ING. J.R.T.G. METODO DE CROSS Calcular los Cortantes y Momentos de la estructura adjunta: Datos: W W = a 1 b 2 c L1 = L2 = H = 4 ! H I 1 = I 2 = I = d e % I 4 = I ! = L1 L2 MOMENTO DE EMPOTRAMIENTO PERFECTO M&ab = '2.(# )n'm. M&ba = 2.(# )n'm. M&bc = '2.(# )n'm. M&cb = 2.(# )n'm. RIGIDECES RELATIVAS K ik = I / L FACTORES DE DISTRIBUCION C ik = Kik / S *ab = I 1 + L1 = 0.!,2!,2!,2( I Cab = *ab + *ab-*ad = '0.#0 Cba = *ba *bc = I 2 + L2 = 0.!,2!,2!,2( I Cad = *ad + *ab-*ad = '0.2,# Cbc = *bc *da = I + H = 0.2! I '1.000 Cbe = *be *eb = I 4 + H = 0.2! I *%c = I ! + H = 0.2! I Ccb = *cb + *cb-*c% = '0.#0 Cc% = *c% + *cb-*c% = '0.2,# '1.000 .!"# ".$%& '".$%& 0.000 '.!"# 0.000 0.000 0.000 0.000 0.000 0.001 0.001 0.000 0.000 '0.002 '0.001 0.001 0.001 0.00 0.00# '0.001 '0.002 '0.01# '0.00$ 0.00# 0.00 0.024 0.04$ '0.00$ '0.01# '0.11( '0.0!$ 0.04$ 0.024 0.1(! 0.1 '0.0!$ '0.11( 0.1( 0.0($ 0.1 0.1(! '0.1,4 '0.$# '0.$#0 '1.#, 1.$#! 0.,$ '0.$# '0.1,4 '2.((# 2.((# '2.((# 2.((# '0.#0 '0.41 '0.41 '0.#0 " . $ % & 0 . 0 0 0 ' 0 . 0 0 1 0 . 0 0 # 0 . 0 4 , 0 . 0 ! # 0 . # , 1 ' 0 . 2 , # a ( 0 . 1 # 4 0 . 1 ( 0 . 1 4 0 0 . 0 2 0 0 . 0 0 0 . 0 0 0 0 . 0 0 0 " . " " " ) 0 . 2 , # 0 . # 4 0 . 0 4 , 0 . 0 0 # 0 . 0 0 1 " . % ! 0 . 0 0 0 ' 0 . 0 0 1 0 . 0 0 4 0 . 0 2 ! 0 . 0 2 , 0 . , ( 0 . 0 0 0 0 . 0 0 0 0 . 0 $ 2 0 . 0 # 0 0 . 0 1 0 0 . 0 0 1 0 . 0 0 0 0 . 0 0 0 " . " " " 0 . 0 0 0 ' 0 . ( # ' 0 . 0 2 ! ' 0 . 0 0 4 0 . 0 0 1 * + , M- i = L 0 /&0