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Dr. Kasra Etemadi January 27, 2006
24

Dr. Kasra Etemadi

Feb 25, 2022

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Page 1: Dr. Kasra Etemadi

Dr. Kasra EtemadiJanuary 27, 2006

Page 2: Dr. Kasra Etemadi

1- Summary

2- Thevenin and Norton Equivalent Circuits

3-Maximum Power Transfer

4- Superposition Principal

5- Wheatson Bridge

Page 3: Dr. Kasra Etemadi

1.combining resistances in series and Parallel2.The node-voltage technique3.The mesh-current technique

voltage across an element

current passing through an element

Power consumed by an element.

Three techniques to solve circuits:

Page 4: Dr. Kasra Etemadi

+-5V 2A 50

+-

50

5V

30

+-5V

2A

50

2A

50=

30

+-

5V=

+-5V 50=

Page 5: Dr. Kasra Etemadi

RTh

VTh

+

-

Thevenin equivalent CircuitThevenin

Norton equivalent circuit

RThIsc

Norton

pp. 82-83

Circuit with Resistances and sources

(Controlling variables for any sources must

appear inside)

Two terminal Circuit

Page 6: Dr. Kasra Etemadi

VTh

RTh

+

-

Circuit with Resistances and sources

(Controlling variables for any sources must

appear inside)

Two terminal Circuit

VOC =

Page 7: Dr. Kasra Etemadi

+-

+-

VThISC ISC

+-

+-VTh

VOC VOC

RTh

RTh

+-

+-

VThVx Vx

RTh

Rx Rx

Page 8: Dr. Kasra Etemadi

+-

+-VTh

=

RTh

Two Ways to determine VTh and RTh

VTh & RTh

pp. 82-86

Page 9: Dr. Kasra Etemadi

+-

+-

Isc

+-

sc

octh I

VR =

First:

+-

Vth=Voc

Vth

Page 10: Dr. Kasra Etemadi

+-

+-

Vth=Voc

+-

Vth

thR

Rth

no dependent source

Second:

Page 11: Dr. Kasra Etemadi

Rth

+-

20V 2A

5

20

KCL

AII

II

PSSC

PSPS

62

40520

=+===×+

20V2A

5

20+-

IPS

+-

Ω=

+=

4

201

511

th

Th

R

R

4

24

02205

20

=

=−+−

OC

OCOC

V

VV

24

Example:

Ω== 4624

thR

Page 12: Dr. Kasra Etemadi

Example 2.16: Thevenin Equivalent of a Circuit with a Dependent Source

+-

+-

10V2Ix

5

10

Ix

AII

AV

I

xsc

x

63

2510

==

=

43.1==SC

OCTh I

VR

8.75VThevenin

Equivalent

+-

10V2Ix

10Ix

5 ISC

VVOC 75.8=

510

102

OCx

OCxx

VI

VII

−=

=+

pp. 86-88

Page 13: Dr. Kasra Etemadi

Circuit with Resistances and sources

(Controlling variables for any sources must

appear inside)

Two terminal Circuit

+-

VOC

RThIth

pp. 88-91

Page 14: Dr. Kasra Etemadi

+-

+-

+-

Rx,Vx

VOC

ISC

RThIth

RThIth

RThIth

ISC

Page 15: Dr. Kasra Etemadi

+-

+-

Isc

+-

Vth=Voc

IThSC

OCTh I

VR =

Page 16: Dr. Kasra Etemadi

+-

Rth

no dependent source

+-

Isc

RThITh

Page 17: Dr. Kasra Etemadi

+-

20V2A

5

20

Rth

+-

20V 2A

5

20

24

02205

20

=

=−+−

OC

OCOC

V

VVKCL

AII

II

PSSC

PSPS

62

40520

=+===×+

IPS

Ω=

+=

4

201

511

th

Th

R

R 46A

Example:

Page 18: Dr. Kasra Etemadi

+-

20V 2A

5

20

46A

+-

4

24

Norton equivalent circuit

Thevenin equivalent Circuit

Sour

ce T

rans

form

atio

n

Page 19: Dr. Kasra Etemadi

Using Source Transformation

+-

40V 1A

5

10

I1

I2

+-

40V 10V

5 10

I1+

-

8A 5 10 1AI3 I2

Norton

Thevenin

pp. 91-92

Page 20: Dr. Kasra Etemadi

Maximum Power Transfer

Two Terminal Circuit

RL

How much is the maximum power transfer from the Two Terminal Circuit to the Load RL?

RL

RTh

VTh

+

-

Thevenin

Equivalent

( )( ) ( )

( ) 02

4

222

2

2

2

=+

+−+=

+=

+=←=

LTh

LThLThLThTh

L

L

LTh

LThL

LTh

ThLLLL

RRRRRVRRV

dRdP

RRRV

P

RRV

iRIP

Th

ThLThL R

VPRR

4max ==pp. 92-93

Page 21: Dr. Kasra Etemadi

Superposition Principle

+-

15V 2A

10

5

IT

+-

VT

VV 5)15(105

51 =

+=

VRIV

R

eqs

eq

66.633.32

33.35/110/1

1

2 =×=×=

Ω=+

=

Voltage divider

VVVVT 66.1166.6521 =+=+=

VT=?

+-

15V

10

5

I1

2A

10

5

V1V2+

-

+-

I2

pp. 95-98

(dependent sources are linear)

Page 22: Dr. Kasra Etemadi

+

-Vs

R1

R3Rx Unknown Resistor

R2I1I2

I3

I4

Iga b

Wheatstone Bridge

Adjustable

resistor

Detector

It is used to accurately measure unknown resistances.

pp. 98-100

Page 23: Dr. Kasra Etemadi

+

-

Vs

R1

R3Rx

R2I1I2

I3

I4

Iga b

Detector

42

31

II

II

==

433

2211

IRVIR

IRVIR

xab

ab

=+=+

KCL

KVL

433

2211

IRIR

IRIR

x==

21

3

RR

RR x=

Wheatstone Bridge

0=abV

Page 24: Dr. Kasra Etemadi

+-

R1

vs1

R2Kix

is2

ix

vT

221

1sx

TsT iKiRv

Rvv =++− 2R

vi T

x =

2121

211

121

2ssT i

KRRRRR

vKRRR

Rv

+++

++=

1121

21 sv

KRRRR

v++

=

2121

212 siKRRR

RRv

++=

21 vvvT +=