Top Banner

of 68

FXX

Apr 10, 2018

Download

Documents

owltbig
Welcome message from author
This document is posted to help you gain knowledge. Please leave a comment to let me know what you think about it! Share it to your friends and learn new things together.
Transcript
  • 8/8/2019 FXX

    1/68

  • 8/8/2019 FXX

    2/68

  • 8/8/2019 FXX

    3/68

  • 8/8/2019 FXX

    4/68

  • 8/8/2019 FXX

    5/68

  • 8/8/2019 FXX

    6/68

  • 8/8/2019 FXX

    7/68

  • 8/8/2019 FXX

    8/68

  • 8/8/2019 FXX

    9/68

  • 8/8/2019 FXX

    10/68

  • 8/8/2019 FXX

    11/68

  • 8/8/2019 FXX

    12/68

  • 8/8/2019 FXX

    13/68

  • 8/8/2019 FXX

    14/68

  • 8/8/2019 FXX

    15/68

  • 8/8/2019 FXX

    16/68

  • 8/8/2019 FXX

    17/68

  • 8/8/2019 FXX

    18/68

  • 8/8/2019 FXX

    19/68

  • 8/8/2019 FXX

    20/68

  • 8/8/2019 FXX

    21/68

  • 8/8/2019 FXX

    22/68

  • 8/8/2019 FXX

    23/68

  • 8/8/2019 FXX

    24/68

  • 8/8/2019 FXX

    25/68

  • 8/8/2019 FXX

    26/68

  • 8/8/2019 FXX

    27/68

  • 8/8/2019 FXX

    28/68

  • 8/8/2019 FXX

    29/68

  • 8/8/2019 FXX

    30/68

    k l f $

  • 8/8/2019 FXX

    31/68

    Risk-Neutral Measure for $

    Theorem: Let QA be the risk-neutral probabilitymeasure for the US Dollar investor, and QB therisk-neutral measure for the UK Pound Sterling investor.Unless = 0 (that is, unless the exchange rate is purelydeterministic), it must be the case that

    QA = QB

    Stochastic Calculus p. 14/2

    Ri k N l M f $

  • 8/8/2019 FXX

    32/68

    Risk-Neutral Measure for $

    Theorem: Let QA be the risk-neutral probabilitymeasure for the US Dollar investor, and QB therisk-neutral measure for the UK Pound Sterling investor.Unless = 0 (that is, unless the exchange rate is purelydeterministic), it must be the case that

    QA = QB

    This is a special case of a more general phenomenon:

    Stochastic Calculus p. 14/2

    N i Ch g

  • 8/8/2019 FXX

    33/68

    Numeraire Change

    Suppose that a market has tradeable assets A, B withshare price processes S At and S Bt (evaluated in a common

    numeraire C ). Let QA

    and QB

    be risk-neutral measuresfor numeraires A, B , respectively.

    Stochastic Calculus p. 15/2

    N meraire Change

  • 8/8/2019 FXX

    34/68

    Numeraire Change

    Suppose that a market has tradeable assets A, B withshare price processes S At and S Bt (evaluated in a common

    numeraire C ). Let QA

    and QB

    be risk-neutral measuresfor numeraires A, B , respectively.

    Theorem: QA = QB if and only if S At /S Bt is a constantrandom variable. Furthermore, in general, for any nitetime T ,

    dQB

    dQA F T =S BT S AT

    S A0S B0

    Stochastic Calculus p. 15/2

    Consequence

  • 8/8/2019 FXX

    35/68

    Consequence

    In the foreign exchange context, the riskless assets forthe two numeraires are US Money Market and UKMoney Market, with share prices (in $)

    At = exp {r A t}B t = exp {r B t}/Y t

    Stochastic Calculus p. 16/2

    Consequence

  • 8/8/2019 FXX

    36/68

    Consequence

    In the foreign exchange context, the riskless assets forthe two numeraires are US Money Market and UKMoney Market, with share prices (in $)

    At = exp {r A t}B t = exp {r B t}/Y t

    Therefore, the likelihood ratio between the risk-neutralmeasures for and $ investors is

    dQB

    dQA F T =

    Y T Y 0

    1

    exp{(r B r A)T }

    Stochastic Calculus p. 16/2

    Consequence

  • 8/8/2019 FXX

    37/68

    Consequence

    In the foreign exchange context, the riskless assets forthe two numeraires are US Money Market and UKMoney Market, with share prices (in $)

    At = exp {r A t}B t = exp {r B t}/Y t

    Therefore, the likelihood ratio between the risk-neutralmeasures for and $ investors is

    dQB

    dQA F T =

    Y T Y 0

    1

    exp{(r B r A)T }

    Stochastic Calculus p. 16/2

    Likelihood Ratio Identity

  • 8/8/2019 FXX

    38/68

    Likelihood Ratio Identity

    Let V it be the time- t share price of any contingent claimin numeraire i = A,B,C . These share prices satisfy:

    Stochastic Calculus p. 17/2

    Likelihood Ratio Identity

  • 8/8/2019 FXX

    39/68

    Likelihood Ratio Identity

    Let V it be the time- t share price of any contingent claimin numeraire i = A,B,C . These share prices satisfy:

    V At = V C t /S AtV Bt = V

    C t /S

    Bt

    Stochastic Calculus p. 17/2

    Likelihood Ratio Identity

  • 8/8/2019 FXX

    40/68

    Likelihood Ratio Identity

    Let V it be the time- t share price of any contingent claimin numeraire i = A,B,C . These share prices satisfy:

    V At = V C t /S AtV Bt = V

    C t /S

    Bt

    The time-zero share price is the discounted expectedvalue of the time t share price for each of thenumeraires A, B . The discount factors are 1, so

    Stochastic Calculus p. 17/2

    Likelihood Ratio Identity

  • 8/8/2019 FXX

    41/68

    Likelihood Ratio Identity

    Let V it be the time- t share price of any contingent claimin numeraire i = A,B,C . These share prices satisfy:

    V At = V C t /S AtV Bt = V

    C t /S

    Bt

    The time-zero share price is the discounted expectedvalue of the time t share price for each of thenumeraires A, B . The discount factors are 1, so

    V A0 = V C 0 /S A0 = E AV C t /S At

    V B

    0 = V C

    0 /S B0 = E

    B

    V C

    t /S Bt

    Stochastic Calculus p. 17/2

    Likelihood Ratio Identity

  • 8/8/2019 FXX

    42/68

    Likelihood Ratio Identity

    It follows that for every contingent claim V with shareprice V C t (in numeraire C ),

    S A0 E A(V C t /S At ) = S B0 E B (V C t /S Bt )

    Stochastic Calculus p. 18/2

    Likelihood Ratio Identity

  • 8/8/2019 FXX

    43/68

    Likelihood Ratio Identity

    It follows that for every contingent claim V with shareprice V C t (in numeraire C ),

    S A0 E A(V C t /S At ) = S B0 E B (V C t /S Bt )

    Apply this to the contingent claim with payoff V C T S BT attime T to obtain the following identity, valid for allnonnegative random variables V C T measurable F T :

    E B V C T = E AV C T S

    BT S A0S AT S B0

    Stochastic Calculus p. 18/2

    Likelihood Ratio Identity

  • 8/8/2019 FXX

    44/68

    Likelihood Ratio Identity

    It follows that for every contingent claim V with shareprice V C t (in numeraire C ),

    S A0 E A(V C t /S At ) = S B0 E B (V C t /S Bt )

    Apply this to the contingent claim with payoff V C T S BT attime T to obtain the following identity, valid for allnonnegative random variables V C T measurable F T :

    E B V C T = E AV C T S

    BT S A0S AT S B0

    This is the dening property of a likelihood ratio.Stochastic Calculus p. 18/2

    Exponential Martingales

  • 8/8/2019 FXX

    45/68

    Exponential Martingales

    Let W t be a standard Wiener process, wth Brownianltration F t , and let t be a bounded, adapted process.Dene

    Z t = exp t

    0s dW s

    t

    02s ds/ 2

    Stochastic Calculus p. 19/2

    Exponential Martingales

  • 8/8/2019 FXX

    46/68

    Exponential Martingales

    Let W t be a standard Wiener process, wth Brownianltration F t , and let t be a bounded, adapted process.Dene

    Z t = exp t

    0s dW s

    t

    02s ds/ 2

    Fact: Z t is a positive martingale.

    Stochastic Calculus p. 19/2

    Exponential Martingales

  • 8/8/2019 FXX

    47/68

    po e t a a t ga es

    Let W t be a standard Wiener process, wth Brownianltration F t , and let t be a bounded, adapted process.Dene

    Z t = exp t

    0s dW s

    t

    02s ds/ 2

    Fact: Z t is a positive martingale. Proof: It!

    Stochastic Calculus p. 19/2

    Exponential Martingales

  • 8/8/2019 FXX

    48/68

    p g

    Let W t be a standard Wiener process, wth Brownianltration F t , and let t be a bounded, adapted process.Dene

    Z t = exp t

    0s dW s

    t

    02s ds/ 2

    Fact: Z t is a positive martingale. Proof: It!

    dZ t = Z t t dW t Z t 2

    t dt/ 2+ Z t 2

    t dt/ 2= Z t t dW t =

    Z t = Z 0 +

    t

    0 Z s s dW sStochastic Calculus p. 19/2

    Girsanovs Theorem

  • 8/8/2019 FXX

    49/68

    Girsanov s Theorem

    Because Z t is a positive martingale under P with initialvalue Z 0 = 1 , for every xed time T the random variableZ T is a likelihood ratio: that is,

    Q(F ) := E P (I F Z T )

    denes a new probability measure on the algebra F T of events F that are observable by time T .

    Stochastic Calculus p. 20/2

    Girsanovs Theorem

  • 8/8/2019 FXX

    50/68

    Girsanov s Theorem

    Because Z t is a positive martingale under P with initialvalue Z 0 = 1 , for every xed time T the random variableZ T is a likelihood ratio: that is,

    Q(F ) := E P (I F Z T )

    denes a new probability measure on the algebra F T of events F that are observable by time T .Theorem: Under the measure Q, the process

    {W t t

    0 s ds}0 t T is a standard Wiener process.

    Stochastic Calculus p. 20/2

    Exchange Rates

  • 8/8/2019 FXX

    51/68

    g

    Consider again the $ and currencies. Assume that eachhas a riskless Money Market, and that the rates of returnr A , r B are constant. Assume that the exchange rate Y tobeys

    dY t = ( r B r A)Y t dt + Y t dW t

    where W t is a standard Wiener process under therisk-neutral probability QB for investors. Thus,

    Y t = Y 0

    exp{(r B r A 2

    / 2)t + W t }.

    Stochastic Calculus p. 21/2

    Exchange Rates

  • 8/8/2019 FXX

    52/68

    g

    Since

    dQA

    dQB F T =Y T Y 0 exp{ (r B r A)T }

    = exp {W T 2 T/ 2}

    Stochastic Calculus p. 22/2

    Exchange Rates

  • 8/8/2019 FXX

    53/68

    Since

    dQA

    dQB F T =Y T Y 0 exp{ (r B r A)T }

    = exp {W T 2 T/ 2}

    Girsanov implies that under QA the process W t is aWiener process with drift . Thus, to the $ investor, itappears that the exchange rate obeys

    dY t = ( r B r A 2 )Y t dt + Y t dW t

    where W t is a standard Wiener process under QA .Stochastic Calculus p. 22/2

  • 8/8/2019 FXX

    54/68

    Stochastic Calculus p. 23/2

    Proof of Girsanov 1

  • 8/8/2019 FXX

    55/68

    The statement that X is a standard Wiener process is anassertion that the increments of X are independentGaussian random variables with the correct variances.Lets show that under Q, the distribution of W T T isgaussian with var T (where T =

    T 0 s ds).

    Stochastic Calculus p. 24/2

    Proof of Girsanov 1

  • 8/8/2019 FXX

    56/68

    The statement that X is a standard Wiener process is anassertion that the increments of X are independentGaussian random variables with the correct variances.Lets show that under Q, the distribution of W T T isgaussian with var T (where T =

    T 0 s ds). For this, it

    sufces to show that for any real ,E Q exp{(W T T )} = exp {

    2 T/ 2}

    Stochastic Calculus p. 24/2

    Proof of Girsanov 1

  • 8/8/2019 FXX

    57/68

    The statement that X is a standard Wiener process is anassertion that the increments of X are independentGaussian random variables with the correct variances.Lets show that under Q, the distribution of W T T isgaussian with var T (where T =

    T 0 s ds). For this, it

    sufces to show that for any real ,E Q exp{(W T T )} = exp {

    2 T/ 2}

    To evaluate the expectation, change measure:

    E Q exp{(W T T )} = E P exp{(W T T )}Z T

    Stochastic Calculus p. 24/2

    Proof of Girsanov 2

  • 8/8/2019 FXX

    58/68

    Objective: Show that E P H T = 1 , where

    H t = exp {(W t t ) 2 t/ 2}Z t

    Stochastic Calculus p. 25/2

    Proof of Girsanov 2

  • 8/8/2019 FXX

    59/68

    Objective: Show that E P H T = 1 , where

    H t = exp {(W t t ) 2 t/ 2}Z t

    = exp { t

    0(s + ) dW s +

    t

    0(s

    2s / 2

    2 / 2) ds}

    Stochastic Calculus p. 25/2

    Proof of Girsanov 2

  • 8/8/2019 FXX

    60/68

    Objective: Show that E P H T = 1 , where

    H t = exp {(W t t ) 2 t/ 2}Z t

    = exp { t

    0(s + ) dW s +

    t

    0(s

    2s / 2

    2 / 2) ds}

    = exp { t0 (s + ) dW s t0 (s + )2 ds/ 2}

    Stochastic Calculus p. 25/2

    Proof of Girsanov 2

  • 8/8/2019 FXX

    61/68

    Objective: Show that E P H T = 1 , where

    H t = exp {(W t t ) 2 t/ 2}Z t

    = exp { t

    0(s + ) dW s +

    t

    0(s

    2s / 2

    2 / 2) ds}

    = exp { t0 (s + ) dW s t0 (s + )2 ds/ 2}Thus, H t is an exponential martingale under P , and soits expectation is constant over time.

    Stochastic Calculus p. 25/2

    Proof of Girsanov 2

  • 8/8/2019 FXX

    62/68

    Objective: Show that E P H T = 1 , where

    H t = exp {(W t t ) 2 t/ 2}Z t

    = exp { t

    0(s + ) dW s +

    t

    0(s

    2s / 2

    2 / 2) ds}

    = exp { t0 (s + ) dW s t0 (s + )2 ds/ 2}Thus, H t is an exponential martingale under P , and soits expectation is constant over time. A similar

    calculation establishes the independence of the

    increments.Stochastic Calculus p. 25/2

    Scratch

  • 8/8/2019 FXX

    63/68

    Stochastic Calculus p. 26/2

    Scratch

  • 8/8/2019 FXX

    64/68

    Stochastic Calculus p. 26/2

    Scratch

  • 8/8/2019 FXX

    65/68

    Stochastic Calculus p. 26/2

    Scratch

  • 8/8/2019 FXX

    66/68

    Stochastic Calculus p. 27/2

    Scratch

  • 8/8/2019 FXX

    67/68

    Stochastic Calculus p. 27/2

    Scratch

  • 8/8/2019 FXX

    68/68

    Stochastic Calculus p. 27/2