.3 Btu/jamfluida2 w= 20821.36 lb/jam 457902 kJ/jam

kJ/kg2 0.83 Btu/lb

hot fluid cold fluid diff176 higher tem 122 5477 lower temp 68 999 differences 54 45

T1 - T2 t2 - t1LMTD = 25.11498R= 1.833333

S = 0.323353ft = 0.905 fig 18

22.72906 pers 7.423 Tc dan tc

0.166667 fig 17Kc = 0.2Fc = 0.42Tc = 118.58 pers 5.28tc = 90.68 pers 5.29

shell side : hot fluid4' flow area 4 flow area

as = 0.295139 ft^2 pers 7.1 at' = 0.515 in5' mass velocity at= 0.016094 ft^2

Gs = 49536 lb/(jam.ft^pers 7.2 5 mass velocity6' Res Gt = 1293755 lb/(ft.jam)

De = 0.0825 ft fig 28 6 Ret pada Tc = 118.58 pada tc = 90.68

0.0605 lb/(ft.jam) fig 14 0.04356 lb/(ft.jam)Res = 67549.09 pers 7.3 D = 0.075167 ft^2

7' jH = 140 fig 28 Ret = 22324898' pada Tc = 118.58 7 L/D = 212.8603

c = 2.3 Btu/(lb.F) fig 4 jH = 800k = 0.028 Btu/(jam.ftfig 1 8 pada tc = 90.68

1.706508 c = 2.3 Btu/(lb.F)9' 81.085 pers 6.15b k = 0.02 Btu/(jam.ft10' tube wall temperature 1.711047

∆t :

∆t2 - ∆t1

∆t =

∆tc/∆th =

μ = μ =

(cμ/k)^(1/3) =ho/Øs =

(cμ/k)^(1/3) =

tw = 96.20304 pers 5.31 9 hi11' pada tw = 96.20304 364.214

0.0605 lb/(ft.jam) fig 14 10 328.5210.95379 fig 24 insert 11 pada tw = 96.20304

12' corrected coefficient 3.63 lb/(ft.jam)h0 = 77.33803 Btu/(jam.ftpers 6.36 Øt = 1.130175

13' clean overall Uc 12 corrected coeficientUc = 64.00578 Btu/(jam.ftpers 6.38 hi0 = 371.2863 Btu/(jam.ft

14 design overall coefficientUd A = 37.6992 ft^2Ud = 506.5316 Btu/(jam.ft^2.F)

15 dirt factorRd = -0.013649 jam.ft^2.F/Btu

77.33803 h outside 371.2863Uc 64.0057814913631Ud 506.531620773891Rd calcula -0.01364937821807Rd require 0.003

1' untuk Res 67549.09 1 untuk Ret 2232489f = 0.00175 ft^2/in^2 fig 29 f = 0.000285 ft^2/in^2s = 0.73 fig 6 s = 0.83Ds = 1.770833 ft 2 4.14743 psi

2' no. Of crosses 3 Gt = 1293755N + 1 = 38.4 pers 7.43 V^2/2g' = 0.15

39 1.445783 psi3' 0.098906 psi pers 7.44 4 5.593213 psi

10 psi allowable 10 psi

hi/Øt =μw = hio/Øt =Øs =

μw =

∆Pt =

∆Pr =∆Ps = ∆PT =allowable ∆ps =

tabel 10pers 7.48

fig 14tabel 10

fig 24

fig 4fig 1

pers 6.15apers 6.5

fig 14fig 24 insert

pers 6.37

fig 26fig 6pers 7.45

fig 27pers 7.46pers 7.47

shell side tube sideID = 21.25 in jumlah tub 1.159458 9baffle spac 5 in lenght = 16 ftpasses = 1 OD = 1 in

BWG = 18 BWGID = 0.902 inpitch = 1.25 in^2passes = 2a" = 0.2618 ft^2/ln ft

asumsi Ud 400A = 4.856739 pers 5.13a

1 heat balancefluida 1 W= 5475 lb/jam Q = 179084.4 Btu/jamfluida2 w= 186.0227 lb/jam 188934 kJ/jam

panas late 2257 kJ/kg2 962.7014 Btu/lb

hot fluid cold fluid diff680 higher tem 662 18680 lower temp 413.6 266.4

0 differences 248.4 -248.4T1 - T2 t2 - t1

LMTD = 92.18344R= 0

S = 0.60058ft = 0.905 fig 18

83.42601 pers 7.423 Tc dan tc

14.8 fig 17Kc = 0.2Fc = 0.42Tc = 680 pers 5.28tc = 517.928 pers 5.29

shell side : hot fluid4' flow area 4 flow area

as = 0.295139 ft^2 pers 7.1 at' = 0.515 in5' mass velocity at= 0.016094 ft^2

Gs = 18550.59 lb/(jam.ft^pers 7.2 5 mass velocity6' Res Gt = 11558.69 lb/(ft.jam)

De = 0.0825 ft fig 28 6 Ret pada Tc = 680 pada tc = 517.928

0.0605 lb/(ft.jam) fig 14 0.04356 lb/(ft.jam)Res = 25296.26 pers 7.3 D = 0.075167 ft^2

7' jH = 140 fig 28 Ret = 19945.568' pada Tc = 680 7 L/D = 212.8603

c = 2.3 Btu/(lb.F) fig 4 jH = 800k = 0.028 Btu/(jam.ftfig 1 8 pada tc = 517.928

1.706508 c = 2.3 Btu/(lb.F)9' 81.085 pers 6.15b k = 0.02 Btu/(jam.ft10' tube wall temperature 1.711047

∆t :

∆t2 - ∆t1

∆t =

∆tc/∆th =

μ = μ =

(cμ/k)^(1/3) =ho/Øs =

(cμ/k)^(1/3) =

tw = 550.0115 pers 5.31 9 hi11' pada tw = 550.0115 364.214

0.0605 lb/(ft.jam) fig 14 10 328.5210.95379 fig 24 insert 11 pada tw = 550.0115

12' corrected coefficient 3.63 lb/(ft.jam)h0 = 77.33803 Btu/(jam.ftpers 6.36 Øt = 1.130175

13' clean overall Uc 12 corrected coeficientUc = 64.00578 Btu/(jam.ftpers 6.38 hi0 = 371.2863 Btu/(jam.ft

14 design overall coefficientUd A = 37.6992 ft^2Ud = 56.94086 Btu/(jam.ft^2.F)

15 dirt factorRd = 0.001938 jam.ft^2.F/Btu

77.33803 h outside 371.2863Uc 64.0057814913631Ud 56.9408624480141Rd calcula 0.001938491692893Rd require 0.003

1' untuk Res 25296.26 1 untuk Ret 19945.56f = 0.00175 ft^2/in^2 fig 29 f = 0.000285 ft^2/in^2s = 0.73 fig 6 s = 0.83Ds = 1.770833 ft 2 0.000331 psi

2' no. Of crosses 3 Gt = 11558.69N + 1 = 38.4 pers 7.43 V^2/2g' = 0.15

39 1.445783 psi3' 0.013871 psi pers 7.44 4 1.446114 psi

10 psi allowable 10 psi

hi/Øt =μw = hio/Øt =Øs =

μw =

∆Pt =

∆Pr =∆Ps = ∆PT =allowable ∆ps =

tabel 10pers 7.48

fig 14tabel 10

fig 24

fig 4fig 1

pers 6.15apers 6.5

fig 14fig 24 insert

pers 6.37

fig 26fig 6pers 7.45

fig 27pers 7.46pers 7.47

annulus : 2 inOD = 2.38 inID = 2.067 ininner pipe : 1.25 inOD = 1.66 inID = 1.38 insurface per lin ft = 0.435 ft^2/ft

1 heat balancehot fluid = W = 6330 lb/jam

c = 0.44 Btu/lb.Fcold fluid w = 9820 lb/jam Q =

c = 0.425 Btu/lb.F2 LMTD

hot fluid cold fluid diff160 higher temperature 120 40100 lower temperature 80 20

20LMTD = 28.8863312598901

3 kalorik temperatureTav = 130tav = 100cek tabel 6.2

annulus : hot fluid4' flow area

D2 = 0.17225 ft tabel 11D1 = 0.138333333333333 ft

0.0082691518402778 ft^2 pers 6.3De = 0.076149046184739 ft

5' mass velocityGa = 765495.678670155 lb/jam.ft^2

6' pada Tc = 1300.41 cp

0.9922 lb/jam.ftRea = 58750.0159133962

7' jH = 167 fig 248' pada Tc = 130

c = 0.44 Btu/lb.F fig 2k = 0.085 Btu/jam.ft^2.(F/ft)) tabel 4

(cμ/k)^(1/3) 1.725351786283419' h0 = 321.624102117792 Btu/jam.ft^2.F

11 clean overall,UcUc = 148.687757378379 Btu/jam.ft^2.F

12 design overall coefficientasumsi Rd = 0.002 jam.ft^2.F/Btu1/Ud = 0.0087255032803758Ud = 114.606569714903 Btu/jam.ft^2.F

summary

∆t2∆t1∆t2 - ∆t1

αa =

μ =

321.624102117792 h outside 276.526987631133Uc = 148.687757378379Ud = 114.606569714903

13 required surfaceQ =A =

50.4445869124986 ft^2required lenght = 115.964567614939 lin ft

120number hairpins required =

14 surface suplied = 52.2 ft^2Ud = 110.752510856834 Btu/jam.ft^2.FRd = 0.0023036373888833 jam.ft^2.F/Btu

pressure drop1' De' = 0.0339166666666667 ft

Rea' = 26167.1656603804f = 0.007182528525489 pers 3.47bs = 0.87 tabel 6

54.3 lb/ft^32' 24.1648989741801 ft3' V = 3.91597953074563 fps

Ft = 0.714358494653046 ft9.38155333720584 psi

allowable Pa =

Ud x A x ∆tQ/(Ud x ∆t)

ρ =∆Fα =

∆Pa =

167000 Btu/jam

inner pipe : cold fluid4 D = 0.115 ft

flow areaap = 0.010381625 ft^2

5 mass velocityGp = 945902.01438 lb/jam.ft^2

6 pada tc = 1000.5 cp

1.21 lb/ft.jamRep = 89899.778226

7 jH = 236 fig 248 pada tc = 100

c = 0.425 Btu/lb.Fk = 0.091 Btu/jam.ft^2.(F/ft))

1.78119295759 hi = 332.63391266 Btu/jam.ft^2.F

10 corect hi to surface at ODhi0 = 276.52698763

μ =

(cμ/k)^(1/3) =

1 Rep = 89899.778226f= 0.0056929327s = 0.88

55 lb/ft^3 tabel 62 8.4069815064 ft

3.2109998809 psiallowable ∆Pp =

ρ =∆Fp =∆Pp =

annulus : 2 inOD = 2.38 inID = 2.067 ininner pipe 1.25 inOD = 1.66 inID = 1.38 insurface per 0.435 ft^2/ft

1 heat balancehot fluid = W = 4172.5 lb/jam

c = Btu/lb.Fcold fluid w = 14620 lb/jam Q = 1309896 Btu/jam

c = Btu/lb.F2 LMTD

hot fluid cold fluid diff680 higher tem 662 18680 lower temp 413.6 266.4

-248.4LMTD = 92.28705

3 kalorik temperatureTav = 680tav = 537.8cek tabel 6.2

annulus : hot fluid inner pipe cold fluid4' flow area 4 D = 0.115 ft

D2 = 0.17225 ft tabel 11 flow areaD1 = 0.138333 ft ap = 0.010382 ft^2

0.008269 ft^2 pers 6.3 5 mass velocityDe = 0.076149 ft Gp = 1408257 lb/jam.ft^2

5' mass velocity 6 pada tc = 537.8Ga = 504586.2lb/jam.ft^2 0.5 cp

6' pada Tc = 680 1.21 lb/ft.jam0.41 cp Rep = 133842.6

0.9922 lb/jam.ft 7 jH = 236Rea = 38725.82 8 pada tc = 537.8

7' jH = 167 fig 24 c = 0.425 Btu/lb.F8' pada Tc = 680 k = 0.091 Btu/jam.ft^2.(F/ft))

c = 0.44 Btu/lb.F fig 2 1.781193k = 0.085 Btu/jam.ft t̂abel 4 9 hi = 332.6339 Btu/jam.ft^2.F

(cμ/k)^(1/3 1.725352 10 corect hi to surface at OD9' h0 = 321.6241 Btu/jam.ft^2.F hi0 = 276.527

11 clean overall,UcUc = 148.6878 Btu/jam.ft^2.F

12 design overall coefficientasumsi Rd 0.002 jam.ft^2.F/Btu1/Ud = 0.008726Ud = 114.6066 Btu/jam.ft^2.F

summary

∆t2∆t1∆t2 - ∆t1

αa =

μ =

μ =

(cμ/k)^(1/3) =

321.6241 h outside 276.527Uc = 148.687757378379Ud = 114.606569714903

13 required surfaceQ =A =

123.8473 ft^2required le 284.7064 lin ft

120number hairpins required =

14 surface sup 52.2 ft^2Ud = 271.9102 Btu/jam.ft^2.FRd = -0.003048 jam.ft^2.F/Btu

pressure drop1' De' = 0.033917 ft 1 Rep = 133842.6

Rea' = 17248.42 f= 0.005355f = 0.007887 pers 3.47b s = 0.88s = 0.87 tabel 6 55 lb/ft^3

54.3 lb/ft^3 2 17.52938 ft2' 11.52937 ft 6.69525 psi3' V = 2.581268 fps allowable ∆Pp =

Ft = 0.310386 ft4.464575 psi

allowable

Ud x A x ∆tQ/(Ud x ∆t)

ρ =ρ = ∆Fp =∆Fα = ∆Pp =

∆Pa =

lb/jam.ft^2

fig 24

Btu/jam.ft^2.(F/ft))

Btu/jam.ft^2.F

tabel 6

shell side tube sideID = 33 in number =Baffle space = 30 in lenght =passes = 1 OD =c' = 0.25 BWG =

ID =pitch =passes =a" =flow area =

asumsi Ud = 100A = 2437.75502268398 ft^2Q shell = 21203000 btu/jamQ air = 21203000 btu/jam w =T air masuk = 80.6T air keluar = 120.2komponen lb/jam mr mol/jamc3 7505 44.0176 170.5c4 16505 58.1162 284c6 4890 86.09155 56.8c7 34150 100.1173 341.1c8 32400 114.0845 284

95450 1136.4average molecular weght = 83.9933122140092karena MR rata2 mendekati mr = toluene maka digunakan sifat =dew point = 283bubble point = 120cp = 0.6condensate sensible heat = 4667505 Btu/jamsubmergence = 22.0134179125595 %hot fluid cold fluid

283 higher temp 120.2 162.8120 lower temp 80.6 39.4163 diff 39.6 -123.4

86.97756666564233 Tc dan tc

dapat digunaka T rata2Tc = 201.5tc = 100.4shell side

4' unsubmerged tubes = 605.29859330621G" = 83.3699434642527asumsi h = 200Tv = 201.5tw = 115.716634683365 Ftf = 158.608317341683 Fsf = 0.6 fig 6

0.21 cp fig 14kf = 0.077btu/jam.ft^2(F/ft) tabel 4h = 206 fig 12.9

clean overall coefficient

∆t =

μf =

Uc = 174.000201085864 btu/(jam.ft^2.F)clean surface required for condensation

Ac = 1401.00701463042 ft^2clean surface required for subcoolingAs = 308.409529114868 ft^2

total surface required ACtotal = 1709.41654374528

weighted overall clean coeficientUc = 142.607431266748

design overall coeficient Uda" 0.1963

total surface = 2437.75502268398Ud = 100

dirt factor RdRd = 0.002987742706553 jam.ft^2.F 6.13pressure drop

1' as = 1.71875 ft^2Gs = 55534.5454545455 lb/jamft^2pada T1 = 283

0.02178 lb/ft.jamDe = 0.0608333333333333 ft fig 15Res = 155112.558087765f = 0.00125

2' no. Of crosses(N + 1) = 6.4rho = P/RT 0.527 lb/ft^3s = 0.008432Ds = 2.75 ft

3' 1.26699941197955 psi 12.57

summary206 h outside 1120.133

Uc = 142.607431266748Ud = 100Rd calculated = 0.00298774270655298Rd required = 0.004

1.26699941197955 11.485282 10

μ =

∆Ps =

calculated ∆Pallowable ∆P

776.157416 ft

0.75 in16

0.6214

0.19630.302

535429.3 lb/jam

170.5284

56.8341.1

284

toluene

tube side4 flow area

at' = 0.302 in^2at = 0.406944 ft^2

5 Gt = 1315733 lb/(jam.ft^2)V = 5.847704 fpsrho air = 62.5

6 hi = 1355 fig 25hi0 = 1120.133 Btu/(jam.ft^2.F)

1 pada t = 100.41.7424 lb/ft.jam fig 14

D = 0.051667 ftRet = 39014.9f = 0.00019 ft/in^2 fig 25

2 7.805279 psi3

V^2/2g = 0.23 fig 273.68 psi pers 7.46

4 ∆Pt = 11.48528 psi pers 7.47

μ =

∆Pt =∆Pr

∆Pr =

shell side tube sideID = 25 in jumlah tub 31.65716 32baffle spac 5 in lenght = 16 ftpasses = 1 OD = 1 in

BWG = 18 BWGID = 0.902 inpitch = 1.25 in^2passes = 1a" = 0.2618 ft^2/ln ft

asumsi Ud 32A = 132.6055 pers 5.13a

1 heat balancefluida 1 W= 14620 lb/jam Q = 2385626 Btu/jamfluida2 w= 114693.5 lb/jam 2516835 kJ/jam

35 kJ/kg2 0.832 Btu/lb

hot fluid cold fluid diff662 higher tem 122 540662 lower temp 77 585

0 differences 45 -45T1 - T2 t2 - t1

LMTD = 562.1999R= 0

S = 0.584416ft = 0.905 fig 18

508.7909 pers 7.423 Tc dan tc

1.083333 fig 17Kc = 0.2Fc = 0.42Tc = 662 pers 5.28tc = 95.9 pers 5.29

shell side : hot fluid4' flow area 4 flow area

as = 3.232674 ft^2 pers 7.1 at' = 0.639 in5' mass velocity at= 0.142 ft^2

Gs = 35479.47 lb/(jam.ft^pers 7.2 5 mass velocity6' Res Gt = 102957.7 lb/(ft.jam)

De = 0.06 ft fig 28 6 Ret pada tc = 95.9 pada Tc = 662

1.694 lb/(ft.jam) fig 14 0.0605 lb/(ft.jam)Res = 1256.652 pers 7.3 D = 0.075167 ft^2

7' jH = 15 fig 28 Ret = 127917.28' pada tc = 95.9 7 L/D = 212.8603

c = 2.3 Btu/(lb.F) fig 4 jH = 295k = 0.37 Btu/(jam.ftfig 1 8 pada tc = 662

2.191862 c = 1 Btu/(lb.F)9' 202.7472 pers 6.15b k = 0.0065 Btu/(jam.ft10' tube wall temperature 2.103523

∆t :

∆t2 - ∆t1

∆t =

∆tc/∆th =

μ = μ =

(cμ/k)^(1/3) =ho/Øs =

(cμ/k)^(1/3) =

tw = 552.8999 pers 5.31 9 hi11' pada tw = 552.8999 53.66083

0.05324 lb/(ft.jam) fig 14 10 48.402070.95379 fig 24 insert 11 pada tw = 552.8999

12' corrected coefficient 0.0605 lb/(ft.jam)h0 = 193.3782 Btu/(jam.ftpers 6.36 Øt = 1

13' clean overall Uc 12 corrected coeficientUc = 38.71245 Btu/(jam.ftpers 6.38 hi0 = 48.40207 Btu/(jam.ft

14 design overall coefficientUd A = 134.0416 ft^2Ud = 34.98029 Btu/(jam.ft^2.F)

15 dirt factorRd = 0.002756 jam.ft^2.F/Btu

193.3782 h outside 48.40207Uc 38.7124454314885Ud 34.9802863601708Rd calcula 0.002756044206182Rd require 0.003

1' untuk Res 1256.652 1 untuk Ret 127917.2f = 0.0033 ft^2/in^2 fig 29 f = 0.00017 ft^2/in^2s = 1 fig 6 s = 1Ds = 2.083333 ft 2 0.007348 psi

2' no. Of crosses 3 Gt = 102957.7N + 1 = 38.4 pers 7.43 V^2/2g' = 0.002304

39 0.009216 psi3' 0.112984 psi pers 7.44 4 0.016564 psi

10 psi allowable 10 psi

hi/Øt =μw = hio/Øt =Øs =

μw =

∆Pt =

∆Pr =∆Ps = ∆PT =allowable ∆ps =

tabel 10pers 7.48

fig 14tabel 10

fig 24

fig 4fig 1

pers 6.15apers 6.5

fig 14fig 24 insert

pers 6.37

fig 26fig 6pers 7.45

fig 27pers 7.46pers 7.47