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Food choice • Foraging: the act of an animal searching for food • Animals seek out food sources that will give them the most energy reward for the least amount of energy expended • Today: examine foraging behaviors of birds in the quad
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Page 1: Food choice tz

Food choice

• Foraging: the act of an animal searching for food

• Animals seek out food sources that will give them the most energy reward for the least amount of energy expended

• Today: examine foraging behaviors of birds in the quad

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• What factors might influence seed selec@on in the birds we will be watching?

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Birds we might seeJunco Bluejay NuthatcherHH H H

Black birdSparrow

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Three types of seeds

• Black oil (soI hulled)• Safflower (small, soI hulled)• Striped sunflower (large, thick hulled)

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• Come up with a hypothesis as to why birds will choose or not choose certain seeds.

• What is your alterna@ve hypothesis?• Would your hypothesis change with different

birds?• If your hypothesis is correct, what do you

expect to observeat the feeders?

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Variables

•What is the independent variable?– Manipulated

•What is the dependent variable?– Measured

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Observa@ons: 20 minutes

• Try to be quiet and s@ll• What species of birds appear?• What types of seeds does each species eat?• How long does it take an individual bird to eat a

seed and return to the feeder?• Do different species of birds have different seed

handling techniques?• Record all of your data!

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Data Analysis: Chi2 Test

• Sta@s@cal test to test our bird feeding hypothesis

• Test based on differences between the observed results and the expected values (based on null hypothesis)

• The formula for X2 is as follows:

– o is the observed frequency– e is the frequency expected under the null hypothesis of

no difference between groups.

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Example: Snail sediment type preference

• 20 snails• 2 sediments: mud and sandNull hypothesis: There is no difference in

sediment preference for this species of snail.• Expected results: 10 in mud, 10 in sand• Actual results:– Trial 1: 13 in mud, 7 in sand– Trial 2: 11 in mud, 9 in sand

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Chi2 Test on snail results

Expected value Mud: (24 x 20)/40= 12 Expected value sand (16 x 20)/40= 8

Chi2= [(13f12)2/12] + [(11f12)2/12] + [(7f8)2/8] + [(9f8)2/8]= .416

• Now you compare your experimental value (0.416) to a cri@cal chi2 value.

Mud Sand Total

Observed 1 13 7 20

Observed 2 11 9 20

Total 24 16 40

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Chi2 Test comparison• Degrees of Freedom: the number of independent

cases(Mf1)(Nf1)

M= # rows N=# columns

(3f1)(3f1)=4• p level: level at which the given sta@s@c is on the

border between rejec@ng or not the null hypothesis– Probability that values outside this set level are due to

chance sampling errors rather than real differences• Use p=0.05– At p=0.05 you are 95% sure your results are real

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Chi2 Table

• If calculated> cri@cal value @ plevel, reject null hypothesis

• If calculated< cri@cal value @ alpha level, fail to reject null hypothesis