EE403.16.ppt

EE403.16 1Name : A. Siva Sankar Designation: lecturerBranch :Electrical and Electronics Engg.nstitution :!ovt. "ol#technic$ "roddaturSemester :%&a'or (o)ic :Single "hase (rans*ormersSu+to)ic :)ro+lems on e,uivalent resistance andreactanceSu+.-ode.(itle : EE/404 . A- &achines/Duration : 00 min.(eaching Aids :""($ AnimationsDE"A1(&EN( 23 (E-4NN-A5 ED6-A(2N AND41A "1ADES4 EE403.16 71eca)8 9e have discussedin the last session a+out (rans*ormation o* resistances $ reactance and im)edances *rom one side o* a trans*ormer to the other side and the develo)ment )hasor diagrams *or various loads.2EE403.16 32+'ective:2n com)letion o* this )eriod$ #ou :ould +e a+le to understand8Solve )ro+lems on *inding e,uivalent resistances or reactance or im)edances o* a trans*ormer andsecondar# voltage at an# load.3EE403.16 4Duration to cover each o+'ective81eca) and introduction 00&in8E;am)le )ro+lems solving 30&in8Summar# 00&in8100% single/)hase trans*ormer has the e,uivalent resistance andreactance re*erred to )rimar#:101?0.3@A01?0.7@B-alculate the voltage on secondar# terminals o* the trans*ormer$ :hen the load current on the secondar# side is 100A at 0.C )o:er *actor lagging.5EE403.16 6Solution:8!iven Data: = 3 . 001R = 2 . 501X8 . 0 cos10022= = A IPhase V kVA Rating = 1 , 100 / 500 , 100 186 . 36 ) 8 . ( cos = = O6EE403.16 D ===012 . 03 . 0 ) 2 . 0 (R K Rsecondary to referred resistance201 2 O2xTotal2 . 050010012= = =EEK ===208 . 02 . 5 ) 2 . 0 (X Ksecondary to referred reactance201 2 O2xXTotalDSolution:EE403.16 C =+ =+ =002 02 026 . 86 208 . 0208 . 0 012 . 0X j R Zsecondaryjto referred impedance Total02 2 2 2terina!Z I E Vvoltage econdar! ={ }00 06 . 86 208 . 0 86 . 36 100 0 100 = x8" . 15 #1 . 13 0 100) 83 . #" 8 . 20 ( 0 1000j jj + = + =Vj03" . 10 888" . 15 58 . 86 = =CEE403.16 EE;am)le 7A 10 =%A$00 4F single/)hase trans*ormer :ith turns ratio 10:1 has the *ollo:ing resistance and leakage reactance:11?4.C ohmB A1?11.7 ohmB 17?0.04C ohmB A7?0.117ohmB no/load current ?1A leading the *lu; +#700. (he secondar# delivers 40 A at a terminal voltage o* 700% and )o:er *actor o* 0.C lagging. Determine the )rimar# a))lied voltage$ the )rimar# )o:er *actor +# the hel) o* vectorG )hasorH diagram.9EE403.16 10Solution:!iven Data:(urns ratio? 10:111?4.C ohmA1?11.7 ohm17?0.04C ohmA7?0.117ohm 0?1AI0?700

7?40AcosI0?0.C lag10EE403.16 11

+ = = ====== j11.2) #.8 ( Z$ 36.86 % #0 &0 250 '(ector reference t)e as ' $ss*in+1 . 0101250 286 . 36) 8 . 0 ( cos102022012KV V11EE403.16 17{ }Vjj jxZ I V EjjX R ZZ00 0 02 2 2 202 2 2025# . 0 23 . 25##3 . 2 22 . 25##3 . 2 22 . # 0 2508 . 66 1218 . 0 86 . 36 #0 0 2508 . 66 1218 . 0) 112 . 0 0#8 . 0 (8 . 66 18 . 12 =+ =+ + + = + =+ = = + =+ = =12EE403.16 13Ax K I IVKEE002 20211# . 1#3 #1 . 0 86 . 36 #0 ,5# . 0 3 . 25#21 . 023 . 25# = = = ===-&2'2.250'&2R2/2&0.1$A I #12 =1E &1R11I01'1&2X2&1X1086 . 36Solution:EE403.16 1400 00 2 1000 0 0 02 00 . 130 " . #3 . 3 63 . 3" . 0 #3 . 0 # . 2 2 . 35 . 11# 1 1# . 1#3 # ,) " . 0 #3 . 0 ( 5 . 115 15 . 115 25 "0 5 . 0 =+ =+ + = + =+ =+ = == + +jj jI I IA j Ito e"#al angle an $!V leads I diagram vector the %rom14EE403.16 10Vjjx000 0 01 11100 . 181 " . 25"601 . #8 #8 . 25"65 . 20# 68 . 5" "6 . 23 18 . 25#2) 8 . 66 18 . 12 0 . 130 " . # ( 5# . 180 3 . 25#2Z & / % '(o!ta+e a11!ied 2riary = = + = + =+ =15Solution:EE403.16 16lag factor po&er Primar!is I and V $et&een angle Phase020 . 0 #0 . #3 cos ,30 . #3 0 . 130 00 . 181001 1== =16Solution:EE403.16 1DSummar#8n this session :e have discussed a+out the :a# o* solving various )arameters o* a trans*ormer i.e. the e,uivalent im)edances$currents and terminal voltages$ at an# given load.17EE403.16 1C1. (hevalue o* resistance in 5% :inding:hen it is re*erred to 4% :inding////aH 9ill decrease+H &a# increasecH Does not changedH none18&a# 7001MLans:ers: aH13.40 K$0.0603 K+H 11E3D0 9M20EE403.16 717. A 00 =%A $ 44400>770% single/)hase trans*ormer has resistance and leakage reactance as *ollo:s: 11?3.40KB17?0.00E KA1?0.7 KA7?0.010 K -alculate the e,uivalent GiH resistance re*erred to )rimar# and secondar#GiiH reactance re*erred to +oth )rimar# and secondar# GiiiH im)edance re*erred to )rimar# and secondar#and GivH total co))er loss *irst using individual resistances and secondl# using e,uivalent resistances.L ans:ers:GiH D.00 K$ 0.01D6 KGiiH 11.7 K$ 0.07C KGiiiH 13.73 K$ 0.0331 K GivH E0E9 M21EE403.16 77(hank #ou 22