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DESIGN OF A MODERN HIGH-RISE BUILDING
IN ABU-DHABI
United Arab Emirates University
Faculty of Engineering
Department of Civil and Environmental Engineering
Graduation Project II
Fall 2010
Thursday 13 January 2010
Student Name ID Number
Abdulrahman Abdulla Alili 200409918
Mohammed Amer Al-Ameri 200416269
Wadah Abdulla Ahmed 200540613
Amr Ezzat Abdel-Havez 200540677
Advisor : Dr. Aman Mwafy
Examination Committee:Dr. Hany Maximos (Faculty)Dr. Amr Sweedan (Dept.)Dr. Bilal El-Ariss (Dept.)
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ObjectivesThe Graduation Project is divided into two main phases, namelyGPI and GPII. The three-dimensional (3D) analytical modeling ofthe 60-story building, load calculations and verifications of theanalytical model were performed in GPI. Tasks and results of this
phase are briefly presented in this report.
The second phase of the project focus on designing differentstructural members of the high-rise building such as floor slabs,
beams, columns, shear walls and foundations using latest analysissoftware and modern design codes.
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Original Building
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Building After Modifications
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Summary of GPI
Geometric and Load Modeling
Structural elements modeling (beams, slabs etc..)
Load modeling
Hand Calculations
Actions and deformations
Preliminary Cost Estimate
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Summary of GPI
0
5000
10000
15000
20000
25000
30000
EarthquakeLoadWind Load E-W
Hand Calculation ETABS Results
0
200000
400000
600000
800000
1000000
1200000
Dead Load
Live Load
Hand ETABS Results
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GPII TasksVerified three dimensional analytical model of a typical 60-story building,
representing the modern tall buildings in the UAE.
Design different structural elements, including the complete design of suitable
floor slab systems, such as solid slabs and flat slabs, at different story levels of
the high-rise building using the SAFE and PROKON programs.
Optimized design of shear walls using the latest version of the ETABS program
with different load combinations and different cross section sizes and
reinforcement ratios to arrive at the most cost-effective design.
Design of columns and different types of beams.
Design of stairs and the piles foundation system.
Final Cost Estimates.
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Design of slab systems
Flat Slab
Hollow Block Slab Solid Slab
Diaphragms and slabs can be defined as a structural system that resist, collect and
distribute the lateral forces, either earthquake or wind, in the horizontal planes of a structure
then transmit them to the vertical bearing elements (shear walls, frames) then to the
foundation and the ground.
In GPII we have designed three types of slab systems
1- Flat Slab
2- Hollow Block Slab
3- Solid Slab
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Design of Hollow Block slabs
Design as a T-Section
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Hollow Block slabs Different alternatives of the slab dimensions are considered. We started with a depth equals to 250 mm, which led to a deflection that
exceeds the
maximum allowed value.
To overcome this issue, we increased the depth of the slab to 350 mm by having
two
layers of blocks each has 150 mm height, which produced safe deflection
Increasing the width of ribs
Increasing the depth & number of blocks
Increasing of the reinforcement
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Solid Slabs
Wu=1.2W D+ 1.6W L == 16.98 kN/m 2
Mu = 13.262 kN.m/m
Rn=[Mu/ ( = 2.62 = 0.0065
As= bd= 487.5 mm 2 use 7 bars #10
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Flat slabsExporting three slabs:
The following three slabs are exported from ETABS to SAFE:
Ground story slab.
17th story slab.
37th story slab.
Two critical load combinations are selected to extract results from SAFE,
1.4 SDL+1.4 O.W+ L.L+ 1.4 EQX) a
1.4 SDL+1.4 O.W+ L.L+ 1.4 EQY).
The design process of flat slabs is started by
determining the most optimum thickness of the slab.
The optimum thickness can be determined byselecting the slab thickness and verifying thedeflection
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Slab Optimum thicknessL < L/360
L + add < L/360add = * D
= / 1+ 50 ` = As`/ bd
Safe Unsafe
Increase the t s
and check
Ground story slab thickness equals to 200mm:
L/360 = 22.2 mm
L/240 = 33.33 mm
d = 200 25 = 175 mm
` = As`/ bd = 0.003686
= / 1+ 50 ` = 1.6887
where = 2
L < L/360 5.22 < 22.22 O.K
D = 13.5 + 13 = 26.5
add =
* D
= 44.71
L+ add < L/360 49.93 > 33.33
unsafe, we have to increase the thickness .
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Design of flat slabs
Strip # Direction Strip width (m) Strip type
S1 x X direction 1 Column strip
S2 y Y direction 4 Middle strip
S3 y Y direction 4 Middle strip
Three strips are defined for each slab, two middle strips and one columnstrip, as shown below.
The defined strips are used to calculate the maximum bending moment, asshown in Figures
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Design of flat slabsExample :Ground story
After extracting the maximum positive and negative moment, each is divided by the stripwidth to get the bending moment per unit length and calculate the correspondingreinforcement
Strip No. +M -M +M/width -M/widthS1x 123.3 240.9 123.3 240.9
S2y 229.13 600.3 57.28 150.1
S3y 298.78 196.9 74.695 49.2
Strip No. +M/width As = bd Mesh top & bot.
S1x 123.3 0.00457 1188.2 6 16
Strip No. -M/width As = bd Amesh As - Amesh Additional Reinf.
S1x 240.9 2410 1188.2 1221.8 6 16
S2y 150.1 1457.64 1188.2 269.44 4 12
S3y 49.2 463.46 1188.2 ---- ----
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Strip No. -M/width As = bd Amesh
As -
Amesh Additional Reinf.
S1x 240.9 2410 1188.2 1221.8 6 16
S2y 150.1 1457.64 1188.2 269.44 4 12S3y 49.2 463.46 1188.2 ---- ----
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Check of Punching Shear
12
')2(
fc
b
d o
s bod
3
' fc bod
6
')
21(
fcc
bodVc1 =
Vc2 =
Vc3 =
Vu = V
c + V
s
Element Vc (KN) f Vc (KN) Vu (KN) fVu (KN) Decision
Col-1 595.9 446 161.88 242.82 Safe
Col-2 1115.94 836.96 275.08 357.6 Safe
Col-3 2147.66 1610.745 151.8 197.34 Safe
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Best Alternative
FlatSlabs
HollowBlockSlabs
DecisionBased
on
Efficiency/Construction
Cost
0.00
10.00
20.00
30.00
40.00
50.00
60.00
Floor slabs cost Hollow block slab
C o s t
i n M i l l i o n s
A E D
- The choice of the slab system for the 60-
stor building is based on the cost and
performance- The hollow block slab system is more
expensive than flat slabs. Moreover, flat
slabs are much easier in construction, and
therefore the flat slabs are selected.
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Stairs
Wu = 16.08kN/m 2 Wu X 0.3 load of each stair = 16.08 X 0.3 = 4.824 kN/m(M max)= (W u x L 2)/2= (4.824 x 1.45 2) /2 = 5.07 kN .m.STEP 1 : Determine steel ratio ( )
R n = [Mu/ (= (5.07*10 6)/ (0.9*300*(195) 2) = 0.49 = ( 1- ) = 0.00117min = 0.003521
STEP 2: Determine A s
As= bd = 0.003521*300*195= 206 mm 2
[ use 3 bars#10 ]Stairs
Design of stairs using hand calculations
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Stairs
Reinforcement details of stairs
3#10 /step
3#10 /step
Reinforcement distribution
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Beams Design of hidden beam Design of edge beam Design of connecting beam
B1
Connecting beams
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Beams
Bending moment diagram of the hidden beam
Beam deflection
Design of hidden beam using Prokon
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Beams Slab Load:Dead load from slab = 48.03 kN/mLive load from slab = 8.5 kN/m
Beam own weight
h b= 620 mmO.W Beam = b w h b c = ((0.25 0.24) + (0.81 0.38)) (25) = 9.195 kN/m)
Wall own weight
O.W wall = b w hw = 0.25 2.88 10 = 7.2 (KN/m)Effective Length
bw + 6 t= 0.25+ (6 0.38)=2.53 Effective width (b E)= Smaller of bw + L / 12 = 0.25 +(6.7/12)=0.81m
bw + b0= 0.25+ 4= 4.25 m
Then, Effective length (b E)= 0.81 m = 810 mm
Edge beam cross section
Design of edge beam using hand calculations
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Beams
Long-term deflection
Moment x-x
Design of edge beam using Prokon
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Reinforcement distribution
Beams Reinforcement distribution
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Beams
Input data in prokon
Design of connecting beams using ETABs & Prokon
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BeamsLevel Beams No. Flange Width Bending Moment Shear Force
groundstory levels
B1_1 750mmM=1270.42 KN.m V=865.2 (KN)
Reinforcement 8 T 25 4 T 8@ 120 mm
B1_2 625mm M=1660.9 KN.m V= 1047.6 (KN)
Reinforcement10 T 25 4 T 10 @ 150 mm
B1_3 625mm
M=1537.34 KN.m V= 1072.71 (KN)Reinforcement 9 T 25 4 T 10@ 120 mm
17 th storylevels
B2_1 750mm M=763.82 KN.m V= 620.4 (KN)Reinforcement 5 T 25 4 T 8@ 150 mm
B2_2 625mm M=895.1 KN.m V= 716.71 (KN)Reinforcement 6 T 25 4 T 8@ 120 mm
B2_3 625mm M=767.92 KN.m V= 619.9 (KN)Reinforcement 5 T 25 4 T 8@ 150 mm
36 th storylevels
B3_1 750mm M=760.1 KN.m V= 630.37 (KN)Reinforcement 5 T 25 4 T 8@ 150 mm
B3_2 625mm M=820.9 KN.m V= 637.1 (KN)Reinforcement 5 T 25 4 T 8@ 150 mm
B3_3 625mm M=679.5 KN.m V= 564.4 (KN)Reinforcement 4 T 25 4 T 8@ 200 mm
Data outcome form Prokon & ETABS
Design of connecting beams using ETABs & Prokon
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Shear Walls Design shear walls using ETABs
Selected shear walls
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Shear Walls
o Define pier section.o Pier section data.o Section designer.o Assign pier section.
o Assign general Reinforcing pier section.o Start design of section.
Design process
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Shear Walls
The D/C ratio indicates the demand over capacity: D/C Ratio less than 1 section is safe in flexure D/C Ratio greater than 1 Section is unsafe
General reinforcing Pier Section
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Shear Walls
As(min) = (0.25/100) Ag Optimization
Level Wall Reinforcement
Layout (1,2 and3)
P3S mm167@12#6P2SS mm167@12#6P1SS mm167@12#6P4S mm167@12#6P5 mm167@12#6
P6 mm200@12#5P7 mm167@16#6
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Columns
Columns name Col(1-20) Col(2-20) Col(2-40)
No. of columns 8 4 4
Columns dimension (1000x300) (1500x400) (1500x300)
Design columns using ETABs
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Columns
If columns un-safe:
Check safety of columns
Increase columnsdimension
Increase concretestrength
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Design of FoundationUsing Safe program 709 piles have been distributed
among the raft area.
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Foundation Results
Point loads representation due to applied loads.
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Foundation Results
Deformed shape.
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Foundation ResultsStrip # 1 in X-direction Strip # 2 in Y-direction Strip # 3 in Y-direction
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Foundation Reinforcement
Reinforcement detailing for the raft foundation
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Cost Estimate
Shear WallsShear walls (cost) = thickness length height number of stories cost of one m3
Floor slabFlat slab (cost) =thickness net area cost of one m3 number of stories
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Stairs
Stairs (cost) = Area Stairs thickness Factor (1.2) number of stories cost of onem3
= [(3 m 7 m) 0.23 m 1.2 60 stories 2500 (Dhs/ m3)] 2= 1,738,800 AED
Cost Estimate
ExcavationExcavations (cost) = Depth Area Raft cost of one m3= 11 m 1750.2 m2 50 (Dhs/m3) = 962,610 AED
Plain ConcreteConcrete Plan(cost)= Area Raft Thickness Cost of one m3= (1750.2) m2 0.4 m 700 (Dhs/ m3)= 490,056 AED Raft Foundation
Raft foundation(cost)= Area Raft Thickness Cost of one m3= (1750.2) m2 3.2 m 2200 (Dhs/m3) = 12,321,408AED Pile Foundation
Piles foundation (cost)= Number of piles length of pile Cost of one meter= 709 piles 25 m 2800 (Dhs/m) = 49,630,000 AED
Foundations
170,969,819AED
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Cost Estimate
010203040506070
C o s
t i n
M i l l i o n
( A E D )
Final cost estimate of structural system
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Project Management
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Outcomes and Deliverable
Verified three dimensional analytical model for a typical60-story building, representing the modern tall buildings inDubai and Abu Dhabi.
Design different structural elements and establish fulldesign of suitable floor slab systems, such as solid slabs andflat slabs, at different story levels of the high-rise buildingusing SAFE and PROKON programs.
Design of columns and different types of beams such asconventional.
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Conclusion
The analytical model and modern design provisionshave been employed in the second phase of the project(GPII) to fully design different structural members of the
60-story high-rise building.
Work in a group and write technical reports.