UNIVERSITI TUN HUSSEIN ONN MALAYSIA FACULTY OF MECHANICAL AND MANUFACTURING ENGINEERING COURSE TITLE : ENGINEERING LABORATORY VI (BDA 37101) TOPIC : RECTILINEAR CONTROL SYSTEM TO COMPARE THE DIFFERENT STIFFNESS OF THE SPRING 1. INTRODUCTION A control system is an interconnection of components forming a system configuration that will provide a desired system response. In control system, the relationship between the input and output represents the cause and effect relationship of the process. The control system requires us to understand and modelled the systems. There are two types of control systems, which open-loop control system and closed-loop control system. An open-loop control system utilizes an actuating device to control the process directly without using feedback. Meanwhile a closed-loop control system uses a measurement of the output and feedback of this signal to compare it with the desired output (reference or command). The transfer function of a linear system is a mathematical representation of the system which defined as the ratio of the Laplace transform of the output variable to the Laplace transform of the input variable, with all conditions equal to zero. This transfer function represents the relationship describing the dynamics of the system under consideration. By using transfer function we can calculate the system with several parameters that can be measured. This technique uses the experimental approach to get the transfer function of a system is known as system identification.
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UNIVERSITI TUN HUSSEIN ONN MALAYSIA FACULTY OF MECHANICAL AND MANUFACTURING ENGINEERING
COURSE TITLE : ENGINEERING LABORATORY VI (BDA 37101)
TOPIC : RECTILINEAR CONTROL SYSTEM TO COMPARE THE
DIFFERENT STIFFNESS OF THE SPRING
1. INTRODUCTION
A control system is an interconnection of components forming a system
configuration that will provide a desired system response. In control system, the
relationship between the input and output represents the cause and effect relationship
of the process. The control system requires us to understand and modelled the
systems. There are two types of control systems, which open-loop control system and
closed-loop control system. An open-loop control system utilizes an actuating device
to control the process directly without using feedback. Meanwhile a closed-loop
control system uses a measurement of the output and feedback of this signal to
compare it with the desired output (reference or command).
The transfer function of a linear system is a mathematical representation of the
system which defined as the ratio of the Laplace transform of the output variable to
the Laplace transform of the input variable, with all conditions equal to zero. This
transfer function represents the relationship describing the dynamics of the system
under consideration. By using transfer function we can calculate the system with
several parameters that can be measured. This technique uses the experimental
approach to get the transfer function of a system is known as system identification.
UNIVERSITI TUN HUSSEIN ONN MALAYSIA FACULTY OF MECHANICAL AND MANUFACTURING ENGINEERING
2. OBJECTIVES
The objectives of this experiment are:
I. To learn how to analyse control system through simulation using rectilinear
plant system.
II. To compare the result obtained from the experiment by using different
parameters of rectilinear plant system.
III. To study the effect of different position of spring and number of encoder of
the rectilinear plant system.
3. LEARNING OUTCOMES
At the end of this experiment, students should be able to:
I. To develop skills for working with others in an experimental environment.
II. To know how to relate the experiment in real application.
4. SCOPE
I. Analyse the parameter by using two springs which 400 N/m and 800 N/m.
II. Analyse the result by using three encoders with and without damper.
UNIVERSITI TUN HUSSEIN ONN MALAYSIA FACULTY OF MECHANICAL AND MANUFACTURING ENGINEERING
5. THEORY
In control theory, a controller is a device which monitors and affects the
operational conditions of a given dynamical system. The operational conditions are
typically referred to us output variables of the system that can be effected by adjusting
certain input variable.
Figure 1: Schematic view of rectilinear system
Schematic of model:
2 masses/inertia ,
Each have a positioning freedom : 2DOF system
Connected via spring element ,
Model damping : a viscous damping ,
Input u ; F to output y : =
UNIVERSITI TUN HUSSEIN ONN MALAYSIA FACULTY OF MECHANICAL AND MANUFACTURING ENGINEERING
Much smaller amplitude response become dominated by nonlinear friction effects and
do not reflect the salient system dynamic. Divide the number of cycles by the time taken to
complete them. Sure to take beginning and end times from the same phase of the respective
cycles. Convert the resulting frequency in Hz to radian/sec. This damped frequency ,
approximates the natural frequency, according to :
f = ……………………. (1)
= ………………………… (2)
= ………………… (3)
Measure the initial cycle amplitude and the last cycle amplitude for the n cycle
measured. Using relationships associated with the logarithmic decrement.
= ln ) ..…………….(4)
UNIVERSITI TUN HUSSEIN ONN MALAYSIA FACULTY OF MECHANICAL AND MANUFACTURING ENGINEERING
6. APPARATUS
Figure 2 shows the equipment used for this experiment. The equipment consists
of:
a. Electromechanical plant
b. System interface software
c. Real-time controller & I/O
UNIVERSITI TUN HUSSEIN ONN MALAYSIA FACULTY OF MECHANICAL AND MANUFACTURING ENGINEERING
7. PROCEDURES
7.1 IDENTIFYING THE PLANT PARAMETER
This procedure is to identify the plant parameters applicable to the equation in
theory (5). The approach will be to indirectly measure the mass, spring, and
damping parameters by making measurements of the plant while set up in a pair of
classical spring-mass configurations.
1. Setup all three carriages. Clamp the first carriage to prevent the first
carriage from moving. Verify the stiffness of the spring that is medium
stiffness (400 N/m) and high stiffness (800 N/m).
2. The medium spring (400 N/m) is connecting to the first carriage and the
second carriage. Meanwhile a high stiffness spring (800 N/m) is
connecting to the second and third carriage.
3. Secure four 500g masses on the second and third mass carriage.
4. With the controller powered up, enter the control Algorithm box via the set
up menu and set Ts=0.00442. Enter the command menu, go to Trajectory
and select step, step-up. Select Open Loop Step and input a step size of
zero a duration of 3000 ms and 1 repetition. Exit to the background screen
by consecutively selecting OK. This put the controller in a mode for
acquiring 6 second of data on command but without driving the actuator.
This procedure may be repeated and the duration adjusted to vary the data
acquisition period.
5. Go to Set Up Data Acquisition in the Data Menu and select Encoder #2
and Encoder #3 as data to acquired and specify data sampling every 2(two)
servo cycles. Select OK to exit. Select zero position from the Utility Menu
to zero the encoder positions.
UNIVERSITI TUN HUSSEIN ONN MALAYSIA FACULTY OF MECHANICAL AND MANUFACTURING ENGINEERING
6. Click on Command, Execute. Prepare to manually compress the third
carriage approximately 2.5 cm. Then, click Run from the Execute box and
release the carriage after one second. Wait while the encoder data is
collected to record the response. Select OK after data is uploaded.
7. Choose several consecutive cycles (say~4) in the amplitude range between
5500 and 1000 counts. This is representative of oscillation amplitudes
during later closed loop control maneuvers. Much smaller amplitude
responses become dominated by nonlinear friction effects and do not
reflect the salient system dynamics. Divide the number of cycles by the
time taken to complete them. Be sure to take beginning and end time from
the same phase of the respective cycles. Convert the resulting frequency in
Hz to radian/sec.
8. Remove all the masses from the second carriage and third carriage and
repeat step 4 until 7 to obtain data for unloaded carriage. If necessary,
repeat step 4 to reduce the execution duration.
9. Next, attach the damper to the third carriage. Repeat step 4 until step 7 to
obtain the data with damper in the system.
10. Measure the initial cycle amplitude X0 and the last cycle amplitude Xn for
the n cycles measured in step 7.
11. Repeat step 4 until step 10 for the opposite position of spring. The high
stiffness spring (800 N/m) is connecting the first and second carriage.
While medium stiffness spring (400 N/m) is connecting the second and
third carriage.
UNIVERSITI TUN HUSSEIN ONN MALAYSIA FACULTY OF MECHANICAL AND MANUFACTURING ENGINEERING
8. OBSERVATION
1. When the medium stiffness spring (400 N/m) is attached between carriage 2 and
carriage 3, the time taken for mass carriages to stop moving after it have been apply
force is shorter.
2. When load (2kg mass) involved in the system, the time taken for carriages to stop
moving are longer compare to system without load.
3. The attachment of damper in the system also cause the time taken for carriages to stop
moving become shorter compare to system that unattached to damper.
4. When the high stiffness spring (800 N/m) is attached between carriage 2 and
carriage 3, the time taken for mass carriages to stop moving after it have been apply
force is longer.
5. When load (2kg mass) involved in the system, the time taken for carriages to stop
moving are also shorter compare to system without load.
6. The attachment of damper in the system also causes the time taken for carriages to
stop moving become longer compare to system that unattached to damper.
UNIVERSITI TUN HUSSEIN ONN MALAYSIA FACULTY OF MECHANICAL AND MANUFACTURING ENGINEERING
9. CALCULATION
Spring 400 N/m with load (Encoder 2)
(Graph 1)
f =
=
= 1.293 Hz
=
= 2
= 8.124 rad/s
= ln )
ln )
= 0.040
=
=
= 8.131 rad/s
800 N/m Encoder 3
f =
=
= 1.293 Hz
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=
= 2
= 8.124 rad/s
= ln )
ln )
= 0.042
=
=
= 8.131 rad/s
Spring 400 N/m without load (Encoder 2)
(Graph 2)
f =
=
= 2.459 Hz
=
= 2
= 15.450 rad/s
= ln )
ln )
= 0.0504
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=
=
= 15.469 rad/s
Spring 800 N/m (Encoder 3)
f =
=
= 2.459 Hz
=
= 2
= 15.450 rad/s
= ln )
ln )
= 0.0553
=
=
= 15.47 rad/s
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Spring 400 N/m with load with damper (Encoder 2)
(Graph 3)
f =
=
= 2.222 Hz
=
= 2
= 13.961 rad/s
= ln )
ln )
= 0.0739
=
=
= 13.999 rad/s
Spring 800 N/m (Encoder 3)
f =
=
= 2.273 Hz
=
= 2
= 14.28 rad/s
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= ln )
ln )
= 0.094
=
=
= 14.344 rad/s
Spring 400 N/m without loaded with damper ( Encoder 2)
Graph 4
f =
=
= 2.127 Hz
=
= 2
= 13.364 rad/s
= ln )
ln )
= 0.349
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=
=
= 14.264 rad/s
Spring 800 N/m (Encoder 3)
f =
=
= 2.127 Hz
=
= 2
= 13.364 rad/s
= ln )
ln )
= 0.4283
=
=
= 14.789 rad/s
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Spring 400 N/m with load ( Encoder 2)
Graph 5
f =
=
= 1.363 Hz
=
= 2
= 8.567 rad/s
= ln )
ln )
= 0.033
=
=
= 8.571 rad/s
Spring 800 N/m ( Encoder 3)
f =
=
= 1.4285 Hz
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=
= 2
= 8.975 rad/s
= ln )
ln )
= 0.026
=
=
= 8.983 rad/s
Spring 800 N/m without load ( Encoder 2)
Graph 6
f =
=
= 3 Hz
=
= 2
= 18.849 rad/s
= ln )
ln )
= 0.0617 rad/s
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=
=
= 18.885 rad/s
Spring 400 N/m ( Encoder 3)
f =
=
= 3 Hz
=
= 2
= 18.849 rad/s
= ln )
ln )
= 0.0533 rad/s
=
=
= 18.875 rad/s
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Spring 800 N/m with load with damper ( Encoder 2)
Graph 7
f =
=
= 1.4084 Hz
=
= 2
= 8.8492 rad/s
= ln )
ln )
= 0.2041 rad/s
=
=
= 9.0394 rad/s
Spring 400 N/m ( Encoder 3)
f =
=
= 1.4925 Hz
=
= 2
= 9.3776 rad/s
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= ln )
ln )
= 0.1281 rad/s
=
=
= 9.4555 rad/s
Spring 800 N/m without load with damper ( Encoder 2)
Graph 8
f =
=
= 2.5 Hz
=
= 2
= 15.707 rad/s
= ln )
ln )
= 0.0109 rad/s
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=
=
= 15.7079 rad/s
Spring 400 N/m (Encoder 3)
f =
=
= 3.5714 Hz
=
= 2
= 22.439 rad/s
= ln )
ln )
= 0.3665
=
=
= 24.117 rad/s
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