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Ch. 8 Feedback 1 ECE 352 Electronics II Winter 2003 Feedback * What is feedback? Taking a portion of the signal arriving at the load and feeding it back to the input. * What is negative feedback? Adding the feedback signal to the input so as to partially cancel the input signal to the amplifier. * Doesn’t this reduce the gain? Yes, this is the price we pay for using feedback. * Why use feedback? Provides a series of benefits, such as improved bandwidth, that outweigh the costs in lost gain and increased complexity in amplifier design. X o X i X f X s + - β f
38

ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Jan 16, 2016

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Page 1: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 1ECE 352 Electronics II Winter 2003

Feedback

* What is feedback? Taking a portion of the signal arriving at the load and feeding it back to the input.

* What is negative feedback? Adding the feedback signal to the input so as to partially cancel the input signal to the amplifier.

* Doesn’t this reduce the gain? Yes, this is the price we pay for using feedback.

* Why use feedback? Provides a series of benefits, such as improved bandwidth, that outweigh the costs in lost gain and increased complexity in amplifier design.

XoXi

Xf

Xs +-

βf

Page 2: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 2ECE 352 Electronics II Winter 2003

Feedback Amplifier Analysis

AA

A

X

XA

X

XA

XX

AX

X

XA

bygivenisfeedbackwithgainsamplifierThe

sourcethefromsignaltheX

amplifierbasicthetosignalinputnettheisXwhereXXX

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Page 3: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 3ECE 352 Electronics II Winter 2003

* Gain desensitivity - less variation in amplifier gain with changes in (current gain) of transistors due to dc bias, temperature, fabrication process variations, etc.

* Bandwidth extension - extends dominant high and low frequency poles to higher and lower frequencies, respectively.

* Noise reduction - improves signal-to-noise ratio* Improves amplifier linearity - reduces distortion in signal due to gain

variations due to transistors

* Cost of these advantages: Loss of gain, may require an added gain stage to compensate. Added complexity in design

Advantages of Negative Feedback

AA

f

LLfHfHf

1

1

Page 4: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 4ECE 352 Electronics II Winter 2003

* There are four types of feedback amplifiers. Why? Output sampled can be a current or a voltage Quantity fed back to input can be a current or a voltage Four possible combinations of the type of output sampling and input

feedback

* One particular type of amplifier, e.g. voltage amplifier, current amplifier, etc. is used for each one of the four types of feedback amplifiers.

* Feedback factor f is a different type of quantity, e.g. voltage ratio, resistance, current ratio or conductance, for each feedback configuration.

* Before analyzing the feedback amplifier’s performance, need to start by recognizing the type or configuration.

* Terminology used to name types of feedback amplifier, e.g. Series-shunt First term refers to nature of feedback connection at the input. Second term refers to nature of sampling connection at the output.

Basic Types of Feedback Amplifiers

Page 5: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 5ECE 352 Electronics II Winter 2003

Basic Types of Feedback Amplifiers

Series - Shunt Shunt - Series

Series - Series Shunt - Shunt

Page 6: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 6ECE 352 Electronics II Winter 2003

* Recognize the feedback amplifier’s configuration, e.g. Series-shunt

* Calculate the appropriate gain A for the amplifier, e.g. voltage gain. This includes the loading effects of the feedback circuit (some

combination of resistors) on the amplifier input and output.

* Calculate the feedback factor f

* Calculate the factor f A and make sure that it is: 1) positive and 2) dimensionless

* Calculate the feedback amplifier’s gain with feedback Af using

* Calculate the final gain of interest if different from the gain calculated, e.g. Current gain if voltage gain originally determined.

* Determine the dominant low and high frequency poles for the original amplifier, but taking into account the loading effects of the feedback network.

* Determine the final dominant low and high frequency poles of the amplifier with feedback using

Method of Feedback Amplifier Analysis

A

AA

ff

1

AA

f

LLfHfHf

1

1

Page 7: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 7ECE 352 Electronics II Winter 2003

Series-Shunt Feedback Amplifier - Ideal Case

* Assumes feedback circuit does not load down the basic amplifier A, i.e. doesn’t change its characteristics

Doesn’t change gain A Doesn’t change pole frequencies of basic

amplifier A Doesn’t change Ri and Ro

* For the feedback amplifier as a whole, feedback does change the midband voltage gain from A to Af

* Does change input resistance from Ri to Rif

* Does change output resistance from Ro to Rof

* Does change low and high frequency 3dB frequencies

A

AA

ff

1

ARR fiif 1

A

RR

f

oof

1

AA

f

LLfHfHf

1

1

Basic Amplifier

Feedback Circuit

Equivalent Circuit for Feedback Amplifier

Page 8: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 8ECE 352 Electronics II Winter 2003

Series-Shunt Feedback Amplifier - Ideal Case

Midband Gain

Vf

V

i

of

V

i

f

V

fi

iV

s

oVf A

A

V

VA

V

VA

VV

VA

V

VA

111

Input Resistance

Vfi

ii

ofi

i

fi

i

sif AR

RV

VV

I

VV

I

VR

1

Output Resistance

Vt

It

fV

o

t

tof

o

fVt

o

tfVt

o

fVtt

tfoff

fis

o

iVtt

A

R

I

VRso

R

AV

R

VAV

R

VAVI

soVVVand

VVsoVBut

R

VAVI

1

1

0

Page 9: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 9ECE 352 Electronics II Winter 2003

Series-Shunt Feedback Amplifier - Ideal Case

of

LLf

of

ofo

Lf

fo

of

L

of

o

ofL

o

L

of

L

o

ff

L

o

AA

AAwhere

s

A

sA

A

A

As

A

s

A

s

A

A

AAthen

s

AAFor

11

11

11

1

1

11

1

11

Low Frequency Pole

High Frequency Pole

ofHHfof

ofo

Hf

fo

ofH

of

o

ofH

o

H

of

H

o

ff

H

o

AA

AAwhere

s

A

A

s

A

A

As

A

sA

sA

A

AAthen

sA

AFor

11

11

1

1

1

11

1

11

Low 3dB frequency lowered by feedback.

Upper 3dB frequency raised by feedback.

Page 10: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 10ECE 352 Electronics II Winter 2003

* Feedback networks consist of a set of resistors Simplest case (only case considered here) In general, can include C’s and L’s (not

considered here) Transistors sometimes used (gives variable

amount of feedback) (not considered here)

* Feedback network needed to create Vf feedback signal at input (desirable)

* Feedback network has parasitic (loading) effects including:

* Feedback network loads down amplifier input Adds a finite series resistance Part of input signal Vs lost across this series

resistance (undesirable), so Vi reduced

* Feedback network loads down amplifier output Adds a finite shunt resistance Part of output current lost through this shunt

resistance so not all output current delivered to load RL (undesirable)

Practical Feedback Networks

Vi

Vf

Vo

* How do we take these

loading effects into account?

Page 11: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 11ECE 352 Electronics II Winter 2003

* Need to find an equivalent network for the feedback network including feedback effect and loading effects.

* Feedback network is a two port network (input and output ports)

* Can represent with h-parameter network (This is the best for this particular feedback amplifier configuration)

* h-parameter equivalent network has FOUR parameters

* h-parameters relate input and output currents and voltages

* Two parameters chosen as independent variables. For h-parameter network, these are input current I1 and output voltage V2

* Two equations relate other two quantities (output current I2 and input voltage V1) to these independent variables

* Knowing I1 and V2, can calculate I2 and V1 if you know the h-parameter values

* h-parameters can have units of ohms, 1/ohms or no units (depends on which parameter)

Equivalent Network for Feedback Network

Page 12: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 12ECE 352 Electronics II Winter 2003

* Feedback network consists of a set of resistors

* These resistors have loading effects on the basic amplifier, i.e they change its characteristics, such as the gain

* Can use h-parameter equivalent circuit for feedback network Feedback factor f given by h12 since

Feedforward factor given by h21 (neglected)

h22 gives feedback network loading on output

h11 gives feedback network loading on input

* Can incorporate loading effects in a modified basic amplifier. Basic gain of amplifier AV becomes a new, modified gain AV’ (incorporates loading effects).

* Can then use feedback analysis from the ideal case.

Series-Shunt Feedback Amplifier - Practical Case

fo

f

IV

V

V

Vh

02

112

1

'1

'1

'1'1

'1

'

Vf

LLfHVfHf

fV

oofVfiif

Vf

VVf

AA

A

RRARR

A

AA

Page 13: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 13ECE 352 Electronics II Winter 2003

Series-Shunt Feedback Amplifier - Practical Case

* How do we determine the h-parameters for the feedback network?

* For the input loading term h11 Turn off the feedback signal by

setting Vo = 0. Then evaluate the resistance seen

looking into port 1 of the feedback network (also called R11 here).

* For the output loading term h22

Open circuit the connection to the input so I1 = 0.

Find the resistance seen looking into port 2 of the feedback network (also called R22 here).

* To obtain the feedback factor f (also called h12 ) Apply a test signal Vo’ to port 2 of the

feedback network and evaluate the feedback voltage Vf (also called V1 here) for I1 = 0.

Find f from f = Vf/Vo’

Summary of Feedback Network Analysis

Page 14: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 14ECE 352 Electronics II Winter 2003

* Evaluate modified basic amplifier (including loading effects of feedback network) Including h11 at input Including h22 at output Including loading effects of source resistance Including load effects of load resistance

* Analyze effects of idealized feedback network using feedback amplifier equations derived

* Note Av’ is the modified voltage gain including the

effects of h11 , h22 , RS and RL. Ri’, Ro’ are the modified input and output

resistances including the effects of h11 , h22 , RS and RL.

Series-Shunt Feedback Amplifier - Practical Case

Summary of Approach to Analysis

'1

'1

'1

''1'

'1

'

Vf

LLfHVfHf

fV

oofVfiif

Vf

VVf

AA

A

RRARR

A

AA

Modified Basic Amplifier

Idealized Feedback Network

Practical Feedback Network

Basic Amplifier

Page 15: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 15ECE 352 Electronics II Winter 2003

* Two stage amplifier

* Each stage a CE amplifier

* Transistor parameters Given: 1= 2 =50, rx1=rx2=0

* Coupled by capacitors, dc biased separately

* DC analysis:

Example - Series-Shunt Feedback Amplifier

Kg

r

VmAV

IgmAI

Kg

r

VmAV

IgmAI

m

T

CmC

m

T

CmC

7.0

,/71,85.1

4.1

,/36,94.0

2

22

222

1

11

111

DC analysis for each stage can be done separately since stages are isolated (dc wise) by coupling capacitors.

Page 16: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 16ECE 352 Electronics II Winter 2003

Example - Series-Shunt Feedback Amplifier

Vi

+_

* Redraw circuit to show Feedback circuit Type of output sampling

(voltage in this case = Vo)

Type of feedback signal to input (voltage in this case = Vf)

Vf

+_ Vo

+

_

Page 17: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 17ECE 352 Electronics II Winter 2003

Example - Series-Shunt Feedback Amplifier

Input Loading Effects

Output Loading Effects

KKK

RRhR ff

8.41.07.4

21222

Amplifier with Loading Effects

I1=0

K

KK

RRhR ff

098.0

7.41.0

21111

Vo=0

R1R2

Page 18: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 18ECE 352 Electronics II Winter 2003

* Construct ac equivalent circuit at midband frequencies including loading effects of feedback network.

* Analyze circuit to find midband gain

(voltage gain for this series-shunt configuration)

Example - Series-Shunt Feedback Amplifier

R1

R2

R1 R2

Page 19: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 19ECE 352 Electronics II Winter 2003

Example - Series-Shunt Feedback AmplifierMidband Gain Analysis

dBdBA

V

VA

K

K

KKKK

KKK

RRRR

RRR

V

V

KKKRrI

RVgIrI

I

VR

KK

K

Rr

r

RVgIrI

rI

V

V

KKKKVmArRRRgV

V

rV

VKKVmARRg

V

V

V

V

V

V

V

V

V

V

V

V

V

VA

Vo

s

oVo

is

i

s

i

mii

mi

Cmo

xo

Cmo

s

i

i

o

o

o

s

oVo

53449log20)(

44952.022.08.221172

52.04.10

4.5

471504.65

471504.6

4.6098.0514.11

22.0098.0514.1

4.1

1

8.227.0334710/36

0since11728.49.4/71

21111

211111

111

111111

1

11

11

1

111111

11

1

1

22212111

1

21

2222

2

1

1

1

1

1

1

2

2

Page 20: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 20ECE 352 Electronics II Winter 2003

Midband Gain with Feedback

* Determine the feedback factor f

* Calculate gain with feedback Avf

* Note f Avo > 0 as necessary for negative feedback

f Avo is large so there is significant feedback. For f Avo 0, there is almost no feedback.

Can change f and the amount of feedback by changing Rf1 and/or Rf2.

NOTE: Since f Avo >> 0

021.07.41.0

1.0

' 21

1

KK

K

RR

R

V

V

X

X

ff

f

o

f

o

ff

dBdBA

A

AA

A

Vfo

Vof

VoVfo

Vof

7.321.43log20)(

1.434.10

449

)021.0(4491

449

1

4.9)021.0(449

dBdBA

A

A

A

AA

A

Vfo

fVof

Vo

Vof

VoVfo

Vof

6.336.47log20)(

6.47021.0

11

1

4.9)021.0(449

1

2

1

211

1

f

f

f

ff

fVfo R

R

R

RRA

Page 21: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 21ECE 352 Electronics II Winter 2003

Input and Output Resistances with Feedback

* Determine input Ri and output Ro resistances with loading effects of feedback network.

* Calculate input Rif and output Rof resistances for the complete feedback amplifier.

KKKK

RRRR iBSi

5.104.65.385

11

KK

ARR Vofiif

5.109)021.0(44915.10

1

KKK

RRR Co

4.28.49.4

22

KK

A

RR

Vof

oof 23.0

4.10

4.2

1

Page 22: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 22ECE 352 Electronics II Winter 2003

Equivalent Circuit for Series-Shunt Feedback Amplifier

* Voltage gain amplifier

* Modified voltage gain, input and output resistances Included loading effects of

feedback network Included feedback effects

of feedback network Include source resistance

effects

* Significant feedback, i.e. f Avo is large and positive

dBdBA

A

A

V

VA

Vfo

Vof

Vo

fS

oVfo

7.321.43log20)(

1.431

KA

RR

KARR

Vof

oof

Vofiif

23.01

5.1091

dBdBA

R

R

R

RR

A

A

A

AA

A

Vf

f

f

f

ff

fVof

Vo

Vof

VoVfo

Vof

6.336.47log20)(

6.471

1

1

4.9)021.0(449

1

2

1

21

Page 23: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 23ECE 352 Electronics II Winter 2003

Low Frequency Poles and Zeros for Series-Shunt Feedback Amplifier

* Six capacitors: Input and output coupling capacitors C1 and C5

Emitter bypass capacitors C3 and C4

Interstage coupling capacitors C2

Feedback coupling capacitor C6

* Analyze using Gray-Searle (Short Circuit) Technique one capacitor at a time

* Find dominant low frequency pole (highest frequency one)

Page 24: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 24ECE 352 Electronics II Winter 2003

Example - Input Coupling Capacitor’s Pole Frequency

Equivalent circuit for C1

sradFKCR

KKKKRRRR

so

KKKRr

I

RVgIrI

I

VR

where

RRRI

VR

xCPL

iBSxC

mii

iBSx

xxC

/2.1954.10

11

4.104.68.355

4.6098.0514.11

111

111

11

1

111111

1

11

111

Note that there are some loading effects of the feedback network on this pole frequency. In Ri1 the feedback resistors determine R1

211 ff RRR

Page 25: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 25ECE 352 Electronics II Winter 2003

Example - Interstage Coupling Capacitor’s Pole Frequency

Equivalent circuit for C2 sradFKCR

so

KKKK

rRRI

VR

xCPL

BCx

xxC

/7.1857.10

11

7.107.04.1910

222

2212

Note: No RE2 since C4 shorts it out.

Page 26: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 26ECE 352 Electronics II Winter 2003

Example - Feedback Coupling Capacitor’s Pole Frequency

Equivalent circuit for C6

sradFKCR

so

KKK

RRI

VR

xCPL

Cx

xxC

/6.2057.9

11

7.98.49.4

666

226

Page 27: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 27ECE 352 Electronics II Winter 2003

sradFKCR

KRrgRRRRr

rgRRRr

I

V

R

VIR

rg

RRr

R

VIR

rgR

VI

RRr

RIRRrIV

becomesVsoR

VIIII

soIIIEnodeAt

rgR

VI

I

soVgIIIEnodeAt

RIRRrIV

R

VI

I

VR

ExEPL

EmEBs

mBs

x

x

E

xx

m

Bs

E

xx

m

E

xx

Bs

Bsx

xE

xxxE

xE

m

E

xx

mEx

Bsx

E

xE

x

xEx

/100502.0

11

2.01

1R

getweg,Rearrangin

1

1

0'

1

0

113

1111111

11111xC3

11

11

11

11

11

111

11111

111

11

11

11

1111

11111

11

Example - Emitter Bypass Capacitor’s Pole Frequency

Equivalent circuit for C3

IE1

Page 28: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 28ECE 352 Electronics II Winter 2003

Example - Emitter Bypass Capacitor’s Pole Frequency

Equivalent circuit for C4

sradFKCR

KKK

KK

rg

RRrR

I

V

RRr

rg

RVI

becomesIso

RRr

VIsoRRrIV

rgIR

VrgIII

soVgIIIEnodeAt

R

VI

I

VR

ExEPL

m

BCE

x

x

BC

m

Exx

x

BC

xBCx

mE

xmEx

mEx

E

xE

x

xEx

/5.28507.0

11

7.050

4.19107.07.4

1R

getweg,Rearrangin

11

thatknowalsoweBut

11

0

224

22

2122xC4

212

22

2

21222122

2222

2222

2222

22

IE2

Page 29: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 29ECE 352 Electronics II Winter 2003

Example - Output Coupling Capacitor’s Pole Frequency

Equivalent circuit for C5

sradFKCR

so

KKK

RRRR

xCPL

ffCxC

/6.41104.2

11

4.28.49.4

555

2125

Page 30: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 30ECE 352 Electronics II Winter 2003

Zeros for Series-Shunt Feedback Amplifier Example

* Coupling capacitors C1, C2 and C5 give zeros at = 0 since ZC = 1/sC and they are in the signal line.

* Emitter bypass capacitors C3 and C4 give a zero when the impedance ZCE || RE.

* Feedback capacitor C6 gives a zero when [ZC6

+R2] || RC2 when

sradFKCR

sradFKCR

CRswhenRZ

CsR

R

sCRZR

RZ

EZ

EZ

EEEC

EE

E

EECE

EC

E

E

E

/3.4507.4

11

/3.4507.4

11

1

11

1

11

1

424

313

226

622

1

622

6262

1

26

2262

26222

1

1

1

1

1

11

C

C

C

C

CCC

CCmo

RRsC

CsRR

CsRR

CsRCsR

RsC

RRZR

RZRgV

V

sradKKFRRC

RRCsorRRsC

Cz

CC

/6.209.48.45

11

101

2266

226226

Page 31: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 31ECE 352 Electronics II Winter 2003

* Midband Gain Low Frequency Poles Low Frequency Zeros

Series-Shunt Example - Low Frequency

dBdBAA

A

dBdBAA

VfoVfo

Voff

VoVo

7.32)(1.43

4.101021.0

53)(449

sradsrad

sradsrad

sradsrad

PLPL

PLPL

PLPL

/6.20/100

/6.41/7.18

/5.28/2.19

63

52

41

sradsrad

sradsrad

sradsrad

ZZ

PLZ

ZZ

/6.20/3.4

/0/0

/3.4/0

63

52

41

sradsrad

Asrad

Vof

PLPLfPL /6.9

4.10

/100

1/100

Low 3dB Frequency

Page 32: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 32ECE 352 Electronics II Winter 2003

* Substitute hybrid-pi model for transistor with C and C

* Short all coupling capacitors and emitter bypass capacitors

* Include loading effects of feedback network R1 and R2

* Find high frequency poles and zeros using Gray-Searle (Open Circuit) Method

Series-Shunt Example - High Frequency

Page 33: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 33ECE 352 Electronics II Winter 2003

Series-Shunt Example - High Frequency Pole - C1

sradxpFKC

KKK

KK

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I

V

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r

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since

7

11xC1

11111

1111xC

1111

11

111

111

1111

11

11

111

Given: C1 = 15 pF

I1

IS

Page 34: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 34ECE 352 Electronics II Winter 2003

Series-Shunt Example - High Frequency Pole - C1

Given: C1 = 1.2 pF

22111111

1111

221

1

11111

111

1

221

1111

221

111

11111

11111

11111111

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01

usingso

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1

1

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o

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Page 35: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 35ECE 352 Electronics II Winter 2003

Given: C2 = 12 pF

Series-Shunt Example - High Frequency Pole - C2

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pFKCR

KKKK

rRRI

VR

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Page 36: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 36ECE 352 Electronics II Winter 2003

Series-Shunt Example - High Frequency Pole - C2

Given: C2 = 1.4 pF

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Page 37: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 37ECE 352 Electronics II Winter 2003

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VmA

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g

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g

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Series-Shunt Example - High Frequency Zeros - C1 & C2

For CE amplifier, a high frequency zero occurs when ZH = gm/C

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oo

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om

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Page 38: ECE 352 Electronics II Winter 2003 Ch. 8 Feedback 1 Feedback *What is feedback?Taking a portion of the signal arriving at the load and feeding it back.

Ch. 8 Feedback 38ECE 352 Electronics II Winter 2003

* Midband Gain High Frequency Poles High Frequency Zeros

Series-Shunt Example - High Frequency

dBdBAA

A

dBdBAA

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Voff

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/104.6/102.5

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64

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83

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