Evaluating Center Evaluating Center Pivots in Missouri Pivots in Missouri Joe Henggeler Joe Henggeler University of Missouri University of Missouri 38th ANNUAL MISSOURI IRRIGATION CONFERENCE 38th ANNUAL MISSOURI IRRIGATION CONFERENCE Wednesday, Feb. 2, 2004 Wednesday, Feb. 2, 2004 309 Hearnes Center, Columbia, MO 309 Hearnes Center, Columbia, MO
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Evaluating Center Pivots in Missouri Joe Henggeler University of Missouri University of Missouri 38th ANNUAL MISSOURI IRRIGATION CONFERENCE Wednesday,
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Evaluating Center Pivots in Evaluating Center Pivots in MissouriMissouri
309 Hearnes Center, Columbia, MO309 Hearnes Center, Columbia, MO
Team Up!Team Up!
Irrigation SchedulingIrrigation Scheduling Proper fertigation (corn)Proper fertigation (corn) Testing center pivotsTesting center pivots
Conducting a TestConducting a Test
Conducting a TestConducting a Test
Conducting a TestConducting a Test
Other Data CollectedOther Data Collected Pivot age / total hours of operationPivot age / total hours of operation Pressure at beginning & endPressure at beginning & end
Other Data Collected, Other Data Collected, cont.cont.
Type of sprinklerType of sprinkler Weather conditions during the testWeather conditions during the test
Distribution UniformityDistribution Uniformity
Average catch of Low QuarterAverage catch
DU =
x 100
Irrigation Distribution Uniformity (DU)Irrigation Distribution Uniformity (DU)
0
0.5
1
1.5
2
2.5
0% 25% 50% 75% 100%
% of the field this amount or less
Cat
ch (
inch
es)
Catch
Average catch = 1.1”
Average Low Quarter catch = 0.8”
Irrigation Distribution Uniformity (DU)Irrigation Distribution Uniformity (DU)
0
0.5
1
1.5
2
2.5
0% 25% 50% 75% 100%
% of the field this amount or less
Cat
ch (
inch
es)
Catch
Average catch = 1.1”
Average Low Quarter catch = 0.8”
DU = (0.8 1.1) x 100 = 72%
Evaluating Catch AmountsEvaluating Catch Amounts
10 ft
Evaluating Catch AmountsEvaluating Catch Amounts
0.8 “ 1.2 “ 0.3 “ 1.0 “ 0.7 “
10 ft
Evaluating Catch AmountsEvaluating Catch Amounts
0.8 “ 1.2 “ 0.3 “ 1.0 “ 0.7 “
(0.8 + 1.2 + 0.3)“3
= 0.7
10 ft
(0.3 + 1.0 + 0.7)“3
= 0.7
(1.2 + 0.3 + 1.0)“3
= 0.8
Lots of data !Lots of data !
Problems with SystemsProblems with Systems
DU ValueDU Value RatingRating
> 75%> 75% ExcellentExcellent
65 – 74 %65 – 74 % GoodGood
50 – 64 %50 – 64 % FairFair
< 49 %< 49 % PoorPoor
ResultsResults
Results, Results, cont.cont.
Results, Results, cont.cont.
Straight Straight ValueValue
Averaging Averaging CatchCatch
50 %50 % 67 %67 %
82 %82 % 86 %86 %
30 %30 % 45 %45 %
Average
Maximum
Minimum
Locations of PivotsLocations of Pivots
Tested 2004
Tested 2003
Tested < 2003
The EndThe End
Joe HenggelerJoe HenggelerDelta Center Research CenterDelta Center Research Center