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Fundamentals of Programming Languages-II Subject Code: 110010 Teaching Scheme Examination Scheme Theory: 1 Hr./Week Online Examination: 50 Marks Practical: 2 Hrs./Week
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Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

Jan 04, 2016

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Page 1: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

Fundamentals of Programming Languages-II

Subject Code: 110010Teaching Scheme Examination SchemeTheory: 1 Hr./Week Online Examination: 50 MarksPractical: 2 Hrs./Week

Page 2: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

Unit-I

Microprocessors and Micro-Controllers Architectures and Programming Concepts

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Page 3: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

1.5 SEGMENTATION AND PAGING

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Page 4: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

Basic Concepts: Pure Paging and Segmentation

• Paging: memory divided into equal-sized frames. All process pages loaded into non-necessarily contiguous frames

• Segmentation: each process divided into variable-sized segments. All process segments loaded into dynamic partitions that are not necessarily contiguous

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Page 5: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

Hardware Translation

• Translation from logical to physical can be done in software but without protection–Why “without” protection?

• Hardware support is needed to ensure protection• Simplest solution with two registers: base and

size

Processor

Physicalmemory

translationbox (MMU)

Page 6: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

Segmentation Hardware

virtual addressoffset

segment

segment table

+ physical address

Page 7: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

Segmentation• Segments are of variable size• Translation done through a set of (base, size,

state) registers - segment table• State: valid/invalid, access permission,

reference bit, modified bit• Segments may be visible to the programmer

and can be used as a convenience for organizing the programs and data (i.e code segment or data segments)

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Page 8: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

Paging hardware

virtual address

page table

+ physical addresspage # offset

Page 9: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

Paging• Pages are of fixed size• The physical memory corresponding to a page is

called page frame• Translation done through a page table indexed by

page number• Each entry in a page table contains the physical

frame number that the virtual page is mapped to and the state of the page in memory

• State: valid/invalid, access permission, reference bit, modified bit, caching

• Paging is transparent to the programmer

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Page 10: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

Combined Paging and Segmentation

• Some MMU combine paging with segmentation• Segmentation translation is performed first• The segment entry points to a page table for that

segment• The page number portion of the virtual address is

used to index the page table and look up the corresponding page frame number

• Segmentation not used much anymore so we’ll concentrate on paging– UNIX has simple form of segmentation but does not

require any hardware support

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Page 11: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

Address Translation

CPU p d

p

f

f d

f

d

page tableMemory

virtual address

physical address

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Page 12: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

Translation Lookaside Buffers

• Translation on every memory access must be fast• What to do?

Caching, of course …

Why does caching work? That is, we still have to lookup the page table entry and use it to do translation, right?

Same as normal memory cache – cache is smaller so can spend more $$ to make it faster

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Page 13: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

Translation Lookaside Buffer• Cache for page table entries is called the

Translation Lookaside Buffer (TLB)– Typically fully associative– No more than 64 entries

• Each TLB entry contains a page number and the corresponding PT entry

• On each memory access, we look for the page frame mapping in the TLB

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Page 14: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

Translation Lookaside Buffer

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Page 15: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

Address Translation

CPU p d

f d

f

d

TLB

Memory

virtual address

physical address

p/f

f

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Page 16: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

TLB Miss• What if the TLB does not contain the appropriate

PT entry?– TLB miss– Evict an existing entry if does not have any free ones

• Replacement policy?

– Bring in the missing entry from the PT

• TLB misses can be handled in hardware or software– Software allows application to assist in replacement

decisions

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Page 17: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

Where to Store Address Space?• Address space may be larger than physical

memory• Where do we keep it?• Where do we keep the page table?

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Page 18: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

Where to Store Address Space?

• On the next device down our storage hierarchy, of course …

Memory

VM

Disk

Page 19: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

Where to Store Page Table?

• Interestingly, use memory to “enlarge” view of memory, leaving LESS physical memory

• This kind of overhead is common–For example, OS uses CPU cycles to implement abstraction of threads

• Gotta know what the right trade-off is

• Have to understand common application characteristics

• Have to be common enough!• Page tables can get large. What

to do?

OS

Code

Globals

Stack

Heap

P1 Page Table

P0 Page Table

In memory, of course …

Page 20: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

Two-Level Page-Table Scheme

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Page 21: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

Two-Level Paging Example• A logical address (on 32-bit machine with 4K

page size) is divided into:– a page number consisting of 20 bits.– a page offset consisting of 12 bits.

• Since the page table is paged, the page number is further divided into:– a 10-bit page number. – a 10-bit page offset.

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Page 22: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

Two-Level Paging Example• Thus, a logical address is as follows:

• where pi is an index into the outer page table, and p2 is the displacement within the page of the outer page table.

page number page offset

pi p2 d

10 10 12

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Page 23: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

Address-Translation Scheme

• Address-translation scheme for a two-level 32-bit paging architecture

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Page 24: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

Multilevel Paging and Performance• Since each level is stored as a separate table in memory, covering a logical

address to a physical one may take four memory accesses.• Even though time needed for one memory access is quintupled, caching

permits performance to remain reasonable.• Cache hit rate of 98 percent yields:• effective access time = 0.98 x 120 + 0.02 x 520• = 128 nanoseconds.

which is only a 28 percent slowdown in memory access time.

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Page 25: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

Paging the Page Table

• Page tables can still get large• What to do?

P1 PT

P0 PT

Kernel PT

Non-page-able

Page-able

OS Segment

Page the page table!

Page 26: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

Inverted Page Table• One entry for each real page of memory.• Entry consists of the virtual address of the page

stored in that real memory location, with information about the process that owns that page.

• Decreases memory needed to store each page table, but increases time needed to search the table when a page reference occurs.

• Use hash table to limit the search to one — or at most a few — page-table entries.

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Page 27: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

Inverted Page Table Architecture

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Page 28: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

How to Deal with VM Size of Physical Memory?

• If address space of each process is size of physical memory, then no problem– Still useful to deal with fragmentation

• When VM larger than physical memory– Part stored in memory– Part stored on disk

• How do we make this work?

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Page 29: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

Demand Paging• To start a process (program), just load the code page

where the process will start executing• As process references memory (instruction or data)

outside of loaded page, bring in as necessary• How to represent fact that a page of VM is not yet in

memory?

012

1 vii

A

B

C

0

1

23

A

0

1

2

B

C

VM

Paging Table Memory Disk

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Page 30: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

Vs. Swapping

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Page 31: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

Page Fault• What happens when process references a page

marked as invalid in the page table?– Page fault trap– Check that reference is valid– Find a free memory frame– Read desired page from disk– Change valid bit of page to v– Restart instruction that was interrupted by the trap

• Is it easy to restart an instruction?• What happens if there is no free frame?

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Page 32: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

Page Fault (Cont’d)• So, what can happen on a memory access?

– TLB miss read page table entry– TLB miss read kernel page table entry– Page fault for necessary page of process page table– All frames are used need to evict a page modify a

process page table entry• TLB miss read kernel page table entry

– Page fault for necessary page of process page table– Uh oh, how deep can this go?

– Read in needed page, modify page table entry, fill TLB

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Page 33: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

Cost of Handling a Page Fault• Trap, check page table, find free memory frame (or find victim) … about

200 - 600 s• Disk seek and read … about 10 ms• Memory access … about 100 ns• Page fault degrades performance by ~100000!!!!!

–And this doesn’t even count all the additional things that can happen along the way

• Better not have too many page faults!• If want no more than 10% degradation, can only have 1 page fault for

every 1,000,000 memory accesses• OS had better do a great job of managing the movement of data between

secondary storage and main memory

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Page 34: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

1.6 PROCESSING OF INTERRUPTS AND EXCEPTIONS

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Page 35: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

INTERRUPTS• The event that causes the interruption is

called interrupt and the special routine which is executed is called interrupt service routine.

• When many I/O devices are connected to a microprocessor based system, one or more than one of the I/O devices may request for service at any time. The microprocessor stops the execution of the current program and gives service to the I/O devices. This feature is called as interrupt.

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Page 36: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

The interrupts are classified as:1. Single level interrupts2. Multi level interrupts

•In a single level interrupt there can be many interrupting devices. But all interrupt requests are made via a single input pin of the CPU.•In multilevel interrupts, processor has more than one interrupt pins.1.The processor completes its current instruction. No instruction is cut off in the middle of its execution.

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Page 37: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

2. The program counter’s current contents are stored on the stack. During the execution of the program counter is pointing to the memory location for the next instruction.

3. The program counter is loaded with the address of an interrupt service routine.

4. Program execution continues with the instruction taken from the memory location pointed by the new program counter contents.

5. The interrupt program continues to execute until a return instruction is executed.

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Page 38: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

6. After execution of the RET instruction processor gets the old address of the program counter from the stack and puts it back into the program counter. This allows the interrupted program to continue executing at the instruction following one where it was interrupted.

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Page 39: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

Exceptions•The internally generated errors which produce an interrupt for microprocessor are called exceptions.•The exceptions are classified as

Faults: Faults are the exceptions that are detected and serviced before the execution of the faulting instruction.

Traps: Traps are exceptions that are reported immediately after the execution of the instructions which causes the problem.

Aborts: Aborts are exceptions which do not permit the precise location of the instruction causing the exception to be determined. Aborts are used to report severe errors, such as hardware error, or illegal values in the system tables.

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Page 40: Fundamentals of Programming Languages-II Subject Code: 110010 Teaching SchemeExamination Scheme Theory: 1 Hr./WeekOnline Examination: 50 Marks Practical:

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