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GIỚI HẠN DÃY SỐ

Apr 05, 2018

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  • 8/2/2019 GII HN DY S

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    GII HN DY S

    http://e-learning.hcmut.edu.vn/

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    DY S THC

    Dy s l tp hp cc s c nh ch st nh n ln trong tp hp s t nhin N.

    VD: 1/ xn = n2, n = 0, 1, 2,

    2/ xn= 1/n, n = 1, 2,

    3/ {xn} l cp s cng: a, a+d, a+2d,

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    Cc cch cho dy s

    21, /n nx n x n

    1/Dng lit k:

    VD: dy 1, 2, 3,; dy 1, 1/2, 1/3,

    2/Dng tng minh:

    {xn} cho dng biu thc gii tch ca bin n.

    3/Dng quy np:

    S hng i sau tnh theo cc s hng i trc

    VD:

    VD: dy 21 11 1, n n nx x x x

    dy 11 2 11 1

    2

    , , n nnx x

    x x x

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    Dy n iu

    {xn} l dy tngxn xn+1, vi mi n ln

    {xn} l dy gimxn xn+1, vi mi n ln

    Dy tng v dy gim gi chung l dy n iu.

    B du = trong nh ngha ta gi l tng(gim) ngt.

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    1.Xt hiu s: xn+1 xn(so vi 0)

    2.Xt thng s: xn+1/xn(so vi 1)(dng cho dy s dng)

    3.Xt o hm ca hm s f(x), vi f(n) = xn

    Phng php kho st dy n iu:

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    V d

    1 11 2

    / :na x n

    1 1 / 1 1 :

    2nb x

    n

    gim1 11

    1

    n

    n

    x

    x n

    1

    1

    1

    n nx x

    n

    0 tng

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    2 3/ :

    3 4n

    nc x

    n

    Biu thc ging hm s, xt o hm

    22 3 1( ) , ( ) 03 4 (3 4)

    xf x f x x x

    f(x) tng {xn} tng.

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    Dy b chn

    {xn} l dy b chn trn M : xn M, n N0

    {xn} l dy b chn di m : xn m, n N0

    {xn} b chn {xn} b chn trn v b chn di

    VD: Xet tnh b chan cua cac day

    / 1 nc n / 3nb

    2

    1/a

    n

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    1 2 3 4 5 6 7 8, , , , , , , , , ,n nx x x x x x x x x x

    DY CON

    Cho {xn}, chn ra cc s hng t dy ny

    1cch ty theoth t ch s tng dn ta

    c 1 dy con ca {xn}.

    VD:

    {x2n 1}{x2n}

    {x2n-1} = {x1, x3, x5, }

    {x2n} = {x2, x4, x6, }

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    GiI HN DY S

    nh ngha n gin: {xn} c gii hn l a

    khi n ra tc l xna khi n ln

    Dy hit

    0 00, : , nN N x a n N

    0 00, : nN a x a n N

    : limhu hann

    n

    a x

    a

    0Nx

    0( )

    nx n N

    a a

    nh ngha cht ch:

    1x

    2x

    3x

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    V d

    lim 11n

    n

    n 1

    1

    1 1

    n

    nx a

    n n

    1 11 1

    1nx n

    n

    Chng minh

    0

    1 11 1nn N n n x

    Chn N0 1/, vi > 0 ( b)

    * Vi = 10-3, tm N0?

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    Tnh cht dy hi t

    Dy hi t th b chn.an 0 v an a th a 0

    an a v a < c th an

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    Cc php ton trn dy hi t

    lim , lim

    lim lim lim

    lim lim lim lim 0

    lim lim 0 & lim 0n

    K :

    K :

    n nn n

    n n n n n n n

    n n n n n n n n n

    n n n

    n n n

    x y

    x y x y

    x y x y y

    x x x x

    lim tng(hiu, tch, thng, cn,)

    =tng(hiu) lim

    (hu hn)

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    S HOI TU VA DAY CON

    VD: dy {xn} = {(1)n} phn k

    2

    2 1

    1 1

    1 1V 2 day conn

    n

    x

    x

    lim xn

    = a Mi dy con caxn

    u a

    Dy xnphn k 1 day con phan ky

    2 day con co lim nhau

    2

    2 1

    nn

    n

    x ax

    x a

    aH qu:

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    GII HAN KEPCho 3 dy xn, yn, zn

    0

    lim lim

    n n n

    n nn n

    x y z n N

    x z a

    lim

    nn

    y a

    n n nx y z

    a

    Hqu: 0 & lim 0 lim 0n n n n n n

    x y n y x

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    Dy phn k ra v cng

    Giihn = : khng th xt | xn a | !

    Dy khng hi t gi l dy phn k:

    Khng c giihn

    Phn k ra vcng

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    0 0lim , : ,> 0n nn

    x M N N x M n N

    0 0lim , : ,> 0n nn

    x M N N x M n N

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    V d

    lim 2n

    n

    22 logn M n M

    Chng minh

    Vi M > 0 (ln) ty ,

    Chn N0 > log2M + 1, ta c :

    0 2log 2nn N n M M

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    Cc php ton trn dy phn k ra

    0

    lim 0

    0( 0),

    nn

    n

    a

    a n N

    1lim 0n

    na limn

    n a 1/ Nu th

    2/ Nu th limnn

    a

    ()

    lim nn

    a

    ,lim nn

    b c

    lim nn

    a

    lim ( )

    lim ,

    n nn

    n nn

    a b

    a b

    neu c 0

    , lim nn

    b

    lim ( )n nn

    a b

    lim n nn

    a b

    lim nn

    a

    , lim nn

    b

    3/

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    GII HAN C BAN

    3 / lim 1,n

    nn

    lim 0, 1n

    n

    na

    a

    4 / lim 1, 0nn

    a a

    1 lim

    1 1 lim 0

    n

    n

    n

    n

    a a

    a a

    0 lim

    0 lim 0

    n

    n

    n

    n

    2/. Ham mu:

    1/. Luy tha:

    lim 0, 0!

    n

    n

    aa

    n

    ln5 / lim 0, 0

    p

    nn

    n

    ln p nn n a

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    2 / lim 1

    nn

    e n

    2 / lim na n

    1 21 / lim lim 0n n

    b nn

    / lim 2

    nn

    c 1 / lim 02

    n

    nd

    2

    / lim 03

    n

    n

    nf

    V d

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    7 DNG V NH

    0, 0 , ,

    0

    0 01 ,0 ,

    i vi 4 php ton cng, tr, nhn, chia:

    i vi dng m nbna

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    2

    sin2 / lim 1n

    n n

    n

    1000

    3 / lim

    n

    n n

    !1 / lim nn

    n

    n ! 1 2 10 0nn nn n n n n

    2 2

    sin

    0 01 1

    n n n

    n n

    Vi n 2000: 1000 10 02

    n n

    n

    V d tng hp

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    Tng cp s nhn

    1 1

    2 1 1lim 1 lim

    1 1

    n qn

    n n

    qq q q

    q q

    1 10 0

    0 0 0

    1

    lim lim 1 1

    n qn

    n n

    u q uu u q u q q q

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    1 1 14 / lim 1

    2 4 2

    nn

    11 1 2 1lim 2

    1 1 2 1 1 2

    n

    n

    2 1 3 9lim ,

    3 2 8 32

    n

    5/ S

    0

    1 3 3 2 8,

    2 2 4 3 21q u S

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    25 / lim 1n

    n n

    2 2

    2

    1lim

    1n

    n n

    n n

    2 2

    1 1 1 1lim lim 0. 0

    21 1 1n n nn n n

    26 / lim 1n

    n n n

    27 / lim 1 2n

    n n

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    8 / lim 3 2n n n

    n

    3

    ( 0 )

    2 3n n 3 2n

    3 1

    n

    3

    lim 3nn

    x

    3 2n n n

    nx

    28 / lim 3 2n n n

    nn

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    TIEU CHUAN WEIRSTRASS

    Dy tng & bchn trn th hit,

    Dy gim & bchndi th hit

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    VD: 1/Chng minh tntigiihn sau:

    2 2 21 1 1lim 1 ...

    2 3 n n

    2 2

    1 1

    1 ... :2nx n

    21 1 1 1

    21 1

    nxn n n n n

    1 21

    0

    ( 1)

    tangn n nx x x

    n

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    2/Chng minh tnti v tm giihn dy s:

    0 13, 12

    nn

    xx x

    1n nx x

    TIEU CHUAN WEIRSTRASS

    Dng quy np chng minh xn > 2 (b chn

    di)

    n iu:

    1

    21 1 2

    2 2n

    k

    xx

    1 02

    nx

    Gs xk> 2,

    12

    n nx x

    {xn} gim v b chn di nn hi t

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    lim nx LGi:

    Khi 1lim nx L

    Ta li c 1 12n

    n

    x

    x

    Qua gii hn khi n, ta c

    1 22

    LL L

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    0

    11

    n knn

    kk

    C

    n n

    2

    1 1 12 1 1!

    n

    kk

    n n k

    1

    2

    1 1 22 2 3

    1 1 22

    n

    k

    k

    B chn:

    2

    1 1 12

    !

    n

    kk

    n n n k

    k n

    2

    1

    2 !

    n

    k k

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    PHA DANG VO NH 1

    : lim 1 .

    na

    n

    aa en

    1 1

    1 / lim 1VD :

    n

    n n e

    2 32

    2 / lim4

    n

    n

    n

    n

    2 3

    4 4 22

    4

    2 1lim 1

    4Bien oi

    nn n

    ne

    n e

    1 .Dang