CSC PATTERN

Latest  CSC Fresher Job Interview Paper Pattern: 10-Feb-2011

Company Name : Computer Sciences CorporationType : FresherJob Interview, Question Paper  

Hi Friend'sI appeared in the placement procedure of the company and faced all the rounds namely.

 Aptitude Test (Written) Technical Test (Written Essay Writing (Written)  Communication Round Technical Interview HR Interview

Now all the rounds in details:

Aptitude:-

Simplification Time and distance (average speed logic)  Sudoku(3 by 3) Probability Permutation and combination English (Passage small one; fill in the blanks easy)

Technical Written:-

DBMS  C Language  Microprocessors Basics  Micro-controllers Basics  Operating Systems Basics DCS Basics  Number Conversions (Decimal, Binary, Octal, Hexadecimal)

Essay Writing:-You have to write an essay on one of the topics and nearly 5-6 topics are provided. Just to check whether you can write efficiently in English.

Communication Round:-Question: Tell Me Something About Yourself.Just to check whether you can speak fluently in English or not (simple one).

Technical Interview:-

DBMS (Keys, Views, Normalized forms  Communication Systems (AM, FM, PM Modulation  and their combinations)

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C Language (Basics) 

 HR Round: If you clear the Technical Interview you have done 99% job. In HR they just ask about your family background, any issue for shift changing Relocation. That's an easy one.

Best of Luck

Exam/Interview Date : 10-Feb-2011No of Rounds : Aptitude Test, Technical Round, GD, Location: DelhiContributor Name : Parag Goswami

Company Name : CSC (Computer  Sciences Corporation)Type : Fresher, Job Interview, Question Paper.

Hi FriendsI am Balaji from siddharth Institute of Engineering and Technology. I attended for CSC held at VIT , as we registered for VIT. CSC came on 28-01-2011.The placement started at 10am and they gave brief introduction about their company and benefits provided by them. At 11am they started the written exam.

  The procedure of CSC is as follows

Aptitude: (40 questions 40min)in half hour they will announce the short listed candidates for Technical writtenTechnical: (75 questions 40min) along with that we should write essay (10min)

Aptitude paper is damn easy to attempt because they will give basic questions anybody can attempt but some of the questions will very tough to attmept You people start the paper from 26-40 you can complete it in 10-15min In 1-25 questions max 10 questions can be easy and find the easy questions and attempt it first and then you may have 4-5 minutes left see the questions and make a guess on it you can easily score 30 marks...questions may be

1.3*3 Sudoku (5 questions damn easy)

2.if A(0,y)=y+1A(x,0)=xA (x,y)=A(0,A(0,y))A(0,0)=1they find A(0,3), A(1,2) you will have 5 questions which can attended damn easy

3.One geometry question they will one diagram and distance covered from A to B like that questions will be given and find the distance like questions

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you will get 2 questions some what tuff to find

4. total 75 students will be der, 25 know typing and 45 know short hand and 10 know neither typing and shorthand. find how many know both typing and shorthand

5. synonym-1,

6. 4 options will be given and will be ask to arrange the sentence.

7. one fill up with suitable word

8. 1 question from probability and 1 question from permutationthere will be two Childs for a mother. select randomly and find probability that both are girls....not sure...some what change will be der In permutation they will be 11 men and 3 women.. a committee of should be formed such that there will be 2 men and 2 women....

9. 1.6(10pow9) divide by 4.8(10pow3)Ans:30(10pow5)

 These are the questions in remember first 8 questions may be some what tough but can be answered start from the last you can easily answered the questions coming to Technical written As you already come to know that previous questions will be given....it is truth...definitely you will be given the same questions without changing the question number and options Refer the previous questions posted in the Fresher world and check the answer once searching in the goggle. you can attempt more than 65 questions. there ends the exam they will announce the short listed candidates for the next round with in half or one hour Nearly 500 students attended among them 288 cleared the aptitude  among 288 members 190 cleared the technical written These numbers will rise your anxiety that how many people had selected finally let me explain it and the next day we prepared well and went to the VIT campus and the panel members came and announced the batches per batch 10 members will be der mine was 5th batch for each batch, they will give you a topic and should be talked for 1 min just like Jam session The HR people will be cool There will be two persons one men and one women while the jam starts one will listen to your words and the other will correct your essay  we are all in the seminar hall and the panel people came and announced the names of 9 we thought that they are promoted to the next round we all shock that she told them that you can leave for day every body stranded and can't understand what is going on finally we came to know that  they need only few people in the replacements talk they had given a number that, they will recruit in the 1:30 ratio that mean for 30 people only one will be selected all the people attended the jam section they disqualified entire batches...and they selected few members. Here ends my journey I also disqualified from my college 2 members are short listed for the Technical Interview.I am happy to tell that, he is my batch mate in the project. I came to know that from him....they will check our confidence level.asked him to write the program for prime number while he is writing he asked him to come...just they will test our confidence. then he said you are promoted to the next round take the break and come again and for the interview. If you complete the communication round( JAM) 75% you are selected...

Mainly you should be aware of the project if any done.HR round will be the cake walk, just it is for the formality.

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Now total number of students attend is 500(approx)

Aptitude-288

Written-190

Finally selected - 10

It will be shock to every bodyAl The Best.

Exam/Interview Date : 28-Jan-2011No of Rounds : Aptitude Test, Technical Round.Contributor Name: E Balaj

Directions (Q. 1-5): In these questions @, #,$, ,% are used with different meanings

as follows:

'P@Q' means 'P is not greater than Q'.

'P#Q' means 'P is neither greater than nor smaller than Q'.

'P$Q' means 'P is not smaller than Q'.

'PQ' means 'P is neither smaller than nor equal to Q'.

'P%Q' means 'P is neither greater than nor equal to Q'.

In each of the following questions assuming the given statements to be true, find out which of the two conclusions I and II given below them is/are definitely true.

Give answer 1): if only conclusion I is true.

Give answer 2): if only conclusion II is true.

Give answer 3): if either conclusion I or conclusion II is true.

Give answer 4): if neither conclusion I nor conclusion II is true.

Give answer 5): if both conclusion I and II are true.

6. Statements: F$W,W#T,TK

Conclusions: I. FK

II. W$K

7. Statements: R@M,M%D,D$H

Conclusions: I. R@H

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II. DR

8. Statements: J$L,L#B,B@E

Conclusions: I. E$L

II. E%L

9. Statements: A$V,V#R,R@U

Conclusions: I. UR

II. U#R

10. Statements: F%G,G@H,HJ

Conclusions: I. F@H

II. G@J

Directions (Q.11-15): In each question below is given a statement followed by two assumptions numbered I and II. An assumption is something supposed or taken for granted. You have to consider the statement and the following assumptions and decide which of the assumptions is implicit in the statement.

Give answer 1): if only assumption I is implicit.

Give answer 2): if only assumption II is implicit.

Give answer 3): if either assumption I or assumption II is implicit.

Give answer 4): if neither assumption I nor assumption II is implicit.

Give answer 5): if both the assumptions I and II are implicit.

11. Statement: ?Enroll with us before 30th November to get the advantage of our 20% discount offer?. -An advertisement by a coaching class

Assumptions:

I. Discount offer is bound to attract good students as well.

II. Even those students who cannot afford to pay the fees of coaching classes may join this class.

12. Statement: ?Join our Yoga institute to keep yourself completely fit.?----An advertisement

Assumptions:

I. People may prefer exercise to medication.

II. There is an awareness to a great extent about Yoga exercises among people.

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13. Statement: If you want to get a good job you must have at least the basic knowledge of computers.

Assumption:

I. All good jobs involve use of computers.

II. Computer knowledge has been made an essential criterion by most of the companies nowadays.

14. Statement: As a measure to avoid occurrence of the epidemics due to monsoon the civic authorities have organized free vaccination camps all over the city.

Assumptions:

I. There may be a good response to the camps organized by civic authorities.

II. people are generally aware about the need for vaccination.

15. Statements: In view of the large number of cases of suicides committed by the farmers in State X the State Government has decided to waive off the agriculture loans granted to the farmers.

Assumptions:

I. This may stop further cases of suicides committed by the farmers in State X.

II. This move of the Government may be welcomed by the public at large.

Answers

1. (4)2. (2)3. (2)4. (5)5. (5)6. (5)7. (2)8. (4)9. (5)10. (4)11. (2)12. (5)13. (3)14. (5)15. (5)

NETWORKS1) whn u open web browser, thn wht will happen wht do u do first thing?2) wht u write first thing, i said DNS or webaddress concept thtn he asked complete web adress like i told thn he asked meaning of each word-http,www,com etc3) wht is URL

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4) tel complete procedure how a site open after opening explorer5) other layers understand DNS or not if not thn wht will happen (concept of mapping to ip adress comes here) thy asked how mapping takes place and at wich layer6) dns procedure use wht tcp/ip or osi7) how many layers in tcp/ip and wich layers are extra in osi model8) tcp/ip conection oriented or conectionless9) wht is DNs he was trying to ask in detail but as i havnot read so i said tht10) wht is arp11) wht is rarp12) wht is ATM(asynchronous mode transfer)

DBMS1) wht is primary key2) if ther is no primary key how will u uniquely identify each tuple (i said composite key or super key)3) diff between tuple and attribute4) wht r anomalies explain each in detail (like insertion anomaly deletion and modification anomaly)5) wht is foreign key constraint6) if i want to delete a tuple from a table having reference in so other table thn wht will happen (concept of cascade comes else error)7) wht r triggers explain8) if i want to hav som tuples havind null value wht to do (outer join)9) wht if i join two tables and no primary key (spurious tuples generate redundant data)10) diff betweenoracle 9i and oracle 811) diff between dbms, rdbms, ordbms 

OS1) wht is os2) wht is a process3) diff between process and thread4) if threads share data section wht will happen (concept of semaphore and crtitcal section comes so )5) wht is semaphore6) wht other thing semaphore do except synchronisation7) wht else happen in threads and process so deadlock concept comes8) deadlocks, and i told abt 4 conditons of deadlocks also9) in os wher do u use stacks and queues (like stacks for saving process satate , on system call context switch etc and queue in scheduling so he asked do we hav only fifo scheduling)10) so types of scheduling

Data Structure

1) u hav fifteen boxes in kitchen and ur mom asked u to make foos for 1 month, wht will u do to make food fast (thn concept of sorting came) i said i will put name tag on boxes and thn sort thm in ascending order or i can put thm in order of color shade firstly lightest and thn little darker and soon but tht can create confusion so first is better way

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2)u hav 1000 names in unorder manner and i asked u to pick any name of my choice randomly and thn giv me complete info of tht person so wht ds will u usei said firstly i will sort thm thn i will use hashing/btrees as thy r faster in decreasing search domain, thy asked wich sort will u use i said radix as good for strings , he asked if one more name increase or decrease i said radix sort take linear time so doesnot affect much on time he said if names r vary in length like one is venkateshraman other is raj i said sort from 3rd last letter or use padding.3) wht is heapsort, concept . wher u can apply it4) wht all ds u know i said heaps binomial fiboncaai, liked list stacks queues trees arrays etc5) advantage and disadvantage of linked list and array over each other in temrs of memory allocation6) insert and delete a node in a linked list write a code(not from me) basically thy asked asll application based question on data structure

java/c/c++1) he write a java code of swapping to name via calling object as parameter and asked whther result will reflect in main or not (as object passed as a reference so reuslt will be reflected)2) in java we use call by reference or call by value3) wht r interfaces4) diff between interfaces and abstraction

Company : CSC

1. with framework CASE tools IPSE can be achieved .IPSE is

a.integrated product software engineering.

b.integrated productivity simulation environment

c.inner project software estimation

d.inntegreted project support environment

2. data structured system devolepment (DSDD) is also called one of the below which

is evolved from work on information domain analysis

a.j.d.methodology

b.yourdon methodology

c.warnier-or methodology

d.Kevin-yenn methodology

3.

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a. COCOMO estimation model is a single valued mode to compute software development

effort(and cost)as a function of program size expressed in estimated lines of codes.

b. PUTNAM model is single valued model assuming a specific distribution of effort over

life of software development project.

a. only a)is correct

b. only b)is correct

c.a ) and b)is correct

d.a)and b)is wrong

4. when in data coupling portion of a data structure(rather than simple argument)is

passed via a model interface it is called one of the below

a.control coupling

b.stamp coupling

c.sub-coupling

d.reference coupling

5. what is measure of reliability for a computer based system if MTBF=mean time

between failure.MTTF=mean time to failure.MTTR=mean time to recover

a.MTBF=MTTF/MTTR

B.MTBF=MTTF*MTTR

C.MTTR=MTTF*MTBF

D.MTBF=MTTF-MTTR(sign is not cleared)

6. in FURPS quality factors by HEWERT PACKAR 

a.functionality is accessed by evaluating o ne feature of program and capability of

algorithm only

b.supportability means breath of premna application and death of standards used

a.a)and b)both correct

b.a)correct b)wrong

c.b)correct a)wrong

d.a)and b) both wrong question is not cleared

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7. ur testing of basis paw message means software devolepme nt quatiative measure

of logical complexity program of independent path in search of program

a.data cycle complexity

b.path complexity metric

c.cyclomatic complexity

d.none of above (question is not cleared so try to understand it)

8.as a general rule

a.MIS performane criteria determine management information needs and these needs

determine

the objective of the firm

b.the objective of the firm determine the management information needs and these needs

determine the MIS performance criteria

c.management information needs determine the MIS performance criteria and these

criteria

determine the objective of form

d.the objectives of firm determine the MISpwrformance criteria and these criteria

detemine the

management information needs.

9.a relatively small project is to be developed by a small team with good applocation

experience needing to fulfull less than rigid requirements. Using the basis

COCOMA model calculate the effort in person-months if the estimated lines of code

is 33200

a.95 person-months.

b.111 perso n-months

c.102 person-months

d.87 person-moths

10.CRC modeling provides a way for identifying classes their respomnsibilities and

their collaboration .a collabration refers to.

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a.services provided by a class to other classes

b.requests sent by a class to ther classes to fulfill its own responsibility.

c.taxonomy of class types

d.characterstics of a class

12.a software was developed using component assembly model.after some time and

old componet is to be replaced by a new one without disturbing the overall

fuctioning of the softwarwe.following statements is true.

a.the new component should be developed in the same language as the old one

b.the new component should have exactly the same attribute as the old one.

c.the new component should inplement exactly the same methods as the old one.

d.The new component should provide exactly the same interface as the old one.

13.a real time system is to be developed .the choice of database would most

appropriately be

a.distributed databases because the reduce redundancy of data.

b.distributed databases because the facilate parallel data processing through miultitasking

c.centralized databases because of high computing power the server.

d.centralized databases because they provide better deadlock handling mechanism .

14.the following statement is equavalence echo~

a.echo SHOME

b.SHOME

c.pwd

d.ps

15.the equavalent of following statement is echo~bin

a.echosbin

b.echo bin

c.pwd

d.echo pwd

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16.the command that gives the process of ID of last command invoked

a.$@

b.$#

c.$!

d.$$

17.the output of the following shell script

$set-a planets mecury venus

$planets[9]=Pluto

$print ${planets[*]}

a.planets

b.mercurity venus puto

c.Pluto mercury Pluto

d.gives an error

18."let"command is used for

a.command substitution

b.arithmetic calculation

c.to create analias

d.not used

19.name the relationship(s)that denotes some semantic dependency among

otherwise unrelated classes.

a.generilazation or specification.

b.part of

c.association

d.all of the above

20.object persistence is best described by the following

a.the ability to retain an object throughout the execution of a method

b.the ability to retain an object throughout the execution of a program

c.the ability to save objects from one execution of a program to the text.

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d.the ability to retain an object throughout time and or space

21.what is socket ? how many required to make connection between two systems

a.a socket is 2-tuple having protocol and port number and requires 4sockets

b.a socket is 3-tuple having protocol address and port number and requires 4 sockets

c.a socket is 2-tuple having protocol and address and requires 2 sockets

d.a socket is 3-tuple having protocol address and port number and requires 2 sockets

22.TCP/IP runs on

a.an Ehtener

b.a token ring

c.an x.25 net

d.all of the above

23.the job og fragmentation and re-assembly of datagrams in TCP/IP protocol suite

is done by

a.network access layer

b.internet layer

c.transport layer

d.application layer

24.the sequence number in TCP header is used to

a.identify the first byte of the enclosed data int segment

b.identify the computer

c.identify the port on which server is running

d.none

25.what is output of the final echo command

$x=hell0

$ echo'x=goodbye'>sedtx

$sh setx ;x=bye

$echo $x

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a.hello

b.goodbye

c.bye

d.none

26. what would be the output of the following echo command in sequence?

$x=1

$echo'x=2'>setx

$sh setx

$echo $x

$x=3

$setx

$echo $x

a.2,2

b.1,2

c2,3

d.1,3

27.memory reference instruction branch subroutine (BSB) IS given instruction

transferming control to subroutine

b.first word of the subroutine

c.address of next instruction in sequence which is presently held in pc (return addres)

d.another BSBinstruction

28.assume memory units has 65536 words of 8bits.the number

of bits in program counter.accumalator. memory address

register instruction respectively are

a.16,8,16,8

b16,16,8,8

c8,16,8,16

d8,8,16,16

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29.which of the following instruction is used to load 2050h address toHL register

pair?

a.LOD H,2050H

B.LOAD H,2050H

C.LXIH,2050H

D.LDAH,2050H

30.what will be the value of the accumalator having AAH after executing RLC

instruction twice?

a.55h

b.abh

c.bah

d.aah

31.the top of the stack contains 5A&next byte down the stack is 14(all address in

hexadecimal) the stack pointer (sp) containts 3A56.an instruction call subroutint

stored at location 67AE whick is 3 bytes long is located at memory address 013F.

What shall be the contents of Program Counter, SP and stack respectively after the

call instruction is executed?

PC SP stack

a. 67AE 3A58 42,01,5A,14

b. 0142 3A58 01,42,5A,14

c. 67AE 3A56 42,01,5A,14

d. 0142 3A56 01,42,5A,14

32. Time oriented metrics is one of the below i.e. times it takes to analyze change

request, design an appropriate modification, implement the change, test it and

distribute to all users

Company Name : CSC (Computer Science Corporation)Type : Fresher, Job InterviewHeld on: June 2010

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Hi friends, I am Dhivyaa. K.S from Ganadipathy Tulsi’s Engineering College, Vellore. Recently I had appeared for off-campus interview conducted by ANNA UNIVERSITY PLACEMENT PROGRAMME on 17th & 18th June 2010 at Sai Ram Engineering College, Chennai and am very glad to say that I got selected.  Here I would like to share my interview experience with you.

Aptitude Technical Group Discussion Technical HR Personal Interview

WRITTEN TEST (MAJOR ELIMINATION TAKES PLACE, SO, CONCENTRATE MUCH ON THIS)

I. APTITUDEIn this round, they asked 40 questions in 40 minutes which includes

Two from Venn diagram, (easy)One from probability,3*3 Sudoku like below, (very easy)8 29

You have to fill the numbers from 1-9 in the boxes, such that it should have 15 from top to bottom and across the diagonal, then you would have the box as like the one below:8 2 51 4 76 9 3

From this you might have questions like, summing up the numbers which are right and left to the number 2. For us, three questions were asked from this:

Some four questions were asked from the four different passages. One problem based on age. (easy) Three questions based on Speed and Distance. One from permutation Percentage ( easy ) Few questions based on functions. (very easy one)

II. TECHNICAL It consists of 75 questions and duration is 40 minutes. We had the questions from previous year papers.

1. ------- is associated with web services. a) WSDL     b) WML     c) web sphere     d) web logic Ans: a

2.any large single block of data stored in a database, such as a picture or sound file, which does not include record fields, and cannot be directly searched by the database’s search engine.

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a) TABLE     b) BLOB     c) VIEW     d) SCHEME Ans: b

3.A reserved area of the immediate access memory used to increase the running speed of the computer program. a) session memory b) bubble memory c) cache memory d) shared memory Ans: c

4.a small subnet that sit between a trusted internal network and an untruster external network, such as the public internet.a) LAN b) MAN c) WAN d) DMZ Ans: d

5.technologies that use radio waves to automatically identify people or objects,which is very similar to the barcode identification systems,seen in retail stores everyday.a) BLUETOOTH b) RADAR c) RSA SECURE ID d) RFID Ans: d

6.main(){float fl = 10.5;double dbl = 10.5if(fl ==dbl)printf(“UNITED WE STAND”);elseprintf(“DIVIDE AND RULE”)}

What is the output?a) compilation error b) UNITED WE STAND c) DIVIDE AND RULE d) Linkage error.Ans: c

7.main(){static int ivar = 5;printf(“%d”,ivar--);if(ivar)

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main();}

What is the output?a)1 2 3 4 5 b) 5 4 3 2 1 c)5 d) Compiler error:main cannot be recursive function.Ans: b

8.main(){extern int iExtern;iExtern = 20;printf(“%d”,iExtern);}

What is the output?a)2 b) 20 c) compile error d) linker error Ans: d

9..#define clrscr() 100main(){clrscr();printf(“%d\n\t”, clrscr());}

What is the output?a)100 b)10 c)compiler errord)linkage errorAns: a

10.main(){void vpointer;char cHar = ‘g’, *cHarpointer = “GOOGLE”;int j = 40;vpointer = &cHar;printf(“%c”,*(char*)vpointer);vpointer = &j;printf(“%d”,*(int *)vpointer);vpointer = cHarpointer;printf(“%s”,(char*)vpointer +3);}

What is the output?a) g40GLE b) g40GOOGLE c) g0GLE

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d) g4GOOAns: a

11.#define FALSE -1#define TRUE 1 #define NULL 0main() {if(NULL)puts(“NULL”);else if(FALSE)puts(“TRUE”);elseputs(“FALSE”);}

What is the output?a) NULL b) TRUE c) FALSE d)0 Ans: b

12.main() {int i =5,j= 6, z;printf(“%d”,i+++j);}

What is the output?a)13 b)12 c)11 d) Compiler errorAns: c

13.main() {int i ;i = accumulator();printf(“%d”,i);}accumulator(){_AX =1000}

What is output?a)1 b)10 c)100 d)1000Ans: d

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14.main() {int i =0;while(+(+i--)!= 0)i- = i++;printf(“%d”,i);}

What is the output?a) -1 b) 0 c) 1 d) Will go in an infinite loopAns: a

15.main(){int i =3;for(; i++=0;)printf((“%d”,i);}

What is the output?a) 1b) 2c) 1 2 3d) Compiler error : L value required.Ans: d

16. main(){int i = 10, j =20;j = i ,j?(i,j)?i :j:j;printf(“%d%d”,i,j);}

What is the output?a) 20 20 b) 20 10 c) 10 20 d) 10 10Ans: d

17.main(){extern i;printf(“%d\t”,i);{int i =20;printf(“%d\t”,i);}}

What is the output?a) “Extern valueof i “ 20 b) Externvalue of i”

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c) 20d) linker Error: unresolved external symbol iAns: d

18.int DIMension(int array[]){return sizeof(array/sizeof(int);}main(){int arr[10];printf(“Array dimension is %d”,DIMension(arr));}

What is output?a) array dimension is 10 b) array dimension is 1 c) array dimension is 2 d) array dimension is 5Ans: b

19. main(){void swap();int x = 45, y = 15;swap(&x,&y);printf(“x = %d y=%d”x,y);}void swap(int *a, int *b){*a^=*b, *b^=*a, *a^ = *b;

What is the output?a) x = 15, y =45 b) x =15, y =15 c) x =45 ,y =15 d) x =45 y = 45Ans: a

20.main(){int i =257;int *iptr =&i;printf(“%d%d”,*((char*)iptr),*((char *)iptr+1));}

What is output?a)1, 257 b)257 1c)0 0d)1 1Ans: d

21.main(){int i =300;char *ptr = &i;*++ptr=2;printf(“%d”,i);}

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What is output?a) 556 b) 300 c) 2 d) 302Ans: a

22.#includemain(){char *str =”yahoo”;char *ptr =str;char least =127;while(*ptr++)least = (*ptrprintf(“%d”,least);}

What is the output?a) 0 b)127 c) yahoo d) yAns: a

23.Declare an array of M pointers to functions returing pointers to functions returing pointers to characters.a) (*ptr[M]()(char*(*)()); b) (char*(*)())(*ptr[M])() c) (char*(*)(*ptr[M]())(*ptr[M]() d) (char*(*)(char*()))(*ptr[M])();

24.void main(){int I =10, j=2;int *ip = &I ,*jp =&j;int k = *ip/*jp;printf(“%d”,k);}

What is the output?a) 2 b) 5 c) 10 d) compile error:unexpected end of file in comment started in line 4Ans: d

25.main(){char a[4] =”GOOGLE”;printf(“%s”,a);}

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What is the output?a) 2 b) GOOGLE c) compile error: yoo mant initializers d) linkage error.Ans: c

26.For 1MB memory, the number of address lines requireda) 12 b) 16 c) 20 d) 32Ans: 16

27.There is a circuit using 3 nand gates with 2 inputes and 1 output,f ind the output.a) AND b) OR c) XOR d) NANDAns: b (not sure)

28. What is done for push operationa) SP is incremented and then the value is stored.b) PC is incremented and then the value is stored.c) PC is decremented and then the value is stored.d) SP is decremented and then the value is stored.Ans: d

29.Memory allocation of variables declared in a program is:a) Allocated in RAMb) Allocated in ROMc) Allocated in stackd) Assigned in registers.Ans: c

30.What action is taken when the processer under execution is interrupted by TRAP in 8085MPU?a) Processor serves the interrupt request after completing the execution of the current instruction.b) processer serves the interrupt request after completing the current task.c) processor serves the interrupt immediately.d) processor serving the interrupt request depent deprnds upon the priority of the current task under execution.Ans: a

31.purpose of PC (program counter)in a microprocessor is:a) To store address of TOS(top of stack)b) To store address of next instructions to be executedc) count the number of instructionsd) to store the base address of the stack.Ans: b

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32.conditional results after execution of an instruction in a microprocess is stored ina) register b) accumulator c) flag register d) flag register part of PSW (program status word)Ans: c

33.The OR gate can be converted to the NAND function by adding----gate(s)to the input of the OR gate.a) NOT b) AND c) NOR d) XORAns: a

34. In 8051 microcontroller , has a dual function.a) port 3 b) port 2 c) port 1 d) port 0Ans: b

35.An 8085 based microprocessor with 2MHz clock frequency,will execute the following chunk of code with how much delay?MVI B,38HHAPPY: MVI C, FFHSADDY: DCR CJNZ SADDYDCR BJNC HAPPY

a) 102.3 b)114.5 c)100.5 d)120

36.In 8085 MPU what will be the status of the flag after the execution of the following chunk of code.MVI B,FFHMOV A,BCMAHLTa) S = 1, Z = 0, CY = 1 b) S = 0, Z = 1, CY = 0 c) S = 1, Z = 0, CY = 0 d) S = 1, Z = 1 ,CY = 1

37.A positive going pulse which is always generated when 8085 MPU begins the machine cycle.

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a) RD b) ALE address latch enable…c) WR d) HOLDAns: b

38.when a ----- instruction of 8085 MPU is fetched , its second and third bytes are placed in the W and Z registers.a) JMP b) STA c) CALL d) XCHGAns: c

39.what is defined as one subdivision of the operation performed in one clock period.a) T- State b) Instruction Cycle c) Machine Cycle d) All of the above Ans: a

40.At the end of the following code, what is the status of the flags.LXI B, AEC4HMOV A,CADD HLT a) S = 1, CY = 0, P = 0 , AC = 1 b) S =0 , CY = 1, P = 0,AC = 1 c) S = 0, CY = 1, P = 0 , AC = 1 d) S = 0, CY = 1, P = 1 , AC = 1

41.In 8051 micro controller what is the HEX number in the accumulator after the execution of the following code.MOV A,#0A5HCLR CRRC ARRC ARL ARL ASWAP Aa)A6 b)6A c)95 d)A5.Ans: a

42.The Pentium processor requires ------------ volts.a)9 b)12 c)5 d)24ans; c

43. The data bus on the Celeron processor is-------bits wide.

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a)64 b)32 c)16 d)128. Ans: a

44.K6 processora) Hitachi b) toshiba c) zilog d) AMD. Ans: d

45. What is the control word for 8255 PPI,in BSR mode to set bit PC3.a)0EH b)0FH c)07H d)06H. ans:c

46.The repeated execution of a loop of code while waiting for an event to occur is called ---------.The cpu is not engaged in any real productive activity during this period,and the process doesn’t progress towards completion.a) dead lock b) busy waiting c) trap door d) none.Ans: b

47. Transparent DBMS is defined asa) A DBMS in which there are no program or user access languages. b) A DBMS which has no cross file capabilities but is user friendly and provides user interface management. c) A DBMS which keeps its physical structure hidden from user d) none.Ans: c

48.Either all actions are carried out or none are. users should not have to worry about the effect of incomplete transctions.DBMS ensures this by undoing the actions of incomplete transctions.this property is known asa) Aggregation b) atomicity c) association d) data integrity.ans : B…

49.------ algorithms determines where in available to load a program. common methods are first fit,next fit,best fit.--------- algorithm are used when memory is full , and one process (or part of a process) needs to be swaped out to accommodate a new program.The ------------- algorithm determines which are the partions to be swaped out.a) placement, placement, replacementb) replacement, placement, placementc) replacement, placement, replacementd) placement, replacement, replacement Ans: D

50.Trap door is a secret undocumented entry point into a program used to grant access without normal methods of access authentication. A trap is a software interrupt,usually the result of an error condition.a)true b)false.Ans: A

51. Given a binary search tree,print out the nodes of the tree according t5o post order traversal. 4/ \2 5/ \1 3a)3,2,1,5,4. b)1,2,3,4,5. c)1,3,2,5,4. d)5,3,1,2,4. Ans: C

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52.which one of the following is the recursive travel technique.a)depth first search b)preorder c)breadth first search d)none.

53.which of the following needs the requirement to be a binary search tree.a) 5/ \2 7/1

b) 5/ \6 7

c) 5/ \2 7/\1 6

d) none.

54.in recursive implementations which of the following is true for saving the state of the stepsa) as full state on the stackb) as reversible action on the stackc) both a and bd) none

55.which of the following involves context switcha)previliged instructionb)floating point exceptionc)system callsd)alle)noneans : c

56.piggy backing is a technique fora)acknowledgeb)sequencec)flow controld)retransmissionans:A

57. a functional dependency XY is ___________dependency if removal of any attribute A from X means that the dependency does not hold any morea)full functionalb) multi valuedc)single valuedd)none

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ans : a

58)a relation schema R is in BCNF if it is in ___________and satisfies an additional constraints that for every functional dependency XY,X must be a candidate keya)1 NFb)2 NFc)3 NFd)5 NF

59) a _________sub query can be easily identified if it contains any references to the parent sub query columns in the _________ clauseA) correlated ,WHEREb) nested ,SELECTc) correlated,SELECTd) none

60) hybrid devise that combines the features of both bridge and router is known asa)router b)bridge c)hub d)brouter

61) which of the following is the most crucial phase of SDLCa)testing b)code generation c) analysys and design d)implementationAns: c

62)to send a data packet using datagram ,connection will be establisheda)no connection is requiredb) connection is not established before data transmissionc)before data transmissiond)none Ans: c

63)a software that allows a personal computer to pretend as as computer terminal isa) terminal adapterb)terminal emulationc)modemd)none Ans: b

64) super key isa) same as primary keyb) primary key and attributec) same as foreign keyd) foreign key and attributeAns: b

65.In binary search tree which traversal is used for ascending order valuesa) Inorder b)preorder c)post order d)noneAns: a

66.You are creating an index on ROLLNO colume in the STUDENT table.which statement will you use?

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a) CREATE INDEX roll_idx ON student, rollno; b) CREATE INDEX roll_idx FOR student, rollno;c) CREATE INDEX roll_idx ON student( rollno);d) CREATE INDEX roll_idx INDEX ON student (rollno);Ans: c

67.A________class is a class that represents a data structure that stores a number of data objectsa. container b.component c.base d.derivedAns: a

68.Which one of the following phases belongs to the compiler Back-end.a. Lexical Analysis b.Syntax Analysis c. Optimization d.Intermediate Representation.Ans: c

69.Every context _sensitive language is context_freea. true b.falseAns: b

70.Input:A is non-empty list of numbers LXß-infinityFor each item in the list L,doIf the item>x,thenXß the itemReturn XX represents:-a)largest numberb)smallest numberc)smallest negative numberd) none

71.Let A and B be nodes of a heap,such that B is a child of A. the heap must then satisfy the following conditionsa)key(A)>=key(B)b)key(A)c)key(A)=key(B)d)none

72.String ,List,Stack,queue are examples of___________a)primitive data typeb)simple data typec)Abstract data typed)noneAns: c

73.which of the following is not true for LinkedLists?a)The simplest kind of linked list is a single linked list ,which has one link per node .this link points to the next node in the list,or to a null value or emptylist if it is the last node.b)a more sophisticated kind of linked list is a double linkedlist or two way linkedlist .Each node has two links ,one to the previous node and one to the next node.

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c) in a circleLinkedList ,the first and last nodes are linked together.this can be done only for double linked list.d) to traverse a circular linkedlist ,u begin at any node and follow the list in either direction until u return to the original node.Ans: c

74.sentinel node at the beginning and /or at the end of the linkedlist is not used to store the dataa) trueb) false Ans:a

2. GROUP DISCUSSION

CSC is mainly looking in your communication and how well you are confident at. These guys are giving chance to everyone in putting their own points. i.e., they are conducting it in orderly fashion. She gave us: Should sex education be included in academic of school children. I was the first to start the GD, so, I went with the topic and No time was given to prepare. Results were immediately announced. In my batch, only one got eliminated. So guys, be confident while putting your points.

3. TECHNICAL HRInitially the HR was started with my project, I explained my project entirely. And he raised few questions from that. I answered for all those. So, you must have thorough knowledge of your project you had done.

Besides, he raised questions like difference between array and Linked list then Stack, Queue from Data Structures, DBMS, and Operator Overloading, paging concept from Operating System, few concepts from Mobile Computing and some more. It took some 25-30 minutes for me.Depending on the panel, you will get questions. You brush up all the concepts from Data Structure, DBMS, Operating System and Programming Languages. If you are belonging to ECE, concentrate much on Microprocessor. (This info was given by my friend).You just give your answers if you are sure, otherwise, you say, sorry mam/sir, at present, I could not recollect. Do not try to give related or fake answers.

4. PERSONAL INTERVIEWOnce you get into this round, you can stay relaxed.  He asked me the general questions like,

Tell me about yourself: I said my name, college, and aggregate, achievements (Paper presentation, Organized Women’s day, Basket ball). He was really impressed and asked me how did u celebrate women’s day? Then I explained that too.

Why should I hire you?I said, I think I do have all the qualities to perform a job in a better way.He asked what the qualities are.Then I replied with sincerity, dedication, and commitment towards the work.

What do you know about CSC?

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I was busy preparing for technical and I could not go through the website, but, before that interview my friend said few points about it.While I saying so, he asked me how do you get this information? (I don’t know whether my friend said the same thing before.)But, I do not like to lie, so I said him, I gathered from my friends. Once you get info about recruiting process, you please go through that company website.

Then he asked whether you are comfort when you are relocated to different locations and night shifts, I confidently said, Yes sir.

At last he asked me to wait till 4 p.m by the next day. My interview started on 17th June nearly at 9.30 a.m and I had completed my HR at 9.30 p.m. I was waiting the whole day on 18th June for results and my name was announced at 9.30 p.m. It was the most wonderful experience.

Guys be honest, confident and success will be yours. GOOD LUCK…!!!!!!!!! SEE YOU AT CSC…!!!!!!!

Exam/Interview Date : 17-Jun-2010No of Rounds : Aptitude Test, Technical Round-1, Technical Round-2, Group Discussion - GD, Client/Manager InterviewLocation : ChennaiContributor Name : Dhivyaa K S

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