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Holt Geometry UNIT 5.1 MID-SEGMENTS OF UNIT 5.1 MID-SEGMENTS OF TRIANGLES TRIANGLES
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Page 1: Geometry unit 5.1

Holt Geometry

UNIT 5.1 MID-SEGMENTS OF UNIT 5.1 MID-SEGMENTS OF TRIANGLESTRIANGLES

Page 2: Geometry unit 5.1

Warm UpUse the points A(2, 2), B(12, 2) and C(4, 8) for Exercises 1–5.

1. Find X and Y, the midpoints of AC and CB.

2. Find XY.

3. Find AB.

4. Find the slope of AB.

5. Find the slope of XY.

6. What is the slope of a line parallel to 3x + 2y = 12?

(3, 5), (8, 5)

5

10

0

0

Page 3: Geometry unit 5.1

Prove and use properties of triangle midsegments.

Objective

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midsegment of a triangle

Vocabulary

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A midsegment of a triangle is a segment that joins the midpoints of two sides of the triangle. Every triangle has three midsegments, which form the midsegment triangle.

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Example 1: Examining Midsegments in the Coordinate Plane

Step 1 Find the coordinates of M and N.

The vertices of ∆XYZ are X(–1, 8), Y(9, 2), and

Z(3, –4). M and N are the midpoints of XZ and

YZ. Show that and .

Page 7: Geometry unit 5.1

Example 1 Continued

Step 2 Compare the slopes of MN and XY.

Since the slopes are the same,

Page 8: Geometry unit 5.1

Step 3 Compare the heights of MN and XY.

Example 1 Continued

Page 9: Geometry unit 5.1

Check It Out! Example 1

Step 1 Find the coordinates of M and N.

The vertices of ΔRST are R(–7, 0), S(–3, 6), and T(9, 2). M is the midpoint of RT, and N is the midpoint of ST. Show that and

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Check It Out! Example 1 Continued

Since the slopes are equal .

Step 2 Compare the slopes of MN and RS.

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Check It Out! Example 1 Continued

The length of MN is half the length of RS.

Step 3 Compare the heights of MN and RS.

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The relationship shown in Example 1 is true for the three midsegments of every triangle.

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Example 2A: Using the Triangle Midsegment Theorem

Find each measure.

BD = 8.5

∆ Midsegment Thm.

Substitute 17 for AE.

Simplify.

BD

Page 14: Geometry unit 5.1

Example 2B: Using the Triangle Midsegment Theorem

Find each measure.

m∠CBD

∆ Midsegment Thm.

Alt. Int. ∠s Thm.

Substitute 26° for m∠BDF.

m∠CBD = m∠BDF

m∠CBD = 26°

Page 15: Geometry unit 5.1

Check It Out! Example 2a

Find each measure.

JL

∆ Midsegment Thm.

Substitute 36 for PN and multiply both sides by 2.

Simplify.

2(36) = JL

72 = JL

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Check It Out! Example 2b

Find each measure.

PM

∆ Midsegment Thm.

Substitute 97 for LK.

Simplify.PM = 48.5

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Check It Out! Example 2c

Find each measure.

m∠MLK

∆ Midsegment Thm.

Similar triangles

Substitute.

m∠MLK = m∠JMP

m∠MLK = 102°

Page 18: Geometry unit 5.1

Example 3: Indirect Measurement Application

In an A-frame support, the distance PQ is 46 inches. What is the length of the support ST if S and T are at the midpoints of the sides?

The length of the support ST is 23 inches.

∆ Midsegment Thm.

Substitute 46 for PQ.

Simplify.ST = 23

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Check It Out! Example 3

What if…? Suppose Anna’s result in Example 3 (p. 323) is correct. To check it, she measures a second triangle. How many meters will she measure between H and F?

∆ Midsegment Thm.

Substitute 1550 for AE.

HF = 775 m Simplify.

Page 20: Geometry unit 5.1

Lesson Quiz: Part I

Use the diagram for Items 1–3. Find each measure.

1. ED

2. AB

3. m∠BFE

10

14

44°

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Lesson Quiz: Part II

4. Find the value of n.

5. ∆XYZ is the midsegment triangle of ∆WUV. What is the perimeter of ∆XYZ?

16

11.5

Page 22: Geometry unit 5.1

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