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11 11
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8. 8.
8.1. 8.1.
8.2. 8.2. --
8.3. 8.3.
8.4. 8.4.
8.5. 8.5.
8.6. 8.6.
8.7. 8.7.
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8.4. 8.4.
B, dsB, ds .. BB-- : : B=B=mm00I/2I/2ppaa
--
BB--
II BB
B ds
I
a
B ds Bds
B ds
00
I B ds B ds ( 2 a ) I
2 a
mp m
p
ds 2 ap
B
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--
mm00II-- , , , , BB
II--
:: IIkk
, ,
II11, I, I33 , , II22 I=0I=0
B ds
0 B ds I m
kI I
B ds 0
I1I2 I3
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BB
BB BB
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8.5 8.5 A long, straight wire of radiusA long, straight wire of radius aa carriescarries
a steady currenta steady current II00 that is uniformlythat is uniformly
distributed through the cross section ofdistributed through the cross section ofthe wire. Calculate the magnetic fieldthe wire. Calculate the magnetic fieldat a distanceat a distance rrfrom the center of thefrom the center of thewire in the regionswire in the regions rraa andand r
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11
((rraa ))
27.1 27.1-- , ,
r
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11 22
((r
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88.6.6
. . NN . . rr
. . ::
-- rr
The magnetic field of a toroidal coil:The magnetic field of a toroidal coil:The toroidal coil consists ofThe toroidal coil consists ofNNturns ofturns ofwire wrapped around a doughnutwire wrapped around a doughnutshaped structure as in Fig. Assumingshaped structure as in Fig. Assumingthat the turns are closely spaced,that the turns are closely spaced,calculate the magnetic field inside thecalculate the magnetic field inside thecoil, a distancecoil, a distance rrfrom the center.from the center.
B ds
r
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II mm00NINI
BB 1/r1/r-- r>>ar>>a
00 00
NN
B ds B ds
0 B ds B ds B( 2 r ) NI p m
0NIB2 r
m
p
r
2a
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88.7.7
. . yzyz jjss .. yy
jjss zz . .
. . ::
BB
, , BB
l, wl, w ll ,, ww
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, ,
jjssll
ww
0 s2Bl j l m s
0
jB
2
m
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8.5. 8.5.
2 2
,,
dAdA BB dAdA-- . .
AA , , BB ddAA-- qq
q=90 q=0 BA
mB dA
B dA
m BAcos q
, : 1=12
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::
BB-- , ,
, ,
: :
: : B dA 0
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88.8.8
BB dAdA dAdA ddmm=BdA=BdA
BB , , rr-- BB
dA=bdrdA=bdr . .
aa ,, bb II cc . .
. . . . ::
0IB2 r
m
p
0m
I BdA dA
2 r
m
p
a c a c0 0 0m cc
I Ib Ibdr a cb ln r ln
2 r 2 2 c
m m m
p p p
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8.6. 8.6.
PP
: :
SS
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: :
NN, , SS
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22 44 : : BB dsds ll 11 BlBl : : BB dsds--
II
ll,, ww
-- 33 B=0B=0
B ds
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ll NN
NINI
n=N/ln=N/l
. ? . ?
1 1 B ds B ds B ds Bl
0 B ds Bl NI m
0 0
N B I nI
lm m 0
NIB
2 r
m
p
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dxdx (N/l)dx(N/l)dx I(N/l)dxI(N/l)dx dxdx PP
x=Rtanx=Rtanff dx=Rsecdx=Rsec22ffddff
ll,, RR ,, NN , , II
PP
2
0x 3
2 2 2
IRB
2( x R )
m
2
0
32 2 2
R NdB I dx
l2( x R )
m
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xx ff ff11-- ff22
PP RR-- ff22=90=90,, ff11==--9090
PP
ff22 9090,, ff11 00
xx--
2
1
0 02 1
NI NI B cos d (sin sin )2l 2l
f
fm mf f f f
0 00
NI NI B ( 1 1 ) nI 2l l
m mm
01 B nI 2
m
8 7 8 7
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8.7. 8.7.
II . :. :
::
0 B ds I m
I dQ / dt
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SS22--
,, SS22
PP SS11 SS22
PP SS11 II mm00II
ed 0
dI
dt
e
E dA
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, , BB......
--
e0 d 0 0 0
d B ds ( I I ) I
dt
m m m
e E dA EA
0 0 E, A ? E / Q / A
e
0
QEA
ed 0
d dQI
dt dt
88 99
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88..99 8 8 3 3
30 30
. . :: ww=2=2pp f=2f=2pp(3(3101033)=6)=6pp101033 cc--11
V=VV=Vmmsinsinwwt=30sin(6t=30sin(6pp1010
33t) Bt) B
4,52 4,52
6 3
d
dQ d( CV ) dV d I C ( 8 10 ) 30 sin( 6 10 t )
dt dt dt dt p
34,52cos(6 10 t ) Ap