Electromagnetic induction
Jan 15, 2015
Electromagnetic induction
Important factors in inducing currents
• 1. An emf is induced if the coil or the magnet (or both) move (change in flux).
• 2. The size of the induced emf depends on the speed of movement.
• 3. The induced emf depends on the strength of the B field.
• 4. Changing the area inside the magnetic field
• 5. Increasing the number of turns also changes the flux linkage, and so induces a greater emf.
What you are going to learn today
• What is magnetic flux, and magnetic flux linkage?
• What must happen to a conductor (or to the magnetic field in which it’s placed) for electricity to be generated?
• What factors would cause the induced emf to be greater?
• What is Lenz’s law and what are the applications of this law?
Flux - The rate of flow of energy through a given surface
• flux density B (The strength of your magnetic field)
• magnetic flux, . rea
• Flux Linkage, N – (N = number of
turns)
Lenz’s Law
• Lenz’s Law states that the direction of the induced current is always such as to oppose the change that causes the current.
• To include this idea in our formula, a minus sign has to be introduced, giving;
• Emf = – N x d/dt
Fleming's Right hand rule
p133
Kinetic energy recovery systems
Toyota• http://www.youtube.com/watch?
v=evZ-C8fVrP4F1
• http://www.youtube.com/watch?v=09knBT2gqqU
Inducing an Emf (no current yet)
• Connect the coil of wire to the micro-voltmeter and place it close to the magnet.
• 1. Move the magnet next to the coil. What happens? How does it depend on speed and direction of movement?
• 2 .Move the coil next to the magnet. What happens? How does it depend on speed and direction of movement?
• 3. Gradually unwind the coil in the magnetic field. What happens?
• 4. Take the coil and crumple it up, keeping it in the field. What happens?
Conductor in a magnetic field
Metal rod, length L in a magnetic field moving with a velocity v down the page.
An electron in the rod will experience a force (= Bev) that will push it towards the
end Q
The electrons will be pushed towards end Q leaving end
p more positive
an electric field E builds up until the force on electrons
in the rod due to this electric field (= Ee)
balances the force due to the magnetic field.
Ee = Bev so E =BvFor a rod of length L,
E = V/L and so V/L = BvHence the induced emf = BLvv = velocity E = Electric field
V = Voltage B = Magnetic field
Completing the circuit• The emf will now cause a current to flow in
the external resistor R. This means that a similar current flows through the rod itself giving a magnetic force, BIL to the left
• L is now the separation of the two conductors along which the rod PQ moves.) An equal and opposite force (to the right) is needed to keep PQ moving at a steady speed.
• The work done in moving the rod will equal the energy dissipated in the resistor.
• In a time t, the rod moves a distance d = v t
• Work done (FxD) on the rod = BIL v t
• Energy dissipated in R = power x time = ItV
• giving BIL v t = ItV
• Emf (V) = BvL
However! You are increasing the area inside the magnetic
fieldEmf (V) = BvL
In one second the area has increased by Lv (A =Lv)
induced emf = B x area swept out per second
= B x A / t
B x A can be called the magnetic flux, .
Thus induced emf = / t = rate of change of magnetic flux
And more generally emf = d / dt
So how can you increase the induced voltage?
L
Flux Linkage (N )
• Increasing the number of turns of wire N in our circuit increases the emf produced
• induced emf = rate of change of flux linkage
• emf = N x d/dt
Sketching Flux Patterns
NSNS
SN
– +