Electromagnetism Christopher R Prior ASTeC Intense Beams Group Rutherford Appleton Laboratory Fellow and Tutor in Mathematics Trinity College, Oxford
Mar 28, 2015
Electromagnetism
Christopher R Prior
ASTeC Intense Beams Group
Rutherford Appleton Laboratory
Fellow and Tutor in Mathematics
Trinity College, Oxford
2
Contents
• Review of Maxwell’s equations and Lorentz Force Law
• Motion of a charged particle under constant Electromagnetic fields
• Relativistic transformations of fields
• Electromagnetic energy conservation
• Electromagnetic waves– Waves in vacuo
– Waves in conducting medium
• Waves in a uniform conducting guide– Simple example TE01 mode
– Propagation constant, cut-off frequency
– Group velocity, phase velocity
– Illustrations
3
Reading
• J.D. Jackson: Classical Electrodynamics
• H.D. Young and R.A. Freedman: University Physics (with Modern Physics)
• P.C. Clemmow: Electromagnetic Theory
• Feynmann Lectures on Physics
• W.K.H. Panofsky and M.N. Phillips: Classical Electricity and Magnetism
• G.L. Pollack and D.R. Stump: Electromagnetism
4
Basic Equations from Vector Calculus
y
F
x
F
x
F
z
F
z
F
y
FF
z
F
y
F
x
FF
FFFF
123123
321
321
,,:curl
:divergence
,,,vectoraFor
z
φ
y
φ
x
φφ
x,y,z,tφ
,,:gradient
,functionscalaraFor
Gradient is normal to
surfaces =constant
5
Basic Vector Calculus
FFF
F
GFFGGF
2)()(
0,0
)(
S C
rdFSdF
dSnSd
Oriented boundary C
n
Stokes’ Theorem
Divergence or Gauss’ Theorem
SV
SdFdVF
Closed surface S, volume V, outward pointing normal
What is Electromagnetism?
• The study of Maxwell’s equations, devised in 1863 to represent the relationships between electric and magnetic fields in the presence of electric charges and currents, whether steady or rapidly fluctuating, in a vacuum or in matter.
• The equations represent one of the most elegant and concise way to describe the fundamentals of electricity and magnetism. They pull together in a consistent way earlier results known from the work of Gauss, Faraday, Ampère, Biot, Savart and others.
• Remarkably, Maxwell’s equations are perfectly consistent with the transformations of special relativity.
Maxwell’s EquationsRelate Electric and Magnetic fields generated by charge and current distributions.
t
DjH
t
BE
B
D
0
1,,In vacuum 20000 cHBED
E = electric field
D = electric displacement
H = magnetic field
B = magnetic flux density
= charge density
j = current density
0 (permeability of free space) = 4 10-7
0 (permittivity of free space) = 8.854 10-12
c (speed of light) = 2.99792458 108 m/s
8
Equivalent to Gauss’ Flux Theorem:
The flux of electric field out of a closed region is proportional to the total electric charge Q enclosed within the surface.
A point charge q generates an electric field
Maxwell’s 1st Equation
000
1
Q
dVSdEdVEEVSV
02
0
30
4
4
q
r
dSqSdE
rr
qE
spheresphere
0
E
Area integral gives a measure of the net charge enclosed; divergence of the electric field gives the density of the sources.
Gauss’ law for magnetism:
The net magnetic flux out of any closed surface is zero. Surround a magnetic dipole with a closed surface. The magnetic flux directed inward towards the south pole will equal the flux outward from the north pole.
If there were a magnetic monopole source, this would give a non-zero integral.
Maxwell’s 2nd Equation 0 B
00 SdBB
Gauss’ law for magnetism is then a statement that There are no magnetic monopolesThere are no magnetic monopoles
Equivalent to Faraday’s Law of Induction:
(for a fixed circuit C)
The electromotive force round a
circuit is proportional to the
rate of change of flux of magnetic field,
through the circuit.
Maxwell’s 3rd Equation t
BE
dt
dSdB
dt
dldE
Sdt
BSdE
C S
SS
ldE
N S
Faraday’s Law is the basis for electric generators. It also forms the basis for inductors and transformers.
SdB
Maxwell’s 4th Equationt
E
cjB
20
1
Originates from Ampère’s (Circuital) Law :
Satisfied by the field for a steady line current (Biot-Savart Law, 1820):
ISdjSdBldBC S S 00
r
IB
r
rldIB
2
4
0
30
current line straight a For
jB
0
Ampère
Biot
12
Need for Displacement
Current• Faraday: vary B-field, generate E-field• Maxwell: varying E-field should then produce a B-field, but not
covered by Ampère’s Law.
Surface 1 Surface 2
Closed loop
Current I
Apply Ampère to surface 1 (flat disk): line integral of B = 0I
Applied to surface 2, line integral is zero since no current penetrates the deformed surface.
In capacitor, , so
Displacement current density ist
Ejd
0
dt
dEA
dt
dQI 0
Aε
QE
0
t
EjjjB d
0000
13
Consistency with Charge Conservation
Charge conservation: Total current flowing out of a region equals the rate of decrease of charge within the
volume.
From Maxwell’s equations: Take divergence of (modified) Ampère’s equation
0
tj
dVt
dVj
dVdt
dSdj
tj
tj
Etc
jB
0
0
1
0000
20
Charge conservation is implicit in Maxwell’s EquationsCharge conservation is implicit in Maxwell’s Equations
14
Maxwell’s Equations in
VacuumIn vacuum
Source-free equations:
Source equations
Equivalent integral forms (useful for simple geometries)
20000
1,,
cHBED
0
0
t
BE
B
jt
E
cB
E
02
0
1
SdEdt
d
cSdjldB
dt
dSdB
dt
dldE
SdB
dVSdE
20
0
1
0
1
Example: Calculate E from B
0
00
0
sin
rr
rrtBBz
dSBdt
dldE
trBE
tBrtBrdt
drErr
cos2
1
cossin2
0
02
02
0
tr
BrE
tBrtBrdt
drErr
cos2
cossin2
02
0
02
002
00
Also from t
BE
dt
E
cjB
20
1 then gives current density necessary to sustain the fields
r
z
16
Lorentz Force Law
• Supplement to Maxwell’s equations, gives force on a charged particle moving in an electromagnetic field:
• For continuous distributions, have a force density
• Relativistic equation of motion
– 4-vector form:
– 3-vector component:
BvEqf
BjEfd
dt
pd
dt
dE
cf
c
fv
d
dPF
,1
,
BvEqfvmdt
d 0
17
Motion of charged particles in constant magnetic fields
1. Dot product with v:
constantisconstantis0So
1But
0
222
0
vdt
ddt
dv
dt
dvcvγ
Bvvm
qv
dt
dv
Bvqvmdt
dBvEqfvm
dt
d 00
No acceleration with a magnetic field
constant,0
0
//
0
vvBdt
d
BvBm
qv
dt
dB
2. Dot product with B:
constantalso
constantandconstant //
v
vv
Motion in constant magnetic field
0
0
0
2
0
frequencyangularat
radiuswithmotioncircular
mmm
qBvω
qB
vmρ
Bvm
qv
Bvm
q
dt
vd
Constant magnetic field gives uniform spiral about B with constant energy.
rigidityMagnetic
0
q
p
q
vmB
19
Motion in constant Electric Field
Solution of Em
qv
dt
d
0
Constant E-field gives uniform acceleration in straight line
Eqvmdt
dBvEqfvm
dt
d 00
2
0
22
0
11
t
m
qE
c
vt
m
qEv is
11
2
0
20
cm
qEt
qE
cmx
v
dt
dx
cmqEtm
qE0
2
0
for2
1
qExEnergy gain is
• According to observer O in frame F, particle has velocity v, fields
are E and B and Lorentz force is
• In Frame F, particle is at rest and force is
• Assume measurements give same charge and force, so
• Point charge q at rest in F:
• See a current in F, giving a field
• Suggests
Relativistic Transformations of E and B
BvEqf
Eqf
BvEEqq
and
0,4 3
0
Br
rqE
Evcr
rvqB
23
0 1
4
Evc
BB
2
1
Rough
idea
////2
////
,
,
BBc
EvBB
EEBvEE
Exact:
21
Potentials• Magnetic vector potential:
• Electric scalar potential:
• Lorentz Gauge:
ABAB
thatsuch0
01
2
Atc
AAf(t)
,
t
AE
t
AE
t
AE
t
AA
tt
BE
so,with
0
Use freedom to set
22
Electromagnetic 4-Vectors
Α,1
,1
01
42
Actc
Atc
Lorentz
Gauge
4-gradient
4 4-potential A
Current 4-vector
000 where),(),(
jcvcVJ
vj
Continuity equation
0,,1
4
jt
jctc
J
Charge-current transformations
2,
c
jvvjj x
xx
23
z
y
x
z
y
x
A
A
Ac
cv
cv
A
A
Ac
1000
0100
00
00
'
'
'
'
Relativistic Transformations• 4-potential vector:
• Lorentz transformation
• Fields:
A
cA
,
1
BvEEEEc
EvBBBB
////2////
vtxxyyy
A
x
ABAB xy
z
',and
2
,andc
vxttzz
t
A
zE
t
AE z
z
Example: Electromagnetic Field of a Single Particle
• Charged particle moving along x-axis of Frame F
• P has
• In F, fields are only electrostatic (B=0), given by
tc
vxtttvbrxbvtx p
pP
2222 ','' so ),,0,'('
Origins coincide at t=t=0
Observer Pz
b
charge qx
Frame F v Frame F’z’
x’
333 '',0',
'
'''
''
r
qbEE
r
qvtEx
r
qE zyxP
tvxtvxx PPP so)(0
Transform to laboratory frame F:
23
2222
23
2222
'
0
'
tvb
bqEE
E
tvb
vtqEE
zz
y
xx
0
'2
zx
zzy
BB
Ec
Ec
vB
33 '',0',
'
''
r
qbEE
r
qvtE zyx
BvEEEE
c
EvBBBB
////
2////
3r
rvqB
At non-relativistic energies, ≈ 1, restoring the Biot-Savart law:
26
Electromagnetic Energy
• Rate of doing work on unit volume of a system is
• Substitute for j from Maxwell’s equations and re-arrange into the form
EjEvBjEvfv d
HBDEt
S
HESt
DE
t
BHS
t
DEEHHEE
t
DHEj
2
1
where
Poynting vector
27
HEDEHBt
Ej
2
1
SdHEdVHBDEdt
d
dt
dW
2
1
electric + magnetic energy densities of the
fields
Poynting vector gives flux of e/m energy across
boundaries
Integrated over a volume, have energy conservation law: rate of doing work on system equals rate of increase of stored electromagnetic energy+ rate of energy flow across boundary.
Review of Waves
• 1D wave equation is with general solution
• Simple plane wave:
2
2
22
2 1
t
u
vx
u
)()(),( xvtgxvtftxu
xktxkt sin:3Dsin:1D
k 2
Wavelength is
Frequency is2
Superposition of plane waves. While shape is relatively undistorted, pulse travels with the group velocity
Phase and group velocities
kt
xv
xkt
p
0
dkekA kxtki )()(
dk
dvg
Plane wave has constant phase at peaks
xkt sin2 xkt
30
Wave packet structure
• Phase velocities of individual plane waves making up the wave packet are different,
• The wave packet will then disperse with time
Electromagnetic waves• Maxwell’s equations predict the existence of electromagnetic
waves, later discovered by Hertz.• No charges, no currents:
00
BD
t
BE
t
DH
2
2
2
2
t
E
t
D
Bt
t
BE
E
EEE
2
2
2
2
2
2
2
2
2
22
:equation wave3D
t
E
z
E
y
E
x
EE
Nature of Electromagnetic Waves
• A general plane wave with angular frequency travelling in the direction of the wave vector k has the form
• Phase = 2 number of waves and so is a Lorentz invariant.
• Apply Maxwell’s equations
)](exp[)](exp[ 00 xktiBBxktiEE
it
ki
BEkBE
BkEkBE
00
Waves are transverse to the direction of propagation,
and and are mutually perpendicularBE
,k
xkt
33
Plane Electromagnetic
Wave
Plane Electromagnetic Waves
Ec
Bkt
E
cB
22
1
2
thatdeduce
withCombined
kc
kB
E
BEk
ck
is in vacuum waveof speed
2Frequency
k
2Wavelength
Reminder: The fact that is an invariant tells us that
is a Lorentz 4-vector, the 4-Frequency vector. Deduce frequency transforms as
xkt
k
c
,
vc
vckv
Waves in a Conducting Medium
• (Ohm’s Law) For a medium of conductivity ,
• Modified Maxwell:
• Put
Ej
t
EE
t
EjH
EiEHki
conduction current
displacement current
)](exp[)](exp[ 00 xktiBBxktiEE
D
40
8-
120
7
1057.21.2,103:Teflon
10,108.5:Copper
D
D
Dissipation factor
Attenuation in a Good Conductor
0since
withCombine
2
2
Ekik
EiEkkEk
EiHkEkk
HEkt
BE
EiEHki
For a good conductor D >> 1, ikik 12
, 2
depth-skin theis2
where
11
,expexpis form Wave
ik
xxti copper.mov water.mov
Charge Density in a Conducting Material
• Inside a conductor (Ohm’s law)
• Continuity equation is
• Solution is
Ej
tE
t
jt
0
0
te 0
So charge density decays exponentially with time. For a very good conductor, charges flow instantly to the surface to form a surface charge density and (for time varying fields) a surface current. Inside a perfect conductor () E=H=0
Maxwell’s Equations in a Uniform Perfectly Conducting Guide
z
y
x
Hollow metallic cylinder with perfectly conducting boundary surfaces
Maxwell’s equations with time dependence exp(it) are:
022
2
2
H
E
E
Hi
EEE
Eit
DH
Hit
BE
Assume )(
)(
),(),,,(
),(),,,(zti
zti
eyxHtzyxH
eyxEtzyxE
Then 0)( 222
H
Et
is the propagation constant
Can solve for the fields completely in terms of Ez and Hz
39
Special cases• Transverse magnetic (TM modes):
– Hz=0 everywhere, Ez=0 on cylindrical boundary
• Transverse electric (TE modes):– Ez=0 everywhere, on cylindrical
boundary
• Transverse electromagnetic (TEM modes):– Ez=Hz=0 everywhere– requires
0
n
H z
i or022
40
A simple model: “Parallel Plate Waveguide”
Transport between two infinite conducting plates (TE01 mode):
22222
22t
)(
,
satisfies )( where)()0,1,0(
KEKdx
EdE
xEexEE zti
KxAE
cos
sini.e.
To satisfy boundary conditions, E=0 on x=0 and x=a, so
integer ,,sin na
nKKKxAE n
Propagation constant is
n
cc
n
K
a
nK
where1
2
22
z
x
y
x=0 x=a
41
Cut-off frequency, c
c gives real solution for , so attenuation only. No wave propagates: cut-off modes.
c gives purely imaginary solution for , and a wave propagates without attenuation.
For a given frequency only a finite number of modes can propagate.
a
ne
a
xnAE
a
nc
zti
c
,sin,1
2
a
na
nc For given frequency, convenient to
choose a s.t. only n=1 mode occurs.
2
1
2
22
122 1,
c
ckik
42
Propagated Electromagnetic Fields
From
kzta
xn
a
nAH
H
kzta
xnAkH
Ei
H
At
BE
z
y
x
sincos
0
cossin
real,isassuming,
z
x
43
Phase and group velocities in the simple wave guide
21
22ckWave
number:wavelengthspacefreethe,
22
kWavelength:
velocityspace-freethanlarger
,1
kvpPhase
velocity:
velocityspace-freethansmaller
1222
k
dk
dvk gc
Group velocity:
44
Calculation of Wave Properties
• If a=3 cm, cut-off frequency of lowest order mode is
• At 7 GHz, only the n=1 mode propagates and
GHz503.02
103
2
1
2
8
a
f cc
ck
v
ck
v
k
k
g
p
c
18
18
189212221
22
ms101.2
ms103.4
cm62
m103103/10572
a
nc
45
Waveguide animations
• TE1 mode above cut-off ppwg_1-1.mov• TE1 mode, smaller ppwg_1-2.mov• TE1 mode at cut-off ppwg_1-3.mov• TE1 mode below cut-off ppwg_1-4.mov• TE1 mode, variable ppwg_1_vf.mov• TE2 mode above cut-off ppwg_2-1.mov• TE2 mode, smaller ppwg_2-2.mov• TE2 mode at cut-off ppwg_2-3.mov• TE2 mode below cut-off ppwg_2-4.mov
46
22
222
22
2
0
2
2
0
2
since
8
1
4
1energy Magnetic
8
1
4
1energy Electric
a
nkW
k
a
naAdxHW
aAdxEW
e
a
m
a
e
Flow of EM energy along the simple guide
kzta
xnA
a
nHHE
kH
kzta
xnAEEE
zyyx
yzx
sincos,0,
cossin,0
Fields (c) are:
Time-averaged energy:Total e/m energy density
aAW 2
4
1
47
Poynting VectorPoynting vector is xyzy HEHEHES ,0,
Time-averaged: a
xnkAS
22
sin1,0,02
1
Integrate over x:
2
4
1 akASz
So energy is transported at a rate:g
me
z vk
WW
S
Electromagnetic energy is transported down the waveguide with the group velocity
Total e/m energy density
aAW 2
4
1
48