CONTINUOUS ONE WAY SLAB EXAMPLE 3.4 Figure below shows a first floor plan of an office building. It is estimated that the 125 mm thick slab will carry 4.0 kN/m 2 variable action and 1.0 kN/m 2 load from finishes & suspended ceiling. This building is exposed to XC1 exposure class. Using concrete class C30/37 and high yield steel, prepare a complete design and detailing for this slab. Design data: For all slab panels, Ly/Lx = 8/3 = 2.67 > 2.0 one / two way continuous slab. Variable action, q k = 4.0 kN/m 2 Loads from finishes & suspended ceiling = 1.0 kN/m 2 f ck = 30 N/mm 2 f yk = 500 N/mm 2 h = 125 mm 4 @ 3 m 8 m continuous discontinuous
12
Embed
Example 3.4 - Continuous One Way Slab-updated 080812
This document is posted to help you gain knowledge. Please leave a comment to let me know what you think about it! Share it to your friends and learn new things together.
Transcript
CONTINUOUS ONE WAY SLAB EXAMPLE 3.4
Figure below shows a first floor plan of an office building. It is estimated that the 125 mm thick
slab will carry 4.0 kN/m2 variable action and 1.0 kN/m2 load from finishes & suspended ceiling.
This building is exposed to XC1 exposure class. Using concrete class C30/37 and high yield steel,
prepare a complete design and detailing for this slab.
Design data:
For all slab panels, Ly/Lx = 8/3 = 2.67 > 2.0
one / two way continuous slab.
Variable action, qk = 4.0 kN/m2
Loads from finishes & suspended ceiling = 1.0 kN/m2
fck = 30 N/mm2
fyk = 500 N/mm2
h = 125 mm
con
tin
uo
us
4 @ 3 m
8 m
con
tin
uo
us
dis
con
tin
uo
us
CONTINUOUS ONE WAY SLAB EXAMPLE 3.4
SOLUTION:
1. Calculate the design load acting on the slab.
Self-weight of slab = 25 x slab thickness = 3.125 kN/m2
Finishes & ceiling = = 1.0 kN/m2
Total charac. permanent action, gk = 4.125 kN/m2
Total charac. variable action, qk = 4.0 kN/m2
Design load, n = 1.35 gk + 1.5 qk
= 1.35 ( 4.125 ) + 1.5 (4)
= 11.57 kN/m2
Consider 1 m width of slab, w = 11.57 x 1 m =11.57 kN/m