· Exercise 5.3 2x + 3y = sin x Differentiating both sides with respect to x, we get — sin x dx dx dx dy cosx — 2 dx 2x + = sin y dy dx cos x Question 2: 2x + = sin y Answer

Page 1 <img data-url='document/exercise-53-2x-3y-sin-x-differentiating-both-sides-with-respect-to-x-we-get.html?page=1' data-page='1' class='cut-thumb lazyload' alt='Page 1: · Exercise 5.3 2x + 3y = sin x Differentiating both sides with respect to x, we get — sin x dx dx dx dy cosx — 2 dx 2x + = sin y dy dx cos x Question 2: 2x + = sin y Answer' loading='lazy' src='data:image/gif;base64,iVBORw0KGgoAAAANSUhEUgAAAAEAAAABCAYAAAAfFcSJAAAADUlEQVR42mNk+P+/HgAFhAJ/wlseKgAAAABJRU5ErkJggg==' data-src='https://reader030.cupdf.com/reader030/viewer/2022040107/5e4acb924ca6492b8f43bab2/html5/thumbnails/1.jpg' width='140' height='200' /> Page 2 <img data-url='document/exercise-53-2x-3y-sin-x-differentiating-both-sides-with-respect-to-x-we-get.html?page=2' data-page='2' class='cut-thumb lazyload' alt='Page 2: · Exercise 5.3 2x + 3y = sin x Differentiating both sides with respect to x, we get — sin x dx dx dx dy cosx — 2 dx 2x + = sin y dy dx cos x Question 2: 2x + = sin y Answer' loading='lazy' src='data:image/gif;base64,iVBORw0KGgoAAAANSUhEUgAAAAEAAAABCAYAAAAfFcSJAAAADUlEQVR42mNk+P+/HgAFhAJ/wlseKgAAAABJRU5ErkJggg==' data-src='https://reader030.cupdf.com/reader030/viewer/2022040107/5e4acb924ca6492b8f43bab2/html5/thumbnails/2.jpg' width='140' height='200' /> Page 3 <img data-url='document/exercise-53-2x-3y-sin-x-differentiating-both-sides-with-respect-to-x-we-get.html?page=3' data-page='3' class='cut-thumb lazyload' alt='Page 3: · Exercise 5.3 2x + 3y = sin x Differentiating both sides with respect to x, we get — sin x dx dx dx dy cosx — 2 dx 2x + = sin y dy dx cos x Question 2: 2x + = sin y Answer' loading='lazy' src='data:image/gif;base64,iVBORw0KGgoAAAANSUhEUgAAAAEAAAABCAYAAAAfFcSJAAAADUlEQVR42mNk+P+/HgAFhAJ/wlseKgAAAABJRU5ErkJggg==' data-src='https://reader030.cupdf.com/reader030/viewer/2022040107/5e4acb924ca6492b8f43bab2/html5/thumbnails/3.jpg' width='140' height='200' /> Page 4 <img data-url='document/exercise-53-2x-3y-sin-x-differentiating-both-sides-with-respect-to-x-we-get.html?page=4' data-page='4' class='cut-thumb lazyload' alt='Page 4: · Exercise 5.3 2x + 3y = sin x Differentiating both sides with respect to x, we get — sin x dx dx dx dy cosx — 2 dx 2x + = sin y dy dx cos x Question 2: 2x + = sin y Answer' loading='lazy' src='data:image/gif;base64,iVBORw0KGgoAAAANSUhEUgAAAAEAAAABCAYAAAAfFcSJAAAADUlEQVR42mNk+P+/HgAFhAJ/wlseKgAAAABJRU5ErkJggg==' data-src='https://reader030.cupdf.com/reader030/viewer/2022040107/5e4acb924ca6492b8f43bab2/html5/thumbnails/4.jpg' width='140' height='200' /> Page 5 <img data-url='document/exercise-53-2x-3y-sin-x-differentiating-both-sides-with-respect-to-x-we-get.html?page=5' data-page='5' class='cut-thumb lazyload' alt='Page 5: · Exercise 5.3 2x + 3y = sin x Differentiating both sides with respect to x, we get — sin x dx dx dx dy cosx — 2 dx 2x + = sin y dy dx cos x Question 2: 2x + = sin y Answer' loading='lazy' src='data:image/gif;base64,iVBORw0KGgoAAAANSUhEUgAAAAEAAAABCAYAAAAfFcSJAAAADUlEQVR42mNk+P+/HgAFhAJ/wlseKgAAAABJRU5ErkJggg==' data-src='https://reader030.cupdf.com/reader030/viewer/2022040107/5e4acb924ca6492b8f43bab2/html5/thumbnails/5.jpg' width='140' height='200' />

· Exercise 5.3 2x + 3y = sin x Differentiating both sides with respect to x, we get — sin x dx dx dx dy cosx — 2 dx 2x + = sin y dy dx cos x Question 2: 2x + = sin y Answer

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