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Day 36 Ppt Batfink Angle Launched Projectile Motion

Jul 21, 2015

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Page 1: Day 36 Ppt Batfink Angle Launched Projectile Motion
Page 2: Day 36 Ppt Batfink Angle Launched Projectile Motion

#1 All students must perform all of the work of the activity in their science journals even though you are working in your lab group.

#2 When you are sure of your answer, transfer the information onto a large whiteboard.

#3 The whiteboard work is to remain on the white board until it is approved.

Page 3: Day 36 Ppt Batfink Angle Launched Projectile Motion

Ebenezer the Freezer and Hugo A-Go-Go strap Batfink to a rocket.

Batfink emits a “BEEP” from his supersonic sonar radar that calculates the displacement the rocket will have at impact with the ground.

The rocket is launched at an angle of 30* to the horizontal and fortunately the rocket is faulty and only has a velocity of 39.2 m/s.

Page 4: Day 36 Ppt Batfink Angle Launched Projectile Motion

Draw a Motion Map for the rocket’s motion.

Page 5: Day 36 Ppt Batfink Angle Launched Projectile Motion
Page 6: Day 36 Ppt Batfink Angle Launched Projectile Motion

Resolve the initial velocity into two vector components, one moving the rocket horizontally and one vertically.

Show all of your work.

Page 7: Day 36 Ppt Batfink Angle Launched Projectile Motion

y

33.95 m/s = (Vx ) 19.6 m/s

30* x

SOH CAH TOA 33.95 m/s

SIN 30* = Vy/V

(39.2 m/s)(0.5) = (Vy )

19.6 m/s = (Vy )

SOH CAH TOACOS 30* = Vx/V (39.2 m/s)(0.866) = (Vx )

Page 8: Day 36 Ppt Batfink Angle Launched Projectile Motion

Calculate the time the rocket will spend in the air.

Page 9: Day 36 Ppt Batfink Angle Launched Projectile Motion

Know Want

Yf = 0 m t

Yo = 0 m

Vo = 19.6 m/s

a = -9.8 m/s2

General Formula Yf = Yo + Vot + ½ at2

0 = 0 + (19.6 m/s)(t) + ½ (-9.8 m/s2 )(t2)

(19.6 m/s)/-4.9 m/s2 = t

4 s = t

Page 10: Day 36 Ppt Batfink Angle Launched Projectile Motion

Calculate the “Xf” distance and the “∆Y” distance that the projectile will travel.

Page 11: Day 36 Ppt Batfink Angle Launched Projectile Motion

Horizontal Distance

X = Vx(t)

X = (33.9 m/s)(4 s)

X = 136 m

Vertical Distance

Y = Vy(t) + ½ gt2

Y = (19.6 m/s)(2s) – ½ (-9.8 m/s2)(2s2)

Y = 19.8 m

Page 12: Day 36 Ppt Batfink Angle Launched Projectile Motion

Construct and complete a Data Table with the first column being time (s), the second column distance (x) and the third distance (y).

Page 13: Day 36 Ppt Batfink Angle Launched Projectile Motion

Time (s) X (m) Y (m)

0.00 0.00 0.00

1.00 33.95 14.7

2.00 67.9 19.6

3.00 101.85 14.7

4.00 135.8 0.00

Page 14: Day 36 Ppt Batfink Angle Launched Projectile Motion

Graph the path of the projectile, distance “Y” over distance “X”.

Page 15: Day 36 Ppt Batfink Angle Launched Projectile Motion

Dis

tan

ce Y

(m

)

Distance X (m)

19.6

14.7

33.9 67.8 102 135.8

Page 16: Day 36 Ppt Batfink Angle Launched Projectile Motion