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Force 2.9 Student Copy

Jul 06, 2018

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Christopher Au
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    2.9 Equilibrium of Force

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    Form 4© COPYRIGHT BY SUPER EDUCATION GROUP (JO

    2.9 Equ!"rum o# For$%

    PREPARED BY JJ &R'EON P% *© COPYRIGHT BY SUPER EDUCATION GROUP (JOHOR JAYA)

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    Newton Memory

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    find the resultant force

    (c)

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    (f)

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    2.9 IDEA OF EQUII!"IUM FO"#E$

     Newton 3rd Law of Motion : Action is e%ual to reaction

    An object state that is in e%uili&rium when :

    1. ………………………………………………………………………………………………

    2. ………………………………………………………………………………………………

    stationary object

      An object movin with !niform ve"ocity

     

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    #t is in a stationary state

    #t is movin with !niform ve"ocity

    Normal reaction, R Normal reaction, R

    Weight, W=mg weight, W=mg

    Magnitude of R = W Magnitude of R = mg cos θ  

    R and W acts in opposite direction. And acts in opposite direction.

    So, Resultant force = W – R = 0 So ,Resultant force = mg cos θ   – R =

    0

    ( o!ect in e"uilirium # ( o!ect in e"uilirium #

    normal reaction, R

    friction force

    force, $ 

      Weight, W 

    $orce , $ = $rictional force

      = –

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    2.9.' Addition of Force

    1. Addition of force is defined as ...……………………………………………………..

    ………………………………………………………………………………………………

    ………………………………………………………………………………………………

      Examples : the forces are acting in one direction

      $1 % 1& N

      $2 % ' N

      es!"tant force $

     Example : the forces are acting in opposite directions

      $1 % 1& N

      $2 % ' N

      es!"tant force $

     Example : the forces are acting in different directions

      $2 % ' N

    '&&  $

     

    $1 % 1& N

     

    *ara""e"oram method:1. +raw to sca"e.

    2. +raw the "ine ,ara""e" with $1 to the ede of $2 and the "ine ,ara""e" with $2 to the ede of $1

    3. -onnect the diaona" of the ,ara""e"oram startin from the initia" ,oint.

    . Meas!re the "enth of the diaona" from the initia" ,oint as the va"!e of the res!"tant force.

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    a res!"tant force is a sin"e force the

    re,resents in manit!de and direction two or more forces actin on an object

    $ res!"tant % the tota" of forces (inc"!din the directions of the forces)

    = $ % & $ ' = %0 & = % N

      = $ % ) $ '  = %0 ) = N

     

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      $2

      $

    $1

    /rian"e method

    1. +raw to sca"e.

    2. +is,"ace one of the forces to the ede of another force.

    3. -om,"ete the trian"e and meas!re the res!"tant force from the initia" ,oint.

    E(am)le '* +!rin 0,ort +ay two teams in t! of war com,etition ,!"" with forces of &&& N and

    '3&& N res,ective"y. hat is the va"!e of the res!"tant force Are the two team in

    e4!i"ibri!m

    E(am)le 2* A boat in a river is ,!""ed hori5onta""y by two wor6men. or6men A

     ,!""s with a force of 2&& N whi"e wor6men whi"e wor6men 7 ,!""s with a force of 3&&

     N. /he ro,es !sed ma6e an an"e 2'& with each other. +raw a ,ara""e"oram and "abe" the

    res!"tant force !sin sca"e of 1 cm : '& N. +etermine the manit!de of res!"tant force.

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    */., $m

    2,/

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    2.9.2 "esolution of a force

    1. eso"!tion of a force is …………………………………………………………………

      θ

    efer to trionometric form!"a:

    E(am)le *  /he fi!re be"ow shows A"i mo,,in the f"oor with a force '& N

    at an an"e of && to the f"oor.

      $ % '& N

    E(am)le of reso"!tion and combination of forces

    PREPARED BY JJ &R'EON P% 0© COPYRIGHT BY SUPER EDUCATION GROUP (JOHOR JAYA)

    re*erse process of +nding the resultant force

      $      $ is the resultant force of $- and

    $

    herefore, $ can e resol*ed

    into $- and $ 

      $

    /ertical $- 

      omponent 

    os θ  =

    F  x 

      , therefore $  -  = $ cos θ 

    Sin θ  =

    F y 

      , therefore $    = $ sin θ 

     

    $  - 

     $    

    mg = 100 N

    600

    F = ?

    200 N

    400

    400

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    +ro&lem sol,in-

    1. hen a system is in e4!i"ibri!m ……………………………………………………….

    2. #f a"" forces actin at one ,oint are reso"ved into hori5onta" and vertica"

    com,onents ……………………………………………………………………………

    3. 89am,"e 1 0how on a fi!re

    a) the direction of tension force / of strin

     b) the res!"tant force act to "am,

    c) ca"c!"ate the manit!de of tension force /

    m"am, % 1.' 6

      "am, % 1.; N

    E(ercise 2.9

    1. /wo force with manit!de 1< N and N act a"on a straiht "ine. ith the aid of diarams determine

    the ma9im!n ,ossib"e va"!e and the minim!m ,ossib"e va"!e of the res!"tant force.

    2. A footba"" is 6ic6ed sim!"taneo!s"y by two ,"ayers with force 22& N and 2&& N res,ective"y as shown

    in $i!re 2.=. -a"c!"ate the manit!de of the res!"tant force.

     

    22& N

    =&&

      2&& N

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      the resultant force is e"ual to 2ero.

    the sum of each component is e"ual to 2ero.

    700  70

    0

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