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Apr 14, 2015

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Page 1: FM_HM

FM &HM

LAB MANUAL

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Page 2: FM_HM

LIST OF EXPERIMENTS

1. Impact jet of water on vane

2. Performance testing on pelton wheel

3. Francis turbine on test ring

4. Performance test on centrifugal pump

5. Calibration of venturimeter

6. Calibration of orifice meter

7. Frictional losses in pipe flow

8. Loss of head due to sudden contraction

9. Performance test on multistage centrifugal pump

10. Performance test on reciprocating pump

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Page 3: FM_HM

IMPACT OF JET OF WATER ON VANE

AIM: - To find the coefficient of impact of jet on flat circular and hemispherical vanes.

APPARATUS: - experimental set-up (counter weight, semicircular vane, horizontral flat

vane), stop watch.

GENERAL DESCRIPTION:

The apparatus consists of mainly (1) Nozzle housing, (2) Nozzle, (3) Vane, (4) Transparent

Tank

(5) Measuring Tank and (6) Sump.

Nozzle housing:

It is of M.S rigidly fixed to the bottom of the tank having transparent tube and suitable to

accommodate nozzle.

Nozzle: It is of Gun Metal machined and polished nozzle of 8 mm is supplied.

Vane:

It is of Gun Metal machined all over and interchangeable.

(1) Flat vane with normal input.

(2) Hemi Spherical vane with normal input.

Transparent tank:

To observe the flow and jet deflection the tank is fitted with transparent tube.

Measuring tank: It is of suitable size and provided with gauge glass, scale arrangement for

quick and easy measurements. A Ball valve is provided to empty the tank.

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Page 4: FM_HM

Sump

It is of suitable size with a supply pump set of 1 HP operating on single phase 220-240V 50Hz

AC Supply, and a drain plug to drain the water when the unit is not in use.

Installation

Fix the transparent tube on the measuring tank with the help of four bolts and nuts provided.

Make sure that the discharge spout is exactly center of the vane and connect the necessary piping

to the apparatus.

Before commissioning

Check whether the nozzle housing, discharge pipe flange etc are fitted with gaskets to

prevent water leakage.

Check the gauge glass and meter scale assembly of the Measuring tank and see that it is

fixed water tight and vertical.

PROCEDURE:

1. Insert the required vane on the lever

2. Measure the differential levr arms and calculate the ratio of lever arms(2.0in this case).

3. Balance the lever system by means of counter weight for no load.

4. Place a weight on the hanger.

5. Open the gate valve and adjust the jet, so that the weight arm is balanced

6. Collect water in the collecting tank.

7. Note: (a) the pressure gauge reading P

(b) the weight placed W

(c) time for 5 cm. rise in the collecting tank t

8. Calculate the discharge by weight.

9. Calculate the vertical force.

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Page 5: FM_HM

Tabular form

Vane

type.

Inlet pressure

Jet

velocity

V

m/sec

Time

taken for

Rcm rise

of water

T sec

Mass flow

rate M

kg/sec

Input

force

F kg

Counter

load

W kg

Vane

coeff.

2W/F

P

Kg/cm2

H

m

of water

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CALCULATIONS:

1. Area of the collecting tank A=0.3*0.3 m2

Rise in water level R= 0.05 m(say)

Actual taken = t sec

Actual flow rate Qa=AR/t m3/sec

Actual flow rate M=1000Qa kg/sec

2. pressure gauge reading = p kg/cm2

Then, water head h= (10p) m of water

Assuming the co-efficient of discharge of nozzle as unity,

Velocity head v2/2g=H

Velocity of jet v

Angle of deflection of the vane to the jet =T1-T2 deg

Mass flow rate of water = M kg/sec

The lifting force =change in momentum per sec.

in vertical F= M*V*(sinT1-sinT2)

For horizontal flat vane, T1=90deg and T2=0deg

F= (M*V)/g

For semicircular vane, T1 =90 deg and T2=-90

F= (2*M*V)/g

3. actual lifting force measured = W*liver arm ratio kg

Fact=2.0W

The efficiency of the jet=Fact/F

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Page 7: FM_HM

PRECUTIONS:

See that there is no leakage of water from pipes.

RESULT:

Efficiency of the semicircular vane =

Efficiency of the flat vane =

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Page 9: FM_HM

PERFORMANCE TEST ON PELTON WHEEL

AIM: To study the characteristics of Pelton wheel turbine

APPARATUS: Pelton wheel turbine test rig.

DESCRIPTION

An impulse turbine is a turbomachine in which kinetic energy from one or

more fast-moving jets is converted to rotational mechanical energy delivered to

the shaft of the machine. A nozzle transforms water under a high head into

a powerful jet. The momentum of this jet is destroyed by striking the runner,

which absorbs the resulting force. No pressure change occurs at the turbine

blades, and so the turbine doesn’t require a housing for operation. The conduit

bringing high-pressure water to the impulse wheel is called the pen-stock.

Impulse turbines are most often used in very high head applications. Several

types of impulse turbines have been invented, but only one has survived in

appreciable numbers to the present day, which is the Pelton turbine. The free

water jet strikes the turbine buckets tangentially. Each bucket has a high center

ridge so that the flow is divided to leave the runner at both sides. Pelton wheels

are suitable for high heads, typically above about 450 meters with relatively low

water flow rates. For maximum efficiency the runner tip speed should equal

about one-half the striking jet velocity. The efficiency can exceed 91 percent

when operating at 60-80 percent of full load.

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PROCEDURE:

1. keep the nozzle opening at about 3/8th

open position.

2. Prime the pump if necessary.

3. Close the delivery gate valve completely and start the pump.

4. After the motor starter has changed to delta mode and the motor is running at normal

speed, open the delivery gate valve until the venture pressure gauge indicate a differential

pressure of about 0.6to 0.65 kg/cm2 this corresponds to the design flow rate.

5. Note the turbine inlet pressure in the pressure gauge fixed in the nozzle bend. If the

pressure higher or lower than 4.6kg/cm2(design head 46 m of water), adjust the delivery

gate valve and/or nozzle opening to set to design inlet pressure. At the same time , ensure

that the flow rate does not exceed the design valve as large flow rates(indicated by larger

pressure difference in the venturimeter pressure gauges)will over load the motor.

6. Note the speed of the turbine.

7. Note the venturimeter pressure gauge reading.

8. Load the turbine by adding weight to the hangar.

9. Repeat the experiment for different loads.

For constant speed tests, at lower load the flow rate and inlet pressure is reducd by

closing the delivery gate valve.

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CALCULATIONS:

1. To deter mine discharge

Venturirmeter line pressure gauge reading = P1 kg/sq.cm

Venturirmeter throat pressure gauge reading =P2 kg/sq.cm

Pressure difference dh= (P1-P2)*10 m of water

Venturirmeter equation Q=0.0055√dH m3/sec

Note: Venturirmeter in let dia .D= 65mm

Throat dia ratio B=0.6

Discharge Q= Cd*A*B2*√(2*9.81*dH)/1-B

4

Where, Cd – venturimeter discharge coefficient-0.98

A- Inlet area- 3.14*d2/4

2. To deter mine head:

Turbine pressure gauge reading = G kg/sq.cm

Totel head H=G*10 m of water

3. Input to the turbine

In put = 9.81QH KW.

4. Turbine out put

Brake drum dia = 0.40m

Rope dia =0.015m

Equiealent drum dia =0.415m

Hanger weight-To =1 kg

Weight- =T1kg

Spring load = T2 kg

Resultant load-T = (T1-T2+To) kg

Speed of the turbin = N rpm

Turbine output = (0.314*D*N*T)/(102*60) KW

=0.000215NT. KW

Turbine efficiency=output/input

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TABULAR FORM FOR CLOSED CIRCUIT

S.

no Inlet

pres..

P

kg/sq.cm

Totle

Head

H

Pressure Gauges

Readings

Kg/cm2

Discharge

m³/sec

Speed

N

rpm

Wt. on

hanger

T1kg

Spring

balance

T2 kg

Net

weight

T kg

Input

Powr

I

KW

Outpt

Power

O

KW

Effiny

%

P1 P2 P1-P2

1.

2.

3.

4.

5.

6.

7.

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TABULAR FORM FOR CONSTANT SPEED

IMPORTANT FORMULA

Efficiency = Output power X 100

Input Power X frictional efficiency

Input Power = 9810 x Supply head in meters (H) x Discharge(Q) = W x Q x H kw;

1000

Frictional efficiency =85%= 0.85

S.

no Inlet

pres..

P

kg/sq.cm

Totle

Head

H

Pressure Gauges

Readings

Kg/cm2

Discharge

m³/sec

Speed

N

rpm

Wt. on

hanger

T1kg

Spring

balance

T2 kg

Net

weight

T kg

Input

Powr

I

KW

Outpt

Power

O

KW

Effiny

%

P1 P2 P1-P2

1.

2.

3.

4.

5.

6.

7.

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Discharge = K√h m³/sec

Where,

h = (P1 - P2) x 10 m

a1 a2 √2g

K = ------------------------

√ (a1² - a2²)

Where, a1= Diameter of the venturimeter inlet = 50 mm/0.05m

a2= Diameter of the Venturimeter throat = 25 mm /0.025m

P1 = Inlet pressure, P2 = Throat pressure

Output Power = 2ΠNT Kw.

60000

N = RPM of the turbine shaft

T= Torque of the turbine shaft

T= (W1-W2) x R x 9.81

W = Load applied on the turbine.

R = Radius of the brake drum with rope in meters = 0.12 meters

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PRECAUTIONS:

1. Do not start a motor without priming.

2. Do not starting the motor without closing the delivery gate valve completely.

3. Only after the starter has changed to delta mode from the start mode ,the delivery gate

valve should be open.

Note: do not operate the motor at very low voltage of 350V and below as this will draw

excessive current, leading to motor coil burn out.

RESULTS AND CONCLUSIONS:

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Page 17: FM_HM

FRANCIS TURBINE TEST RIG

AIM: To study the characteristics of francis turbine.

APPARATUS: Francis turbine test rig.

THEORY:

Francis turbine is a reaction type hydraulic turbine to convert the hydraulic energy

into mechanical energy and electrical energy. Francis turbine are best suited for

medium heads say 40 m to 300 m. the specific speed range from 25 to 300.

The turbine test rig consists of a 3.72KW turbine supplied with a water from a

suitable 15 HP centrifugal pump through suitable pipe lines.

Water under pressure from pump enters through the guide vanes into the runner

while passing through the spiral casing and guide vanes a portion of the pressure

energy is converted velocity energy. Water thus enters the runner at a high velocity

and as it passes through the runner vanes, the remaining pressure energy converted

into kinetic energy. Due to the curvature of the vanes the KE is transformed into

the mechanical energy.

PROCEDURE:

1. Keep the guide vane at required opening (say 3/8th

).

2. Prime the pump if necessary.

3. Close the main sluice valve and then start the pump.

4. Open the sluice valve for required discharge when the pump motor switches from star to

delta mode.

5. Load the turbine by adding weight in the weight hanger. Open the brake drum cooling

water gate valve for cooling the brake drum.

6. Measure the turbine rpm wit tachometer.

7. Note the pressure gauge and vacuum gauge reading.

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Page 18: FM_HM

8. Note the venturimeter pressure gauge reading.

9. Repeat the experiment for other loads.

10. For constant speed tests, the main sluice valve has to be adjusted to vary the inlet head

and discharge for varying loads(at given guide vane opening position.

11. The experiment can be repeated fir other guide vane position.

CALCULATIONS:

1 To deter mine discharge

Venturirmeter line pressure gauge reading = P1 kg/sq.cm

Venturirmeter throat pressure gauge reading =P2 kg/sq.cm

Pressure difference dh= (P1-P2)*10 m of water

Venturirmeter equation Q=0.013√dH m3/sec

Note: Venturirmeter in let dia .D= 100mm

Throat dia ratio B=0.6

Discharge Q= Cd*A*B2*√(2*9.81*dH)/1-B

4

Where, Cd – venturimeter discharge coefficient-0.98

B- Inlet area- 3.14*d2/4

2 To deter mine inlet head of water :

Turbine pressure gauge reading = G kg/sq.cm

Turbine vacuum gauge reading = Vmm of Hg

Total head H=10(G+V/760) m of water

3 Input to the turbine

In put = 9.81QH KW.

4 Turbine out put

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Brake drum dia = 0.30m

Rope dia =0.015m

Equivalent drum dia =0.315m

Hanger weight-To =1 kg

Weight- =T1kg

Spring load = T2 kg

Resultant load-T = (T1-T2+To) kg

Speed of the turbine = N rpm

Turbine output = (0.314*D*N*T)/(102*60) KW

=0.000162NT. KW

Turbine efficiency=output/input

TABULAR COLUMN FOR CLOSED CIRCUIT

S.

no Inlet

pres..

P

kg/sq.cm

Totle

Head

H

Pressure Gauges

Readings

Kg/cm2

Discharge

m³/sec

Speed

N

rpm

Wt. on

hanger

T1kg

Spring

balance

T2 kg

Net

weight

T kg

Input

Powr

I

KW

Outpt

Power

O

KW

Effiny

%

P1 P2 P1-P2

1.

2.

3.

4.

5.

6.

7.

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TABULA COLUMN FOR CONSTANT SPEED

PRECAUTIONS:

1. Do not start a motor without priming.

2. Do not starting the motor without closing the delivery gate valve completely.

3. Only after the starter has changed to delta mode from the start mode ,the delivery gate

valve should be open.

Note: do not operate the motor at very low voltage of 350V and below as this will draw

excessive current, leading to motor coil burn out.

RESULTS AND CONCLUSIONS:

S.

no Inlet

pres..

P

kg/sq.cm

Totle

Head

H

Pressure Gauges

Readings

Kg/cm2

Discharge

m³/sec

Speed

N

rpm

Wt. on

hanger

T1kg

Spring

balance

T2 kg

Net

weight

T kg

Input

Powr

I

KW

Outpt

Power

O

KW

Effiny

%

P1 P2 P1-P2

1.

2.

3.

4.

5.

6.

7.

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Page 22: FM_HM

PERFORMANCE TEST ON CENTRIFUGAL PUMP

AIM: - To conduct a test on single stage centrifugal pump at various speeds to obtain the pump

characteristics.

APPARATUS: - centrifugal pump, stop watch, scale, collecting tank.

DESCRIPTION:

A centrifugal pump is a rotodynamic pump that uses a rotating impeller to

Increase the pressure of a fluid. It works by the conversion of the rotational

Kinetic energy, typically from an electric motor to an increased static fluid pressure.

They are commonly used to move liquids through a piping system. In

Pump terminology, the rotating assembly that consists of the shaft, the hub, the

Impeller blades and the shroud is called the impeller.

The performance of a pump is characterized by its net head h, which is defined

As the change in Bernoulli head between the suction side and the delivery

Side of the pump. h is expressed in equivalent column height of water.

The specific speed will be a constant for a particular pump, or pumps similar

to it. If we know the head, speed and the discharge desired, it is easy to

find the general type of rotodynamic pump that would prove satisfactory using

specific speed. But it is not really a speed, and is a dimensionless number. The

speed and discharge used in the expression should be the speed and discharge

for maximum efficiency. Centrifugal pumps have low specific speeds among rotodynamic

pumps, ranging from 0.02 to 1.5.

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CALCULATIONS:

1. Discharge:

Area of tank A=0.5*0.5 sq m

Rise of level h =0.1 m

Volume collected =A h cu.m

=0.25 cu.m

Time taken = t sec

Discharge Q=volume/time

=0.025/t cu.m/sec

2. Head

Total head H=10(P+V/760)m of water.

3. Output of the pump

Output = 9.81*Q*H KW

4. Input of the motor

Energy meter constant N=1200revs per KWH

Time for 10 rev = T sec

Input to motor = (3600*10)/(N*T) KW

Efficiency of motor =80% (assumed)

Transmission efficiency = 90% (assumed)

Pump input = motor output*0.8*0.9 KW

=3600*10*0.8*0.9/(100*T)

=21.6/T KW

Pump efficiency =pup output /pump input

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PROCEDURE:

1. Loosen the V-belt by rotating the hand wheel of the motor bed and position the V-belt in

the required groove of the pully.

2. Prime the pump with water if required.

3. Close the delivery gate valve completely.

4. Start the motor and adjust the gate valve to required pressure and delivery

5. Note the following reading .

The pressure gauge reading P kg/sq.cm.

The vacuum gauge reading V mm of hg.

Time for 10 rev of energymeter disc-T secs.

Time for 10 cm rise in the collecting tank t- sec

Pump speedin rpm.

Take 3 or 4 sets of reading by varying the head from a maximum at shut off to a

minimum where gate valve is fully open. The experiment is repeated for other

pump speeds.

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TABULAR FORM

s.

no

Pump

speed

N

rpm

Pressure

gauge

reading

p

kg/sq.cm

Vacuume

gauge

reading

V m of

Hg

Total

head

(P + V)

Time

taken for

collecting

10cm rise

of water

In

collecting

tank

Time taken

for 10rev of

energyMeter

disc-T sec

Discharge

Q

Cu.m/sec

Input

Power

Kw

Output

Power

Kw

Efficiency

RESULTS AND CONCLUSIONS

Graphs for :-

1. Discharge Vs Head

2. Discharge Vs Input power

3. Discharge Vs Efficiency.

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Page 27: FM_HM

CALIBRATION OF VENTURIMETER

AIM: To calibrate a given venture meter and to study the variation of coefficient of discharge of it with

discharge.

APPARATUS: Venturimeter, manometer, stop watch, experimental set-up.

DESCRIPTION:

The obstruction flow meter is a device used to measure the discharge of an

Internal flow. In these meters flow rate is calculated by measuring the pressure

Drop over an obstruction which is inserted in to path of the flow. There are many

Classifications according to the type obstruction used. The most commonly used

Categories are Venturi meter, orifice meter and nozzle meter.

Venturi meters are generally made from castings machined to close tolerances

To duplicate the performance of the standard design, so they are heavy,

Figure 2.1: Venturi meter

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Page 28: FM_HM

Bulky, and expensive. Inside the venturi meter the fluid is accelerated through

a converging cone of angle 15�20o. The pressure difference between the upstream

Side of the cone and the throat is measured by using a differential manometer

And it provides a measure for the discharge. The conical diffuser section

Downstream from the throat with a lower angle 8�12o gives excellent pressure

Recovery and so overall head loss is low compared to other obstruction flow meters.

Venturi meters are self-cleaning because of their smooth internal shape.

PROCEDURE:-

1. Select the require flow meter.

2. Open it cocks and close the other cocks so that only pressure for the meterin use

communicated to the manometer.

3. Open the flow control valve and allow a certain flow rate.

4. Vent the manometer if required.

5. Observe the readings in the manometer.

6. Collect the tank in the collecting tank.

7. Close the drain valve and find the time taken for 10cm. rise in the tank.

CALCULATIONS:

Theoretical discharge for venturimeter

Difference in nmanometer level = h m. of Hg

The equivalent pressure drop = h(13.6-1) m of water

dH = 12.6 h m of water

Flow meter equations Q= K√dH m3/sec

Where, K- flow meter constant

Note: flow meter inlet dia D=20mm/25mm

Throat dia B=0.6

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Theoretical discharge Qt=A*B2*(2*9.81*dh)/(1.B4)

Where A=inlet area

Qa = flow rate

Cd=flow meter discharge coefficient

Qt= 0.000537√dH for 20mm pipelines

=0.000839√dH for 25mm pipelines

Actual discharge

Area of the collecting tank A=104*0.4 sq.m

Rise r = 0.1 m

Time taken =t sec

The actual discharged Qa=AR/t

=0.016/t

= Cd*Qt

Where Cd is the discharge constant

Hence cd=Qa/Qt

S. No. Venturi inlet diameter

d1

Throat Diameter

d2

1. 25mm 13.5 mm

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RESULTS AND CONCLUSIONS

S. No. Differential head in

m of mercury

Time for

(10 cm)

raise of

water level

t sec

Actual discharge

Qa cu. m/sec*10-3

Theoretical

discharge = Qt

cu. m/sec*10-3

cd = Qt/Qa

h1 h2

dH

m of

water

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Page 32: FM_HM

CALIBRATION OF ORIFICE METER

AIM: -

To calibrate a given Orifice meter and to study the variation of coefficient of discharge of it with

discharge.

APPARATUS:

Orifice meter, manometer, stop watch, experimental set-up.

DESCRIPTION:

The orifice meter consists of a flat orifice plate with a circular hole drilled

in it. The construction is very simple and so cost is low compared to other

obstruction meters. There is a pressure tap upstream from the orifice plate and

another just downstream. Reduction of cross-section of the flowing stream in

passing through orifice increases the velocity head at the expense of pressure

head. This reduction of pressure between taps is measured using a differential

manometer and it gives a measure of the discharge. The pressure recovery is

poor compared to the Venturi meter.

The expression for discharge through any obstruction flow meter can be theoretically

obtained using the continuity and Bernoulli’s equations together. The

Bernoulli’s equation is defined for steady, incompressible and inviscid regions of

flow. Since the Bernoulli’s equation is a simplified form of energy equation, the

assumptions used for simplification must be satisfied when using it for practical

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PROCEDURE:

1. Select the require flow meter.

2. Open it cocks and close the other cocks so that only pressure for the meterin use

communicated to the manometer.

3. Open the flow control valve and allow a certain flow rate.

4. Vent the manometer if required.

5. Observe the readings in the manometer.

6. Collect the tank in the collecting tank.

7. Close the drain valve and find the time taken for 10cm. rise in the tank.

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CALCULATIONS:

Theoretical discharge for orificemeter:

Difference in mnanometer level = h m. of Hg

The equivalent pressure drop = h(13.6-1) m of water

dH = 12.6 h m of water

Flow meter equations Q= K√dH m3/sec

Where, K- flow meter constant

Note: flow meter inlet dia D=20mm/25mm

Throat dia B=0.6

Theoretical discharge Qt=A*B2*(2*9.81*dh)/(1.B4)

Where A=inlet area

Qa = flow rate

Cd=flow meter discharge coefficient

Qt= 0.000537√dH for 20mm pipelines

=0.000839√dH for 25mm pipelines

Actual discharge

Area of the collecting tank A=104*0.4 sq.m

Rise r = 0.1 m

Time taken =t sec

The actual discharged Qa=AR/t

=0.016/t

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Page 35: FM_HM

=Cd*Qt.

Where Cd is the discharge constant Cd=Qa/Qt

Tabular column

RESULTS AND CONCLUSIONS

S. No. Differential head in

m of mercury

Time for

(10 cm)

raise of

water level

t sec

Actual discharge

Qa cu. m/sec*10-3

Theoretical

discharge = Qt

cu. m/sec*10-3

cd = Qt/Qa

h1 h2

dH

m of

water

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Page 36: FM_HM

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Page 37: FM_HM

FRICTIONAL LOSSES IN PIPE FLOW

AIM:

The goal of this experiment is to study pressure losses due to frictional effects

(major losses) in fluid flow through pipes.

APPARATUS:

The pipe flow rig with pipes of different materials, a collecting tank with

stop watch to measure the discharge and a differential manometer to measure

the pressure drop in the test section.

DESCRIPTION:

When a fluid flows through a pipe, there is a loss of energy (or pressure) in

the fluid. This is because energy is dissipated to overcome the viscous (frictional)

forces exerted by the walls of the pipe as well as the moving fluid layers itself. In

addition to the energy lost due to frictional forces, the flow also loses pressure as

it goes through fittings, such as valves, elbows, contractions and expansions. The

pressure loss in pipe flows is commonly referred to as head loss. The frictional

losses are referred to as major losses while losses through fittings etc, are called

minor losses.

PROCEDURE:-

1. Select the require pipe line.

2. Connect the pressure tapping of the required pipe line (or the pipe fitting for minor losses

study) to the manometer b opening the appropriate pressure cocks and closing all other

pressure cocks.

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Page 38: FM_HM

3. Open the flow control valve in the pipe line and allow water to pass.

4. Vent the manometer at a reduce flow rate. Care should be taken to avoid spill over of

mercury into the header pipes while venting. Expermint should always be started by

slowly opening the control valve and simultaneously observing the mercury column in

the manometer. For accidental spill over, stop the experiment and recover the mercury

from the bottom of the header.

5. By controlling the valve, required flow rate can be obtain to get a particular Reynolds

number.

6. Note the pressure difference from the manometer mercury columns.

7. Collect the water in the collecting tank for a particular rise of level and note the time

taken.

8. Repeat the experiments if required at other flow rates.

CALCULATIONS:

Area of the collecting tank A= 0.4*0.4 sq.m

Rise of level R=0.1 m (say)

Volume collected =AR cu.m

Time taken =t sec

Discharge Q=(AR/t) cu.m/sec

1. Manometer reading (mercury filled):

Reading in the left limb=h1 m

Reading in the right limb=h2 m

Difference level=(h1-h2) m of Hg

Equivalent loss of water head = (13.6-1)*(h1-h2)

H=12.6(h1-h2) m of water

Major losses

2. Pipe line :

Diameter of the pipe line =d m

Area of the pipe a=3.12*d2/4 sq m

Velocity in the pipe V=Q/a m/sec

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Page 39: FM_HM

Test length in the pipe l=1.25 m

3. Darcy’s constant-f

Head loss H=(4flv2/2gd)

Substituting the values,

L=1.25 m; g=9.81m/sq.sec

F=3.93Hd/v2

Tabular column:

s.no

Pipe

dia

m

Manometer

reading

Head

losses

H m of

water

Time

for R

cm rise

T sec

Flow

rate Q

cu.m/sec

*10-3

Pipe

area

A

sq.m*10

-3

Flow

velocity

V

m/sec

Friction

factor f

h1 m of

hg

h2 m of

hg

RESULTS AND CONCLUSIONS

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Page 40: FM_HM

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Page 41: FM_HM

LOSS OF HEAD DUE TO SUDDEN CONTRACTION

AIM:-

To determine the coefficient of loss in sudden contraction.

APPARATUS: -

Experimental set-up, stop watch, manometer.

DESCRIPTION:

When a fluid flows through a pipe, there is a loss of energy (or pressure) in

the fluid. This is because energy is dissipated to overcome the viscous (frictional)

forces exerted by the walls of the pipe as well as the moving fluid layers itself. In

addition to the energy lost due to frictional forces, the flow also loses pressure as

it goes through fittings, such as valves, elbows, contractions and expansions. The

pressure loss in pipe flows is commonly referred to as head loss. The frictional

losses are referred to as major losses while losses through fittings etc, are called

minor losses.

PROCEDURE:-

1. Select the required pipe setting sudden expanission or contraction.

2. Connect the pressure tapping to the required pipe setting to manometer.

3. By operating the pressure cocks &closing the all remain cocks.

4. Open the flow control to the pipe line and allow water to pipe.

5. Pressure difference is measured in manometer.

6. Collect the water in the collecting tank&time taken for required rise of water.

7. Repeate this procedure for sudden contraction & bend flow fitting.

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CALCULATIONS:

1. Diameter of the pipe =d m.

Area of the pipe a=3.14*d2/4 sq.m

Velocity in the pipe V=Q/a m/sec

Velocity head hv=V2/2g

2. Loss coefficient for bend and elbow

Loss coefficient K=loss/velocity head

K=H/hv.

3. Loss coefficient for sudden expanision:

Let section 1 correspond to uniform region up stream of the expansion and section

2 correspond to uniform regiondown stream of the expansion. then from

bernoullies theorem,

P1+V12/2g+Z1= P2+V2

2/2g+Z2+losses

Where P,V,Z are the static pressure, velocity and elevation of the water partical

and losses is the pressure loss due to the sudden expansion. Since elevation is

constant, rearranging the equation,

Loss=(P1-P2)+V12/2g(1-(V2/V1)

2)

But (P1-P2) is the measured static pressure difference H in the manometer and

V2/V1=a1/a2, the area ratio of the pipes. Hence,

Loss=H+V12/2g(1-(a1/a2)

2)

Since a1/a2=(d1/d2)2=0.25,

Loss=H+0.9375(V12/2g)

Loss coefficient K=loss(V12/2g).

4. Loss coefficient for sudden contraction:

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Page 43: FM_HM

Let section 1 correspond to uniform region up stream of the expansion and section

2 correspond to uniform region downstream of the contraction. Then from

bernoullies theorem,

P1+V12/2g+Z1= P2+V2

2/2g+Z2+losses

Where P,V,Z are the static pressure, velocity and elevation of the water partical

and losses is the pressure loss due to the sudden expansion. Since elevation is

constant, rearranging the equation,

Loss=(P1-P2)+V22/2g((V1/V2)

2-1)

But (P1-P2) is the measured static pressure difference H in the manometer and

V1/V2=a2/a1, the area ratio of the pipes. Hence,

Loss=H+V22/2g((a2/a1)

2-1)

Since a1/a2=(d2/d1)2=0.25,

Loss=H-0.9375(V22/2g)

Loss coefficient K=loss(V22/2g)

PRECAUTIONS:

Readings will be taking without parallax error.

Apparatus the experiment carefully.

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TABULAR FORM

S. No.

Manometer

reading Head

loss

H m of

water

Time for

R cm

rise t sec

Flow

rate

Q

cu.m/sec

*10-3

Velocity

V m/sec

Velocity

coefficient

V2/2g m

of water

Loss

coefficient

K

h1m of

Hg

h 2 m of

Hg

1.

2.

3.

4.

5.

RESULTS AND CONCLUSIONS

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PERFORMANCE TEST ON MULTISTAGE CENTRIFUGAL

PUMP

AIM:

To conduct a test at various heads of given multistage centrifugal pump find its efficiency.

APPARATUS: -

multistage centrifugal pump, stop watch, collecting tank, piezometer,

Meter scale, driving unit, energy meter, pressure gauge, vacuum gauge.

DESCRIPTION:

A centrifugal pump is a rotodynamic pump that uses a rotating impeller to

increase the pressure of a fluid. It works by the conversion of the rotational

kinetic energy, typically from an electric motor to an increased static fluid pressure.

They are commonly used to move liquids through a piping system. In

pump terminology, the rotating assembly that consists of the shaft, the hub, the

impeller blades and the shroud is called the impeller. Centrifugal pumps are

used for large discharge through smaller heads.

Fluid enters axially through the hollow middle portion of the pump called

the eye, after which it encounters the rotating blades. It acquires tangential and

radial velocity by momentum transfer with the impeller blades, and acquires

additional radial velocity by centrifugal forces. The flow leaves the impeller

after gaining both speed and pressure as it is flung radially outward into the

scroll (or volute). The purpose of the scroll is to decelerate the fast-moving fluid

leaving the trailing edges of the impeller blades, thereby further increasing the

fluid pressure, and to combine and direct the flow from all the blade passages

toward a common outlet. If the flow is steady, incompressible and if the outlet

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Page 46: FM_HM

and inlet diameters are are same, then, according to the continuity equation the

average flow speed at the outlet is identical to that at the inlet.

A centrifugal pump is a rotodynamic pump that uses a rotating impeller to

increase the pressure of a fluid. It works by the conversion of the rotational

kinetic energy, typically from an electric motor to an increased static fluid pressure.

They are commonly used to move liquids through a piping system. In

pump terminology, the rotating assembly that consists of the shaft, the hub, the

impeller blades and the shroud is called the impeller.

PROCEDURE:-

1. The internal plan dimensions of the collecting tank and the difference in level between the

centers of vacuum and pressure gauges (X) measured.

2. The speed of the pump and the energy meter constant (Ne) are noted.

3. The pump is primed with water.

4. With the delivery valve fully closed the driving unit is started.

5. By regulating the delivery valve, the discharge and hence the delivery head varied. For

each position of the delivery valve, form completely closed to maximum open

(a) Vacuum gauge reading (Hs)

(b) Pressure gauge reading (Hd)

(c) Time (T) taken for Nr revolution of the energy meter disc

(d) Time(t) taken for a particular rise(h) of water level in the collecting tank keeping output

valve completely closed

6. The above observations, for different delivery openings are tabulated. The efficiency of the

pump is computed.

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Page 47: FM_HM

CALCULATIONS:

Internal area of collecting tank A=1*B

Actual discharge Qa=Ah/t

Weight of water W*Q*9810 N/S

Out put from the pump po=WH

Input the motor Pi=(360/Ne)*(Nr/T)*1000= watts

% efficiency of the pump = (output/input)*100

Speed of the pump=

Avg efficiency=

Energy meter constant=

Max effi. =

Internal diemensions of collecting tank

Length=

Breadth=

Difference in level between the centers of the vaccum and pressure gauge, X= m

A=10(l) m2

.

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TABULAR FORM

S.

No.

Suction

head

Delivery

hear

Total head

Ht=Hs+Hd+X

In (m)

Time

taken

for

5rev

of

energy

Meter

disc

Time

taken for

collecting

10 cm

rise of

water In

collecting

tank

Discharge

Q

Weight

of

water

Output

from

pump

Po

Input

to

motor

Pi

efficiency

m of

water

m of

water

RESULTS AND CONCLUSIONS

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Page 49: FM_HM

PERFORMANCE TEST ON RECIPROCATING PUMP

AIM-

To determine the coefficient of discharge and efficiency of double acting reciprocating

pump.conduct a test at various heads of given reciprocating pump find its efficiency.

APPAATUS:

Reciprocating pump , stop watch , scale , collecting tank.

DESCRIPTION:

Reciprocating pump is a positive displacement pump, which causes a fluid to

move by trapping a fixed amount of it then displacing that trapped volume into

the discharge pipe. The fluid enters a pumping chamber via an inlet valve and

is pushed out via a outlet valve by the action of the piston or diaphragm. They

are either single acting; independent suction and discharge strokes or double

acting; suction and discharge in both directions.

Reciprocating pumps are self priming and are suitable for very high heads

at low flows. They deliver reliable discharge flows and is often used for metering

duties because of constancy of flow rate. The flow rate is changed only by

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Page 50: FM_HM

adjusting the rpm of the driver. These pumps deliver a highly pulsed flow. If a

smooth flow is required then the discharge flow system has to include additional

features such as accumulators. An automatic relief valve set at a safe pressure is

used on the discharge side of all positive displacement pumps.

PROCEDURE:-

1. Fillup the sufficient water in the sump tank.

2. Fill up the vessel for about 2/3rd

capacity.

3. Open the gate valve in the discharge pipe of the pump fully.

4. Check rate bodes driving belt for properly tighten.

5. Divert funnels into measuring tank and slowly increase the pump speed slightly close the

discharge valve and note down the varies readings.

6. In the observations table repeat the procedure for different gate valve openings. Take care

that discharge pressure does not rise above 4 kg/m2.

CALCULATIONS:

1. Volume per stroke =2πR12

2. Theoretical discharge Qth= m3/sec

3. Suction head =Hs-suction volume of Hg*(Pgh-pw_

4. Where рgh= specific gravity of mercury=13.6

5. рw =Sp. Gravity of water =1000

6. Hg = 12.6*suction valve

7. Head= Hd-discharge pressure kg/cm2*10

8. Total head = Hd-discharge pressure kg/cm2*10

9. Actual discharge Qa=0.016/t

10. Output power of pump Po=(wQaHt/1000)=(n/te)*(3600/600)kw

11. Number of pumps =( Po/Sp)*100

12. Coefficient of discharge of the pump= Qa/Qth

13. Slip =((Qth-Qa)/Rl)*100

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TABULAR FORM

Suction

gauge

reading

m of

Hg.

Delivery

gauge

reading

kg/sq.cm

Sucti

on

head

Speed

rpm

Total

head

(P + V)

meters

Time

taken for

10cm

rise

sec

Actual

Discharge

Q

Cu.m/sec

Input

Power

Kw

Qth

%of

slip

Shaft

power

w

Delivery

head

m

%of

pump

Precautions:

1. Head is discharge ip pump speed is discharge at constant head.

2. Operate all the count.

3. Never allow the rise discharge above 4kg/sq.m

4. Always use clean water for equipment.

5. Pump speed is tube measured with tachometer and is not part of the equipment

RESULTS AND CONCLUSIONS

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