6 Vin=Sinusoidal FREQ = 500 Hz VAMPL = 1V 3 2 CH 1 R2 12k - + 741 OPAMP + - OUT CH 2 - 12 R1 1.2k + 12 4 7 Ece 232 Lab1 supplementary notes: LM741 1) V in ! A R 1 = A ! V out R 2 , A = 0 Volt V out = !10V in if V in (t ) = Sin(2! ft ) then V out (t ) = !10 Sin(2! ft )
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6
Vin=Sinusoidal
FREQ = 500 HzVAMPL = 1V
3
2
CH 1
R2
12k
-
+
741
OPAMP
+
-
OUT
CH 2- 12
R1
1.2k
+ 12
47
Ece 232
Lab1 supplementary notes:
LM741
1)
Vin ! AR1
=A!VoutR2
, A = 0Volt
Vout = !10Vin
if Vin (t) = Sin(2! ft) then Vout (t) = !10Sin(2! ft)
CH 1
741
OPAMP
+
-
OUT3
2
67
+
R2
12k
- 12CH 2
C1
47n
-
4
+ 12Vin=Square wave
FREQ = 500 HzVAMPL = 1 V
2)
C1d(Vin ! A)
dt=A!VoutR2
Vout = !C1R2dVindt
C1R2 = 564!10*6
a) If Vin (t) = Sqr( ft) (square wave with frequency f and period T)
Vin (t) =1Volt, 0 ! t ! T
2
"1Volt, T2! t ! T
#
$%%
&%%
'
(%%
)%%
(square wave)
Vout (t) =!564"10!6!(t ! n T
2), n even
!564"10!6!(t ! n T2), n odd
#
$%%
&%%
'
(%%
)%%
(impulse train)
b) IfVin (t) = Tri( ft) (triangular wave with frequency f and period T)
Vin (t) =
4Tt, 0 ! t ! T
4
"4Tt + 2, T
4! t ! 3T
44Tt " 4, 3T
4! t ! T
#
$
%%%
&
%%%
'
(
%%%
)
%%% (triangular wave)
Vout (t) =
!564"10!6 4T, 0 # t # T
4
564"10!6 4T, T
4# t # 3T
4
!564"10!6 4T, 3T
4# t # T
$
%
&&&
'
&&&
(
)
&&&
*
&&& (square wave)
741
OPAMP
+
-
OUT +
Vin=Square wave
FREQ = 500 HzVAMPL = 1 V
-
CH 1
3
2
6
R2
1M
C
10n
74
+ 12
R1
100k
- 12CH 2
Example: If f=500Hz and T=2 msec
Vout (t) =
!1.128Volt, 0 " t " T4
1.128Volt, T4" t " 3T
4
!1.128Volt, 3T4" t " T
#
$
%%%
&
%%%
'
(
%%%
)
%%%
3.)
Vin ! AR1
=A!VoutR2
+C d(A!Vout )dt
Since R2 is very high the above equation can be written as,