1 | Page Geometry Geometry Honors T.E.A.M.S. Geometry Honors Summer Assignment
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Dear Parents and Students:
All students entering Geometry or Geometry Honors are required to complete this assignment.
This assignment is a review of essential topics to strengthen math skills for the upcoming
school year.
If you need assistance with any of the topics included in this assignment, we strongly
recommend that you to use the following resource: http://www.khanacademy.org/.
If you would like additional practice with any topic in this assignment visit: http://www.math-
drills.com.
Below are the POLICIES of the summer assignment:
The summer assignment is due the first day of class. On the first day of class,
teachers will collect the summer assignment. Any student who does not have the
assignment will be given one by the teacher. Late projects will lose 10 points each
day.
Summer assignments will be graded as a quiz. This quiz grade will consist of 20%
completion and 80% accuracy. Completion is defined as having all work shown in the
space provided to receive full credit, and a parent/guardian signature.
Any student who registers as a new attendee of Teaneck High School after August
15th will have one extra week to complete the summer assignment.
Summer assignments are available on the district website and available in the THS
guidance office.
HAVE A GREAT SUMMER!
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An Introduction to the Basics of Geometry
Directions: Read through the definitions and examples given in each section, then complete the practice questions,
found on pages 20 to 26. Those pages will be collected by your Geometry Teacher on the first day of school.
Section 1: Points, Lines and Planes
Undefined term: words that do not have formal definitions, but there is an agreement about what they mean. In
Geometry, the words point, line and plane are undefined terms.
Undefined Term Meaning Example/Picture and symbols
Point A point has no dimension but has location. A dot is used to represent a point.
Line
A line has one dimension. It is represented by a line with two arrowheads, showing that it extends in two directions without end. Through any two points there is exactly one line. You can use any two points on a line to name it, or it can be named by a lowercase letter written by the line.
Plane
A plane has two dimensions. It is represented by a shape that looks like a floor or a wall, but it extends without end. Through any three points not on the same line, there is exactly one plane. You can use three points that are not on the same line to name a plane, or you can use a capital letter (without a point next to it) to name a plane.
Collinear points: points that lie on the same line. Coplanar points: points that lie in the same plane.
Example 1: Naming Points, Lines and Planes
a. Give two other names for ππ β‘ and plane R.
Answer: Other names for ππ β‘ are ππ β‘ and line n. Other names for plane R are
plane SVT and plane PTV.
b. Name three points that are collinear. Name four points that are coplanar.
Answer: Points S, P, and T lie on the same line, so they are collinear. Points S, P, T, and V lie in the same plane, so
they are coplanar.
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Defined Terms: Segment and Ray
The definitions below use line AB (written as π΄π΅ β‘ ) and points A and B.
Defined Term Definition Example/Picture and Symbols
Segment
The line segment AB, or segment AB (written as π΄π΅Μ Μ Μ Μ ) consists
of the endpoints A and B and all points on π΄π΅ β‘ that are between A and B. The endpoints are like stop and start points. Unlike lines, segments do not continue on forever in both directions and they can be measured. Note that π΄π΅Μ Μ Μ Μ can also be called π΅π΄Μ Μ Μ Μ .
π΄π΅Μ Μ Μ Μ (read βsegment ABβ)
Ray
The ray AB (written as π΄π΅ ) consists of the endpoint A and all
points on π΄π΅ β‘ that lie on the same side of A as B. In other words, rays have a starting point (called an endpoint) and continue in the direction of the other point.
Note that π΄π΅ and π΅π΄ are two different rays because they are going in different directions.
Top: π΄π΅ (read βray ABβ)
Bottom: π΅π΄ (read βray BAβ)
Opposite Rays
If point C lies on π΄π΅ β‘ between A and B, then πΆπ΄ and πΆπ΅ are opposite rays. They have the same point but go in opposite directions to form a line.
πΆπ΄ and πΆπ΅ are opposite rays.
Intersection
Two or more geometric figures intersect when they have one or more points in common. The intersection of the figures is the set of all points they have in common.
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Example 2: Naming Segments, Rays and Opposite Rays
a. Give another name for πΊπ»Μ Μ Μ Μ .
Answer: Another name for πΊπ»Μ Μ Μ Μ is π»πΊΜ Μ Μ Μ .
b. Name all rays with endpoint π½. Which of these rays are opposite rays?
Answer: The rays with endpoint π½ are π½πΈ , π½πΊ , π½πΉ , and π½π» . The pairs of opposite rays with endpoint π½ are π½πΈ and
π½πΉ , and π½πΊ and π½π» .
Practice Questions for Section 1 can be found on Page 20.
Section 2: Measuring Segments
In Geometry, a rule that is accepted without proof is called a postulate or an axiom. A rule that can be proved is called a
theorem.
The Ruler Postulate: The points on a line can be matched one to one with the real numbers.
The real number that corresponds to a point is the coordinate of the point.
The distance
between points A and B, written as AB (notice there is no symbol above the 2 letters), is
the absolute value of the difference of the coordinates of A and B.
Congruent Segments: Line segments that have the same length are called congruent
segments. You can say βthe length of π΄π΅Μ Μ Μ Μ is equal to the length of πΆπ·Μ Μ Μ Μ ,β or you can say βπ΄π΅Μ Μ Μ Μ
is congruent to πΆπ·Μ Μ Μ Μ .β The symbol β means βis congruent to.β
In the diagram above, of π΄π΅Μ Μ Μ Μ and πΆπ·Μ Μ Μ Μ have tick marks on them, indicating π΄π΅Μ Μ Μ Μ β πΆπ·Μ Μ Μ Μ . When there is more than one pair
of congruent segments, use multiple tick marks.
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When three points are collinear, you can say that one
point is between the other two.
Segment Addition Postulate
If B is between A and C, then AB + BC=AC.
If AB+BC=AC, then B is between A and C.
Example 1: Comparing Segments for Congruence
a. Plot J(β3, 4), K(2, 4), L(1, 3), and M(1, β2) in a coordinate plane. Then determine whether π½πΎΜ Μ Μ and πΏπΜ Μ Μ Μ are
congruent.
Answer:
Plot the points, as shown.
To find the length of a horizontal segment, find the absolute value of the
difference of the x-coordinates of the endpoints.
π½πΎ = |β3 β 2| = 5, Ruler Postulate
To find the length of a vertical segment, find the absolute value of the
difference of the y-coordinates of the endpoints.
πΏπ = |3 β (β2)| = 5, Ruler Postulate
π½πΎ = πΏπ. So, π½πΎΜ Μ Μ β πΏπΜ Μ Μ Μ .
Example 2: Using the Segment Addition Postulate
a. Find π·πΉ.
Answer: Use the Segment Addition Postulate to write an equation. Then solve the equation to find π·πΉ.
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b. Find πΊπ».
Answer: Use the Segment Addition Postulate to write an equation. Then solve the equation to find πΊπ».
Example 3: Using the Segment Addition Postulate
The cities shown on the map lie
approximately in a straight line. Find the
distance from Tulsa, Oklahoma, to St.
Louis, Missouri.
Answer:
1. Understand the Problem. You are given the distance from Lubbock to St. Louis and the distance from
Lubbock to Tulsa. You need to find the distance from Tulsa to St. Louis.
2. Make a Plan. Use the Segment Addition Postulate to find the distance from Tulsa to St. Louis.
3. Solve the Problem. Use the Segment Addition Postulate to write an equation. Then solve the equation
to find ππ.
So, the distance from Tulsa to St. Louis is 361 miles.
Practice Questions for Section 2 can be found on Page 21.
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Section 3: Using Midpoint and Distance Formulas
Midpoints and Segment Bisectors
The midpoint of a segment is the point that divides the segment into two congruent segments.
A segment bisector is a point, ray, line, line segment, or plane that intersects the segment at its midpoint. A midpoint or
a segment bisector bisects a segment. (βBiβ means two, βsectβ means sections).
Example 1: Finding Segment Lengths
In the skateboard design, ππΜ Μ Μ Μ Μ bisects ππΜ Μ Μ Μ at point T, and ππ = 39.9 cm.
Find ππ.
Answer:
Point π is the midpoint of ππΜ Μ Μ Μ , so ππ = ππ = 39.9 cm.
ππ = ππ + ππ Segment Addition Postulate ππ = 39.9 + 39.9 Substitute
ππ = 79.8 Add
So, ππ = 79.8 cm
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Example 2: Using Algebra with Segment Lengths
Point M is the midpoint of ππΜ Μ Μ Μ Μ . Find the length of ππΜ Μ Μ Μ Μ .
Answer:
1. Write and solve an equation. Use the fact that ππΜ Μ Μ Μ Μ = ππΜ Μ Μ Μ Μ Μ .
ππ = ππ Write the equation
4π₯ β 1 = 3π₯ + 3 Substitute
π₯ β 1 = 3 Subtract 3π₯ from both sides
π₯ = 4 Add 1 to each side
2. Evaluate ππ = 4π₯ β 1 when π₯ = 4
ππ = 4(4) β 1 = 15
So the length of ππΜ Μ Μ Μ Μ is 15 units.
Using the Midpoint Formula
The coordinates of the midpoint of a segment are the averages of the
x-coordinates and of the y-coordinates of the endpoints.
If A(π₯1, π¦1), and B(π₯2, π¦2) are points in a coordinate plane, then the
midpoint M of AB has coordinates
Example 3: Using the Midpoint Formula
a. The endpoints of π πΜ Μ Μ Μ are R(1, β3) and S(4, 2). Find the
coordinates of the midpoint M.
Answer:
Use the midpoint formula: π (1+4
2,β3+2
2) = π (
5
2,β1
2)
So the coordinates of π are (5
2, β
1
2).
b. The midpoint of π½πΎΜ Μ Μ is π(2, 1). One endpoint is π½(1, 4). Find the coordinates of endpoint πΎ.
Answer:
Let (x, y) be the coordinates of endpoint πΎ. Use the Midpoint Formula.
Step 1: Find x Step 2: Find y 1 + π₯
2= 2
4 + π¦
2= 1
1 + π₯ = 4 4 + π¦ = 2 π₯ = 3 π¦ = β2
The coordinates of endpoint πΎ are (3, -2).
Using the Distance Formula
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If A(π₯1, π¦1), and B(π₯2, π¦2) are points in a coordinate plane, then the distance between A and B is
π΄π΅ = β(π₯2 β π₯1)2 + (π¦2 β π¦1)2
Example 4: Using the Distance Formula
Your school is 4 miles east and 1 mile south of your apartment. A recycling center, where your class is going on a
field trip, is 2 miles east and 3 miles north of your apartment. Estimate the distance between the recycling
center and your school.
Answer:
You can model the situation using a coordinate plane with your apartment at the origin (0, 0). The coordinates
of the recycling center and the school are π (2, 3) and π(4, β1), respectively. Use the Distance Formula. Let
(π₯1, π¦1) = (2, 3) and (π₯2, π¦2) = (4, β1).
π π = β(π₯2 β π₯1)2 + (π¦2 β π¦1)2 Distance Formula
π π = β(4 β 2)2 + (β1 β 3)2 Substitute
π π = β(2)2 + (β4)2 Subtract
π π = β4 + 16 Evaluate Powers
π π = β20 Add
π π β 4.5 Use Calculator
So, the distance between your school and the recycling center is about 4.5 miles.
Practice Questions for Section 3 can be found on Page 22.
Section 4: Perimeter and Area in the Coordinate Plane
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Polygons
In geometry, a figure that lies in a plane is called a plane figure. Recall that a
polygon is a closed plane figure formed by three or more line segments called
sides. Each side intersects exactly two sides, one at each vertex, so that no two
sides with a common vertex are collinear. You can name a polygon by listing
the vertices in consecutive order.
A polygon is convex when no line that contains a side of
the polygon contains a point in the interior of the
polygon. A polygon that is not convex is concave.
*One way to determine that a polygon is convex is to
imagine turning it on all sides and pouring waters over it
each time. If the water will roll off the polygon no
matter which side it is sitting on, then it is convex.
Polygon Types
Number of sides
Type of Polygon
3 Triangle
4 Quadrilateral
5 Pentagon
6 Hexagon
7 Heptagon
8 Octagon
9 Nonagon
10 Decagon
11 Undecagon
12 Dodecagon
N n-gon (example β 23 sides 23-gon)
Example 1: Classifying Polygons
Classify the polygon by the number of sides. Tell whether it is concave or convex.
a.
Answer: The polygon has four sides. So, it is a
quadrilateral. The polygon is concave.
b.
Answer: The polygon has six sides. So, it is a
hexagon. The polygon is convex.
Finding Perimeter and Area in the Coordinate Plane
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You can use the formulas given below and the Distance Formula to find the perimeters and areas of polygons in the
coordinate plane.
Example 2: Finding Perimeter in the Coordinate Plane
Find the perimeter of β³ π΄π΅πΆ with vertices π΄(β2, 3), π΅(3, β3), and πΆ(β2, β3).
Answer:
Step 1 Draw the triangle in a coordinate plane. Then find the length of each side.
Side π¨π©Μ Μ Μ Μ
π΄π΅ = β(π₯2 β π₯1)2 + (π¦2 β π¦1)2 Distance Formula
π΄π΅ = β(3 β (β2))2 + (β3 β 3)2 Substitute
π΄π΅ = β(5)2 + (β6)2 Subtract
π΄π΅ = β25 + 36 Evaluate powers
π΄π΅ = β61 Add
π΄π΅ β 7.81 Use Calculator Side π©πͺΜ Μ Μ Μ
π΅πΆ = β£ β2 β 3 β£ = 5 Ruler Postulate Side π¨πͺΜ Μ Μ Μ
π΄πΆ = β£ 3 β (β 3) β£ = 6 Ruler Postulate
Step 2 Find the sum of the side lengths.
π΄π΅ + π΅πΆ + πΆπ΄ β 7.81 + 5 + 6 = 18.81
So, the perimeter of β³ π΄π΅πΆ is about 18.81 units.
Example 3: Finding Area in the Coordinate Plane
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Find the area of β³ π·πΈπΉ with vertices π·(1, 3), πΈ(4, β3), and πΉ(β4, β3).
Answer:
Step 1 Draw the triangle in a coordinate plane by plotting the vertices and
connecting them.
Step 2 Find the lengths of the base and height.
Base
The base is πΉπΈΜ Μ Μ Μ , which is a horizontal segment so we can use the
Ruler Postulate:
πΉπΈ = |β4 β 4| = 8
Height
The height is the distance from point π· to πΉπΈΜ Μ Μ Μ . By counting grid lines, you can determine the height is 6
units.
Step 3 Substitute the values for the base and height into the formula for the area of a triangle.
π΄ =1
2πβ
π΄ =1
28 β 6
π΄ = 24
So, the area of β³ π·πΈπΉ is 24 square units.
Practice Questions for Section 4 can be found on Page 23.
Section 5 β Angles and their Measures
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Naming Angles
An angle is a set of points consisting of two different rays that have the same endpoint, called the vertex. The rays are
the sides of the angle.
You can name an angle in several different ways.
Use its vertex, such as β A.
Use a point on each ray and the vertex, such as β BAC or β CAB.
(notice the vertex is always in the middle when naming this way).
Use a number, such as β 1.
The region that contains all the points between the sides of the angle is the interior of
the angle. The region that contains all the points outside the angle is the exterior of the
angle.
Example 1: Naming Angles
A lighthouse keeper measures the angles formed by
the lighthouse at point M and three boats. Name
three angles shown in the diagram.
Answer:
β JMK or β KMJ
β KML or β LMK
β JML or β LMJ
*Common Error: When a point is the vertex of more than one angle, you cannot use the vertex alone to name
the angle.
Measuring and Classifying Angles
A protractor helps you approximate the measure of an angle. The measure is usually given in degrees.
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Protractor Postulate
Consider ππ΅ β‘ and a point π΄ on one side of ππ΅ β‘ . The rays of the form ππ΄ can be
matched one to one with the real numbers from 0 to 180.
The measure of β AOB, which can be written as πβ π΄ππ΅, is equal to the absolute
value of the difference between the real numbers matched with ππ΄ and ππ΅ on a
protractor.
In the diagram, πβ π΄ππ΅ = 140Β°, because ππ΄ passes through the 40Β°/140Β° line and ππ΅ passes through the 180Β°/0Β° line.
Using the outer numbers |180 β 40| = 140Β° Using the inner numbers |0 β 140|=140Β°.
Types of Angles
Acute angle Right angle Obtuse angle Straight angle
(a small square drawn at the vertex of an angle symbolizes a right angle)
Measures greater than 0Β° and less than 90Β°
Measures 90Β° Measures greater than 90Β° and less than 180Β°
Measures 180Β°
Example 2: Measuring and Classifying Angles
Find the degree measure of each of the following
angles. Classify each angle as acute, right, or
obtuse.
a. β AOB
ππ΄ lines up with 0Β° on the inner scale, and
ππ΅ passes through 35Β° on the inner scale,
so πβ π΄ππ΅ = 35Β°. It is an acute angle.
b. β BOE
ππ΅ lines up with 35Β° on the inner scale,
and ππΈ passes through 145Β° on the inner
scale, so πβ π΅ππΈ = |35 β 145|Β° = 110Β°.
It is an obtuse angle.
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Congruent angles are two angles with equal measures. If πβ π΄π΅πΆ =
πβ π·πΈπΉ, then β π΄π΅πΆ β β π·πΈπΉ. (Angles are congruent when their measures are
equal.
An angle bisector is a ray between two sides of an angle the creates two
congruent angles.
Example 3: Identifying Congruent Angles
Use the diagram to answer the questions.
a. Identify the angles congruent to β ADG.
Because β π΅πΈπ» and β πΆπΉπΌ have matching arcs, β π΄π·πΊ β
β π΅πΈπ» β β πΆπΉπΌ.
b. Identify the angles congruent to β DAG.
Because β π·π΄πΊ, β π΄πΊπ·, β πΈπ΅π», β πΈπ»π΅, β πΉπΆπΌ and β πΉπΌπΆ have
matching arcs, so
β π·π΄πΊ β β π΄πΊπ· β β πΈπ΅π» β β πΈπ»π΅ β β πΉπΆπΌ β β πΉπΌπΆ.
Angle Addition Postulate
Words
If P is in the interior of β RST, then the measure of β RST is equal to the sum of the measures of β RSP and β PST.
Symbols If P is in the interior of β RST, then mβ RST = mβ RSP + mβ PST.
If ππ bisects β π ππ , then
β π ππ β β πππ
Reading: In diagrams, matching
arcs indicate congruent angles.
When there is more than one pair
of congruent angles, use multiple
arcs.
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Example 4: Using the Angle Addition Postulate to Find Angle Measures
Given that πβ πΏπΎπ = 145Β°, find πβ πΏπΎπ and πβ ππΎπ.
Step 1 Write and solve an equation to find the value of x.
πβ πΏπΎπ = πβ πΏπΎπ + πβ ππΎπ Angle Addition Postulate 145Β° = (2π₯ + 10)Β° + (4π₯ β 3)Β° Substitute
145 = 6π₯ + 7 Simplify (Combine Like Terms) 138 = 6π₯ Subtract 23 = π₯ Divide
Step 2 Evaluate the given expressions when x = 23.
πβ πΏπΎπ = (2π₯ + 10)Β° = (2 β 23 + 10)Β° = 56Β° πβ ππΎπ = (4π₯ β 3)Β° = (4 β 23 β 3)Β° = 89Β°
So, πβ πΏπΎπ = 56Β° and πβ ππΎπ = 89Β°.
Example 5: Using a Bisector to Find Angle Measures
ππ bisects β πππ , and πβ πππ = 24Β°. Find πβ πππ .
Step 1 Draw a diagram.
Step 2 Because ππ bisects β πππ , πβ πππ = πβ π ππ. So, πβ π ππ = 24Β°.
Use the Angle Addition Postulate to find πβ πππ .
πβ πππ = πβ πππ + πβ π ππ Angle Addition Postulate πβ πππ = 24Β° + 24Β° Substitute Angle
Measures πβ πππ = 48Β° Add
So, πβ πππ = 48Β°.
Practice Questions for Section 5 can be found on Page 25.
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Section 6 β Describing Pairs of Angles
Complementary and Supplementary Angles
Complementary angles
Two positive angles whose measures have a sum of 90Β°. Each angle is the complement of the other.
Supplementary angles
Two positive angles whose measures have a sum of 180Β°. Each angle is the supplement of the other.
Adjacent Angles
Angles can be adjacent angles or nonadjacent angles. Adjacent angles are two angles that share a common vertex and
side, but have no common interior points.
Example 1: Identifying Pairs of Angles
In the figure, name a pair of complementary angles, a pair of
supplementary angles, and a pair of adjacent angles.
Answer:
Because 37Β° + 53Β° = 90Β°, β BAC and β RST are complementary
angles.
Because 127Β° + 53Β° = 180Β°, β CAD and β RST are supplementary angles.
Because β BAC and β CAD share a common vertex and side, they are adjacent angles.
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Example 2: Finding Angle Measures
a. β 1 is a complement of β 2, and mβ 1 = 62Β°. Find mβ 2.
Answer: If β 1 is a complement of β 2, then
πβ 1 + mβ 2 = 90 Definition of Complementary Angles
62 + mβ 2 = 90 Substitute
mβ 2 = 28Β° Subtract
b. β 3 is a supplement of β 4, and mβ 4 = 47Β°. Find mβ 3.
Answer: If β 3 is a complement of β 4, then
πβ 3 + mβ 4 = 180 Definition of Supplementary Angles
πβ 3 + 47 = 180 Substitute
mβ 3 = 133Β° Subtract
Linear Pairs and Vertical Angles
Two adjacent angles are a linear pair when their noncommon sides are opposite rays. The angles in a linear pair are supplementary angles.
β 1 and β 2 are a linear pair.
Two angles are vertical angles when their sides form two pairs of opposite rays.
β 3 and β 6 are vertical angles. β 4 and β 5 are vertical angles.
Example 4: Identify Angle Pairs
Identify all the linear pairs and all the vertical angles in the figure.
Answer:
To find vertical angles, look for angles formed by intersecting lines.
β 1 and β 5 are vertical angles.
To find linear pairs, look for adjacent angles whose noncommon sides
are opposite rays.
β 1 and β 4 are a linear pair. β 4 and β 5 are also a linear pair.
Practice Questions for Section 6 can be found on Page 26.
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Name: _________________________________ Teacher:____________________
Practice Questions
Section 1 Questions β Points. Line and Planes:
In exercises 1 β 4, use the diagram at right.
1. Give two other names for πΆπ· β‘
2. Give another name for plane M.
3. Name three points that are collinear. Then name a fourth point that is not collinear with these three points.
4. Name a point that is not coplanar with points A, C, E.
In exercises 5 β 7, use the diagram at right.
5. What are two other names for ππ β‘ ?
6. What is another name for π πΜ Μ Μ Μ ?
7. Name all rays with endpoint T. Which of these rays are opposite rays?
In Exercises 9 and 10, sketch the figure described.
8. π΄π΅Μ Μ Μ Μ and π΅πΆΜ Μ Μ Μ
9. line k in plane M.
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Section 2 Questions β Measuring Segments:
In Exercises 1β3, plot the points in the coordinate plane. Then determine whether π΄π΅Μ Μ Μ Μ and πΆπ·Μ Μ Μ Μ are congruent.
1. A(-5, 5), B(-2, 5)
C(2, -4), D(-1, -4)
2. A(4, 0), B(4, 3)
C(-4, -4), D((-4, 1)
3. A(-1, 5), B(5, 5)
C(1, 3), D(1, -3)
In exercises 4 β 6, find VW.
4.
5.
6.
7. A bookstore and a movie theater are 6 kilometers apart along the same street. A florist is located between the
bookstore and the theater on the same street. The florist is 2.5 kilometers from the theater. How far is the
florist from the bookstore? (Hint: draw a line segment and label 3 points with each location)
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Section 3 Questions β Using Midpoint and Distance Formulas:
In Exercises 1β3, identify the segment bisector of π΄π΅Μ Μ Μ Μ . Then find AB.
1.
2.
3.
In Exercises 4-6, identify the segment bisector of πΈπΉΜ Μ Μ Μ . Then find EF.
4.
5.
6.
In Exercises 7β9, the endpoints of ππΜ Μ Μ Μ are given. Find the coordinates of the midpoint M and the length of ππΜ Μ Μ Μ .
7. P(-4, 3) and Q(0, 5)
8. P(-2, 7) and Q(10, -3)
9. P(3, -15) and Q(9, -3)
In Exercises 10β12, the midpoint M and one endpoint of JK are given. Find the coordinates of the other endpoint.
10. J(7, 2) and M(1, -2)
11. J(5, -2) and M(0, -1)
12. J(2, 16) and M(β9
2, 7)
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Section 4 Questions β Perimeter and Area in the Coordinate Plane:
In Exercises 1β4, classify the polygon by the number of sides. Tell whether it is convex or concave.
1.
2.
3.
4.
In Exercises 5β8, find the perimeter and area of the polygon with the given vertices.
5. X(2, 4), Y(0, -2), Z(2, -2)
6. P(1, 3), Q(1, 1), R(-4, 2)
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7. J(-4, 1), K(-4, -2), L(6, -2), M(6, 1)
8. D(5, -3), E(5, -6), F(2, -6), G(2, -3)
In Exercises 9β14, use the diagram.
9. Find the perimeter of ΞABD.
10. Find the perimeter of ΞBCD.
11. Find the perimeter of quadrilateral ABCD.
12. Find the area of ΞABD.
13. Find the area of ΞBCD.
14. Find the area of quadrilateral ABCD.
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Section 5 Questions β Measuring Angles:
In Exercises 1β3, name three different angles in the diagram.
1.
2.
3.
In Exercises 4β9, find the indicated angle measure(s).
4. Find πβ π½πΎπΏ.
5. πβ π ππ = 91Β°. Find πβ π ππ.
6. β πππ is a straight angle. Find
πβ πππ πππ πβ πππ.
7. Find πβ πΆπ΄π· and πβ π΅π΄π·.
8. πΈπΊ bisects β π·πΈπΉ. Find πβ π·πΈπΊ and πβ πΊπΈπΉ.
9. ππ bisects β πππ. Find πβ πππ and πβ πππ.
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Section 6 Questions β Describing Pairs of Angles:
In Exercises 1 and 2, use the figure.
1. Name the pair(s) of adjacent complementary angles.
2. Name the pair(s) of nonadjacent supplementary angles.
In Exercises 3 and 4, find the angle measure.
3. β A is a complement of β B and mβ =36 .Β° Find mβ B.
4. β C is a supplement of β D and mβ D=117 .Β° Find mβ C.
In Exercises 5 and 6, find the measure of each angle.
5.
6.
In Exercises 7β9, use the figure.
7. Identify the linear pair(s) that include β 1.
8. Identify each vertical angle pair.
9. Are β 6 and β 7 a linear pair? Explain.