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Elect Magnet 11

Apr 06, 2018

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Bayar Jargal
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    11 11

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    8. 8.

    8.1. 8.1.

    8.2. 8.2. --

    8.3. 8.3.

    8.4. 8.4.

    8.5. 8.5.

    8.6. 8.6.

    8.7. 8.7.

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    8.4. 8.4.

    B, dsB, ds .. BB-- : : B=B=mm00I/2I/2ppaa

    --

    BB--

    II BB

    B ds

    I

    a

    B ds Bds

    B ds

    00

    I B ds B ds ( 2 a ) I

    2 a

    mp m

    p

    ds 2 ap

    B

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    --

    mm00II-- , , , , BB

    II--

    :: IIkk

    , ,

    II11, I, I33 , , II22 I=0I=0

    B ds

    0 B ds I m

    kI I

    B ds 0

    I1I2 I3

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    BB

    BB BB

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    8.5 8.5 A long, straight wire of radiusA long, straight wire of radius aa carriescarries

    a steady currenta steady current II00 that is uniformlythat is uniformly

    distributed through the cross section ofdistributed through the cross section ofthe wire. Calculate the magnetic fieldthe wire. Calculate the magnetic fieldat a distanceat a distance rrfrom the center of thefrom the center of thewire in the regionswire in the regions rraa andand r

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    11

    ((rraa ))

    27.1 27.1-- , ,

    r

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    11 22

    ((r

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    88.6.6

    . . NN . . rr

    . . ::

    -- rr

    The magnetic field of a toroidal coil:The magnetic field of a toroidal coil:The toroidal coil consists ofThe toroidal coil consists ofNNturns ofturns ofwire wrapped around a doughnutwire wrapped around a doughnutshaped structure as in Fig. Assumingshaped structure as in Fig. Assumingthat the turns are closely spaced,that the turns are closely spaced,calculate the magnetic field inside thecalculate the magnetic field inside thecoil, a distancecoil, a distance rrfrom the center.from the center.

    B ds

    r

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    II mm00NINI

    BB 1/r1/r-- r>>ar>>a

    00 00

    NN

    B ds B ds

    0 B ds B ds B( 2 r ) NI p m

    0NIB2 r

    m

    p

    r

    2a

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    88.7.7

    . . yzyz jjss .. yy

    jjss zz . .

    . . ::

    BB

    , , BB

    l, wl, w ll ,, ww

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    , ,

    jjssll

    ww

    0 s2Bl j l m s

    0

    jB

    2

    m

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    8.5. 8.5.

    2 2

    ,,

    dAdA BB dAdA-- . .

    AA , , BB ddAA-- qq

    q=90 q=0 BA

    mB dA

    B dA

    m BAcos q

    , : 1=12

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    ::

    BB-- , ,

    , ,

    : :

    : : B dA 0

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    88.8.8

    BB dAdA dAdA ddmm=BdA=BdA

    BB , , rr-- BB

    dA=bdrdA=bdr . .

    aa ,, bb II cc . .

    . . . . ::

    0IB2 r

    m

    p

    0m

    I BdA dA

    2 r

    m

    p

    a c a c0 0 0m cc

    I Ib Ibdr a cb ln r ln

    2 r 2 2 c

    m m m

    p p p

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    8.6. 8.6.

    PP

    : :

    SS

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    : :

    NN, , SS

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    22 44 : : BB dsds ll 11 BlBl : : BB dsds--

    II

    ll,, ww

    -- 33 B=0B=0

    B ds

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    ll NN

    NINI

    n=N/ln=N/l

    . ? . ?

    1 1 B ds B ds B ds Bl

    0 B ds Bl NI m

    0 0

    N B I nI

    lm m 0

    NIB

    2 r

    m

    p

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    dxdx (N/l)dx(N/l)dx I(N/l)dxI(N/l)dx dxdx PP

    x=Rtanx=Rtanff dx=Rsecdx=Rsec22ffddff

    ll,, RR ,, NN , , II

    PP

    2

    0x 3

    2 2 2

    IRB

    2( x R )

    m

    2

    0

    32 2 2

    R NdB I dx

    l2( x R )

    m

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    xx ff ff11-- ff22

    PP RR-- ff22=90=90,, ff11==--9090

    PP

    ff22 9090,, ff11 00

    xx--

    2

    1

    0 02 1

    NI NI B cos d (sin sin )2l 2l

    f

    fm mf f f f

    0 00

    NI NI B ( 1 1 ) nI 2l l

    m mm

    01 B nI 2

    m

    8 7 8 7

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    8.7. 8.7.

    QQ

    II . :. :

    ::

    0 B ds I m

    I dQ / dt

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    SS22--

    ,, SS22

    PP SS11 SS22

    PP SS11 II mm00II

    ed 0

    dI

    dt

    e

    E dA

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    , , BB......

    --

    e0 d 0 0 0

    d B ds ( I I ) I

    dt

    m m m

    e E dA EA

    0 0 E, A ? E / Q / A

    e

    0

    QEA

    ed 0

    d dQI

    dt dt

    88 99

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    88..99 8 8 3 3

    30 30

    . . :: ww=2=2pp f=2f=2pp(3(3101033)=6)=6pp101033 cc--11

    V=VV=Vmmsinsinwwt=30sin(6t=30sin(6pp1010

    33t) Bt) B

    4,52 4,52

    6 3

    d

    dQ d( CV ) dV d I C ( 8 10 ) 30 sin( 6 10 t )

    dt dt dt dt p

    34,52cos(6 10 t ) Ap