Name: David, Rodel C. Topic: Acoustics Question: What is the sound pressure level (SPL) of a sound having an RMS pressure of 200 N/m 2 ? Choices: A. 150 dB C. 170 dB B. 140 dB D. 160 dB Solution: SPL=20 log P Po =20log 200 N/ m 2 2 x 10 −5 N/ m 2 SPL=140 dB
This document is posted to help you gain knowledge. Please leave a comment to let me know what you think about it! Share it to your friends and learn new things together.
Transcript
Name: David, Rodel C. Topic: Acoustics
Question: What is the sound pressure level (SPL) of a sound having an RMS pressure of 200 N/m2 ?
Question A measure of how well the receiver can respond to every weak signals.
Choices: A. Selectivity C. Fidelity
B. Sensitivity D. Quality factor
Background:
Selectivity is the ability to separate the wanted signal from nearby unwanted signals (other stations). Sensitivity defines the limit of detection of weak signals. Fidelity is the ability of the receiver to reproduce the original signal. Quality factor is the ratio of the resonant frequency/center frequency to the bandwidth of a certain frequency response of a filter.
Question: A church has an internal volume of 90050 ft3 (2550 m3). When it contains 2,000 customary sabines of absorption (186 metric sabines), what will be its reverberation time ine seconds?
Question: A certain machine with a slightly out-of-balance motor rotating at 1800/min is fixed on a perfectly elastic mount with a static compression of 2.50 mm. Calculate the resonant frequency of mount.
Question: From the low-frequency end of a channel, what is the visual carrier frequency?
Choices: A. 3.58 MHz C. 1.25 MHz
B. 0.25 MHz D. 4.5 MHz
Background:
The visual carrier frequency of a TV channel is usually 1.25 MHz above the low-frequency end of it. The sound carrier is 4.5 MHz above the visual carrier. The Chrominance carrier frequency is 3.58 MHz above the visual carrier. The 0.25 MHz is the location of the sound carrier below the high-frequency end of a channel.
Question: All airtime classifications shall be submitted to and subject for approval by the
Choices: A. NTC C. DOTC
B. KBP – SA D. CCITT
Background:
NTC – responsible for the supervision, adjudication and control over all telecommunications services throughout the country.
DOTC – responsible for the maintenance and expansion of viable, efficient, and dependable transportation and communications systems as effective instruments for national recovery and economic progress.
CCITT – is the primary international body for fostering cooperative standards for telecommunications equipment and systems
KBP-SA – provides broadcast media regulations and guidelines for news, public affairs and commentaries, political broadcasts, children’s shows, religious programming, and including advertising to its members.
Question: The allowable deviation ratio of commercial FM broadcast.
Choices: A. 15 C. 25
B. 5 D. 75
Solution:
Deviation Ratio is defined as:
𝐷𝑅 = 𝛿𝑚𝑎𝑥 (max) For commercial FM broadcast (FCC Standards),
𝛿𝑚𝑎𝑥 = 75 𝑘𝐻𝑧 (Maximum Frequency Deviation)
(max) = 15 𝑘𝐻𝑧 (Maximum Audio Frequency Bandwidth)
Such that,
DR= δmaxf m(max )
=75kHz15kHz
=5
Reference: Self-Sufficient Guide to Electronics Communications Engineering; Ampoloquio, J.M., p.2-86
Answer. B
Name: David, Rodel C. Topic: Television
Question: Numerical frequency band designation of Channel 9.
Choices: A. 488 – 494 MHz C. 632 – 638 MHz
B. 530 – 536 MHz D. 186 – 192 MHz
Background:
488 – 494 MHz is for channel 17
530 – 536 MHz is for channel 24
632 – 638 MHz is for channel 41
186 – 192 MHz is for channel 9
Reference: Self-Sufficient Guide to Electronics Communications Engineering; Ampoloquio, J.M., p.2-86
Answer. D
Name: David, Rodel C. Topic: Broadcasting
Question: Part of broadcast day from midnight to local sunrise.
Choices: A. Daytime C. Nighttime
B. Experimental D. Dawntime
Background:
Based on the broadcasting standards, experimental spans from midnight to local sunrise. For the daytime, itspansfrom 5 AM to 6 PM of local time. For the nighttime, itspansfrom 6 PM to 5 AM of local time. The term downtime cannot be found in broadcasting standards hence, it is not an answer.
Question: Calculate the lowest resonant frequency for a brick partition 120mm thick, 4m by 2m in area with longitudinal wave velocity of 2350 m/s. (Assume that it is supported at its edge)
Question: What is the reverberation time of a room whose surface area is 75 m 2, whose volume is 42 m3, and whose average absorption coefficient is 0.9, 0.2?
Solution:
for α=0.9
RT60=0.07V
−S log(1−α)=
0.07 (42)−(75) log (1−0.9)
=0 .0392 s
39.2ms is very small value of reverberation time for a typical room.
for a=0.2
RT60=0.07V
−S log(1−α)=
0.07(42)−(75) log (1−0.2)
=0 .4045 s
404.5ms is in the range of typical reverberation time for typical room.
Radiance – is the radiant flux emitted, reflected, transmitter or received by a surface per unit solid angle per unit projected
Chrominance – is the signal used in video systems to convey the color information of the picture, separately from the accompanying luma signal (or Y for short).
Reflectance – the measure of the proportion of light or other radiation striking a surface that is reflected off it.
Luminance – is a photometric measure of the luminous intensity per unit area of light travelling in a given direction. It describe the amount of light that passes through, is emitted or reflected from a particular area, and falls within a given solid.
Question: A third symbol radio emission represents telephone transmission including sound broadcasting.
Choices: A. W C. C
B. F D. E
Background:
For the third symbol for radio emission, we have F is for television (video), C for facsimile, E for telephony (including sound broadcasting), and W for combinations of signals.