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Page 1: Day 40 Ppt Batfink Momentum
Page 2: Day 40 Ppt Batfink Momentum

#1 All students must perform all of the work of the activity in their science journals even though you are working in your lab group.

#2 When you are sure of your answer, transfer the information onto individual mini whiteboards.

#3 The whiteboard work is to remain on the white board until it is approved.

Page 3: Day 40 Ppt Batfink Momentum

The mad scientist, Hugo A-go-go has developed a way to disrupt the electrical service to Chicago.

The mass of the Eastbound (traveling to your right) CTA is 40,000 kg while the mass of the Westbound CTA is 30,000kg.

The Eastbound transit is traveling at 20 m/s and the Westbound transit is traveling at 25 m/s.

There are two separate, stationary cars also on the same track. They are 10,000 kg each.

Page 4: Day 40 Ppt Batfink Momentum

What is the eastbound train’s momentum?

Page 5: Day 40 Ppt Batfink Momentum

P = mvKnown Want

m = 40,000 kg P (momentum)v = 20 m/s

P = mvP = (40,000 kg )(20 m/s) P = 800,000 (kg)( m/s)

Page 6: Day 40 Ppt Batfink Momentum

Draw a momentum vector diagram of the eastbound train.

Page 7: Day 40 Ppt Batfink Momentum

N y

W E

S

x

800,000 (kg)( m/s)

Page 8: Day 40 Ppt Batfink Momentum

What is the westbound train’s momentum?

Page 9: Day 40 Ppt Batfink Momentum

P = mvKnown Want

m = 30,000 kg P (momentum)v = 25 m/s

P = mvP = (30,000 kg )(25 m/s) P = 750,000 (kg)( m/s)

Page 10: Day 40 Ppt Batfink Momentum

Draw a momentum vector diagram of the westbound train.

Page 11: Day 40 Ppt Batfink Momentum

y

x

750,000 (kg)( m/s)

Page 12: Day 40 Ppt Batfink Momentum

What is the momentum of each of the stationary transits?

Page 13: Day 40 Ppt Batfink Momentum

P = mvKnown Want

m = 10,000 kg P (momentum)

v = 0 m/s

P = mv

P = (10,000 kg )(0 m/s)

P = 0 (kg)( m/s)

Page 14: Day 40 Ppt Batfink Momentum

The Eastbound train collides with one of the stationary transits. Draw a momentum vector diagram that represents the above scenario just before the collision.

Page 15: Day 40 Ppt Batfink Momentum

y

x

800,000 (kg)( m/s)

Page 16: Day 40 Ppt Batfink Momentum

The Eastbound train collides with one of the stationary transits. Draw a momentum vector diagram that represents the above scenario just after the collision.

Page 17: Day 40 Ppt Batfink Momentum

y

800,000 (kg)( m/s) x

Page 18: Day 40 Ppt Batfink Momentum

The Eastbound train collides with one of the stationary transits. Sticking together, they continue to roll along the track. What is their velocity after the collision?

Page 19: Day 40 Ppt Batfink Momentum

Net Momentum before = Net Momentum after

Known Wantme = 40,000 kg P beforeve = 20 m/s v afterms = 10,000 kgvs = 0 m/s

Pnet = (mv)net

P = me ve + ms vs

P = (40,000 kg )(20 m/s) + (10,000 kg )(0 m/s) P = 800,000 (kg)( m/s)

v = P/mv = 800,000 (kg)( m/s) / (40,000 kg ) + (10,000 kg )v = 16 m/s E

Page 20: Day 40 Ppt Batfink Momentum

The Westbound train collides with one of the stationary transits. Sticking together, they continue to roll along the track. What is their velocity after the collision?

Page 21: Day 40 Ppt Batfink Momentum

Net Momentum before = Net Momentum after

Known Want

mw = 30,000 kg P beforevw = 25m/s v afterms = 10,000 kgvs = 0 m/s

Pnet = (mv)net

P = mw vw + ms vs

P = (30,000 kg )(25 m/s) + (10,000 kg )(0 m/s) P = 750,000 (kg)( m/s)

v = P/m

v = 750,000 (kg)( m/s) / (30,000 kg ) + (10,000 kg )v = 18.75 m/s W

Page 22: Day 40 Ppt Batfink Momentum

The Westbound train, after the initial impact with the stationary transit collides with the Eastbound train also after its initial impact with one of the stationary transits. Calculate the velocity after the crash between the two trains if they stuck together.

Page 23: Day 40 Ppt Batfink Momentum

Net Momentum before = Net Momentum after

Known WantPw = 750,000 (kg)( m/s) Pnet beforePe = -800,000 (kg)( m/s) v after

Pnet = Pe - Pw

Pnet = 800,000 (kg)( m/s) - 750,000 (kg)( m/s) Pnet = 50,000 (kg)( m/s) v = P/mv = 50,000 (kg)( m/s) / (40,000 kg ) + (50,000 kg )v = .56 m/s E

Page 24: Day 40 Ppt Batfink Momentum

The Battalac, which has a mass of 1500 kg is occupied by batfink, 50 kg, and Karate, 150kg and is traveling at 50 m/s when it is forced off the road and down a 50 meter embankment.

Page 25: Day 40 Ppt Batfink Momentum

Calculate the vertical velocity of the Battalacjust before it strikes the ground.

Page 26: Day 40 Ppt Batfink Momentum

Known Want

mB = 1,500 kg v

vohB = 50 m/s

mb = 50 kg

mk = 150 kg

vf2 = vo

2 + 2a∆y

vf2 = 0 m/s + 2(9.8 m/s2)(50m)

v = 31.3 m/s

Page 27: Day 40 Ppt Batfink Momentum

Calculate the magnitude of the velocity of the Battalac at impact with the ground.

Page 28: Day 40 Ppt Batfink Momentum

y

50 m/s

31.3 m/s x

a2 + b2 = c2

502 + 31.32 = 58.99 m/s

or

TAN -1= 31.3/50

= 32.05*

Vf = Vx/COS 32.05*

= 58.99 m/s

or

Vf = Vy/SIN 32.05*

= 58.98 m/s

Page 29: Day 40 Ppt Batfink Momentum

Calculate the momentum of the Battalac at the moment of first impact with the ground.

Page 30: Day 40 Ppt Batfink Momentum

Known Want

mB = 1,500 kg P

vfB = 58.99 m/s

mb = 50 kg

mk = 150 kg

P = mv

P = (1700 kg)(58.99 m/s)

P = 100,283 (kg)(m/s)

Page 31: Day 40 Ppt Batfink Momentum