Energy Saving Presentation

TECHNO SUPPORT ENGINEERS

� AN ISO 9001: 2008 COMPANY WITH TUV AUSTRIA CERTIFICATION

� QUALITY MANAGEMENT SYSTEM

� 24 X 7 TECHNICAL ASSISTANCE

� ELECTRICAL & MECHANICAL SOLUTIONS UNDER ONE ROOF

� FABRICATION EXPERTEE� FABRICATION EXPERTEE

� PROJECT MANAGEMENT & PLANNING

� ERECTION & COMMISSIONING SUPPORTS

� TURNKEY PROJECTS

� ENERGY SAVING SOLUTIONS

� AC DRIVE APPLICATIONS FOR PLASTIC INJECTION MOULDING

� FREE AMC FOR ONE YEAR *

� OVER 95 % CUSTOMER SATISFACTION RATIO


WE ARE THE LEADER IN ELECTRICAL AUTOMATION WHO SUCCESSFULLY APPLY AC VARIABLE FREQUENCY DRIVES IN VARIOUS HYDRAULIC OPERATIONS WHICH INCLUDES PLASTIC MOLDING MACHINES, COOLING TOWERS, AIR COMPRESSORS ETC. WITHOUT DISTURBING IT’S PROCESS PARAMETERS.

WE CAN IMPLEMENT THESE DRIVES FOR ANY


WE CAN IMPLEMENT THESE DRIVES FOR ANY HYDRAULIC PLASTIC INJECTION MACHINE. THESE DRIVES HAVING ADVANTAGES NOT TO SAVE YOUR ELECTRICITY BILLS BUT SAVES MAINTENANCE COST ALSO.

WE HAVE SUCCESSFULLY INSTALLED VFD UNITS IN DIFFERENT PLASTICS LIKE L&T, FERROMATIK, ASB, ISBM, CMPs , BLOMA ETC.

TECHNICAL ADVANTAGES OF VARIABLE FREQUENCY DRIVES & ACTUALLY HOW IT WORKS ?

� VFDs (Variable Frequency Drives) are basically a green energy savings product that matches the amount of work or load on a motor to the amount of energy it needs to power that amount of work. This reduces excess energy from being wasted.

� We use a lot of energy in this country and most of that energy is used to move air and water around a building. About half the electricity in commercial a building. About half the electricity in commercial companies just used to move air and water around, so a VFD is a big way to save energy there. If you look at a typical pump motor the life cycle cost of a pump, 90% of its life cycle costs is the energy it consumes and only 10%


� Variable frequency drives (VFD) are becoming more common place and more widely used in applications. They are capable of varying the output speed of a motor without the need for mechanical pulleys, thus reducing the number of mechanical components and overall maintenance. But the biggest advantage that a VFD has is the ability to save the user money through its inherit nature to save energy by consuming only the through its inherit nature to save energy by consuming only the power that’s needed. The main question now is, How does a VFD accomplish this? The simple answer to this question is power conversion.

� A VFD is similar to the motor to which it’s attached, they both convert power to a usable form. In the case of an induction motor, the electrical power supplied to it is converted to mechanical power through the rotation of the motor’s rotor and the torque that it produces through motor slip. A VFD, on the other hand, will convert its incoming power, a fixed voltage and frequency, to a variable voltage and frequency. This same concept is also the basis to vary the speed of the motor without the need of adjustable pulleys or gearing changes


� Electrical

� Electrical power is defined as the following:� Power (P) = √3 x Voltage (V) x Current (I) x Power Factor (PF)� In an ideal VFD, the following would hold true:� Powerin = Powerout

� But because a VFD has inefficiencies and requires a small amount of power consumption to power the brains of the drive, the input power power consumption to power the brains of the drive, the input power will be slightly greater than the output power. For this, we will assume that this extra power draw is negligible.

� With these two equations, we can then define the relationship between the VFD’s input and output:

� Vin x Iin x PFin = Vout x Iout x PFout

� Taking these equations into account, let’s use a 100-hp motor as an example with the following properties:

� Power = 100 hpSpeed = 1,785 rpmVoltage = 460 VFLA = 115 APower factor = 0.86


� “A VFD will convert its incoming power, a fixed voltage and frequency, to a variable voltage and frequency.”

� Assume that the motor is running at 60 Hz on a VFD, drawing a no-load current of 40 A on the output of the VFD. With this, one would assume that the input current would also be the same, 40 A. However, using an ammeter on the drive’s input, a person is reading nearly zero amps! How is this possible? Is the drive creating power somehow? The answer simply is no, the drive is not creating power. The power factor causes this “discrepancy” in current When a motor is running at no load, the motor’s power factor can be assumed to be zero, not 0.86 86 as stated on the nameplate. The reason the can be assumed to be zero, not 0.86 86 as stated on the nameplate. The reason the power factor isn’t at 0.86 is because this is the motor power factor at full load. Alternatively, mechanical (friction) and electrical (resistive) losses in the motor prevent the power factor from being zero when running no load, but we’ll assume these losses to be zero just like we did for the VFD. Therefore, you would have the following:

� Pout = 460V x 40A x 0Pout = 0

� Because the output power is zero, the input power also will be zero. With a fixed input voltage, the two variables would be current and power factor. Because current is needed for a power factor to exist, both current and power factor are zero, which means the low input current reading is indeed correct.

� This explains why the input current to the VFD is so low when the motor is operating under no load conditions. But what about under load? The same concept still applies when the motor is under load. For example, assume the same motor is now operating at half speed, 30 Hz and producing full motor rated torque and drawing the motor’s full-load amps (FLA). This means that the electrical power that the motor is drawing is


� Pout = √3 x 230V x 115A x 0.86 = 39.4kW� Because the VFD is a power converter, this means that the input current is (assuming a

0.89 input power factor from a 3% line impedance):� Iin = (39.4kW) / (√3 x 460V x 0.89) = 55.6A� Because the VFD is operating at half speed and under full load, the input current is less

than half of the output current.

�Power Voltage Current Frequency PF

�

�

� In this example, the input current is less than half of the output, a result of having a higher power factor on the input side.

� The difference in power factor between the input and output side of the motor is what makes it possible to have a higher output current than input current. Assuming the motor is now running at full load and using the same power factor values, your input current now becomes:

� Iin = (√3 x 460V x 115A x 0.86) / (√3 x 460V x 0.89) = 111A


Power

KW

Voltage

V

Current

A

Frequency

Hz

PF

Input 39.4 460 55.6 60 0.89

Output 39.4 230 115 30 0.86

� which is 4 A lower than the output current.� If Then� PFin < Pfout Iin < Iout

� PF = Pf I = I� PFin = Pfout Iin = Iout

� PFin > Pfout Iin > Iout

� Mechanical

� The current a VFD draws on the input side also can be related to the mechanical power a motor is delivering. The basic relationship for motor power is as below .


� Powermechanical ∝ Speed x Torque� This means that if the motor is operating at half the speed

and producing full torque, the motor is outputting half of its rated power. Consequently, if the motor is running at full speed and producing half torque, the motor is also outputting half of its rated power.\outputting half of its rated power.\

� Because of motor losses, the power relationship between the electrical power going into the motor and the mechanical power is:

� PowerElectrical = (Powermechanical) / (EfficiencyMotor)� Revisiting the above example, if the motor is operating at

30 Hz, half the motor’s rated speed and producing full torque, then the mechanical power being produced is 50 hp. Assuming that the motor is 95% efficient, the electrical power that’s required is:

� PowerElectrical = (50HP x 0.746) / 0.95 = 39.3kW


� which means that the current on the input side of the VFD will be approximately 55 A. This same current will also hold true even if the motor is operating at full speed and producing half torque. Ultimately, a VFD is merely a power conversion device that converts the fixed voltage and frequency of incoming power to a variable voltage and frequency output to provide the variable speed frequency of incoming power to a variable voltage and frequency output to provide the variable speed capabilities for which it was designed. Keep in mind the variables associated with electrical power (voltage, current and power factor) and their relationships when comparing the VFD’s input to its output. This also will hold true when using the motor’s mechanical power (speed and torque) to determine the amount of input power/current to the VFD. Taking all the variables into consideration, one can be pleasantly surprised to find the input current lower than the output current.


� We are having one year AMC free with installation of above control panel (replacement of electrical components will be at customer’s scope)

� Improves Power Factor� Improves life of motor & bearings� Reduces maintenance cost� 24 X 7 technical assistance � 24 X 7 technical assistance � Saving electricity approximately 30- 50% of your previous energy bills.� Easy for maintenance* ( 30 % to 50 % depends of HP capacity of motor )� Technical future adaptation possible if you need to change the process

parameters� Safety of your electric motor� Provision of Auto & Manual modes � RPM reading, voltmeter analog meter, phase indicators, emergency

stop� Aesthetical look of control panel with standard provision


� We firstly visit the factory premises to see the actual technical requirements

� Trial installation to the plastic injection machine if requiredmachine if required

� Total calculated difference of energy saved

� Provision of standard electrical automation solutions


� Contact Us : www.techsuppen.com

� Email : [email protected]� [email protected]� [email protected]� Facebook :

https://www.facebook.com/Techsuppen?fref=nf

� Linkedin:https://in.linkedin.com/pub/techsuppen-enterprises/b9/b22/b1a


Energy Saving Presentation

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