Grade 7 Exponents and Powers For more such worksheets visit www.edugain.com Answer the questions (1) Find value of x. (2) Anthony plants a jasmine on his 8 th birthday. If the plant has one jasmine to start with, and number of jasmines doubles every week, then how many jasmines will be there af ter x weeks? (3) Find number f or f ollowing expanded f orms A) 3×10 4 + 0×10 6 + 9×10 0 + 0×10 1 + 6×10 0 B) 2×10 5 + 0×10 3 + 4×10 3 + 2×10 1 + 0×10 3 + 0×10 5 + 3×10 5 + 7×10 5 (4) (5) Simplif y f ollowing and write answer in exponential f orm A) 17 3 17 7 × 17 5 × 17 4 B) 13 9 × 13 2 × 13 2 × 13 3 13 3 × 13 8 × 13 5 C) 5 3 5 6 × 5 7 × 5 4 × 5 6 × 5 5 D) 7 4 × 7 6 × 7 3 × 7 4 7 6 × 7 7 × 7 5 × 7 6 × 7 6 (6) = ? (7) (-4) 2 × (-3) x = -48 Find value of x. (8) If x=7 and y=1, f ind the value of (xy) y (9) What is the remainder when 2 50 is divided by 10? ID : ww-7-Exponents-and-Powers [1] (C) 2016 Edugain (www.Edugain.com) Personal use only, commercial use is strictly prohibited
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Grade 7Exponents and Powers
For more such worksheets visit www.edugain.com
Answer the questions
(1)
Find value of x.
(2) Anthony plants a jasmine on his 8th birthday. If the plant has one jasmine to start with, andnumber of jasmines doubles every week, then how many jasmines will be there af ter x weeks?
Rules of the exponent:Rule 1: When you multiply two numbers with the same base, you add the exponents.Rule 2: When you divide two numbers with the same base, you subtract the exponents.Rule 3: When you have an exponent expression that is raised to a power, you can multiplythe exponent and power.
Rule 4: (x)-n can be written as 1
(x)n
Rule 5: If (y)x = (y)10 then we can write x = 10.
Step 2
Now
[{( 1
5 )-1}1]x =
1
5
⇒ {( 1
5 )-1}1x =
1
(5)1
⇒ ( 1
5 )-1x =
1
(5)1
⇒ ( 1
5 )-1x = (
1
5 )1
⇒ -1x = 1⇒ x = -1
Step 3
Theref ore the value of x is -1 .
ID : ww-7-Exponents-and-Powers [4]
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(2) 2x
Step 1
If you look at the question caref ully, you will notice that Anthony plants a jasmine on his 8th
birthday. If the plant has one jasmine to start with, and number of jasmines doubles everyweek.
Step 2
Number of jasmine at starting = 1 Number of jasmine after 1 week = 21
Number of jasmine after 2 week = 22
Number of jasmine after 3 week = 23 --------------------------------- --------------------------------- Number of jasmine after x week = 2x
Step 3
Theref ore the total number of jasmines af ter x weeks will be 2x.
(3) A) 30015
Step 1
3×104 + 0×106 + 9×100 + 0×101 + 6×100 can be solved by the f ollowing steps:
3×104 + 0×106 + 9×100 + 0×101 + 6×100
= 30000 + 0 + 9 + 0 + 6= 30015
Step 2
Now the number f or expended f orm 3×104 + 0×106 + 9×100 + 0×101 + 6×100 is30015.
B) 1204020
Step 1
2×105 + 0×103 + 4×103 + 2×101 + 0×103 + 0×105 + 3×105 + 7×105 can be solvedby the f ollowing steps:
Now the number f or expended f orm 2×105 + 0×103 + 4×103 + 2×101 + 0×103 +
0×105 + 3×105 + 7×105 is 1204020 .
ID : ww-7-Exponents-and-Powers [5]
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(4) 64
1
Step 1
If you look at the question caref ully, you will notice that
you have to f ind out the value of ( 4
2 )3 × (
4
2 )3 .
Step 2
By solving each term separately
( 4
2 )3 =
64
8
and
( 4
2 )3 =
64
8
Step 3
Now ( 4
2 )3 × (
4
2 )3 =
64
8 ×
64
8
= 64
1
Step 4
Theref ore the value of ( 4
2 )3 × (
4
2 )3 is
64
1 .
ID : ww-7-Exponents-and-Powers [6]
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(5) A) 175
Step 1
Rules of the exponent:Rule 1: When you multiply two numbers with the same base, you add theexponents.Rule 2: When you divide two numbers with the same base, you subtract theexponents.Rule 3: When you have an exponent expression that is raised to a power, youcan multiply the exponent and power.
Step 2
173
177 × 175 × 174 can be simplif ied as:
173
177 × 175 × 174
= 17 (3)
17 (7) × 17 (5 + 4)
= 173
177 × 179
= 173 ÷ 177 × 179
= 17 (3 - 7 + 9)
= 175
Step 3
Theref ore the value of 173
177 × 175 × 174 in exponential f orm is 175 .
ID : ww-7-Exponents-and-Powers [7]
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B) 1310
Step 1
Rules of the exponent:Rule 1: When you multiply two numbers with the same base, you add theexponents.Rule 2: When you divide two numbers with the same base, you subtract theexponents.Rule 3: When you have an exponent expression that is raised to a power, youcan multiply the exponent and power.
Step 2
139 × 132 × 132 × 133
133 × 138 × 135 can be simplif ied as:
139 × 132 × 132 × 133
133 × 138 × 135
= 13(9 + 2 + 2 + 3)
13(3 + 8) × 13(5)
= 1316
1311 × 135
= 1316 ÷ 1311 × 135
= 13(16 - 11 + 5)
= 1310
Step 3
Theref ore the value of 139 × 132 × 132 × 133
133 × 138 × 135 in exponential f orm is
1310 .
ID : ww-7-Exponents-and-Powers [8]
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C) 519
Step 1
Rules of the exponent:Rule 1: When you multiply two numbers with the same base, you add theexponents.Rule 2: When you divide two numbers with the same base, you subtract theexponents.Rule 3: When you have an exponent expression that is raised to a power, youcan multiply the exponent and power.
Step 2
53
56 × 57 × 54 × 56 × 55 can be simplif ied as:
53
56 × 57 × 54 × 56 × 55
= 5(3)
5(6) × 5(7 + 4 + 6 + 5)
= 53
56 × 522
= 53 ÷ 56 × 522
= 5(3 - 6 + 22)
= 519
Step 3
Theref ore the value of 53
56 × 57 × 54 × 56 × 55 in exponential f orm is 519 .
ID : ww-7-Exponents-and-Powers [9]
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D) 721
Step 1
Rules of the exponent:Rule 1: When you multiply two numbers with the same base, you add theexponents.Rule 2: When you divide two numbers with the same base, you subtract theexponents.Rule 3: When you have an exponent expression that is raised to a power, youcan multiply the exponent and power.
Step 2
74 × 76 × 73 × 74
76 × 77 × 75 × 76 × 76 can be simplif ied as:
74 × 76 × 73 × 74
76 × 77 × 75 × 76 × 76
= 7 (4 + 6 + 3 + 4)
7 (6 + 7) × 7 (5 + 6 + 6)
= 717
713 × 717
= 717 ÷ 713 × 717
= 7 (17 - 13 + 17)
= 721
Step 3
Theref ore the value of 74 × 76 × 73 × 74
76 × 77 × 75 × 76 × 76 in exponential f orm is
721.
ID : ww-7-Exponents-and-Powers [10]
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(6)
1
81
Step 1
Rules of the exponent:Rule 1: When you multiply two numbers with the same base, you add the exponents.Rule 2: When you divide two numbers with the same base, you subtract the exponents.Rule 3: When you have an exponent expression that is raised to a power, you can multiplythe exponent and power.
Rule 4: (x)-n can be written as 1
(x)n
Step 2
Now [ { (- 1
3 )1}2]2 can be simplif ied as:
= { (- 1
3 )1} 2 × 2
={ (- 1
3 )1}4
= (- 1
3 ) 1 × 4
=(- 1
3 )4
= 1
81
Step 3
Theref ore the value of [ { (- 1
3 )1}2]2 is
1
81 .
ID : ww-7-Exponents-and-Powers [11]
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(7) 1
Step 1
If you look at the question caref ully, you will notice that you have to f ind out the value of x
f rom (-4)2 × (-3)x = -48
Step 2
Now (-4)2 × (-3)x = -48
⇒ 16 × (-3)x = -48
⇒ (-3)x = -48
16
⇒ (-3)x = -3
⇒ (-3)x = (-3)1
⇒ x = 1
Step 3
Theref ore the value of x is 1.
(8) 7
Step 1
If you look at the question caref ully, you will notice that x = 7 and y = 1,
you have to f ind out the value of (xy)y.
Step 2
Now put the value of x and y in (xy)y
(xy)y = (7 × 1)1
= (7)1
= 7
Step 3
Theref ore the value of (xy)y at x = 7 and y = 1 is 7 .
ID : ww-7-Exponents-and-Powers [12]
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(9) 4
Step 1
Let us try to observe the pattern of remainders when we divide the number by 10 on smallerpower ranges.Number Dividend Divisor Remainder
21 2 10 2
22 4 10 4
23 8 10 8
24 16 10 6
25 32 10 2
26 64 10 4
27 128 10 8
28 256 10 6 .......
If we see closely, we notice that when we divide 2n by 10, the remainder is repeated af ter
every 4 th power of 2.
Step 2
Hence, if we divide 50 (the power of 2 in question) by 4, the remainder will tell us whatpower to use to simplif y the problem.
Step 3
When we divide 50 by 4, we get the remainder of 2.
Theref ore we should use 22 to simplif y the problem.
Step 4
This implies that when 250 is divided by 10, we will get the same remainder as we get when
22 is divided by 10. Which is 4.
Step 5
Thus, the remainder when 250 is divided by 10 is 4 .
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(10)a.
26
5
Step 1
If you look at the question caref ully, you will notice that you have to f ind out the value of (
x
y +
y
x )x at x = 1 and y = 5.
Step 2
Now put x = 1 and y = 5 in ( x
y +
y
x )x
( x
y +
y
x )x = (
1
5 +
5
1 )1
= ( 1 + 25
5 )1
= ( 26
5 )1
= 26
5
Step 3
Theref ore the value of ( x
y +
y
x )x at x = 1 and y = 5 is
26
5 .
(11) c. -343
Step 1
(-7)3 can be written as:
(-7)3 = (-7) × (-7) × (-7) = -343
Step 2
Now the value of (-7)3 is -343.
ID : ww-7-Exponents-and-Powers [14]
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(12) d. -2
Step 1
Rules of the exponent:Rule 1: When you multiply two numbers with the same base, you add the exponents.Rule 2: When you divide two numbers with the same base, you subtract the exponents.Rule 3: When you have an exponent expression that is raised to a power, you can multiplythe exponent and power.
Rule 4: (x)-n can be written as 1
(x)n
Rule 5: If (y)x = (y)10 then we can write x = 10.
Step 2
Now
{( 1
3 )x}-1 =
1
9
⇒ ( 1
3 )x × -1 =
1
9
⇒ ( 1
3 )(x)(-1) = (
1
32 )
⇒ ( 1
3 )(x)(-1) = (
1
3 )2
Comparing both side ⇒ (x)(-1) = 2 ⇒ x = -2
Step 3
Theref ore the value of x is -2 .
ID : ww-7-Exponents-and-Powers [15]
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(13) A) 13
Step 1
Rules of the exponent:Rule 1: When you multiply two numbers with the same base, you add theexponents.Rule 2: When you divide two numbers with the same base, you subtract theexponents.Rule 3: When you have an exponent expression that is raised to a power, youcan multiply the exponent and power.
Step 2
First of all you have to simplif y each number with the same base.
Now 252 × 1253 can be simplif ied as:
252 × 1253
= (5 × 5)2 × (5 × 5 × 5)3
= (52)2 × (53)3
= 54 × 59
= 5(4 + 9)
= 513
Step 3
Theref ore the value of 252 × 1253 in exponential f orm is 513.
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B) 15
Step 1
Rules of the exponent:Rule 1: When you multiply two numbers with the same base, you add theexponents.Rule 2: When you divide two numbers with the same base, you subtract theexponents.Rule 3: When you have an exponent expression that is raised to a power, youcan multiply the exponent and power.
Step 2
First of all you have to simplif y each number with the same base.
Now 495 × 495 ÷ 75 can be simplif ied as:
495 × 495 ÷ 75
= (7 × 7)5 × (7 × 7)5 ÷ 75
= (72)5 × (72)5 ÷ 75
= 710 × 710 ÷ 75
= 7 (10 + 10 - 5)
= 715
Step 3
Theref ore the value of 495 × 495 ÷ 75 in exponential f orm is 715 .
ID : ww-7-Exponents-and-Powers [17]
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(14) A) 36 1
Step 1
If you look at the question caref ully, you will notice that
you have to f ind out the value of ( -3
2 )2 ÷ (
-1
2 )4 .
Step 2
By solving each term separately
( -3
2 )2 =
9
4
and
( -1
2 )4 =
1
16
Step 3
Now ( -3
2 )2 ÷ (
-1
2 )4 =
9
4 ÷
1
16
= 9
4 ×
16
1
= 36
1
Step 4
Theref ore the value of ( -3
2 )2 ÷ (
-1
2 )4 is
36
1 .
ID : ww-7-Exponents-and-Powers [18]
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B) 243 1600
Step 1
If you look at the question caref ully, you will notice that
you have to f ind out the value of ( 3
4 )3 ÷ (
-5
3 )2 .
Step 2
By solving each term separately
( 3
4 )3 =
27
64
and
( -5
3 )2 =
25
9
Step 3
Now ( 3
4 )3 ÷ (
-5
3 )2 =
27
64 ÷
25
9
= 27
64 ×
9
25
= 243
1600
Step 4
Theref ore the value of ( 3
4 )3 ÷ (
-5
3 )2 is
243
1600 .
ID : ww-7-Exponents-and-Powers [19]
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C) 144 625
Step 1
If you look at the question caref ully, you will notice that
you have to f ind out the value of ( -3
4 )2 ÷ (
-5
4 )4 .
Step 2
By solving each term separately
( -3
4 )2 =
9
16
and
( -5
4 )4 =
625
256
Step 3
Now ( -3
4 )2 ÷ (
-5
4 )4 =
9
16 ÷
625
256
= 9
16 ×
256
625
= 144
625
Step 4
Theref ore the value of ( -3
4 )2 ÷ (
-5
4 )4 is
144
625 .
ID : ww-7-Exponents-and-Powers [20]
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D) 25 81
Step 1
If you look at the question caref ully, you will notice that
you have to f ind out the value of ( -2
3 )4 ÷ (
4
5 )2 .
Step 2
By solving each term separately
( -2
3 )4 =
16
81
and
( 4
5 )2 =
16
25
Step 3
Now ( -2
3 )4 ÷ (
4
5 )2 =
16
81 ÷
16
25
= 16
81 ×
25
16
= 25
81
Step 4
Theref ore the value of ( -2
3 )4 ÷ (
4
5 )2 is
25
81 .
ID : ww-7-Exponents-and-Powers [21]
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(15) A) 8
Step 1
Rules of the exponent:Rule 1: When you multiply two numbers with the same base, you add theexponents.Rule 2: When you divide two numbers with the same base, you subtract theexponents.Rule 3: When you have an exponent expression that is raised to a power, youcan multiply the exponent and power.
Step 2
1258
1259 × 55 × 1252 can be simplif ied as:
1258
1259 × 55 × 1252
= (5 × 5 × 5)8
(5 × 5 × 5)9 × (5)5 × (5 × 5 × 5)2
= (53)8
(53)9 × (5)5 × (53)2
= 524
527 × 55 × 56
= 5(24)
5(27) × 5(5 + 6)
= 524
527 × 511
= 524 ÷ 527 × 511
= 5(24 - 27 + 11)
= 58
Step 3
Theref ore the value of 1258
1259 × 55 × 1252 in exponential f orm is 58.
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B) 10
Step 1
Rules of the exponent:Rule 1: When you multiply two numbers with the same base, you add theexponents.Rule 2: When you divide two numbers with the same base, you subtract theexponents.Rule 3: When you have an exponent expression that is raised to a power, youcan multiply the exponent and power.
Step 2
492
76 × 496 can be simplif ied as:
492
76 × 496
= (7 × 7)2
(7)6 × (7 × 7)6
= (72)2
(7)6 × (72)6
= 74
76 × 712
= 7 (4)
7 (6) × 7 (12)
= 74
76 × 712
= 74 ÷ 76 × 712
= 7 (4 - 6 + 12)
= 710
Step 3
Theref ore the value of 492
76 × 496 in exponential f orm is 710 .
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