Factoring by Grouping Warm Up: 1) Simplify: (x + 2) (x 2 + 8) 2) Fill in the missing ?'s for the box method problem below: Aim: To factor by grouping, using the "reverse box method" Homework: pg. 531 - 532 # 14 - 30 (even #'s only)- Google form 2x 2 -3x -4x 6 2x ? ? ? Warm Up: 1. Read the article about Factoring. As you read, write down new vocabulary words that you read about and what you think they mean. 2. Find the missing values Aim: To factor polynomials by grouping Homework: pg. 531 - 532 # 14 - 30 (even #'s only)- Google form 2x 2 -3x -4x 6 2x ? ? ? (x + 2)(x + 3) x 2 + 5x + 6 Distributing Factoring Remember: 2(y + 3) 2y + 6 Distributing Factoring So, if we use the box method to distribute polynomials, can we use the box method in reverse to factor polynomials? x +1 x +3 x 2 x 3x 3 Yes, we can. Some four-term polynomials are the product of two binomials. For these, we will use the "reverse box method". Ex 1: Watch, do not copy x 3 - 4x 2 - 2x + 8 Discussion question: Do you think it matters where we put each term in the reverse box method? If you're not sure, how do you think you can test it?